Answer:
a) z(s) is in the rejection region for H₀ we reject H₀.
We have enough support to conclude that the two populations are different
z(s) is in the rejection region so we reject H₀
The two population have a different proportion of non-contaminated food
Step-by-step explanation:
Conditions:
-Independent samples
-Random samples
- Size samples big enough
a) A Brand Chickens Sample:
sample size n₁ = 80
We will go through a z- test
number of contamination cases x₁ = 31
Then p₁ = 31/80 p₁ = 0.3875 and q₁ = 1 - p₁ ; q₁ = 1 - 0.3875
q₁ = 0.6125
B Brand Chickens Sample:
sample size n₂ = 80
number of contamination cases x₂ = 61
Then p₂ = 61/80 p₂ = 0.7625 and q₂ = 1 - p₂ ; q₂ = 1 - 0.7625
q₂ = 0.2375
Hypothesis Test:
Null Hypothesis H₀ p₂ = p₁
Alternative Hypothesis Hₐ p₂ ≠ p₁
The alternative hypothesis call for a two-tail test ( ≠ ) we will test if the proportion differs )
A significance level α = 0.01 then α/2 = 0.005
From z -Table α/2 = 0.005 correspond to z(c) = 2.575
To calculate z(s)
z(s) = ( p₂ - p₁ ) / √( p₁*q₁/n₁) + (p₂*q₂)/n₂)
z(s) = ( 0.7625 - 0.3875 ) / √(0,3875*0.6125)/80 + (0.7625*0.2375)/80
z(s) = ( 0.375 ) / √(0.00296) + (0.00226)
z(s) = ( 0.375 ) /0.072
z(s) = 5.21
Comparing z(s) and z(c) z(s) > z(c)
z(s) is in the rejection region for H₀ we reject H₀.
We have enough support to conclude that the two populations are different
b) folowing the same procedure now talking about non-contaminated chickens
Tyson Brand Chickens p₁ = 0,5 then q₁ = 0.5
Perdue Brand chickens p₂ = 0.25 then q₂ = 0.75
n₁ = n₂ = 80
Hypothesis Test:
Null Hypothesis H₀ p₁ = p₂
Alternative Hypothesis Hₐ p₁ ≠ p₂
Alternative hypothesis indicates a two-tail test
z(c) = 2.575
And z(s) = (0.5 - 0.25)/ √(0.5*0.5)/80 + (0.25*0.75)/80
z(s) = 0.25 / √( 0.003125 + 0.002343
z(s) = 0.25 / 0.0739
z(s) = 3.38
Comparing z(s) and z(c)
z(s) > z(c)
z(s) is in the rejection region so we reject H₀
The two population have different proportion of non-contaminated food
Is 69 square routed a even number
subtract
a2-b2 from a2 +b2
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
plus a square and minus a square gets cancel
b^2 + b^2
since they are like terms they can be added
2b^2
Answer:
2b^2
Step-by-step explanation:
according to the question equation is
(a^2 + b^2 ) - (a^2 - b^2)
a^2 + b^2 - a^2 + b^2
= b^2 + b^2
like terms can be added
+2b^2
Cos15°°- Sin 15°= 1/√2
Hope it's help you
ANYONE KNOW THE ANSWER TO THIS??
Answer:
x = 14 is your answer
Step-by-step explanation:
76 = 7x-22, so to figure it out, you first move -22 to the other side and get
76+22 = 7x.
add them together and you get 98 = 7x
7x would be your equation, so divide 98 by 7 and you get your solution
x = 14 is your answer
Tính (1,5)4; ((-2)/3)3; (√3)5.
Step-by-step explanation:
câu trả lời là trong bức ảnh trên
PLEASE HELP ASAP Determine the period.
A TRIANGLE HAS SIDE LENGTH 3, 8 AND 9. FIND THE ANGLE MEASUREMENTFOR THE ANGLE CROSS FROM THE SIDE WITH LENGTH OF 8.
Answer:tu culo
Step-by-step explanation:
What is the answer. I need it ASAP u have to choose 3 answers
four times the difference of 15 and 6
Answer:
36
Step-by-step explanation:
9 is the difference
9 times 4 is 36
Subtraction is a mathematical operation. The statement "Four times the difference of 15 and 6" is equal to 36.
What is subtraction?Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.
The statement "Four times the difference of 15 and 6" can be expressed as,
= 4 × (15 - 6)
= 4 × (9)
= 36
Hence, The statement "Four times the difference of 15 and 6" is equal to 36.
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solve for x 7_3x=2x_3
[tex]7 - 3x = 2x - 3 = [/tex]
[tex]7 - 3x = 2x - 3 \\ 7 - 3x - 2x = - 3 \\ 7 - 5x = - 3 \\ - 5x = - 3 - 7 \\ - 5 = - 10 \\ x = \frac{ - 10}{ - 5} \\ x = 2[/tex]
HOPE IT HELPS!!!I NEED BRAINLIEST ✌️ PLZQuestion 1 of 10
The number √3 goes on forever with no repeating pattern; therefore, it is
rational.
A. True
B. False
SUBMIT
Answer:
False
Step-by-step explanation:
Rational number :
A rational number is a number which can be represent as p/q of two integers where q is not equal to zero
Example: 2/3
[tex]\sqrt{3}[/tex] = 17320508075........ and it keeps extending. Since it does not terminate or repeated after the decimal point.
Therefore [tex]\sqrt{3}[/tex] is an irritational number,
Hence given statement is FALSE
In mixture A of candy ingredients there are 3 parts of milk-chocolate for every Z parts peanut separate mixture B. there are 4 parts of nougat for every 3 parts of caramel equat parts of A and combined in one mixing bow what is the ratio of peanut butter to nougat in the bowl
Answer:
D. 7:10
Step-by-step explanation:
The Correct Answer
There are 5,000 books in the town's library. Of these, 4,700 are fiction. To find the percent of the books that are fiction, first set up the percent equation. Then find the percent.
Answer:
94%
Step-by-step explanation:
4,700/5,000 x 100%
0.94 x 100% = 94%
Answer:
94%
Step-by-step explanation:
06.04 find the area of the image below a.24.6 units b.25.8 units c.26.3 units d.27.5 units
A box has three balls, one white and two red. We select one ball, put it back in the box, and select a second ball (sampling with replacement). Find the probability of the following events:
a. Let F= the event of getting the white ball twice.
b. Let G= the event of getting two balls of different colors.
c. Let H= the event of getting white on the first pick.
d. Are F and G mutually exclusive?
e. Are G and H mutually exclusive?
Answer:
See explaation
Step-by-step explanation:
Given
Represent the balls with the first letters
[tex]W =1[/tex]
[tex]R =2[/tex]
Solving (a): P(F) --- White balls twice
The event of F is:
[tex]F = \{(W,W)\}[/tex]
So:
[tex]P(F) = P(W) * P(W)[/tex]
[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(F) = \frac{1}{3} * \frac{1}{3}[/tex]
[tex]P(F) = \frac{1}{9}[/tex]
Solving (b): P(G) --- two different colors
The event of G is:
[tex]G = \{(W,R),(R,W)\}[/tex]
So:
[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]
[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}[/tex]
[tex]P(G) = \frac{2}{9} + \frac{2}{9}[/tex]
[tex]P(G) = \frac{4}{9}[/tex]
Solving (c): P(H) --- White picked first
The event of H is:
[tex]H = \{(W,R),(W,W)\}[/tex]
So:
[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]
[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]
[tex]P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}[/tex]
[tex]P(H) = \frac{2}{9} + \frac{1}{9}[/tex]
[tex]P(H) = \frac{3}{9}[/tex]
[tex]P(H) = \frac{1}{3}[/tex]
Solving (d): F and G, mutually exclusive?
We have:
[tex]F = \{(W,W)\}[/tex]
[tex]G = \{(W,R),(R,W)\}[/tex]
Check for common elements
[tex]n(F\ n\ G) = 0[/tex]
Hence, F and G are mutually exclusive
Solving (e): G and G, mutually exclusive?
We have:
[tex]G = \{(W,R),(R,W)\}[/tex]
[tex]H = \{(W,R),(W,W)\}[/tex]
Check for common elements
[tex]n(G\ n\ H) = 1[/tex]
Hence, F and G are not mutually exclusive
Evaluate the expression for the given value of the variable.
3x + 4 when x = 2
5y - 3.6 when y = 4
7z4+ 1.05 when z = 1.2
20 - b3.2when b = 5.2
Answer:
I NOT 100% SURE BUT I THINK ITS .B)
Step-by-step explanation:
Which of the following represents the factorization of the trinomial below?
x2 - 14x + 49
O A. (x-7)
O B. (x-7)(x+7)
O C. (x+7)
O D. (x+2)(x+7)
ANSWER ASAP!!
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: ( {x - 7})^{2} }}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] {x}^{2} - 14x + 49[/tex]
[tex] = {x}^{2} - 7x - 7x + 49[/tex]
Taking "[tex]x[/tex]" as common from first two terms and "7" from last two terms, we have
[tex] = x \: ( \: x - 7 \: ) - 7 \: ( \: x - 7 \: )[/tex]
Taking the factor [tex](x-7)[/tex] as common,
[tex] = ( \: x - 7\:) \: (\: x - 7\: )[/tex]
[tex] =( {x - 7})^{2} [/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
Please can you help me
Answer:
[tex]x = 24.75[/tex]
Step-by-step explanation:
Required
Find x
To find x, we have:
[tex]\angle PQR + \angle RPQ + \angle QRP = 180[/tex] -- angles in a triangle
Because [tex]\bar {PR}[/tex] is extended to S, then:
[tex]\angle QRS = \angle QRP[/tex]
So, we have:
[tex]2x + 6 + x - 7 + 5x -17 = 180[/tex]
Collect like terms
[tex]2x + x + 5x = 180 + 17 + 7-6[/tex]
[tex]8x = 198[/tex]
Divide by 8
[tex]x = 24.75[/tex]
Select all the correct answers.
These examples show the application of the negative exponent property. Which two examples correctly apply this property?
Answer:
First one and Third one
Step-by-step explanation:
Answer is correct from Plato
The correct expressions are:
[tex]17^{-1/4}[/tex] [tex]= \frac{1}{17^{1/4}}[/tex]
[tex]y^{1/2}[/tex] [tex]= \frac{1}{y^{-1/2}}[/tex]
In the given expression,
Since we know that the rule of exponent,
[tex]a^{-n} = \frac{1}{a^n}[/tex]
Therefore,
For the given expression,
[tex]17^{-1/4}[/tex]
Using the above property of exponent we can write it,
[tex]= \frac{1}{17^{1/4}}[/tex]
Hence this is the correct expression.
For the given expression,
[tex]y^{1/2}[/tex]
Using the above property of exponent we can write it,
[tex]= \frac{1}{y^{-1/2}}[/tex]
Hence this is the correct expression.
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Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. The population is observed once a year. Given that the Leslie matrix is equal to
Answer: hello your question lacks some information attached below is the complete question
answer :
a) attached below
b) 65 students aged 1-2 years
Step-by-step explanation:
For a Leslie matrix ; there is a relation
Pn = L^n Po where ; Pn = population vector after n years , Po = initial population vector .
a) Initial population vector
attached below
[tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
b) Number of birds aged 1-2 years are available after 10 years
i.e. P10 = L^10 Po
note : Po = Xo
∴ P10 = [tex]\left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex] [tex]\left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
we will apply MATLAB to resolve the above matrix
P10 = [tex]\left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]
∴ Number of children between 1-2 years left after 10 years = 65.24 ≈ 65
The total number of birds aged between 1-2 years which are available after 10 years is 65 and this can be determined by using the Leslie matrix relation.
Given :
Consider a species of bird that can be split into three age groupings: those aged 0-1 years, those aged 1-2 years, and those aged 2-3 years. [tex]\rm L = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right][/tex]According to the given data, the initial population vector is given by:
[tex]x_0 = \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
Now, the total number of birds aged between 1-2 years which are available after 10 years is:
[tex]\rm P_{10} = \left[\begin{array}{ccc}0&2&1\\0.2&0&0\\0&0.4&0\end{array}\right] \left[\begin{array}{ccc}1100\\2400\\3200\end{array}\right][/tex]
Now, solve the above matrices in order to determine the value of [tex]\rm P_{10}[/tex].
[tex]\rm P_{10} = \left[\begin{array}{ccc}217.91\\65.24\\31.911\end{array}\right][/tex]
Therefore, the total number of birds aged between 1-2 years which are available after 10 years is 65.
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please help its urgent
Answer:
Step-by-step explanation:
18x-6=120
18x=120+6
18x=126
x=126÷18
x=7
Which operation should you perform first in the expression 7x2^3?
Answer:
Below,
Step-by-step explanation:
The exponent part is done first
7 x 2^3
= 7 * 8
= 56.
You use the acronym PEMDAS:-
( E ( exponential) comes before M (multiply))
Find the length of side x
Answer:
Step-by-step explanation:
tan(30) = x/1
sqrt(3) / 3 = x/1
x= sqrt(3) / 2
Which expression can be modeled using the number line?
Answer:
7 x 1/10 = 7/10
Step-by-step explanation:
There are 7 "bumps" on the number line, and each "bump" moves the line 1/10.
This can also be modeled as
1/10 + 1/10 + 1/10 +1/10 +1/10 +1/10 +1/10 = 7/10
To solve the equation, Lorie applies the distributive property, combines like terms, then applies the addition and subtraction properties of equality to isolate the variable term on one side of the equation and the constant term on the other side. What are the possible coefficients of x after Lorie has completed these steps?
10 (one-half x + 2) minus 5 = 3 (x minus 6) + 1
–32 and 2
–2 and 32
–2 and 2
–32 and 32
Answer:
-2 and -2
Step-by-step explanation:
find the equation of straight line passing through each of the following pairs of points
a) (2,4) and (7,2)
Answer:
The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]
Step-by-step explanation:
Equation of a line:
The equation of a line has the following format:
[tex]y = mx + b[/tex]
In which m is the slope and b is the y-intercept.
Slope:
Having two points, the slope is given by the change in y divided by the change in x. Points (2,4) and (7,2), so:
Change in y: 2 - 4 = -2
Change in x: 7 - 2 = 5
Slope: [tex]m = \frac{-2}{5} = -\frac{2}{5}[/tex]
So
[tex]y = -\frac{2}{5}x + b[/tex]
(2,4)
This means that when [tex]x = 2, y = 4[/tex]. So
[tex]y = -\frac{2}{5}x + b[/tex]
[tex]4 = -\frac{2}{5}(2) + b[/tex]
[tex]b = 4 + \frac{4}{5} = \frac{20}{5} + \frac{4}{5} = \frac{24}{5}[/tex]
The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]
Which is equivalent to f/125)*? O 125+ 0 1254 125" C. 125/11
Answer:
I think choose (1)
[tex]125 ^{ \frac{1x}{3} } [/tex]
help please show work
67 2/3% of the animals at an animal shelter are dogs. About what fraction of the animals at the shelter are dogs?
Answer:
2/3
Step-by-step explanation:
2/3 is 66 2/3%
WILL GIVE BRAINLIEST Solve for x
Answer:
Step-by-step explanation:
sin x° = [tex]\frac{17}{19}[/tex]
x° = [tex]sin^{-1}[/tex] [tex]\frac{17}{19}[/tex]
x° ≈ 63°