Answer:
PE/SE = 5.02×10¹
Step-by-step explanation:
Sun-Earth (SE) = 93×10⁶ miles
Pluto-Earth (PE) = 4.67×10⁹ miles
so, PE/SE = (4.67×10⁹) / (93×10⁶) = (4.67×10³)/93 =
= 50.215053763440860215... =
= 5.02×10¹ / 1 or simply 5.02×10¹
in other words, Pluto is a little bit more than 50 times farther away from Earth, than Earth is from the Sun.
Which of the following represents the factorization of the trinomial below?
x2 - 14x + 49
O A. (x-7)
O B. (x-7)(x+7)
O C. (x+7)
O D. (x+2)(x+7)
ANSWER ASAP!!
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: ( {x - 7})^{2} }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] {x}^{2} - 14x + 49[/tex]
[tex] = {x}^{2} - 7x - 7x + 49[/tex]
Taking "[tex]x[/tex]" as common from first two terms and "7" from last two terms, we have
[tex] = x \: ( \: x - 7 \: ) - 7 \: ( \: x - 7 \: )[/tex]
Taking the factor [tex](x-7)[/tex] as common,
[tex] = ( \: x - 7\:) \: (\: x - 7\: )[/tex]
[tex] =( {x - 7})^{2} [/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
Is 69 square routed a even number
Question 1 of 10
The number √3 goes on forever with no repeating pattern; therefore, it is
rational.
A. True
B. False
SUBMIT
Answer:
False
Step-by-step explanation:
Rational number :
A rational number is a number which can be represent as p/q of two integers where q is not equal to zero
Example: 2/3
[tex]\sqrt{3}[/tex] = 17320508075........ and it keeps extending. Since it does not terminate or repeated after the decimal point.
Therefore [tex]\sqrt{3}[/tex] is an irritational number,
Hence given statement is FALSE
four times the difference of 15 and 6
Answer:
36
Step-by-step explanation:
9 is the difference
9 times 4 is 36
Subtraction is a mathematical operation. The statement "Four times the difference of 15 and 6" is equal to 36.
What is subtraction?Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.
The statement "Four times the difference of 15 and 6" can be expressed as,
= 4 × (15 - 6)
= 4 × (9)
= 36
Hence, The statement "Four times the difference of 15 and 6" is equal to 36.
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Simplify
x×x×x×у×у and
2×x×x×3×y×y×y
Step-by-step explanation:
1.x³y²
2. 6x²y³
hope it helps
In mixture A of candy ingredients there are 3 parts of milk-chocolate for every Z parts peanut separate mixture B. there are 4 parts of nougat for every 3 parts of caramel equat parts of A and combined in one mixing bow what is the ratio of peanut butter to nougat in the bowl
Answer:
D. 7:10
Step-by-step explanation:
The Correct Answer
The ice cream man just ended his shift for the day. Let 1/2x^2 6/11x + 8 represent the amount of chocolate ice cream bars he sold. Let 5/9x^2 + 2/3 represent the amount of vanilla ice cream bars he sold. Finally let 1/3x^2 + 4x + 4/3 represent the amount of strawberry ice cream bars he sold. Select all the statements that are true
a. The total amount of ice cream bars sold can be represented by the expression 25/18x^2+ 50/11x +10
b. The total amount of ice cream bars sold can be represented by the expression 25/18x^2 + 172/33x +28/3
c. He sold 1/6x^2 + 50/11x + 28/3 more chocolate than strawberry ice cream bars.
d. He sold 1/6x^2 - 38/11x + 20/3 more chocolate than strawberry ice cream bars.
Answer:
A and D
Step-by-step explanation:
Total ice cream bars sold = sum of chocolate sold , vanilla and strawberry ice-creams sold.
=(1/2)x2 + (6/11)x + 8 + (5/9)x2 + (2/3) +(1/3)x2 + 4x +(4/3) (Given in the question)
=(25/18)x2 + (50/11)x + 10 (Adding terms corresponding to x2,x ,constant respectively)
Difference in chocolate and strawberry bars =[ (1/2)x2 + (6/11)x + 8] - [(1/3)x2 + 4x +(4/3)]
= (1/6)x2 - (38/11)x +(20/3)
So, the correct options are A and D
DO THIS FAST PLEASE I WILL GIVE BRAINLY CROWN
Use a model to divide. 5 ÷ 1/2 10 4 2 20
5 ÷ 1/2 => 5 x 2/1 => 10/1 => 10
Answer:
10
Step-by-step explanation:
In the pic, it shows ten half squares.
Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. The population is observed once a year. Given that the Leslie matrix is equal to
Answer: hello your question lacks some information attached below is the complete question
answer :
a) attached below
b) 65 students aged 1-2 years
Step-by-step explanation:
For a Leslie matrix ; there is a relation
Pn = L^n Po where ; Pn = population vector after n years , Po = initial population vector .
a) Initial population vector
attached below
[tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
b) Number of birds aged 1-2 years are available after 10 years
i.e. P10 = L^10 Po
note : Po = Xo
∴ P10 = [tex]\left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex] [tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
we will apply MATLAB to resolve the above matrix
P10 = [tex]\left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]
∴ Number of children between 1-2 years left after 10 years = 65.24 ≈ 65
The total number of birds aged between 1-2 years which are available after 10 years is 65 and this can be determined by using the Leslie matrix relation.
Given :
Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. [tex]\rm L = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]According to the given data, the initial population vector is given by:
[tex]x_0 = \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
Now, the total number of birds aged between 1-2 years which are available after 10 years is:
[tex]\rm P_{10} = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right] \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
Now, solve the above matrices in order to determine the value of [tex]\rm P_{10}[/tex].
[tex]\rm P_{10} = \left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]
Therefore, the total number of birds aged between 1-2 years which are available after 10 years is 65.
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67 2/3% of the animals at an animal shelter are dogs. About what fraction of the animals at the shelter are dogs?
Answer:
2/3
Step-by-step explanation:
2/3 is 66 2/3%
what is 1+1+3+4+6+2+6+3+5=+8+2+5
Answer:
16
Step-by-step explanation:
baámmáy tính
please help its urgent
Answer:
Step-by-step explanation:
18x-6=120
18x=120+6
18x=126
x=126÷18
x=7
What is the volume in cubic centimeters of the figure below?
Answer:
so that you will multiply 15 * 4.
Step-by-step explanation:
15*4 = 60 now you divide 60 by 4 and the answer will be 15.
WILL GIVE BRAINLIEST Solve for x
Answer:
Step-by-step explanation:
sin x° = [tex]\frac{17}{19}[/tex]
x° = [tex]sin^{-1}[/tex] [tex]\frac{17}{19}[/tex]
x° ≈ 63°
A TRIANGLE HAS SIDE LENGTH 3, 8 AND 9. FIND THE ANGLE MEASUREMENTFOR THE ANGLE CROSS FROM THE SIDE WITH LENGTH OF 8.
Answer:tu culo
Step-by-step explanation:
Diana is going to roll a 6-sided die. What's the probability she will role a 4 or
a 5? *
The probability of rolling any one number on a 6 sided die is 1/6
The probability of rolling a 4 is 1/6
The probability of rolling a 5 is 1/6
The probability of rolling a 4 or a 5 is the probability of rolling a 4 plus the probability of rolling a 5:
1/6 + 1/6 = 2/6 = 1/3
The answer is 1/3
A crew clears brush from 1/3 acre of land in 2 days. How long will it take the same crew to clear the entire plot of 2 1/ 2 acres?
Answer:
15 days
Step-by-step explanation:
Given that :
Time taken to clear 1/3 acre = 2 days
This means that, they will be able to clear ;
1/3 ÷ 2 = 1/3 * 2 /1 = 1/6 acre in one day
1/6 acres per day :
Hence, the number of days it will take to clear 2 1/2 acres will be :
2 1/2 acres ÷ 1/6
5 / 2 ÷ 1/ 6
5/2 * 6 /1 = (5*6) / (2*1) = 30/2 = 15
Hence, it will take 15 days to clear 2 1/2 acres
Find Length of x line OR
Both figures r similar (given )
so :-[tex] \frac{5}{2.5} = \frac{3}{1.5} = \frac{2}{1} = \frac{4}{x} \\ \frac{2}{1} = \frac{4}{x} \\ \frac{ \cancel{2}}{1} = \frac{ \cancel{4}^ { \tiny{2}}}{x} \\ x = 2 \: \: ans[/tex]
The interarrival time of nuclear particles in a Monte Carlo simulation of a reaction is designed to have a uniform distribution over an interval from 0 to 0.5 milliseconds. Determine the probability that the interarrival time between two particles will be:
Answer:
Incomplete question, but you can use the formulas given to solve it.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
[tex]P(X < x) = \frac{x - a}{b - a}[/tex]
The probability of finding a value between c and d is:
[tex]P(c \leq X \leq d) = \frac{d - c}{b - a}[/tex]
The probability of finding a value above x is:
[tex]P(X > x) = \frac{b - x}{b - a}[/tex]
Uniform distribution over an interval from 0 to 0.5 milliseconds
This means that [tex]a = 0, b = 0.5[/tex]
Determine the probability that the interarrival time between two particles will be:
Considering [tex]a = 0, b = 0.5[/tex], and the question asked, you choose one of the three formulas above.
subtract
a2-b2 from a2 +b2
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
plus a square and minus a square gets cancel
b^2 + b^2
since they are like terms they can be added
2b^2
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
= b^2 + b^2
like terms can be added
+2b^2
solve for x 7_3x=2x_3
[tex]7 - 3x = 2x - 3 = [/tex]
[tex]7 - 3x = 2x - 3 \\ 7 - 3x - 2x = - 3 \\ 7 - 5x = - 3 \\ - 5x = - 3 - 7 \\ - 5 = - 10 \\ x = \frac{ - 10}{ - 5} \\ x = 2[/tex]
HOPE IT HELPS!!!I NEED BRAINLIEST ✌️ PLZPlease can you help me
Answer:
[tex]x = 24.75[/tex]
Step-by-step explanation:
Required
Find x
To find x, we have:
[tex]\angle PQR + \angle RPQ + \angle QRP = 180[/tex] -- angles in a triangle
Because [tex]\bar {PR}[/tex] is extended to S, then:
[tex]\angle QRS = \angle QRP[/tex]
So, we have:
[tex]2x + 6 + x - 7 + 5x -17 = 180[/tex]
Collect like terms
[tex]2x + x + 5x = 180 + 17 + 7-6[/tex]
[tex]8x = 198[/tex]
Divide by 8
[tex]x = 24.75[/tex]
Find the length of side x
Answer:
Step-by-step explanation:
tan(30) = x/1
sqrt(3) / 3 = x/1
x= sqrt(3) / 2
Which expression can be modeled using the number line?
Answer:
7 x 1/10 = 7/10
Step-by-step explanation:
There are 7 "bumps" on the number line, and each "bump" moves the line 1/10.
This can also be modeled as
1/10 + 1/10 + 1/10 +1/10 +1/10 +1/10 +1/10 = 7/10
Select all the correct answers.
These examples show the application of the negative exponent property. Which two examples correctly apply this property?
Answer:
First one and Third one
Step-by-step explanation:
Answer is correct from Plato
The correct expressions are:
[tex]17^{-1/4}[/tex] [tex]= \frac{1}{17^{1/4}}[/tex]
[tex]y^{1/2}[/tex] [tex]= \frac{1}{y^{-1/2}}[/tex]
In the given expression,
Since we know that the rule of exponent,
[tex]a^{-n} = \frac{1}{a^n}[/tex]
Therefore,
For the given expression,
[tex]17^{-1/4}[/tex]
Using the above property of exponent we can write it,
[tex]= \frac{1}{17^{1/4}}[/tex]
Hence this is the correct expression.
For the given expression,
[tex]y^{1/2}[/tex]
Using the above property of exponent we can write it,
[tex]= \frac{1}{y^{-1/2}}[/tex]
Hence this is the correct expression.
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I need help please anyone
Answer:
20
Step-by-step explanation:
l*w*h
4*5*1= 20
There is a bag filled with 3 blue and 4 red marbles.
A marble is taken at random from the bag, the colour is noted and then it is replaced.
Another marble is taken at random.
What is the probability of getting exactly 1 blue?
Answer:
its a three in seven chance, since there are seven total outcomes and there is only one favorable outcome. Hope that helps.
Step-by-step explanation:
find the equation of straight line passing through each of the following pairs of points
a) (2,4) and (7,2)
Answer:
The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]
Step-by-step explanation:
Equation of a line:
The equation of a line has the following format:
[tex]y = mx + b[/tex]
In which m is the slope and b is the y-intercept.
Slope:
Having two points, the slope is given by the change in y divided by the change in x. Points (2,4) and (7,2), so:
Change in y: 2 - 4 = -2
Change in x: 7 - 2 = 5
Slope: [tex]m = \frac{-2}{5} = -\frac{2}{5}[/tex]
So
[tex]y = -\frac{2}{5}x + b[/tex]
(2,4)
This means that when [tex]x = 2, y = 4[/tex]. So
[tex]y = -\frac{2}{5}x + b[/tex]
[tex]4 = -\frac{2}{5}(2) + b[/tex]
[tex]b = 4 + \frac{4}{5} = \frac{20}{5} + \frac{4}{5} = \frac{24}{5}[/tex]
The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]
ANYONE KNOW THE ANSWER TO THIS??
Answer:
x = 14 is your answer
Step-by-step explanation:
76 = 7x-22, so to figure it out, you first move -22 to the other side and get
76+22 = 7x.
add them together and you get 98 = 7x
7x would be your equation, so divide 98 by 7 and you get your solution
x = 14 is your answer
A box has three balls, one white and two red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Find the probability of the following events:
a. Let F= the event of getting the white ball twice.
b. Let G= the event of getting two balls of different colors.
c. Let H= the event of getting white on the first pick.
d. Are F and G mutually exclusive?
e. Are G and H mutually exclusive?
Answer:
See explaation
Step-by-step explanation:
Given
Represent the balls with the first letters
[tex]W =1[/tex]
[tex]R =2[/tex]
Solving (a): P(F) --- White balls twice
The event of F is:
[tex]F = \{(W,W)\}[/tex]
So:
[tex]P(F) = P(W) * P(W)[/tex]
[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(F) = \frac{1}{3} * \frac{1}{3}[/tex]
[tex]P(F) = \frac{1}{9}[/tex]
Solving (b): P(G) --- two different colors
The event of G is:
[tex]G = \{(W,R),(R,W)\}[/tex]
So:
[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]
[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}[/tex]
[tex]P(G) = \frac{2}{9} + \frac{2}{9}[/tex]
[tex]P(G) = \frac{4}{9}[/tex]
Solving (c): P(H) --- White picked first
The event of H is:
[tex]H = \{(W,R),(W,W)\}[/tex]
So:
[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]
[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}[/tex]
[tex]P(H) = \frac{2}{9} + \frac{1}{9}[/tex]
[tex]P(H) = \frac{3}{9}[/tex]
[tex]P(H) = \frac{1}{3}[/tex]
Solving (d): F and G, mutually exclusive?
We have:
[tex]F = \{(W,W)\}[/tex]
[tex]G = \{(W,R),(R,W)\}[/tex]
Check for common elements
[tex]n(F\ n\ G) = 0[/tex]
Hence, F and G are mutually exclusive
Solving (e): G and G, mutually exclusive?
We have:
[tex]G = \{(W,R),(R,W)\}[/tex]
[tex]H = \{(W,R),(W,W)\}[/tex]
Check for common elements
[tex]n(G\ n\ H) = 1[/tex]
Hence, F and G are not mutually exclusive