Point B has coordinates (4,2). The x-coordinate of point A is - 1. The distance between point A and
point B is 13 units. What are the possible coordinates of point A?

Answer:

Step-by-step explanation:

Answer:

The volume of the rock is 648 cm^3

Step-by-step explanation:

Likely the only dimension that is free to move is the depth of 7 cm.

Volume of the Rock = L * W * h1

L = 24

W = 10

h1 = 2.7

V = 24 * 10 * 2.7

V = 648 cm^3

Answer:

67 mph

Step-by-step explanation:

201/3 = 67

Answer:

39.2 AU.

Step-by-step explanation:

If my memory serves me right an astronomical unit is 93,000,000 miles.

So the answer is 3647720000/93000000

= 39.2 AU.

The coordinates of the image after a dilation by scale factor -1/3 with center (-1, 2) are (0, 2), (0, 4), and (-1, 4).

In Geometry, dilation can be defined as a type of transformation which typically changes the size of a geometric object, but not its shape.

Next, we would have to dilate the coordinates of the pre-image by using a scale factor of -1/3 centered at the point (-1, 2) by using this mathematical expression:

(x, y)  →  (k(x - a) + a, k(y - b) + b)

For coordinate A, we have;

Coordinate A = (-4, 2)  →  (-1/3(-4 - (-1)) + (-1), -1/3(2 - 2) + 2)

Coordinate A = (-4, 2)  →  (-1/3(-4 + 1) - 1, -1/3(2 - 2) + 2)

Coordinate A' = (1, 1)  →  (0, 2)

For coordinate B, we have;

Coordinate B = (-4, -4)  →  (-1/3(-4 - (-1)) + (-1), -1/3(-4 - 2) + 2)

Coordinate B = (-4, -4)  →  (-1/3(-4 + 1) - 1, -1/3(-4 - 2) + 2)

Coordinate B' = (1, 1)  →  (0, 4)

For coordinate C, we have;

Coordinate C = (-1, -4)  →  (-1/3(-1 - (-1)) + (-1), -1/3(-4 - 2) + 2)

Coordinate C = (-1, -4)  →  (-1/3(-1 + 1) - 1, -1/3(-4 - 2) + 2)

Coordinate C' = (1, 1)  →  (-1, 4).

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Answer:

f(x) - g(x) = x^3 - 3x^2 - 4x - 4

Step-by-step explanation:

f(x) - g(x)

x^3 - 2x^2 - 3x - 5 - ( x^2 + x - 1 )

x^3 - 2x^2 - 3x - 5 - x^2 - x + 1

x^3 - 3x^2 - 4x - 4

Answer:

I believe it is the first choice

Step-by-step explanation:

As the x-values go to positive infinity, the function's

values go to negative infinity is the answer because the x-valures are in the first coordinate which is positive but the functions is going negative because of the line in the 3rd coordinate.

I tried my best, i hope you get it correct.

Please let me know if this is correct or not, if not i will edit my answer.

Please mark brainliest :)

Answer:

Step-by-step explanation:

The product of 35 and (-1) is -35.

As,

35 × (-1) = -35

Answer:

1+1=11 2+2=22 ok na yan kuya or ate

Answer:

10x² + 16xy + 6x

Step-by-step explanation:

2x(5x+8y+3)

10x² + 16xy + 6x

Answer:

[tex]10x^{2} + 16xy + 6x[/tex]

Hope this helped!

Answer:

3 units

Step-by-step explanation:

Answer:

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

[tex] \frac{x}{7} - 4 = 6 \\ \frac{x}{7} = 6 + 4 \\ \frac{x}{7} = 10 \\ x = 10 \times 7 \\ x = 70[/tex]

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

➳ RainbowSalt2²2² ❦

Step-by-step explanation:

V≈3323.42cm³

r Radius

11.2

cm

h Height

25.3

cm

Solution

V=πr2h

3=π·11.22·25.3

3≈3323.41966cm³

hope it is helpful

BC would equal the same as EF, they are similar. All you would have to do is figure out the pre image (BC) of EF.

Answer: 8

Step-by-step explanation:

Answer:

x=109/56

dn did djs. hd hd hd hd hd hd

Answer:

400

Step-by-step explanation:

sqrt(160000)=sqrt(16)*sqrt(10000)=4*100

=========================================================

Explanation:

Let's say that point A is at (0,0) and B is somewhere else on the parabola.

I'll make point B go to the right of point A.

For now, let's say B is at (4,16).

If we compute the slope of line AB, then we find the average rate of change (AROC). The AROC in this case is (y2-y1)/(x2-x1) = (16-0)/(4-0) = 16/4 = 4. Because point A is at (0,0), we're really just computing y/x where the x,y values come directly from point B.

--------------

Now let's move B to (3,9). If we used the slope formula again, we would get the slope of 3. Note how y/x = 9/3 = 3.

Then let's move B to (2,4). The AROC is now y/x = 4/2 = 2

As B gets closer to A, the AROC is decreasing. The AROC is slowly approaching the IROC (instantaneous rate of change).

--------------

Point B is generally located at (x,x^2) for any real number x. Keeping A always fixed at the origin, the slope of line AB is y/x = (x^2)/x = x.

What does this all mean? It means that if x = 0, then the IROC is 0. You might be quick to notice that we cannot divide by zero. So instead of letting x be zero itself, we'll just get closer and closer to it. This is where the concept of limits come into use. This is what calculus is based on (both integral and differential calculus).

Anyway, when calculating the IROC, we're really calculating the slope of the tangent line to the f(x) curve. Refer to the diagram below.

----------------

In short, the slope of the tangent line at x = 0 is m = 0. We have a flat horizontal line that touches the parabola at (0,0).

A1/ the difference of 3 and x divided by 7

A2/ 3e - 5

A3/ -1

A4/ g + (g - 8)

A5/ One half the difference between eight and a number y

I'm not sure, but I hope it helps :)

Answer:

10

Step-by-step explanation:

Sum of 8 and 7 = 8 + 7 = 15

5 subtracted from sum of  8 and 7 = 15 - 5 = 10

The answer to this question = 10

The sum is the result of the addition of two or more numbers.

The difference between the two numbers is called subtraction.

First, we find the sum of 8 and 7

8 + 7 = 15

Now, we subtract 5 from 15

15 - 5 = 10

∴ The result to the given question = 10

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Answer:

The equation of the new function is [tex]g(x) = \frac{x}{3}[/tex]

Step-by-step explanation:

Horizontally stretching a function:

Horizontally stretching a function f(x), by a factor of a, means that:

[tex]g(x) = f(\frac{x}{a})[/tex]

In this question:

[tex]f(x) = x[/tex], horizontally stretched by a factor of 3, so [tex]a = 3[/tex], and:

[tex]g(x) = f(\frac{x}{3}) = \frac{x}{3}[/tex]

The equation of the new function is [tex]g(x) = \frac{x}{3}[/tex]

1:6

Hope this helps! :)

______________

Answer:

n value is 6

2:12=1:6

n is 6

Answer:

8.5 miles an hour.

Step-by-step explanation:

There are many ways to do this, but I am going to do it the way I think is the most simple.

First, divide 748 yards by 3 minutes to get the amount of yards per minute. 748 / 3 = 249.33333

Second, divide the previously gotten number (249.33333, [3's go on forever]) by the amount of yards in a mile (which is 1760 yards per mile). This turns into 249.33333 / 1760 = 0.1416666 (6's go on forever). This is miles per minute so you must make it per hour.

You then multiply that infinite number by the amount of minutes in an hour (60 minutes per hour). 0.14166666 * 60 = 8.5 miles per hour.

Answer:0.02

Step-by-step explanation:

Answer:

The Area of the Enclosed Region Is 64/3.

Step-by-step explanation:

As Given in Question

We have, Curve 4x+[tex]Y^{2}[/tex]=12

& X=Y

Solution.

4Y+[tex]Y^{2}[/tex]=12   (X=Y)

[tex]Y^{2}[/tex]+4Y-12=0

[tex]Y^{2}[/tex]+6Y-2Y-12=0

Y(Y+6)-2(Y+6)=0

(Y-2)*(Y+6)=0

Y=2 & -6  (X=Y)

Now at (2,2) & (-6,-6) both curves intersect each other.

The Area Of Enclosed Region is    [tex]\int\limits^2_{-6} [(3-Y^{2}/4 )-Y] \, dy[/tex]

by Solving This Equation we get Area of Region = 64/3 .    

this equation Solution & Curve Diagram please see In Attachment .  

Answer:

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2\sqrt{x + 49} +49\ln|\frac{\sqrt{x + 49}-7}{\sqrt{x + 49}+7}|+c[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx[/tex]

Required

Solve by substitution

Let:

[tex]u = \sqrt{x + 49}[/tex]

Square both sides

[tex]u^2 = x + 49[/tex]

Differentiate

[tex]2udu = dx[/tex]

Also notice that:

[tex]x = u^2 - 49[/tex]

So, we have:

[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{u}{u^2 - 49}} \, 2udu[/tex]

[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2}{u^2 - 49}} \, du[/tex]

Add 0 to the numerator

[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2+0}{u^2 - 49}} \, du[/tex]

Express 0 as 98 -98

[tex]\int\limits {\frac{\sqrt{x + 49}}{x}} \, dx =\int\limits {\frac{2u^2-98+98}{u^2 - 49}} \, du[/tex]

Split the fraction

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( \frac{2u^2-98}{u^2 - 49}+\frac{98}{u^2 - 49} )\, du[/tex]

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( \frac{2(u^2-49)}{u^2 - 49}+\frac{98}{u^2 - 49} )\, du[/tex]

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( 2+\frac{98}{u^2 - 49} )\, du[/tex]

Rewrite as:

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =\int( 2+\frac{98}{u^2 - 7^2} )\, du[/tex]

Integrate

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +\int\frac{98}{u^2 - 7^2} \, du[/tex]

Remove constant (98)

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98\int\frac{1}{u^2 - 7^2} \, du[/tex]

As a general rule,

[tex]\int \frac{1}{x^2 - a^2} \, dx = \frac{1}{2}\ln|\frac{x-a}{x+a}|[/tex]

So, we have:

[tex]\int \frac{1}{u^2 - 7^2} \, du = \frac{1}{2}\ln|\frac{u-7}{u+7}|[/tex]

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98\frac{1}{u^2 - 7^2} \, du[/tex] becomes

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +98*\frac{1}{2}\ln|\frac{u-7}{u+7}|+c[/tex]

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2u +49\ln|\frac{u-7}{u+7}|+c[/tex]

Substitute values for u

[tex]\int{\frac{\sqrt{x + 49}}{x}} \, dx =2\sqrt{x + 49} +49\ln|\frac{\sqrt{x + 49}-7}{\sqrt{x + 49}+7}|+c[/tex]

Answer:

spongebob at the bottom of the sea

Step-by-step explanation:

In a plain, robust, conversational style, the author known as “Elena Ferrante” has captivated readers worldwide with her chronicle of a complicated friendship between two women.

The step would be, "Suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational." Option A is correct.

Given that,
a and b are rational numbers, b ≠ 0, and r is an irrational number, then a + br is irrational. the first step of the proof with contradiction is to be determined.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

here,
For the statement,

a and b are rational numbers, b ≠ 0, and r is an irrational number, then a + br is irrational.

Contradiction will be "suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational."

Thus, the step would suppose not. That is, suppose there exist irrational numbers a and b such that b ≠ 0, r is a rational number, and a + br is rational.

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The answer is 2.1 Km. Hope this helps!