moon Triton, Neptune's largest moon Triton
The moon Triton is the captured moon which most likely originated in the Kuiper belt.
What is Kuiper belt?This is defined as a donut-shaped region beyond Neptune and has an extension from 30 to 50 AU or more from the Sun.
The moon Triton is the captured moon which originates from this belt thereby making it the most appropriate choice.
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Can Hotspots can be found at the edges of tectonic plates?
Answer:
No.
Explanation:
Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.
10C of charge flow through a resistor in 4 seconds. What is the current?
Answer:
Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.
Explanation:
The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps
Given Data
Charge = 10 Columbs
Time = 4 seconds
Current = ?
Current, charge and time RelationshipElectrical current is defined by how much electric charge has been transferred per second, giving the following relationship:
Charge = Current*Time
Rearranging this we get:
Current = Charge/Time
The symbol for charge is Q , it is measured in coulombs (C).
The symbol for current is I , it is measured in amperes (A).
The symbol for time is T, it is measured in seconds (s).
Substituting our given Data into the expression we have
Current = 10/4
Current = 2.5 Amps
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How much force is required to move a tractor 60m, when using 250J of work?
Answer:
Work done,W= 250J
Displacement , s = 60
We know that, Work done = Force x displacement
i.e , W = Fxs
250 J = F x 60m
F = 250/60
=4.16 N
Hence , 4.16 N of Force is applied on the body.
Please find attached photograph for your answer.
Hope it helps.
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The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?
Answer:
Period: 1/3= 0.33 seconds.
The frequency and period of the metronome's vibration when the metronome is set at 180 is 3Hz and 0.33 s.
What is the frequency?Frequency is the number of oscillations per second.
The time period is the reciprocal of the frequency.
Given is the metronome set at 180.
The reading of metronome = frequency in seconds = 180 / 60 = 3 Hz
The time period of the metronome's vibration T = 1/3 = 0.33 seconds.
Thus, the frequency and the time period is 3Hz and 0.33 s.
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The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
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Find the volume of this figure.
4 dm
2 dm
3 dm
Answer:
4×2×3= 24dm^3
.......................
Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.
Answer:
hi I don't know sorry sorry forgive me
Explanation:
sorry
A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps
how to find the latitude and longitude of an address
Answer:
To get the latitude of the address in cell B2, use the formula = GetLatitude (B2) To get the longitude of the address in cell B2, use the formula = GetLongitude (B2) To get both the latitude and longitude of the address in cell B2, use the formula = GetCoordinates (B2)
Explanation:
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What is the relationship between momentum and kinetic energy.
Answer:
constant object, momentum increases directly with speed
Explanation:
whereas kinetic energy increases the square of the velocity due to energy momentum
3.
If the specific heat of iron = 0.46 J/g Cº, how much heat is needed to warm 50 g of
iron from 20° C to 100° C?
Answer:
1.84 kJ (kilojoules)
Explanation:
A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.
If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:
Heat = (specific heat)*(mass)*(temp change)
Heat = (0.46 J/g Cº)*(50g)*(100° C - 20° C)
[Note how the units cancel to yield just Joules]
Heat = 1840 Joules, or 1.84 kJ
[Note that the number is positive: Energy is added to the system. If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C). The number is -1.84 kJ: the negative means heat was removed from the system (the iron).
Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 5.6-kg projectile from rest to a speed of 3.5 × 103 m/s. The net force accelerating the projectile is 2.5 × 105 N. How much time is required for the projectile to come up to speed?
Answer:
7.84 s
Explanation:
Ok, one step at a time. We know the mass of the projectile, we know the force. Acceleration is easily obtained from Newton second law:
[tex]\vec F = m\vec a[/tex][tex]2.5\times 10^5 = 5.6a \rightarrow a = (2.5/5.6) \times 10^5 = 4.46 \times 10^4 ms^-^2[/tex].
At this point, we know the acceleration, we know initial and final velocity, we can time the ammount of time it took to get there.
[tex]v= v_0 +at \rightarrow 3.5\times10^3 = 0 + 4.46\times10^4 t\\t= \frac{3.5\times10^3}{4.46\times10^4} = 7.84 s[/tex]
Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
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A truck with a mass of 1500 kg is decelerated at a rate of 5m/s2.how much force did this require ?
Answer:
6500N
Explanation:
F = ma so therefore Were given mass (m) = 1500 kg, acceleration (a) = 5 m/s2, well have to calculate the force to be:
1500 x 5 = 6500 N
What can the magnetic fields influence?
A) It can cause objects to be pulled towards the magnet and pushed away from the magnet.
B) It only causes a repel force between the magnets.
C)It cause only an attraction force.
Explanation:
Magnetic fields are areas where an object exhibits a magnetic influence. The fields affect neighboring objects along things called magnetic field lines. A magnetic object can attract or push away another magnetic object. You also need to remember that magnetic forces are NOT related to gravity.
What kind of force could cause this ball to not be at rest anymore, or cause it to move?
Answer:
friction
Explanation
Answer:
Friction
Explanation:
What force prevents an object at rest?
Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.
a girl runs once around a circular track with a radius of 100m at speed of 10m/s.
calculate her displacement
Answer:
0 m
Explanation:
Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned
The fundamental frequency, wavelength of the wave, and mass per unit
length of the string, determines the tension in the string.
The tension to which the D-string must be tuned is approximately 19.718 NewtonsReasons:
From a similar question, we have;
Fundamental frequency, f₁ = 146.8 Hz
Oscillating length on the D-string, λ₁ = 0.61 m
Mass of the string = 1.5 × 10⁻³ kg.
We have;
[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]
Therefore;
[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]
Which gives;
[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]
The tension to which the D-string must be tuned, T ≈ 19.718 Newtons
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The parameters given in a similar question obtained online are;
The fundamental frequency of the tone, f₁ = 146.8 Hz
The oscillating length on the D-string, λ₁ = 0.61 m
The mass of the string = 1.5 × 10⁻³ kg.
In an exothermic reaction, energy is
the surroundings.
In an endothermic reaction, energy is
the surroundings.
Trick to identify:-
Exothermic reaction has +∆H sign on product sideEndothermic reaction has -∆H sign on product side or +∆H sign on reactant sideAnswer:
In an exothermic reaction, energy is
✔ released to
the surroundings.
In an endothermic reaction, energy is
✔ absorbed from
the surroundings.
Explanation:
What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second
Answer:
6J
Explanation:
simply apply kinetic energy definitoon:
[tex]k = \frac{1}{2} mv {}^{2} = \frac{1}{2} 3 \times 2 {}^{2} = 6[/tex]
2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?
Answer:
3.125 Kilometers
Explanation:
To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answer:
B
Explanation:
I don't know but its b
given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?
If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Given data:
The gravitational force = 30 N
Mass 1 =m₁
Mass 2=m₂
Distance between charges = R
Condition given:
Mass 1 = 2m₁
Mass 2= 2m₂
Distance between charges = 3R
[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]
Case 2;
[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]
Hence, the forces between the masses will be 13..33 N.
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if you have 3 moles of iron, how many grams of iron do you have?
Answer:
55.84 look at periodic table
so 55.84*3= 167.52gFe
When waves are closer together and there are more waves, then the wave has a higher ____________.
Answer:
When waves are closer together and there are more waves, then the wave has a higher frequency.
Explanation:
Hoped this helped.
Answer:
frequency
Explanation:
A cyclist sitting still at the top of a hill displays gravitational potential energy. What makes it possible for the cyclist to have this type of energy?
Explanation:
because its speed (v) is 0
Give an example of when a conscientious objector might exercise their right:
I couldn't answer this question may someone please help me
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s²
By using the formula:
v²= u²+ 2as
v²=0²+ 2×10×15
v²= 300
V= 10root over 3
[tex]10 \sqrt{3} [/tex]
For calculating time,
v= u+ at
10 root over 3 = 0+ 10t
10 root over= 10t
t = 1 root over 3
t = 1.73 s
[tex]1 \sqrt{3} [/tex]
The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.