Serine has pK 1 = 2.21 and PK 2 = 9.15. Use the Henderson-Hasselbalch equation to calculate the ratio neutral form/protonated form at pH = 3.05. Calculate the ratio, deprotonated form/neutral form, at pH = 9.87. Pay attention to significant figures in both

Answers

Answer 1

The ratio of neutral form/protonated form of serine at pH 3.05 is approximately 1:6.48 and the ratio of deprotonated form/neutral form of serine at pH 9.87 is approximately 7.94:1.

The Henderson-Hasselbalch equation relates the pH of a solution, the pKa of a weak acid, and the ratio of its conjugate base and acid forms. It is given as:

pH = pKa + log ([conjugate base]/[weak acid])

Using this equation, we can calculate the ratio of neutral form/protonated form and deprotonated form/neutral form of serine at different pH values.

At pH = 3.05, the solution is acidic, and the hydrogen ion concentration is higher. The protonated form of serine predominates in this pH range. Using the Henderson-Hasselbalch equation, we get:

3.05 = 2.21 + log ([serine-]/[Hserine])

Taking the antilog of both sides, we get:

[serine-]/[Hserine] = 10^(3.05 - 2.21) = 6.48

At pH = 9.87, the solution is basic, and the hydroxide ion concentration is higher. The deprotonated form of serine predominates in this pH range. Using the Henderson-Hasselbalch equation, we get:

9.87 = 9.15 + log ([Hserine]/[serine-])

Taking the antilog of both sides, we get:

[Hserine]/[serine-] = 10^(9.87 - 9.15) = 7.94

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Answer 2

At pH = 3.05, the ratio of neutral form/protonated form of serine is 0.001, and at pH = 9.87, the ratio of deprotonated form/neutral form is 1000.

The Henderson-Hasselbalch equation is used to calculate the ratio of a weak acid's protonated and deprotonated forms at a given pH. For serine, which has two pKa values, the equation is:

[tex]pH = pKa + log([A-]/[HA])[/tex]

where [A-] is the deprotonated form (negative ion) of serine and [HA] is the protonated form (positive ion) of serine.

At pH = 3.05, the pH is lower than both pKa values, so serine is mostly protonated. Plugging in the values, we get:

[tex]3.05 = 2.21 + log([A-]/[HA])[/tex]

l[tex]og([A-]/[HA]) = 0.84[/tex]

[tex][A-]/[HA] = 10^0.84 = 6.31[/tex]

Therefore, the ratio of neutral form/protonated form is 1/6.31, which is approximately 0.001.

At pH = 9.87, the pH is higher than both pKa values, so serine is mostly deprotonated. Plugging in the values, we get:

[tex]9.87 = 9.15 + log([A-]/[HA])[/tex]

[tex]log([A-]/[HA]) = 0.72[/tex]

[tex][A-]/[HA] = 10^0.72 = 5.01[/tex]

Therefore, the ratio of deprotonated form/neutral form is 5.01/1, which is approximately 1000.

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Answer:

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Answer:

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Answers

Answer:

2 Cu2O + C = 4 Cu + CO2

Explanation:

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CO2 has 1 coefficient

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2CU2O + C -----> 2Cu + CO2

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Answer:

A. Has only one kind of atom

Explanation:

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Answer:

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Explanation:

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What is Stoichiometry?

The stoichiometry is an important concept of chemistry which help us to use the balanced chemical equation to calculate the amounts of reactants and products. The stoichiometric coefficient is the number of molecules that can participate in the reaction.

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1 g of NaOH is produced from 62/80 g of Na₂O .

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Answer:

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Answer:

D

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Answer:

true

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Answer:

True

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Eurkaryote... sorry if i wrong

Explanation:

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Explanation:

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it’s to produce sex cells

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A)sex cells

Explanation:

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adding because evaporation speed is increased with increased temperature

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Answers

Answer:

D) 100*C

Explanation:

Answer:

A. 0°C

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Answers

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i have no idea sorry

Answer:

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Explanation:

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Answer:

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Answer:

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Explanation:

20.What do carbon and silicon have in common?

a.They belong to the same column (family), therefore they have the same number of valence electrons.
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The carbon and silicon have in common that they belong to the same column (family), therefore they have the same number of total electrons. So, option B is correct.

What do carbon and silicon have in common?

Carbon's closest analogue is silicon. Silicon and carbon are both tetravalent atoms that primarily form covalent (non-ionic) compounds. However, aside from the fact that both elements "can form four covalent bonds," there is surprisingly little in common between them.

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Thus, option B is correct.

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