Select the correct answer.

For which system of inequalities is (3,-7) a solution?

A.
x + y < -4
3x + 2y < -5
B.
x + y ≤ -4
3x + 2y < -5
C.
x + y < -4
3x + 2y ≤ -5
D.
x + y ≤ -4
3x + 2y ≤ -5

Answer:  [tex]2\sqrt{2}+\sqrt{3}\\\\[/tex]

a = 2 and b = 1

=======================================================

Explanation:

Set the expression equal to the given form we want. Then square both sides so we get rid of the outer-most square root

[tex]\sqrt{11+4\sqrt{6}} = a\sqrt{2}+b\sqrt{3}\\\\\left(\sqrt{11+4\sqrt{6}}\right)^2 = \left(a\sqrt{2}+b\sqrt{3}\right)^2\\\\11+4\sqrt{6} = \left(a\sqrt{2}\right)^2+2*a\sqrt{2}*b\sqrt{3}+\left(b\sqrt{3}\right)^2\\\\11+4\sqrt{6} = 2a^2+2ab\sqrt{2*3}+3b^2\\\\11+4\sqrt{6} = 2a^2+3b^2+2ab\sqrt{6}\\\\[/tex]

In the third line, I used the rule that (x+y)^2 = x^2+2xy+y^2

-------------------

At this point, we equate the non-radical and radical terms to get this system of equations

[tex]\begin{cases}11 = 2a^2+3b^2\\ 4\sqrt{6} = 2ab\sqrt{6}\end{cases}[/tex]

The second equation turns into 4 = 2ab when we divide both sides by sqrt(6)

Then 4 = 2ab turns into ab = 2 after dividing both sides by 2.

We're told that a,b are rational numbers. Let's assume that they are integers (which is a subset of the rational numbers).

If so, then we have these four possibilities

If a,b are negative, then you'll find that [tex]a\sqrt{2}+b\sqrt{3}[/tex] overall is negative. But this contradicts that [tex]\sqrt{11+4\sqrt{6}}[/tex] is positive. So a,b must be positive.

Let's assume that a = 1 and b = 2. If so, then,

2a^2+3b^2 = 2(1)^2+3(2)^2 = 14

but we want that result to be 11 instead.

Let's try a = 2 and b = 1

2a^2+3b^2 = 2(2)^2+3(1)^2 = 11

which works out perfectly.

Therefore,

[tex]\sqrt{11+4\sqrt{6}} = 2\sqrt{2}+\sqrt{3}\\\\[/tex]

---------------------------------

Checking the answer:

Use a calculator to find that

[tex]\sqrt{11+4\sqrt{6}} \approx 4.5604779\\\\2\sqrt{2}+\sqrt{3} \approx 4.5604779\\\\[/tex]

both have the same decimal approximation, so this is a fairly informal way to confirm the answer.

Another thing you can do is to take advantage of the idea that if x = y, then x-y = 0

So if you want to see if two things are equal, you subtract them. You should get exactly 0 or something very small (pretty much equal to 0).

Answer:

Perimeter

Step-by-step explanation:

Required

What does 36m represent?

From the question, we understand that the 36m is the measurement of the wall.

This, in other words, means the perimeter of the wall.

Hence, Supriya measured the perimeter

Answer:

I'm not sure what to do not doing this in skl

Answer:

£13,268.35 (sorry if this is incorrect :P)

Step-by-step explanation:

16.5% = 0.165

15890.23 x 0.165 ≈ 2621.88

15890.23 - 2621.88 = 13,268.35

Answer:

[tex]8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6 - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5 + n^6[/tex]

Step-by-step explanation:

Given

[tex]8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3[/tex]

Required

Correctly combine the like terms

We have:

[tex]8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3[/tex]

Collect like terms (in decreasing degrees of m)

[tex]- 2m^6 - 4m^6 - mn^5- m^3n^3 - 4m^3n^3+ 5m^2n^4 + 9m^2n^4 + 8mn^5 + n^6[/tex]

[tex]-6m^6 - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5 + n^6[/tex]

So:

[tex]8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6 - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5 + n^6[/tex]

Answer:

20

Step-by-step explanation:

alternate angles of two parallel lines WX and ZY

Answer:

20!

Step-by-step explanation:

Answer:

(- x + 9)(- x - 9)

(x y + x)(x y + x)

(2 x - 3)(- 3 + 2 x)

(16 - x squared)(x squared - 16)

(4 y squared + 25)(25 + 4 y squared)

Step-by-step explanation:

Answer:

Depending on how much he had before he bought the game system.

Answer:

2 1/3

Step-by-step explanation:

Answer:

option A

Step-by-step explanation:

since the two sides of the triangle are equal the given triangle is an isosceles triangle.

Base angles of an isosceles triangle are equal.

angle P = angle R

32 degree = angle R

The measure of <QRP = 32 degree.

An isosceles triangle is one with two sides that are the same size and a third side that is a different size.

According to the isosceles triangle theorem, if two sides of a triangle are congruent, the angles across from those sides are likewise congruent.

We have,

A triangle whose two sides are 8 unit each and an angle 32.

As, we know a triangle whose two sides are equal is said to be isosceles triangle.

So, the given triangle is isosceles.

Now, angle opposite to equal sides are also equal.

so, <QPR = <QRP = 32 degree

Learn more about isosceles triangle here:

https://brainly.com/question/2456591

#SPJ7

Answer:

5

Step-by-step explanation:

Answer:

y:3 4

Step-by-step explanation:

[tex]\sqrt{34} x \sqrt{y} :34\\\sqrt{34y}:34\\34y:1156\\[/tex]

[tex]y:34\\\sqrt{34} \sqrt{34}:34\\ 34:34\\y:34[/tex]

Answer: grid #1 and grid #3

Step-by-step explanation:

grid 3 is 100% out of 100% making one whole and grid 1 has 40 out of 100 squares filled. 100 + 40 = 140/140%

Answer:

67.38 degrees

Step-by-step explanation:

Here, we want to find the value of the angle at X

We are going to use the appropriate trigonometric ratio here

From the question, the vertex X faces the side 12 and that makes the side the opposite

The side 13 faces the right angle and that makes it the hypotenuse

The trigonometric ratio that connects both is the sine

so we have that;

sine X = 12/13

X = arc sin (12/13)

X = 67.38

answer:

the answer is 40 because any expression divides itself is equals to 1

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\frac{1}{x^3}[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the Answer...}}\\\\x^5\div x^8\\---------\\\rightarrow \text{Rewrite as:} \frac{x^5}{x^8}\\\\\rightarrow \text{Recall the exponent rule: } \frac{x^a}{x^b}=x^{a-b}\\\\\rightarrow \frac{x^5}{x^8} = x^{-3}\\\\\rightarrow \text{Recall the exponent rule: }x^{-b}=\frac{1}{x^b}\\\\\rightarrow x^{-3}\\\\\rightarrow \boxed{\frac{1}{x^3}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

25+40x=195

Step-by-step explanation:

If he already has $25, you need to add that to 40x (40 times the amount of weeks it takes to get to 195, added with 25).

Answer:

26.6 but that is not one of yor answers...

I think you have a typo in "A"

I think that your have a typo in the answers

x/sin(40) = 32/sin(90)

x = 26.6

Step-by-step explanation:

Answer

It is (7,9) (5,9) and (6,8)

Step-by-step explanation:

Step-by-step explanation:

Hola supiste algo bro o no

Answer:

£9000

Step-by-step explanation:

= £10 000× 5 ×2

100

= 1000

= £10 000-1000

= £9000

Answer:

(-5/2, 4)

Second quadrant

Step-by-step explanation:

Mathematically, we can calculate the midpoint using the formula;

(x,y) = (x1 + x2)/2, (y1 + y2/2

We have;

(x,y) = (-4-1)/2, (3+5)/2

(x,y) = (-5/2, 4)

to get the quadrant, as we can see, this is negative x and positive y and that makes it the 2nd quadrant

Answer:

[tex]5x^{2}(x+7)(x-3)[/tex]

Step-by-step explanation:

5x4+20x3-105x2

5x2( x^2 +4x -21)

[tex]5x^{2}(x+7)(x-3)[/tex]

Answer:

y = 1/3 x +4

Step-by-step explanation:

m = 1/3

3 = 1/3(-3) + b

3 = -1 +b

b=4

Answer:

C i think

Step-by-step explanation:

because c has y=x-2.

Answer: it would be D

Step-by-step explanation: because the x intercept is zero and the equation solved is 6  

D

its just a basic logarithmic law.

Answer:

The answer is "Option b".

Step-by-step explanation:

[tex]m\angle A = 55^{\circ}\\\\m\angle B = 44^{\circ}\\\\m\angle C = 180^{\circ}-(55^{\circ}+44^{\circ})\\\\[/tex]

         [tex]= 180^{\circ}-99^{\circ}\\\\=81^{\circ}\\\\[/tex]

 [tex]\frac{a}{\sin 55^{\circ}}= \frac{68}{\sin 44^{\circ}}\\\\a = \frac{68 \ \sin 55^{\circ}}{\sin 44^{\circ}}\\\\a= 80.2^{\circ}\\\\\frac{c}{\sin 81^{\circ}}= \frac{68}{\sin 44^{\circ}}\\\\c = \frac{68 \ \sin 81^{\circ}}{\sin 44^{\circ}}\\\\c= 96.7^{\circ}\\\\[/tex]

[tex]\cfrac{\frac{a}{b}}{\frac{c}{ d}}\implies \cfrac{a}{b}\cdot \cfrac{ d}{c} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{~~\frac{3x^2-3}{x^2+3x}~~}{\frac{x+1}{x(x+3)}}\implies \cfrac{3x^2-3}{x^2+3x}\cdot \cfrac{x(x+3)}{x+1}\implies \stackrel{\textit{common factoring}}{\cfrac{3(x^2-1)}{~~\begin{matrix}x (x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} x (x+3) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{x+1}[/tex]

[tex]\textit{keeping in mind that}\qquad x^2-1\implies x^2-1^2\implies (x-1)(x+1) \\\\\\ \cfrac{\stackrel{~~\textit{difference of squares}}{3(x^2-1^2)~\hfill }}{x+1}\implies \cfrac{3(x-1)~~\begin{matrix} (x+1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{\begin{matrix} (x+1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies 3(x-1)[/tex]