plz help! will give brainliest!

Answer:

[tex]P(F\ and\ R) = 0.21[/tex]

[tex]P(F\ and\ R^{-}) = 0.14[/tex]

[tex]P(R^{-}|F)= 0.40[/tex]

[tex]P(F^{-} and\ R) = 0.39[/tex]

[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]

[tex]P(F^{-}) =0.65[/tex]

Step-by-step explanation:

The variables have been defined in the question as:

[tex]F = Female\ Moviegoer[/tex]

[tex]F^{'} = Male\ Moviegoer[/tex]

[tex]R = Romantic\ Comedy[/tex]

[tex]R^{'} = War\ File[/tex]

Also, we have the following given parameters:

[tex]P(F) = 0.35[/tex]

[tex]P(F^{-}) =0.65[/tex]

[tex]P(R) =0.60[/tex]

[tex]P(R^{-}) = 0.40[/tex]

The solution is as follows:

[tex]a.\ P(F\ and\ R)[/tex]

[tex]P(F\ and\ R) = P(F) * P(R)[/tex]

Substitute values for P(F) and P(R)

[tex]P(F\ and\ R) = 0.35 * 0.60[/tex]

[tex]P(F\ and\ R) = 0.21[/tex]

[tex]b.\ P(F\ and\ R^{-})[/tex]

[tex]P(F\ and\ R^{-}) = P(F) * P(R^{-})[/tex]

Substitute values for P(F) and P(R-)

[tex]P(F\ and\ R^{-}) = 0.35 * 0.40[/tex]

[tex]P(F\ and\ R^{-}) = 0.14[/tex]

[tex]c.\ P(R^{-}|F)[/tex]

[tex]P(R^{-}|F)=\frac{P(R^{-}\ and\ F)}{P(F)}[/tex]

[tex]P(R^{-}|F)=\frac{P(R^{-})\ *\ P(F)}{P(F)}[/tex]

Substitute values for P(F) and P(R-)

[tex]P(R^{-}|F)=\frac{0.40 * 0.35}{0.35}[/tex]

[tex]P(R^{-}|F)= 0.40[/tex]

This implies that both events are independent

[tex]d.\ P(F^{-} and\ R)[/tex]

[tex]P(F^{-} and\ R) = P(F^{-}) * P(R)[/tex]

Substitute values for P(F-) and P(R)

[tex]P(F^{-} and\ R) = 0.65 * 0.60[/tex]

[tex]P(F^{-} and\ R) = 0.39[/tex]

[tex]e.\ P(F^{-}\ and\ R^{-})[/tex]

[tex]P(F^{-}\ and\ R^{-}) =P(F^{-}) * P(R^{-})[/tex]

Substitute values for P(F-) and P(R-)

[tex]P(F^{-}\ and\ R^{-}) =0.65 * 0.40[/tex]

[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]

[tex]f.\ P(F^{-})[/tex]

[tex]P(F^{-}) =0.65[/tex] --- Given

Answer:

yes 40

Step-by-step explanation:

she got it correct

Answer:

C

Step-by-step explanation:

there would have to be one more zero between 0 and 8 for both of them

Answer:

c is the correct answer

Step-by-step explanation:

Answer:

x = 56°

Step-by-step explanation:

Base angles of an isosceles triangle are equal.

This:

The angle of the triangle to our right, which is the third unequal angle = 180 - 2(31)

= 180 - 62

= 118°

The base angle of the triangle to our left = 180 - 118 (angles on a straight line)

= 62°

x = 180 - 2(62)

x = 180 - 124

x = 56°

Answer:

0.5440

Step-by-step explanation:

Given that ;

          Brand 1 : Couple      Brand 2: Sedan        Total

                           100                            200              300

                           240                              85              325

            Total  :  340                              285             625

The probability that a vehicle selected at random is a couple given that it was brand 1 will be;

The probability that a selected vehicle is a couple is  340/625

=0.5440

Answer:

Answer are right here

Step-by-step explanation:

66 as a fraction is 33/50 and as a decimal, it would be 0.66

2/3 as a fraction would be 2/3 and as decimal it would be 0.66666667

Answer:

65 reaminder  85  

Step-by-step explanation:

u divided it and theres a big remainder so i did the two first reinders i found

1.order of operations

2.12 or variable

3.error

4.Line(12¨

hope this helps

plz consider marking brainliest

Answer:

13

Step-by-step explanation:

Just replace x with 10, so F(10) = 10/2 + 8. Which is 5 + 8.

Answer:

thats correct

Step-by-step explanation:

i had that on my test and i ot it right

Answer:

$14.9

Step-by-step explanation:

238.40 / 16 = $14.9 hourly

Answer:

Gabriel earns $14.90 per hour

Step-by-step explanation:

238.4 divided by 16 gives you 14.9

Hope this helps

Answer:

20/6=p/12

cross multiply

20*12=6p

240=6p

divide both sides by 6

p=40

Answer:

C - 40

Step-by-step explanation:

Answer:

output is -17

Step-by-step explanation:

x is input, y is output. You do y = -24 + 7

then y = -17

Answer:

113 inches or 3.13889 yards

Answer:

(a). y = - 4x + 19 ; (b). y = [tex]\frac{1}{4}[/tex] x + 2  

Step-by-step explanation:

Slope "m" of given line is

m = - 4

Slope of parallel line is ( - 4) and perpendicular line is [tex]\frac{1}{4}[/tex]

P(4, 3)

y - [tex]y_{P}[/tex] = m( x - [tex]x_{P}[/tex] )

(a). y - 3 = - 4 (x - 4)

y = - 4x + 19

(b). y - 3 = [tex]\frac{1}{4}[/tex] ( x - 4 )

y = [tex]\frac{1}{4}[/tex] x + 2

Answer:

-1.5

Step-by-step explanation:

You were on the free points page

Answer:

A

   The correct option is  C

B

  The  value of  z-test is  [tex]z = -2.267[/tex]

Step-by-step explanation:

From the question we are told that  

    The null hypothesis  [tex]H_o : p = 0.22[/tex]

    The alternative hypothesis  [tex]H_a : p \ne 0.22[/tex]

    The  level of significance is  [tex]\alpha = 0.01[/tex]

    The sample proportion is  [tex]\^ p = 0.15[/tex]

     The sample size is  n = 180

Generally from central limit theorem

if   np  and  nq  are  >  5  then  normal sampling distribution can be used

So  

     np =  180  * 0.22 =  39.6  >  5

and  

     nq =  180 * (1 -0.22) =  140.4 > 5

So normal sampling distribution can be used

Generally the z-test is mathematically represented as

      [tex]z = \frac{\^ p - p }{ \sqrt{\frac{ p(1- p ) }{n } } }[/tex]

=>   [tex]z = \frac{ 0.15 - 0.22 }{ \sqrt{\frac{ 0.2(1- 0.22 ) }{ 180 } } }[/tex]

=>   [tex]z = -2.267[/tex]

Answer:

The indifference point is 8 classes.

Step-by-step explanation:

Giving the following information:

Option 1:

$40 joining fee and $20 per class

Option 2:

$0 joining fee and $25 per class

First, we establish the total cost formulas:

Option 1= 40 + 20x

Option 2= 0 + 25x

x= number of classes

Now, we equal both formulas and isolate x:

40 + 20x = 25x

40=5x

8=x

The indifference point is 8 classes.

Prove:

Option 1= 40 + 20*8= $200

Option 2= 0 + 25*8= $200

Answer:

it goes 4233 miles

Step-by-step explanation:

sorry if am wrong luv!

Answer:

The required equation will be:

Step-by-step explanation:

We know the slope-intercept form of the line equation

[tex]y = mx+b[/tex]

where 'm' is the slope or rate of change and 'b' is the y-intercept of the equation

Given that Bea's catering charges $3 per person.

Given that the clean-up fee to cater banquets = $60

In other words, $60 is the initial condition or y-intercept.

Given that the cost budget = c = $200

Thus, the equation becomes

c = mn+b

substituting c = 200, m = rate of cgange = 3, b = 60

200 = 3n + 60            ∵ comparing with y = mx+b

Thus, the required equation will be:

The equation that determines the no of students should be 200 = 3n + 60  

Here we assume n be the number of students

And, c be the the cost budget.

So, we know the equation should be formed by applying the following expression

c = mn+b

Here c = 200, m = r = 3, b = 60

Therefore, the equation is 200 = 3n + 60        

Hence, The equation that determines the no of students should be 200 = 3n + 60  

Learn more about an equation here; https://brainly.com/question/18510004

Answer:

9/10 of a paragraph in a minute

Step-by-step explanation:

find out how much he can type in 1/3 of a minute

(3/5)/2     3/5=6/10    (6/10)/2   3/10

(3/10)*3=9/10

Answer:

9/10

Step-by-step explanation:

hope it worked

Answer:

both student one and student two

Step-by-step explanation:

With the properties of congruent triangle we conclude that the statement of both student I and student II are correct.

Congruent triangle-If the sides of two triangle measure same lengths and the angle have same measures then the two triangle are said to be congruent.

Given-

Statement of student 1-Because reflections preserve side lengths,

[tex]QR \cong SR[/tex],

[tex]PQ \cong TS[/tex],

[tex]PR \cong TR.[/tex] so,

[tex]\bigtriangleup PQR \cong \bigtriangleup TSR[/tex]

In all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangle are said to be congruent by the side side side (SSS) rule. Hence, the above statement is correct.

Statement of student 2- Because reflections preserve both side lengths and angle measures,

[tex]\angle RQP \cong \angle RST[/tex]

[tex]QR \cong SR[/tex]

[tex]PQ \cong TS[/tex]

[tex]\bigtriangleup PQR \cong \bigtriangleup TSR[/tex]

In any two sides and the angle included between the sides of one triangle are equivalent to the corresponding two sides and the angle between the sides of the second triangle, then the two triangle are said to be congruent by the side angle side (SAS) rule. Hence the above statement is correct.

Hence, with the properties of congruent triangle we conclude that the statement of both student I and student II are correct.

https://brainly.com/question/25813512

Answer:

circle 3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given:

Arrival rate λ = 1.25 min

Mean μ = 2

Computation:

(a) Probability [No customers in system]

Probability [No customers in system] = 1-[λ/μ]

Probability [No customers in system] = 1-[1.25/2]

Probability [No customers in system] = 0.375

(b) Customers waiting for service

Customers waiting for service = λ²/ [μ(μ-λ)]

Customers waiting for service = 1.25²/ [2(2-1.25)]

Customers waiting for service = 25/24

(c) Average time customer wait

Average time customer wait = λ / [μ(μ-λ)]

Average time customer wait = 1.25/ [2(2-1.25)]

Average time customer wait = 1.25/1.5

(d) May be wait because Customers waiting for service = 25/24

(e) Per customer average time

Per customer average time = 1/(μ-λ)

Per customer average time = 1/(2-1.25)

Per customer average time = 1.33 (Approx)

Answer:

30

Step-by-step explanation:

Perimeter of rectangle = 5y - 1 + 4y + 2 + 5y - 1 + 4y + 2

                                      = 18y + 2

18y + 2 = 128

18y = 128 - 2

     = 126

y = 126 ÷ 18

y = 7

Length of AD = 4y + 2

                      = 4(7) + 2

                      = 28 + 2

                      = 30

Answer:

C: 12x squared

Step-by-step explanation:

the equation would look like [tex]2x^{2}[/tex] · [tex]6[/tex] or [tex]6(2x^{2})[/tex]

you only multiply the coefficients, leave the exponent alone for this one

so 2 times 6 would be 12 and the [tex]x^{2}[/tex] remains the same giving you [tex]12x^{2}[/tex]