Question 22
When 85 g of CH4 are mixed with 320 g of O2 the limiting reactant is
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Answers

Answer 1

Answer:

O2, oxygen.

Explanation:

Hello.

In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:

[tex]n_{CO_2}^{by\ CH_4}=85gCH_4*\frac{1molCH_4}{16gCH_4} *\frac{1molCO_2}{1molCH_4} =5.3molCO_2\\\\n_{CO_2}^{by\ O_2}=320gO_2*\frac{1molO_2}{32gO_2} *\frac{1molCO_2}{2molO_2} =5molCO_2[/tex]

Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.

Best regards.


Related Questions

squence the steps in constructing and interpreting an electron dot diagram

Answers

43 EXPLAINION The cardiac system comes in various different shapes and sizes

Calculate the molarity of solution of "sodium sulfate" that contains 5.2 grams sodiums sulfate diluted to 500mL

Answers

Taking into account the definition of molarity, the molarity of solution of sodium sulfate is 0.0732 [tex]\frac{moles}{liter}[/tex].

Definition of molarity

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]Molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Molarity of solution of sodium sulfate.

In this case, you have:

number of moles of sodium sulfate= [tex]5.2 grams\frac{1 mole}{142 grams} = 0.0366 moles[/tex] (being 142 g/mole the molar mass of sodiums sulfate)volume= 500 mL= 0.5 L (being 1000 mL= 1 L)

Replacing in the definition of molarity:

[tex]Molarity=\frac{0.0366 moles}{0.5 L}[/tex]

Solving:

Molarity= 0.0732 [tex]\frac{moles}{liter}[/tex]

Finally, the molarity of solution of sodium sulfate is 0.0732 [tex]\frac{moles}{liter}[/tex].

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How many moles of Co would be required to react with 6.14m of P4

Answers

The number of moles of Co that would be required to react with 6.14 moles of P4 would be 36.84 moles

Stoichiometric calculations

From the equation of the reaction:

6Co + P4 → 2Co3P2

For every 1 mole of P4, 6 moles of Co is required for complete reaction.

Thus, the mole of Co that would be needed for 6.14 moles of P4 would be:

                      6 x 6.14 = 36.84 moles

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How many grams are in 2.3 moles of Aluminum

Answers

Answer:

62.1 gram

Explanation:

Al molar mass = 27 g/mol

mass = molar mass × no of moles

= 27 × 2.3 = 62.1 gram

A 0.205 g sample of CaCO3 (Mr = 100.1 g/mol) is added to a flask along with 7.50 mL of 2.00 M HCl. CaCO3(aq) + 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g) Enough water is then added to make a 125.0 mL solution. A 10.00 mL aliquot of this solution is taken and titrated with 0.058 M NaOH. NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) How many mL of NaOH are used?​

Answers

The required volume of sodium hydroxide is 15 mL.

What is concentration?

The term concentration refers to the amount of substance present. It is the quotient of the number of moles and volume of solution.

We have the reaction; 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)

Number of moles of CaCO3 = 0.205 g / 100.1 g/mol = 0.0020 moles

Number of moles of HCl = 2.00 M * 7.50/1000 = 0.015 moles

Since 2 moles of HCl reacts with 1 mole of CaCO3

x moles of HCl reacts with 0.0020 moles

x = 0.004 moles of HCl

This means that HCl is in excess by the amount 0.011 moles.

Now consider the reaction; NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)

Concentration of HCl = 0.011 moles/0.125L = 0.088 M

From;

CAVA/CBVB = na/nb

CAVAnb = CBVBna

VB = CAVAnb/CBna

VB = 0.088 M * 10mL * 1/0.058 M * 1

VB = 15 mL

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A rock has been placed in water. The mass of the rock is 20 g. What is the rock's density?
g/mL

Answers

Answer:

0.67 g mL-1

Explanation:

Every time a problem asks you to find the density of a substance, your goal will essentially be to determine the mass of one unit of volume of said substance.

Cu + 2AgNO3


How many atoms of oxygen are mixed in the chemical equation above

Answers

2 oxygen because
It’s 2AgNO3 to solve it you do this
2(AgNO3) you multiply the two times oxygen which there is one of them and it give you (1)(2)= 2

At 600. K how many moles of gas are in a 1.00 L cylinder at atmospheric pressure?

Answers

Answer:

0.02moles

Explanation:

To answer this question, the general gas law equation is used. The General gas law is:

Pv = nRT

Where; P = standard atmospheric pressure (1 atm)

V = volume (L)

n = number of moles

R = Gas law constant

T = Temperature

For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?

Therefore; Pv = nRT

n = PV/RT

n = 1 × 1/ 0.0821 × 600

n = 1/49.26

n = 0.0203moles

Hence, there are 0.02 moles of gas.

The number of mole of the gas present in the cylinder is 0.02 mole

From the question given above, the following data were:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Number of mole (n) =?

The number of mole of the gas present in the cylinder can be obtained by using the ideal gas equation (PV = nRT) as illustrated below:

Temperature (T) = 600 K

Volume (V) = 1 L

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

PV = nRT

1 × 1 = n × 0.0821 × 600

1 = n × 49.26

Divide both side by 49.26

[tex]n = \frac{1}{49.26}\\\\[/tex]

n = 0.02 mole

Thus, 0.02 mole of the gas is present in the cylinder.

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Polllination refers to the ___________

Answers

Explanation:

from internet

the act of transferring pollen grains from the male anther of a flower to the female stigma

Answer:

transfer of pollen from anther to stigma.

Explanation:

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what is the purpose of shaking the petroleum ether-ethanol extract of the leaves with water in a separatort funnel

Answers

Answer:

Shaking the separatory funnel allows the two solvents to mix and provides the opportunity for components dissolved in one of the solvents to be transferred to the other solvent.

The purpose of shaking the petroleum ether-ethanol extract of the leaves with water in a separator funnel is that the shaking process will increase the surface area which is in contact between the two liquids and will allow the equilibrium to be established more rapidly.

This shaking process of petroleum ether-ethanol extract of the leaves with water in a separator funnel form layers of separation.

Shaking the separatory funnel allows the two solvents to mix and provides the opportunity for components dissolved in one of the solvents to be transferred to the other solvent.

Ether extraction is mainly used in the determination of Uranyl nitrate which is also known as Uranium.

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Explain what happens to the imidazole side chain of histidine in a buffer of pH 4.0 and at pH 10.2.

Answers

Histidine, an essential amino acid, has as a positively charged imidazole functional group. The imidazole makes it a common participant in enzyme catalyzed reactions. The unprotonated imidazole is nucleophilic and can serve as a general base, while the protonated form can serve as a general acid.

What's meant by chemistry

Answers

Answer: Chemistry is the properties, composition, and structure of elements and compounds, how they can change, and the energy that is released or absorbed when they change.

Explanation:

Answer:

The scientific study of the structure of substances and what happens to them in different conditions or when mixed with each other is known as Chemistry.

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What is chemical energy

Answers

Energy stored in the bonds of
chemical compounds. Chemical energy may be released during a chemical reaction, often in the form of
heat; such reactions are called exothermic. Reactions that require an input of heat to proceed may store some
of that

HELP PLZ!!! A sample contains only the compound CaCl2 and water. When it is dried, its weight decreases from 5.00g to 4.24g. What is the mass percentage of water in the original sample? Round to three significant figures.

Answers

Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

The percentage of water in the original sample is 15.2 %.

From the information provided in the question;

Weight of the wet sample = 5.00g

Weight of the dried sample = 4.24g

Loss in mass =  5.00g - 4.24g = 0.76 g

percentage of water in the original sample = Difference in mass between wet and dry sample/ mass of wet sample × 100/1

Hence, when we substitute values;

percentage of water in the original sample =  0.76 g/5.00g × 100/1

percentage of water in the original sample = 15.2 %

So, the percentage of water in the original sample is 15.2 %.

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Number of electrons for all of these even the ones with a number by them ? Will give brain-list!!!!

Answers

Explanation:

s=2

p=6

d=10

f=14

I hope this was helpful

A 2.74-g sample of a substance suspected of being pure gold is warmed to 72.1 oC and submerged into 15.2 g of water initially at 24.7 oC. The final temperature of the mixture is 26.3 oC. What is the heat capacity of the substance? Could the substance be pure gold?

(The specific heat capacity of water is 4.184 J/g oC)

J/g oC (Round to three significant digits)

Look up the specific heat capacity of gold.

Could the unknown substance be pure gold? Write yes or no in the following box:

Answers

1. The specific heat capacity of the sample of gold obtained is 0.81 J/gºC

2. The substance is not pure gold

1. How to determine the specific heat capacity of gold From the question given above, the following data were obtained:Mass of gold (M₉) = 2.74 gTemperature of gold (T₉) = 72.1 °CMass of water (Mᵥᵥ) = 15.2 g Temperature of water (Tᵥᵥ) = 24.7 °C Equilibrium temperature (Tₑ) = 26.3 °C Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC Specific heat capacity of gold (C₉) =?

The specific heat capacity of the sample of gold can be obtained as follow:

Heat loss = Heat gain

M₉C₉(M₉ –Tₑ) = MᵥᵥC(Tₑ – Tᵥᵥ)

2.74 × C₉(72.1 – 26.3) = 15.2 × 4.184 (26.3 – 24.7)

C₉ × 125.492 = 101.75488

Divide both side by 125.492

C₉ = 101.75488 / 125.492

C₉ = 0.81 J/gºC

2. How to determine if the substance is pure Specific heat capacity of gold calculated = 0.81 J/gºC Specific heat capacity of pure gold = 0.13 J/gºC

From the above we can conclude that the substance is not pure gold since the calculated and standard value of the specific heat capacity of the gold sample is not the same

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What happens to the electricity in a strand of Christmas lights if they are plugged in and not working? What happens if they are plugged in but the wires get cut

Answers

when a circuit is open the electricity fails to pass through any of the wire causing all the lights to go out. If the lights are in a straight line each light is on its own circuit to the power source.

Number of electrons for all of these even the ones with a number by them ? Will give brainlist!!!!

Answers

Explanation:

s=2

p=6

d=10

f=14

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If the molecular weight of horseradish peroxidase is about 44,000 g/mol, how many moles of enzyme are used per mole of vanillin?

Answers

What is when the molecular weight of horseradish peroxidase is about 44,000 g/mol, The number of moles of the enzyme used per mole of vanillin is

ME=289.188moles

What is the number of moles of the enzyme used per mole of vanillin?

Generally, the equation for the moles of the enzyme  is mathematically given as

[tex]ME=\frac{molecular weight}{vanilin MW}[/tex]

Therefore

ME=44000/152.15

ME=289.188moles

In conclusion, the number of moles of the enzyme is

ME=289.188moles

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What is the slope of the line on the graph?

Answers

Answer:

6

Explanation:

slope= [tex]\frac{rise}{run}[/tex]

slope=[tex]\frac{6}{1}[/tex]

slope=6

Answer:

its one half

Explanation:

i learned this last week

lead 2 nitrate and potassium iodide net ionic equation​

Answers

Answer:

Pb2+(aq) + l+(aq) ------------pbl2(s) net ionic equation

Explanation:

Pb(NO3)2(aq) + kI(aq)------------PbI2(s) + kNo3(aq)

Pb2+ (aq)No3-(aq) + k+(aq) l-(aq) ______PbI2(s) + k+(aq) + NO32+(aq)

Pb2+(aq) + I-(aq). ------------Pbl2(s)

For the chemical reaction
2 NaOH + H2SO4 — Na2SO4 + 2H2O
how many moles of sodium sulfate will be produced from 28.3 g of sodium hydroxide?

Answers

The number of mole of sodium sulphate, Na₂SO₄ that will be produced from 28.3 g of sodium hydroxide, NaOH is 0.35 mole

How to determine the mole of NaOH Mass of NaOH = 28.3 gMolar mass of NaOH = 40 g/mol Mole of NaOH =?

Mole = mass / molar mass

Mole of NaOH = 28.3 / 40

Mole of NaOH = 0.7075 mole

How to determine the mole of Na₂SO₄ produced

2NaOH + H₂SO₄ —> Na₂SO₄ + H₂O

From the balanced equation above,

2 moles of NaOH reacted to produce 1 mole of Na₂SO₄.

Therefore,

0.7075 mole of NaOH will react to produce = (0.7075 × 1) / 2 = 0.35 mole of Na₂SO₄

Thus, 0.35 mole of Na₂SO₄ was obtained from the reaction

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Determine the subunit composition of a protein from the following information:

a. Molecular mass by gel filtration: 200 kD
b. Molecular mass by SDS-PAGE: 100 kD
c. Molecular mass by SDS-PAGE with 2-mercaptoethanol: 40 kD and 60 kD

Answers

Answer:

Explanation:

The protein comprises of two 60-kD polypeptides and two 40-kD polypeptides. Each one of the 40-kD chains has a disulfide-bond which is directly bonded to a 60-kD chain.

The 100-kD units attach noncovalently to produce a protein with a molecular mass of 200 kD. The interaction among the different subunits in the protein is not affected by the Gel filtration chromatography.

Hence, the protein seems to be 200 kD in size. When SDS-PAGE takes place samples are being subjected to heat and therefore undergoing denaturation conditions. The aftermath effect of this causes disorganization in the 100 kD units.

However, the reducing agent (BME) main task is the reduction of disulfide bonds in a protein.

It implies that BME is responsible for the reduction between the R1-S-S-R2 bond between 40 kD and 60 kD to R1-SH and R2-SH, resulting in seperate proteins.

Pure gold has a density of 19.32g/cm^3. You find a gold ring with a mass of 6g and a volume of 0.31cm^3.is this ring pure gold?

Answers

Answer:

Yes, this ring is pure gold because when we divide the mass by the volume we get our density for the ring, which comes out to about 19.32.

Explanation:

What was the major organic product obtained when propanal was heated with a catalytic amount of KOH in water

Answers

Answer:

Commercially, 2-methylpentenal is synthesized by the aldol condensation of propanal in the presence of liquid base like KOH or NaOH in stoichiometric amount,,. Under optimum reaction conditions, 99% conversion of propanal is achieved with 86% selectivity of 2-methylpentenal using liquid base.

Explanation:

hope this helps

Answer:

HMM, what the person above said.

How do you know what’s inside of an atom

Answers

Answer:

microscope

Explanation:

What is the rate law for the following mechanism? Step 1: A + B = C (fast) Step 2: B + C=D (slow) Rate = k*​

Answers

Answer:

The rate law is

rate

=k[A][B]^2

What is the density at 27 °C of 28.0 milliliters of a liquid that has a mass of 4.05 grams?

Answers

Answer:

The answer is 0.14 g/mL

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\[/tex]

From the question

mass = 4.05 g

volume = 28 mL

We have

[tex]density = \frac{4.05}{28} \\ = 0.1446428571...[/tex]

We have the final answer as

0.14 g/mL

Hope this helps you

SOMEONE PLEASE HELP I WILL Mark u BRAINLIST

Answers

Answer:

answer 7.4 atm

Explanation:

i did this and got it correct

the # molecules in 52.1 grams of NH4OH

Answers

Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains [tex]\frac{ 6.023*10^{23} }{35}[/tex] molecules.

52.1 grams contains [tex]\frac{6.023*10^{23} }{35} *52.1[/tex] molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

Hope it helps!

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