simplificar cada expresion numerica. -24+(-65)÷5​

Answer:

7.8 mL

Step-by-step explanation:

Answer:

.78 L

Step-by-step explanation:

Well, simple conversions

a milliliter is .0001 of a liter and 1 liter is 1000 mL, so we can safely say that .78 L is 780 mL, dwarfing the given 7.8 mL

Answer:

14 answers  

Step-by-step explanation:

since there is 1/4 of a chance to get a question right by guessing you need to see what 1/4 of 56 is, which is 14

Answer:

1.1025rad

Step-by-step explanation:

1°=0.0175rad

63°=0.0175rad*63=1.1025rad

Answer:

K = [tex]\frac{P}{TV}[/tex]

Step-by-step explanation:

P = KTV

Divide both sides by TV

(P/TV) = K

Answer:

10,000 is the answer

Step-by-step explanation:

14 465

round up the 4 which is 0 then your answer would be 10000

Answer:

[tex]y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]

Step-by-step explanation:

[tex]y''-y=5e^{-4x}+2x,\: y(0)=y'(0)=0\\\\\mathcal{L}\{y''\}-\mathcal{L}\{y\}=\mathcal{L}\{5e^{-4x}\}+\mathcal{L}\{2x\}\\\\s^2Y(s)-sy(0)-y'(0)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\s^2Y(s)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\(s^2-1)Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\Y(s)=\frac{5}{(s+4)(s^2-1)}+\frac{2}{s^2(s^2-1)}\\ \\Y(s)=\frac{5s^2+2(s+4)}{s^2(s+4)(s^2-1)}\\ \\Y(s)=\frac{5s^2+2s+8}{s^2(s-1)(s+1)(s+4)}[/tex]

Perform the partial fraction decomposition

[tex]\frac{5 s^{2} + 2 s + 8}{s^{2} \left(s - 1\right) \left(s + 1\right) \left(s + 4\right)}=\frac{A}{s}+\frac{B}{s^{2}}+\frac{C}{s + 1}+\frac{D}{s - 1}+\frac{E}{s + 4}\\\\5 s^{2} + 2 s + 8=s^{2} \left(s - 1\right) \left(s + 1\right) E + s^{2} \left(s - 1\right) \left(s + 4\right) C + s^{2} \left(s + 1\right) \left(s + 4\right) D + s \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) A + \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) B[/tex]

[tex]5 s^{2} + 2 s + 8=s^{4} A + s^{4} C + s^{4} D + s^{4} E + 4 s^{3} A + s^{3} B + 3 s^{3} C + 5 s^{3} D - s^{2} A + 4 s^{2} B - 4 s^{2} C + 4 s^{2} D - s^{2} E - 4 s A - s B - 4 B\\\\5 s^{2} + 2 s + 8=s^{4} \left(A + C + D + E\right) + s^{3} \left(4 A + B + 3 C + 5 D\right) + s^{2} \left(- A + 4 B - 4 C + 4 D - E\right) + s \left(- 4 A - B\right) - 4 B[/tex]

Solve for each constant

[tex]\begin{cases} A + C + D + E = 0\\4 A + B + 3 C + 5 D = 0\\- A + 4 B - 4 C + 4 D - E = 5\\- 4 A - B = 2\\- 4 B = 8 \end{cases}[/tex]

[tex]-4B=8\\B=-2[/tex]

[tex]-4A-B=2\\-4A-(-2)=2\\-4A+2=2\\-4A=0\\A=0[/tex]

[tex]A+C+D+E=0\\C+D+E=0\\E=-C-D[/tex]

[tex]-A+4B-4C+4D-E=5\\4(-2)-4C+4D-(-C-D)=5\\-8-4C+4D+C+D=5\\-3C+5D=13\\5D=13+3C[/tex]

[tex]4A+B+3C+5D=0\\4(0)+(-2)+3C+13+3C=0\\-2+6C+13=0\\11+6C=0\\6C=-11\\C=-\frac{11}{6}[/tex]

[tex]5D=13+3C\\5D=13+3(-\frac{11}{6})\\5D=13-\frac{33}{6}\\5D=\frac{15}{2}\\D=\frac{15}{10}\\D=\frac{3}{2}[/tex]

[tex]E=-C-D\\E=-(-\frac{11}{6})-(\frac{3}{2})\\E=\frac{11}{6}-\frac{3}{2}\\E=\frac{2}{6}\\E=\frac{1}{3}[/tex]

Take the inverse transform and solve for the IVP

[tex]Y(s)=\frac{0}{s}+\frac{-2}{s^2}+\frac{-\frac{11}{6}}{s+1}+\frac{\frac{3}{2}}{s-1}+\frac{\frac{1}{3}}{s+4}\\ \\y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]

Answer:

- 1.628 x 10^9

Step-by-step explanation:

(1.9 x 10^9) - 6,300,000 × (5.6 x 10^2) =  - 1628000000

 - 1628000000 = - 1.628 x 10^9

I think you forgot the graph. Please add it.

Answer:

I believe the answer is A: x = - 1

Answer:

-90x^3y^3

Step-by-step explanation:

Answer:

y=3x

Step-by-step explanation:

Since 6 small bricks have the same mass as 5 large bricks and the mass of one small brick is 2.5 kg, the mass of one of the large bricks is 3 kg

Mass is the quantity of matter in a physical body.

6 small bricks have the same mass as 5 large bricks.

let

the total mass of the small or large bricks = x

Therefore,

6 × 2.5 = x

x = 15 kg

Therefore, the mass of each large bricks can be calculated as follows:

let the mass of each large bricks  = y

15 = 5y

divide both sides by 6

y = 15 / 5

y = 3 kg

Therefore, the mass of one of the large bricks is 3 kg

.learn more on mass here: https://brainly.com/question/895643

Answer:

Step-by-step explanation:

Complementary angles sum to 90°.

We have the measure of one angle, find the missing one as below.

Complementary angles have sum 90°

[tex]\\ \sf\longmapsto x+21=90[/tex]

[tex]\\ \sf\longmapsto x=90-21[/tex]

[tex]\\ \sf\longmapsto x=69[/tex]

Answer:

Each of them would play 2 games to get the same cost amount

Step-by-step explanation:

for example

#1) $5 + $3 = $8 x 2 = $16

#2) $6 + $2 = $8 x 2 = $16

Answer:

x = 23

Step-by-step explanation:

Add 4x to the left and add 86 to the right.

5x = 115

Now, divide 5 on both sides to get x.

x = 23.

The result is 23.

Answer:

x= – 115/3

Step-by-step explanation:

I don’t know what exact form you want so I’ll give you mixed number form.

Answer:

  7 - (-3)

Step-by-step explanation:

You want the sum 7 + 3 expressed as a difference.

The difference of A and B is written A - B. The subtraction operation is involved.

Subtraction is the same as addition of the opposite. Or, addition is the same as subtracting the opposite:

  7 + 3 = 7 - (-3)

__

Additional comment

We can also write the difference as ...

  3 - (-7)

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Divide total fat by number of chocolates

56/40 = 1.4 grams

answer: 1.4 grams

Answer:

-1/6

Step-by-step explanation:

the equation to do this is y2-y1/x2-x1

therefore you set it up as 4-3/-1-5

then when you simplify it it would be 1/-6

therefore the slope is -1/6

Answer:

It should be -4/7

Step-by-step explanation:

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Answer:

Step-by-step explanation:

Let the number be x

[tex]\dfrac{3}{4}+x \leq 2\dfrac{3}{4}\\\\\\\dfrac{3}{4}+ x \leq \dfrac{11}{4}[/tex]

Subtract 3/4 from both sides

[tex]\dfrac{3}{4}-\dfrac{3}{4}+x\leq \dfrac{11}{4}-\dfrac{3}{4}\\\\\\x \leq \dfrac{11-3}{4}\\\\\\x \leq \dfrac{8}{4}\\\\\\x \leq 2[/tex]

Answer:  Any number less than or equal to 2

Answer:

4

Step-by-step explanation:

4*2=8

and 4/8 also equals four anyway you simplify the question it will equal 4

Answer:

Step-by-step explanation:

Let Brandon's age be [tex]x[/tex]

Therefore Ella=[tex]2x[/tex]

Tristan= [tex]\frac{2x}{3}[/tex]

Fifteen years time add 15 to each age

Brandon: [tex]x+15[/tex]

Ella: [tex]2x+15[/tex]

Tristan:[tex]\frac{2x}{3} +15[/tex]

All their ages together=89

So: [tex]x+15[/tex] +  [tex]2x+15[/tex] + [tex]\frac{2x}{3} +15[/tex][tex]=89[/tex]

[tex]3\frac{2}{3} x=44[/tex]

[tex]x= \frac{44}{3\frac{2}{3} } =12[/tex]

No, this is not a plausible value for the population mean, because 5 is not within the 95% confidence interval.

====================================================

Explanation:

The greek letter mu is the population mean. It has the symbol [tex]\mu[/tex] which looks like the letter 'u' but with a tail at the front or left side.

The question is asking if mu = 5 is plausible if the researcher found the 95% confidence interval to be 5.2 < mu < 7.8

We see that 5 is not in that interval. It's a bit to the left of 5.2

Since mu = 5 is not in the interval, it's not a plausible value for the population mean.

Have we ruled it out with 100% confidence? No. Such a thing is not possible. There's always room for (slight) error. The researcher would need to do a census to be fully confident; however, such practices are very time consuming and expensive. This is the main reason why statistics is important to try to estimate the population with a sample.

Answer:

no

Step-by-step explanation:

quad- 4

pent- 5

they have a different number of sides