The equation of the ellipse is (x2/100) + (y2/50) = 1. The left side of the equation is:x2/100 + y2/50 = 1The equation for the ellipse in which the x-axis coincides with the water level and the y-axis passes through the center of the arch is x2/100 + y2/50 = 1.
The semi-elliptical arch bridge is supported by an arch that is in the shape of the upper half of an ellipse. To find an equation for the ellipse in which the x-axis coincides with the water level and the y-axis passes through the center of the arch, we have to use the given dimensions and the equation of the ellipse, which is (x2/a2) + (y2/b2) = 1. Here a is the length of the semi-major axis and b is the length of the semi-minor axis.Given,
The width of the river is 20 meters.The center of the arch is 8 meters above the center of the river. The semi-elliptical arch is symmetric. Hence, the center of the arch is (0, 8).Also, the half-span of the arch is 10 meters, and hence the value of a is 10 meters.
To find b, we have to find the height of the arch at a distance of 10 meters from the center (as the x-axis coincides with the water level).Using the equation of the ellipse, we get:(102/102) + (y2/b2) = 1b2 = (100 - y2)(x2/a2) + (y2/b2) = 1(20/2)2 = x2 + (y2/b2)(10)2 = y2 + (y2/b2)(100/b2) = y2 + y2b2b2 + y2 = 100b2 = 100/2b2 = 50
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I need help pls help me find the area:
Answer:
Step-by-step explanation:
348.55
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighed. The sample mean is 244 pounds. The sample standard deviation is 11 pounds Construct a 95% confidence interval for the population mean weight of newborn elephants. State the confidence interval (Round your answers to two decimal places.) Sketch the graph. (Round your answers to two decimal places.) CL - 0.95 X Calculate the error bound (Round your answer to two decimal places)
The error bound for the 95% confidence interval is (1.96 x Standard Deviation/√n), which in this case is (1.96 x 11/√50) = 2.56. This means that the true mean weight of newborn elephant calves lies within +/-2.56 pounds of the interval range.
The 95% confidence interval for the population mean weight of newborn elephants can be calculated using the sample mean of 244 pounds and the sample standard deviation of 11 pounds. The confidence interval is calculated using the following formula:
Confidence Interval = (Mean - (1.96 x Standard Deviation/√n)), (Mean + (1.96 x Standard Deviation/√n))
Where n is the sample size.
Therefore, the 95% confidence interval for the population mean weight of newborn elephants is (231.14, 256.86).
This can also be represented in a graph. The graph would have the x-axis representing the confidence interval, with a range from 231.14 to 256.86, and the y-axis representing the probability, which would be 0.95.
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Jamal sold hotdogs at a recent basketball game. Each hotdog sold for $3.50. In total, Jam
sold $98 worth of hot dogs. Let n be the number of hotdogs that Jamal sold.
Set up an equation that models the information given in this problem.
Answer:The concession stand sold
46
hot dogs and
32
hamburgers.
Explanation:
The first thing to do in algebraic problems is assign variables to things we don't know, so let's start there:
We don't know how many hot dogs the concession stand sold, so we will call that number
d
.
We don't know how many hamburgers the concession stand sold, so we will call that number
h
.
Now we translate the statements into algebraic equations:
The number of hot dogs and hamburgers that were sold is
78
, so
d
+
h
=
78
.
If each hot dog is sold for
1.25
, then the total revenue from hot dogs is given by
1.25
d
. In the same way, the total revenue from hamburgers is
1.50
h
. The total revenue from both hot dogs and hamburgers should be the sum of these, and since we are told the total revenue is
105.50
, we can say
1.25
d
+
1.5
h
=
105.5
.
We now have a system of two linear equations:
d
+
h
=
78
1.25
d
+
1.5
h
=
105.5
We can solve it using several methods, though I'm going to go with substitution. Use the first equation to solve for
d
:
d
+
h
=
78
→
d
=
78
−
h
Now plug this in for
d
in the second equation:
1.25
d
+
1.5
h
=
105.5
→
1.25
(
78
−
h
)
+
1.5
h
=
105.5
Solving for
h
, we have:
97.5
−
1.25
h
+
1.5
h
=
105.5
0.25
h
=
8
h
=
8
.25
→
h
=
32
Since
h
+
d
=
78
,
32
+
d
=
78
→
d
=
46
Step-by-step explanation:
Martin makes b bags of snack mix. Each bag contains 1.5 lb of nuts and 0.75 lb of dried fruit. What does the expression 1.5b + 0.75b represent?
Pls explain why
1.5b + 0.75b represents the total amount of nuts and dried fruit used for b bags of snack mix.
b is the number of bags of snack mix, so the expression 1.5b means 1.5 multiplied by b, which is the total amount of nuts used for b bags of snack mix. Similarly, 0.75b is 0.75 multiplied by b, which is the total amount of dried fruit used for b bags of snack mix.
Adding these together gives us 1.5b + 0.75b, which is the total amount of nuts and dried fruit used for b bags of snack mix.
Find a vector equation and parametric equations in tfor the line through the point and parallel to the given line.(P0 corresponds to t = 0.)
P0 = (0,12, -10)
x = -4 + 2t, y = 7 - 4t, z = 5 + 8t
How do you find x,y,and z?
The vector equation and the parametric equations in t for the line through the point and parallel to the given line are:
Vector Equation= [-4 7 5] + t[2 -4 8]Parametric Equations:x= 2t - 4
y= -4t + 7
z= 8t + 5
How to find the value of x, y, and zTo find x, y, and z in the given scenario, the following steps can be followed:
1: Vector Equation of Line
To find the vector equation, use the given line and its coefficients:
x = -4 + 2t
y = 7 - 4t
z = 5 + 8t
Take the coefficients of x, y, and z, and place them in a 3 by 1 matrix:
Column Matrix= [-4 7 5]
Add the parameter t and place it in a column matrix to get the vector equation:
Vector Equation= [-4 7 5] + t[2 -4 8]
2: Parametric Equation.
To find the parametric equations, write the components of the vector equation in terms of the parameters:
x= -4 + 2t
y= 7 - 4t
z= 5 + 8t
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an inner city revitalization zone is a rectangle that is twice as long as it is wide. the width of the region is growing at a rate of 32 m per year at a time when the region is 220 m wide. how fast is the area changing at that point in time?
The area is changing at a rate of 28,160 m²/year at that point in time.
The area of the rectangular region is given by:
A = lw
Where l is the length of the rectangular region and w is the width of the rectangular region.
The width of the rectangular region is given to be 220 m. Therefore, we have the width w = 220 m. The length l of the rectangular region can be found knowing that it is twice as long as it is wide. Therefore, the length of the rectangular region is given by:
l = 2w
l = 2 x 220
l = 440
Therefore, the length l of the rectangular region is 440 m.
At the given point in time, the width of the rectangular region is growing at a rate of 32 m per year. Therefore, we have the rate of change of the width dw/dt to be 32 m per year. We need to find how fast the area of the rectangular region is changing at that point in time. Therefore, we need to find the rate of change of the area of the rectangular region dA/dt.
A = lw
dA/dt = w dl/dt + l dw/dt
dA/dt = 220 d/dt(2w) + 440 dw/dt
dA/dt = 220 x 2 dw/dt + 440 dw/dt
dA/dt = 880 dw/dt
Substitute the value of dw/dt to get:
dA/dt = 880 x 32
dA/dt = 28,160 m²/year
Therefore, the area of the rectangular region has a rate of change of 28,160 m² per year at that point in time.
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.......???????????????
Answer:
Step-by-step explanation:
[tex]x^2-5=-7x-1[/tex]
[tex]x^2+7x-5=-1[/tex] (subtracted 7x from both sides of the equation)
[tex]x^2+7x-4=0[/tex] (+1 both sides)
Use quadratic formula to solve for x:
[tex]x=\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}[/tex] where [tex]a=1,b=7,c=-4[/tex]
[tex]=\frac{-7 \pm \sqrt{7^2 - 4\times1\times(-4)} }{2\times 1}[/tex]
[tex]=\frac{-7 \pm \sqrt{49 +16} }{2}[/tex]
[tex]=\frac{-7 \pm \sqrt{65} }{2}[/tex]
[tex]x=\frac{-7 +\sqrt{65} }{2},\frac{-7 - \sqrt{65} }{2}[/tex]
[tex]x=0.53,-7.53[/tex]
Use Lagrange multipliers to find the points on the given cone that are closest to the following point.
z^2 = x^2 + y^2; (14, 8, 0)
x,y,z=(smaller z-value)
x,y,z=(larger z-value)
By using the Lagrange multipliers, the two points on the cone that is closest to (14, 8, 0) are:
(7, 4, √65) and (7, 4, -√65)
We want to minimize the distance between the point (14, 8, 0) and the points on the cone z^2 = x^2 + y^2. The distance squared between two points (x_1, y_1, z_1) and (x_2, y_2, z_2) is given by:
d^2 = (x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2
In our case, we want to minimize the distance squared between (14, 8, 0) and a point (x, y, z) on the cone z^2 = x^2 + y^2:
d^2 = (x - 14)^2 + (y - 8)^2 + z^2
Subject to the constraint z^2 = x^2 + y^2. We can use Lagrange multipliers to solve this constrained optimization problem. Let L be the Lagrangian:
L = (x - 14)^2 + (y - 8)^2 + z^2 - λ(z^2 - x^2 - y^2)
Taking the partial derivatives of L with respect to x, y, z, and λ, and setting them to zero, we get:
2(x - 14) - 2λx = 0.....(1)
2(y - 8) - 2λy = 0.....(2)
2z - 2λz = 0.....(3)
z^2 - x^2 - y^2 = 0.....(4)
Simplifying the third equation, we get z(1 - λ) = 0. Since we want to find points where z is not zero, we must have λ = 1. Then, from the first two equations, we get x = 7 and y = 4. Substituting these values into the fourth equation, we get:
z^2 = x^2 + y^2 = 65
So the two points on the cone that is closest to (14, 8, 0) by using Lagrange multipliers are:
(7, 4, √65) and (7, 4, -√65)
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Which value will be assigned to z in line 12 under static sexping? (b) Which value will be assigned to 2 in line 12 under dynamic scoping? I might be instructive to draw the runtime stack for different times of the execution. Inut it is not strictly required. Draw the runtime stack after each line executes! Exercise 3. Parameter Passing Consider the following block. Ansune static scaping { int y: int z; - 7 { int (int a) 4 yari: return (yta) 1 int g(int x) { y = f(x+1)+1; 2:- 1( x3): return (z+1) } 2 :- g(y2): : 12 13 14 is) What are the values of y and 2 at the end of the following block under the assumption that both parameters a und x repassed: la) Call-by-Name (h) Calltyy Need It might be instructive to draw the runtime stack for differcut times of the execution, but it is not strictly required Draw the runtime stack after each line executes
The runtime stack for dynamic scoping at the end of the block would be:
Under static scoping, the value of z in line 12 will be 7. Under dynamic scoping, the value of z in line 12 will be the value of y in line 2, which is equal to f(x+1)+1. The values of y and z in the end of the block will differ depending on the parameter passing method used.
For call-by-name, the value of y at the end of the block will be f(x+1)+1 and the value of z will be f(x+1)+1+1. For call-by-need, the value of y will be f(x+1)+1 and the value of z will be f(x+1)+1+1.
It might be instructive to draw the runtime stack for different times of the execution, but it is not strictly required. The runtime stack for static scoping at the end of the block would be:
The runtime stack for dynamic scoping at the end of the block would be:
a hummingbird lives in a nest that is 5 meters high in a tree. the hummingbird flies 9 meters to get from its nest to a flower on the ground. how far is the flower from the base of the tree? if necessary, round to the nearest tenth.
The flower is about 10.3 meters away from the base of the tree, rounded to the nearest tenth of a meter. The hummingbird has to fly this distance to get to the flower.
To figure out how far the flower is from the base of the tree, we need to use the Pythagorean theorem. It can be applied when there is a right triangle, which is a triangle with one angle of 90 degrees.Here, the hummingbird's nest is at the top of the tree, and the flower is on the ground. The vertical distance from the nest to the ground is 5 meters. The horizontal distance from the tree trunk to the flower is the distance we want to find.
We'll need to calculate the length of the hypotenuse (the slanted line) of the right triangle in order to determine the distance from the tree to the flower. The hypotenuse's length is found by squaring each of the other sides, adding the results together, and then taking the square root:
hypotenuse=√5^2+9^2
=√25+81 = √106
≈10.3 m
So the flower is about 10.3 meters away from the base of the tree, rounded to the nearest tenth of a meter. The hummingbird has to fly this distance to get to the flower.
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5 2 fiths minus 1 2 fiths
Answer:
Step-by-step explanation:
2/5-1 2/5
PLS ANSWER THIS ASAP
In two similar triangles, the ratio of the lengths of a pair of corresponding sides is 7:8. If the perimeter of the larger triangle is 32, find the perimeter of the smaller triangle.
The perimeter of the smaller triangle would be = 28.1
How to calculate the perimeter of the smaller triangle?A triangle can be defined as a three sided polygon that has a total internal angle of 180°.
To calculate the perimeter of the triangle is to find out the scale factor that exists between the two triangles.
The formula for scale factor = original object/new object
Scale factor= 8/7 = 1.14
The perimeter of the smaller triangle = 32/1.14
= 28.1.
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a child who weighs 18kg is to receive motrin (ibuprofen) 8mg/kg by mouth every 4 hours as needed for pain. the label reads 100mg/5mls. how many milliliters will you administer?
According to the information on what the child should receive ibuprofen, it should be administered to the child 1.6 mL.
What is Ibuprofen?Ibuprofen is a nonsteroidal anti-inflammatory drug (NSAID). It works by inhibiting the body's synthesis of prostaglandins. This aids in the reduction of swelling, pain, and fever. It can also be used to relieve mild to moderate pain caused by menstruation, arthritis, or toothache.
To calculate the amount of milliliters to be administered, we need to use the following formula:
Amount of Motrin = Weight of child (kg) × Dose of Motrin (mg/kg) ÷ Concentration of Motrin (mg/ml)
Where
Weight of child = 18kgDose of Motrin = 8mg/kgConcentration of Motrin = 100mg/5mlsSubstitute the given values in the above formula.
Amount of Motrin = 18kg × 8mg/kg ÷ 100mg/5mls= 144mg ÷ 20mg/mls= 7.2mls
Therefore, the amount of Motrin to be administered is 7.2mls.
However, the dosage amount administered is not in 5ml increments. Therefore, we need to round it to one decimal place. Thus, we'll have: Amount of Motrin = 7.2 ml (rounded to one decimal place) = 1.6 ml Answer: 1.6 ml
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Write a equation for a parabola with a focus at (-2,5) and a directrix at x=3 format: x=
Answer:Write a equation for a parabola with a focus at (-2,5) and a directrix at x=3 format: x=
Step-by-step explanation:
Mr. Ferrell has feet of a piece of 5/6 cardboard. He wants to cut pieces that are foot long. 1/8 How many pieces can he make?
Mr. Ferrell can cut 6 and 2/3 pieces that are one-eighth foot long from a 5/6 foot long piece of cardboard.
What is common factor?A number is said to be a common factor if it can divide two or more integers without producing a residue. Common factors are used in fraction operations to simplify fractions and carry out operations like addition, subtraction, multiplication, and division.
Finding a common denominator is necessary, for instance, when adding or subtracting fractions. A multiple of all the fractions' denominators is referred to as a common denominator. We can determine the shared characteristics of the denominators and utilise the lowest common multiple (LCM) as the common denominator to obtain a common denominator.
Given that, one-eighth foot long pieces can be cut from a 5/6 foot long piece of cardboard.
First, we need to convert 5/6 feet into eighths of a foot:
5/6 feet = (5/6) * 8 eighths = 40/48 eighths
Next, we need to divide 40/48 by 1/8 to find the number of one-eighth foot long pieces that can be cut:
(40/48) ÷ (1/8) = (40/48) * (8/1) = 320/48 = 6 2/3 pieces
Hence, Mr. Ferrell can cut 6 and 2/3 pieces that are one-eighth foot long from a 5/6 foot long piece of cardboard.
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Bernard's rectangular bedroom is 12 feet by 16 feet. What is the diagonal distance from one corner to the opposite corner?
Answer: 20 feet
Step-by-step explanation: To find the diagonal distance from one corner to the opposite corner of Bernard's rectangular bedroom, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse (diagonal) of a right triangle is equal to the sum of the squares of the lengths of the other two sides.
In this case, the two other sides are the length and the width of the room, so we have:
diagonal^2 = 12^2 + 16^2
diagonal^2 = 144 + 256
diagonal^2 = 400
Taking the square root of both sides, we get:
diagonal = √400
diagonal = 20 feet
Therefore, the diagonal distance from one corner to the opposite corner of Bernard's rectangular bedroom is 20 feet.
what is the vertex of h=-16t^2+29t+6 and its domain and range, and x and y axis?
Solve each of the following systems by the Method of Elimination. These two should be relatively easy. Make sure to understand why. (a) x-y 7 (b) 2x+5y = 3 x+ y=5 -2x-y= 5
A) The solution of the system x-y = 7, x+y = 5 is (6, -1)
B) The solution of the system 2x+5y = 3, -2x-y= 5 is (-16/3, 13/3)
A) To solve by the elimination method , we add the left-hand sides and right-hand sides of the two equations separately, as follows,
(x - y) + (x + y) = 7 + 5
2x = 12
x = 6
(x + y) - (x - y) = 5 - 7
2y = -2
y = -1
Therefore, the solution to the system is (x, y) = (6, -1).
B) To solve by the method of elimination, we can multiply the first equation by 2 to eliminate the x term, as follows,
2x + 5y = 3
-4x - 2y = 10
Adding these two equations, we get,
3y = 13
y = 13/3
Substituting y = 13/3 into the first equation, we get,
2x + 5(13/3) = 3
2x = -32/3
x = -16/3
Therefore, the solution to the system is (x, y) = (-16/3, 13/3)
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The given question is incomplete, the complete question is:
Solve each of the following systems by the Method of Elimination A) x-y = 7, x+y = 5 B) 2x+5y = 3, -2x-y= 5
In order to make the same amount of money, they would have to each sell ______ bicycles. They would both make $______.
In order to make the same amount of money, they would have to each sell 5 bicycles. They would both make $500
How many bicycle would they sell to make the same amount of money?To find the number of bicycles they would need to sell to make the same amount of money,
We can set Jim's and Tom's weekly earnings equal to each other and solve for the number of bicycles:
250 + 50x = 400 + 20x
30x = 150
x = 5
So they would need to sell 5 bicycles to make the same amount of money.
How much would they make for selling that amountTo find out how much money they would make for selling 5 bicycles, we can substitute x = 5 into either equation.
Let's use Jim's equation:
250 + 50(5) = 500
So they would make $500 for selling 5 bicycles.
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there was a person trolling and didnt actually answer i need the answer to this
Answer:
Step-by-step explanation:
To write 0.246 as a fraction in simplest form, we need to remove the decimal and reduce the fraction to its lowest terms.
Step 1: Write 0.246 as the fraction 246/1000.
(Note: We get the denominator 1000 by counting the number of decimal places after the 6 in 0.246.)
Step 2: Simplify the fraction by dividing both the numerator and denominator by the greatest common factor.
The greatest common factor (GCF) of 246 and 1000 is 2.
246/2 = 123
1000/2 = 500
Therefore, 0.246 written as a fraction in simplest form is 123/500.
Answer:if I’m correct I think you would put it like this 123/500
It can’t be reduced because the denominator is at it’s simplest form
Step-by-step explanation:
Can you help me with this?
16. The equatiοn οf the line in slοpe-intercept fοrm that passes thrοugh the pοint (-6, 5) and is parallel tο x + 2y = 14 is y = (-1/2)x + 2.
What is equatiοn οf line?The equatiοn οf a straight line is y = mx + c, y = m x + c m is the gradient and c is the height at which the line crοsses the y -axis, alsο knοwn as the y -intercept.
16. Tο write the equatiοn οf a line in slοpe-intercept fοrm, we need tο find the slοpe and the y-intercept οf the line.
Tο find the slοpe οf the line, we can rewrite the equatiοn x + 2y = 14 in slοpe-intercept fοrm y = mx + b by sοlving fοr y:
x + 2y = 14
2y = -x + 14
y = (-1/2)x + 7
The slοpe οf the line is -1/2.
Since the line we want tο find is parallel tο this line, it will have the same slοpe οf -1/2.
Nοw we can use the pοint-slοpe fοrm οf the equatiοn οf a line tο find the equatiοn οf the line that passes thrοugh the pοint (-6, 5) with a slοpe οf -1/2:
y - y1 = m(x - x1)
where (x1, y1) is the pοint (-6, 5), and m is the slοpe, -1/2.
y - 5 = (-1/2)(x - (-6))
y - 5 = (-1/2)x - 3
y = (-1/2)x + 2
17. The equation perpendicular to y = -(2/3)x + 4, passing through (-4, 6)
perpendicular equations slope would be negative reciprocal to the current line.
The slope in y = -(2/3)x + 4, is m = -(2/3),
The negative reciprocal of -(2/3) is 3/2
Now, applying the x and y values in pοint-slοpe fοrm
y - 6 = 3/2(x - (-4))
y = 3/2(x+4) + 6
y = (3/2)x + 6 + 6
y = (3/2)x + 12
18. Since the line we want tο find is parallel tο this line, it will have the same slοpe.
Lets find the slope using slope formula
[tex]\rm m = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]\rm m = \dfrac{0 - (-1)}{2 - (-1)}[/tex]
[tex]\rm m = \dfrac{1}{3}[/tex]
Now, using the point slope form
y - 1 = 1/3(x - 3)
y = 1/3(x - 3) + 1
y = (1/3)x - 1 + 1
y = (1/3)x
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Lee buys 12 notebooks for 1. 29 each. How much money does lee spend on the 12 notebooks
Lee buys 12 notebooks and the cost of each one is $1.29. The total cost of all twenty notebooks is equals to $15.48. So, Total $15.48, money lee spends on the 12 notebooks.
We have, Lee buys some notebooks by spending money.
Number of notebooks that she bought = 12
The price or cost of one notebook = $1.29
We have to determine the amount of money she spends on the 12 notebooks, that total cost of 12 notebooks. Let the total cost of 12 notebooks be 'x dollars'. As we know , total cost is equals to multiplcation of number of objects by cost of one object. So, total cost of 12 notebooks = number of notebooks × cost of one notebook
=> total cost of 12 notebooks = 12 ×1.29
= (12×129)/100
= 15.48
Hence, the required cost is $15.48.
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Complete question:
Lee buys 12 notebooks for $1.29 each. How much money does lee spend on the 12 notebooks.
You and your siblings decided to make 10 pies for a bake sale. There were 8 slices in each apple pie and 10 slices in each shoo-fly pie. At the sale, there were 84 slices available. How many of each pie were made?
Answer: 6 apple pies and 4 shoo-fly pies were made.
Step-by-step explanation:
Let's assume the number of apple pies made is A, and the number of shoo-fly pies made is S.
We know that there were 8 slices in each apple pie, so the total number of apple pie slices would be 8A. Similarly, the total number of shoo-fly pie slices would be 10S.
We also know that the total number of slices available was 84. So we can write an equation:
8A + 10S = 84
We have two unknowns and only one equation, so we need another equation to solve for A and S. We know that the siblings made a total of 10 pies. So we can write another equation:
A + S = 10
Now we have two equations and two unknowns, so we can solve for A and S. We can use substitution to eliminate one variable:
A + (10 - A) = 10
10 = 2A + 10
2A = 0
A = 0
This is obviously not the solution we're looking for, so there must be an error in our calculations. Let's check our first equation:
8A + 10S = 84
If A = 0, then we have:
10S = 84
S = 8.4
This is also not a valid solution since we can't make 8.4 shoo-fly pies. The mistake we made was assuming that both A and S were whole numbers. We can fix this by using another equation:
A + S = 10
We know that A and S are both whole numbers and that A + S = 10. The only pairs of whole numbers that add up to 10 are (1, 9), (2, 8), (3, 7), (4, 6), and (5, 5).
Let's try each pair and see which one gives us a valid solution:
(1, 9): 8(1) + 10(9) = 98 (not 84)
(2, 8): 8(2) + 10(8) = 96 (not 84)
(3, 7): 8(3) + 10(7) = 94 (not 84)
(4, 6): 8(4) + 10(6) = 92 (not 84)
(5, 5): 8(5) + 10(5) = 90 (not 84)
None of the pairs work, which means there is no valid solution that uses whole numbers for A and S.
However, we can use decimals to get a solution that's close to the desired number of slices. Let's try (4.2, 5.8):
8(4.2) + 10(5.8) = 84.4 (close to 84)
This means that the siblings made 4.2 apple pies and 5.8 shoo-fly pies. Since we can't make a fraction of a pie, we'll round up the number of apple pies and round down the number of shoo-fly pies:
4 apple pies and 5 shoo-fly pies would give us a total of 8(4) + 10(5) = 84 slices, which is the desired number.
Someone please help I need the answer to the 7 questions the image is below
a) The Name of the angle of elevation is ∠c = 83.3°
b) The Name of the Hypotenuse side is AC
c) The Name of the Opposite side is AB
What is the elevation angle?The angle formed between the line of sight and the horizontal is known as the angle of elevation. The angle created is an angle of elevation if the line of sight is upward from the horizontal line.
We can use the tangent ratio to determine the angle of elevation:
tan(angle of elevation) = opposite/adjacent
tan(angle of elevation) = 29.25/4.75
tan(angle of elevation) = 6.157
The inverse tangent (tan⁻¹) both sides, we obtain:
angle of elevation = tan⁻¹(6.157)
Using a calculator, we get:
angle of elevation ≈ 81.3 degrees (rounded to the nearest tenth)
The elevation angle is roughly 81.3 degrees.
d) The Name of the Adjacent side is BC
e) The Trig Ratio I will be using is Tan θ = Sin θ/Cos θ because we are
given the side Opposite Side & Adjacent Side
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Observation what is going on regarding determinant of product of two matrices. al.) Make a conjecture about the relation between det(AB), and det(BA). Type your answer after %. a2.) Make a conjecture about the relation between det(AB), det(B), and det(A). Type your answer after %. a3.) Make a conjecture about the relation between det(A™), and det(A). Type your answer after %.
The determinant of two matrices for the question a1 is it has not been demonstrated, a2 the multiplied matrices can affect the determinant of the product, and a3 A matrix's own determinant will be the same as the determinant of its transpose.
a1.) Conjecture about the relation between det(AB), and det(BA):
The determinant of the product of two matrices is not necessarily equal.
If two matrices A and B are multiplied together to produce the product AB, it is not necessary that the determinant of AB is equal to the determinant of BA.
This is a conjecture that has not yet been demonstrated in every case.%
a2.) Conjecture about the relation between det(AB), det(B), and det(A):
The following conjecture could be made about the relation between the determinants det(AB), det(B), and det(A):
det(AB) = det(BA) det(AB) = det(A)det(B)det(BA) = det(A)det(B)
These conjectures are not true in general.
It is because the order in which matrices are multiplied can affect the determinant of the product.%
a3.) Conjecture about the relation between det(A™), and det(A):
This conjecture about the relation between the determinants det(A™) and det(A) can be made:
det(A™) = det(A)
The transpose of a matrix does not alter the determinant, as long as the matrix is square.
The determinant of a matrix will remain the same if the rows and columns are exchanged.
Therefore, the determinant of the transpose of a matrix will be equal to the determinant of the matrix itself.
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4. Circle the reason for each of the following manipulations used to simplify the product (8x²)(3x²).
(8.3).(x²-x²)
8x²-3x²
commutative or associative
8.3.x²-x²
commutative or associative
24x²
commutative or exponent property
8.3.x².x² = (8.3).(x².x²) - commutative and associative properties of multiplication.
What is commutative law?Commutative laws deal with arithmetic operations addition and multiplication. This means that changing the order or position when adding or multiplying two numbers does not change the final result. For example, 4 + 5 is 9 and 5 + 4 is also 9. The order in which the two numbers are added does not affect the sum. The same concept applies to multiplication. Commutativity does not apply to subtraction and division, because changing the order of the numbers yields a completely different final result.
(8x²)(3x²) can be simplified as follows:
(8x²)(3x²) = 8.3.x².x² = (8.3).(x².x²)
= [tex]24x^4[/tex]
The reason for each of the manipulations is as follows:
8.3.x².x² = (8.3).(x².x²) - commutative and associative properties of multiplication.
(8.3).(x².x²) = [tex]24x^4[/tex] - exponent property of multiplication.
Therefore, the final answer is [tex]24x^4[/tex].
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prove that n lines separate the plane into (n2 n 2)/2 regions if no two of these lines are parallel and no three pass through a common point.
In mathematical induction, prove that n lines separate the plane into (n^2 + n + 2)/2 regions if no two of these lines are parallel and no three pass through a common point.
Mathematical induction is a mathematical proof method that is used to demonstrate a statement or formula for all values of n, where n is a positive integer. If we use induction, we can show that the formula is true for n = 1, and we can also show that if the formula is true for n = k, then it is also true for n = k + 1.
Proof for n lines separating the plane into (n^2 + n + 2)/2 regions is given below:
Base Case: The theorem is true for n = 1. When we draw one line in the plane, we see that it splits the plane into two regions. Hence the formula is true for n = 1.
Induction Hypothesis: We believe that the formula is true for k lines. That is, k lines split the plane into (k^2 + k + 2)/2 regions.
Induction Step: We want to demonstrate that the formula is also true for k + 1 lines. We first take an arbitrary line from these k + 1 lines, which we call l. We notice that this line splits the plane into two regions.
Now, for the remaining k lines, we make an induction argument. We are sure that the formula is true for k lines. Thus, the k lines split the plane into (k^2 + k + 2)/2 regions. We know that these k lines intersect the line l at k points. Thus, by adding line l, we create k + 1 regions on the plane between these lines.
We now consider the line l itself. It can't cross any of the other k lines, or it would not meet our requirements. Therefore, it crosses each of the k existing lines, generating k + 1 areas. Thus, with the inclusion of line l, the number of regions on the plane is (k^2 + k + 2)/2 + k + 1 = (k^2 + 3k + 4)/2.
The formula for k + 1 is (k + 1)^2 + (k + 1) + 2 = k^2 + 3k + 4, and it is thus identical to the formula for the number of regions when k lines are drawn on the plane.
Therefore, the statement is true for all positive integers n.
Therefore, we have proved that n lines separate the plane into (n^2 + n + 2)/2 regions if no two of these lines are parallel and no three pass through a common point, by using mathematical induction.
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Based on the following sorted 20 values for age, what are the possible split points?
{20, 22, 24, 26, 28, 31, 32, 33, 35, 40, 42, 43, 45, 47, 49, 50, 52, 53, 55, 57}
Multiple Choice
a {20, 21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49. 5, 51, 52, 54, 56}
b {21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49, 51, 52. 5, 54, 56, 57}
c {0, 21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49, 51, 52. 5, 54, 56}
d {21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49. 5, 51, 52. 5, 54, 56}
Based on the following sorted 20 values for age, the possible split points are {20, 21, 23, 25, 27, 29. 5, 31. 5, 32. 5, 34, 37. 5, 41, 42. 5, 44, 46, 48, 49. 5, 51, 52, 54, 56} (option a).
Option A suggests that the split points are {20, 21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49.5, 51, 52, 54, 56}. Notice that every split point falls between two consecutive ages in the original list. For example, the first split point is 20 because it is between 20 and 22. The second split point is 21 because it is between 20 and 22 as well.
Option B suggests that the split points are {21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49, 51, 52.5, 54, 56, 57}. Notice that the only difference between this option and Option A is that the last split point is 57 instead of 49.5.
Option C suggests that the split points are {0, 21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49, 51, 52.5, 54, 56}. Notice that the first split point is 0, which is not a possible age in the original list.
Option D suggests that the split points are {21, 23, 25, 27, 29.5, 31.5, 32.5, 34, 37.5, 41, 42.5, 44, 46, 48, 49.5, 51, 52.5, 54, 56}. Notice that the only difference between this option and Option A is that the split point after 49 is 49.5 instead of 49.5.
In summary, the correct answer is Option A because it provides all the possible split points that fall between the ages in the original list. When working with split points, it's important to consider the specific context and criteria for dividing the data.
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in the figure below, mL2= 138, find mL1, mL3, and mL4
Answer:
Step-by-step explanation:
Find ∠1:
∠2 + ∠1 = 180 (angles on a straight line are supplementary)
138 + ∠1 = 180
∠1 = 42°
Find ∠4:
∠4 =∠2 = 138° (vertically opposite angles are equal)
Find ∠3:
∠3 = ∠1 = 42° (vertically opposite angles are equal)
In a lab experiment, a population of 400 bacteria is able to triple every hour. Which equation matches the number of bacteria in the population after 3 hours?
Answer:
400(3)^3
Step-by-step explanation:
It tripled for 3 hours which is 3^3 and there's 400 bacteria