Answer:
mass
Explanation:
hope this helps you!!
1) How many moles are in 4.0x10^24 atoms?
Answer:
6.64 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{4 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 6.644518...[/tex]
We have the final answer as
6.64 molesHope this helps you
A saturated hydrocarbon having molecular formula CnH2n+2 diffuses through a porous membrane twice as fast as sulphur dioxide. Calculate the volume occupied by the hydrocarbon at27°C and 2atm ?
Help me fast !
Answer:
12.3 L
Explanation:
Now we have that the rate of diffusion of the saturated hydrocarbon is R1
Rate of diffusion of sulphur dioxide is R2
Molar mass of hydrocarbon is M1
Molar mass of sulphur dioxide is 64 gmol-1
From Graham's law;
R1/R2 = √64/M1
2/1 =√64/M1
(2/1)^2 = (√64/M1)^2
4/1 = 64/M1
4M1 =64
M1 = 16
To obtain the number of moles of the gas;
(n*12) + (2n + 2) 1 = 16
12n + 2n + 2 = 16
14n + 2 = 16
14n = 16 - 2
n = 14/14
n = 1
Hence the hydrocarbon is CH4
Volume occupied by CH4 at STP = 22.4 L
Hence;
P1 = 1 atm
T1 = 273 K
V1 = 22.4 L
T2 = 300 K
P2 = 2 atm
V2 = ?
P1V1/T1 = P2V2/T2
P1V1T2 = P2V2T1
V2 = P1V1T2/P2T1
V2 = 1 * 22.4 * 300/2 * 273
V2 = 12.3 L
The volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L
Let the hydrocarbon be initially at standard temperature and pressure (STP)
Thus, we can obtain the new volume of the hydrocarbon by using the combined gas equation as illustrated below:
Initial volume (V₁) = STP = 22.4 L Initial pressure (P₁) = STP = 1 atmInitial temperature (T₁) = STP = 273 KFinal temperature (T₂) = 27 °C = 27 + 273 = 300 KFinal pressure (P₂) = 2 atmFinal volume (V₂) =?P₁V₁ / T₁ = P₂V₂ / T₂
(1 × 22.4) / 273 = (2 × V₂) / 300
22.4 / 273 = (2 × V₂) / 300
Cross multiply
273 × 2 × V₂ = 22.4 × 300
546 × V₂ = 6720
Divide both side by 546
V₂ = 6720 / 546
V₂ = 12.31 L
Thus, the volume occupied by the hydrocarbon at 27 °C and 2 atm is 12.31 L
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?Are you good.....
sailing 2
a)at
b)in
Answer:
A
Explanation:
common sense
Answer:
are you good at sailing A.
Heeellllpppp ASAP ......
Answer:
I saw B, he vented SUS
Explanation:
Iodoethane Is the answer.
Determine the mass of the H2CO3 produced.
Answer:
62.03 g/mol
Explanation:
An ideal gas sample is confined to 3.0 L and kept at 27 °C. If the temperature is raised to 77 °C and the initial pressure was 1500 mmHg, what is the final pressure?
The gas is confined in 3.0 L container ( rigid container) ⇒ the volume remains constant when the temperature is increased from from 27oC to 77oC and therefore V1=V2 .
Hope it helps you please mark as brainlistIdeal gas law is valid only for ideal gas not for vanderwaal gas. Ideal gas is a hypothetical gas. Vanderwaal gas can behave as ideal gas at low pressure and high temperature. Therefore the final pressure is 1,750 mmHg.
What is ideal gas equation?Ideal gas equation is the mathematical expression that relates pressure volume and temperature.
Mathematically the relation between Pressure, volume and temperature can be given as
PV=nRT
where,
P = pressure of gas
V= volume of gas
n =number of moles of gas
T =temperature of gas
R = Gas constant = 0.0821 L.atm/K.mol
At constant volume, the above equation can be rearranged as
P₁/T₁ = P₂/T₂
Substituting all the given values in the above equation, we get
1500 ÷300= P₂÷350
P₂ =1,750 mmHg
Therefore the final pressure is 1,750 mmHg.
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If I change the volume of a solution from 5.00 L to 10.0 L, what was the new
concentration if the original concentration was 4.0 M? Please help me as soon as possible with explanation.
The new concentration = 2 M
Further explanationDilution is a process of decreasing the concentration of a solution by adding a number of solvents
Can be formulated
M₁V₁=M₂V₂
M₁ = Initial Molarity
V₁ = Initial volume
M₂ = Final Molarity (after dilution)
V₂ = Final volume (after dilution)
V₁=5 L
V₂=10 L
M₁=4 M
The new concentration(M₂) :
[tex]\tt M_2=\dfrac{V_1.M_1}{V_2}\\\\M_2=\dfrac{5\times 4}{10}\\\\M_2=2~M[/tex]
what is the Curie used to measure
Answer:
it's used to measure intensity of radioactivity in a sample of material
Which of the following is an essential condition for a combustion reaction?
A - Oxygen is a product.
B - Oxygen is a reactant.
C - Carbon dioxide is a product.
D - Carbon dioxide is a reactant.
Answer:
oxygen is a reactant.
Explanation:
Combustion is the reaction with atmospheric oxygen forming carbon dioxide and water. Therefore, the essential condition is option B oxygen as a reactant.
What is combustion?Combustion is a type of reaction in which a molecule or compound reacts with atmospheric oxygen producing carbon dioxide and water. Combustion reaction is exothermic thus, evolves heat during reaction.
The general chemical equation for a combustion reaction can be written as:
[tex]\rm M + nO_{2} \rightarrow xH_{2}O + y CO_{2}[/tex]
Where, M be a reactant.
Combustion is an aerobic process that is only taking place in presence of oxygen. Hydrocarbon gases easily undergo combustion forming heat energy and they are used as fuels propellants.
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A certain first-row transition metal ion forms many different colored solutions. When four coordination compounds of this metal, each having the same coordination number, are dissolved in water, the colors of the solutions are red, yellow, green, and blue. Further experiments reveal that two of the complex ions are paramagnetic with four unpaired electrons and the other two are diamagnetic. What can be deduced from this information about the four coordination compounds
Answer:
See explanation
Explanation:
From the analysis we have in the question, we must look towards a first row transition metal ion having a d^6 configuration because it yields a paramagnetic complex having four unpaired electrons and a diamagnetic complex having no unpaired electrons.
We have two possible candidates in mind, Fe^2+ and Co^3+. However, Fe^2+ does not form as many coloured complexes as stated in the question so we have to eliminate that option.
We are now left with only Co^3+. Various ligands are going to cause these various colours of Co^3+ to appear in solution.
Hence, we can deduce from all these that the nature of ligands determines the colour of the complex . Don't forget that the colour of a complex arises from crystal field splitting.
What kind of reactions tend to be spontaneous?
O A. Reactions that are endothermic
B. Reactions that are exothermic
C. Reactions that decrease in entropy
D. Reactions that increase in enthalpy
The spontaneous reactions are said to be exothermic in nature. Hence, option B is correct.
What is a spontaneous reaction?The type of reaction that has not been utilizing energy input output to the reaction system in order to favor the formation of product are termed as exothermic reaction.
The entropy has been the tendency of the randomness of atoms in the system, and the enthalpy has been the energy of the system.
With the spontaneous reaction, there has been an increase in the entropy of the system with the formation of the products, and a decrease in the enthalpy. The reaction forms no use of the input energy, and thereby cannot be endothermic in nature.
Therefore, the reaction that is exothermic tends to be spontaneous reactions. Hence, option B is correct.
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Converting benzoic acid to phenylmethanol
Answer:
The Conversion of Benzoic acid to Benzyl alcohol in presence of Potassium Permanganate is an oxidizing reaction where potassium permanganate is strong oxidizing agent.This reaction occurs in basic medium in presence of sodium carbonate.This reaction gives best yield in acidic medium.But it takes longer duration for reaction to complete as compared to basic medium.less duration is required which is necessary for laboratary scale
How many grams are in 2.3 x 1024 formula units of KNO3?
390 g KNO₃
General Formulas and Concepts:ChemistryAtomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.MathPre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:Step 1: Define
2.3 × 10²⁴ formula units KNO₃
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g.mol
Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol
Step 3: Convert
[tex]2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )[/tex] = 386.172 g KNO₃
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
386.172 g KNO₃ ≈ 390 g KNO₃
Which statement describes a physical change? *
A. An iron bolt on a bridge rusts and weakens the bridge.
B. The surface of a silver cup turns black when it is exposed to air.
C. A sculptor casts a statue in molten bronze and allows it to harden.
D. Slivers of magnesium in fireworks form a bright glow as they burn.
The statement that describes a physical change is a sculptor casts a statue in molten bronze and allows it to harden. The correct option is C.
What are physical changes?"A physical change is one that simply affects the physical nature of the substance." Usually, increasing the temperature or applying pressure, both, will cause a physical change. In other words, physical changes are reversible.
All the other options like rusting of iron bolts on a bridge is a chemical change when iron reacts with oxygen in the air, it gets rust.
Similarly, silver cups exposed to air react with air is a chemical change, and option d, silver off magnesium that creates light, is also a chemical change.
Thus, the correct option is C. A sculptor casts a statue in molten bronze and allows it to harden.
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Which is the noble gas configuration for 31 Ga?
Answer:
1s22s22p63s23p63d104s24p1.
Explanation:
Gallium, Ga has 31 protons and 31 electrons.
Answer:
Ar 3d10 4s2 4p1
Explanation:
hope this serves you well!!
Gold III Bromide is heated in a flask filled with chlorine gas.
The reactants of this reaction are:
I
The type of reaction is:
The products of this reaction are:
Answer:
detail is given below.
Explanation:
Chemical equation:
AuBr₃ + Cl₂ → AuCl₃ + Br₂
Balanced chemical equation:
2AuBr₃ + 3Cl₂ → 2AuCl₃ + 3Br₂
The reactants of this chemical reaction are,
AuBr₃
Cl₂
The product of this chemical reaction is,
AuCl₃
Br₂
Reaction type:
The reaction type is single replacement reaction.
Single replacement:
It is the reaction in which one elements replace the other element in compound.
AB + C → AC + B
In a similar way chlorine replace the bromine and form gold(III) chloride and bromine gas.
If a system's internal energy increases by 250 kJ after the addition of375 kJ of energy as heat, what was the value ofthe work in the process?
(A) -625 kJ
(B) -125 kJ
(C) 125 kJ
(D) 625 kJ
Answer:
(B) -125 kJ
Explanation:
Going by the First Law of Thermodynamics it states that"
"A system can do work and increase it's internal energy provided we supply heat."
ΔU= q+w-----------1
where U= the internal heat
q= the quantity of heat added or removed from the system
w= the work done
Given
ΔU= 250kJ
q= 375kJ
from equation 1 make w subject of the formula we have
w= ΔU-q
w= 250-350
w= -125kJ
Please Help!
Your car has 1.95 gallons of gasoline (octane, d = 0.6916 g/mL), which reacts with oxygen
according to the balanced reaction below. Your car uses the energy produced by this reaction
at a rate of 115 kJ per second while traveling at a speed of 65 miles per hour. Calculate the
distance (in miles) the car can travel using this amount of octane.
2 C8H18(g) + 25 O2(g) -----> 16 CO2(g) + 18 H2O(g) ΔHrxn = -10,900 kJ
Answer:
38.3 miles
Explanation:
First, we convert 1.95 gallons to mililiters:
1.95 gallons * [tex]\frac{3.785 L}{1gallon}*\frac{1000mL}{1 L}[/tex]= 7380.75 mLThen we calculate how many grams of octane are available for the reaction, using its density:
0.6916 g/mL * 7380.75 mL = 5104.53 g C₈H₁₈Now we convert octane grams into octane moles, using its molar mass:
5104.53 g C₈H₁₈ ÷ 114 g/mol = 44.78 mol C₈H₁₈Then we calculate how many kJ are produced from the combustion of 44.78 mol C₈H₁₈, if 2 moles produce 10900 kJ:
44.78 mol * 10900 kJ / 2 mol = 244032 kJWe calculate how many seconds is the car available to keep going, if it spends 115 kJ per second:
244032 kJ * 1 s / 115 kJ = 2122.02 sWe convert seconds to hours:
2122.02 / 3600 = 0.59 hoursFinally we calculate the distance:
65 mi/hour * 0.59 hour = 38.3 miWhich is larger: barium atom or a barium ion? Explain your answer in terms of atomic structure
3. Using the solubility of ionic compounds table and/or the solubility rules,
list 3 substances that will NOT form a solution with water? (Hint:
identify substances that are insoluble with water)
Describe the characteristics
of the different sections
(families) of the periodic
table
Answer: The vertical columns on the periodic table are called groups or families because of their similar chemical behavior. All the members of a family of elements have the same number of valence electrons and similar chemical properties. The horizontal rows on the periodic table are called periods
HELP 20 POINTS
What is the frequency of an Electromagnetic wave has with wavelength 2.94 x 10^-8 cm?
Answer:
gccdfjjkjggffffgggggbbbhb
Don’t know need the anwser !!DUE MONDAY!!
Answer: The distance is slightly less than 3.5 m
Explanation: assuming wall and target are the same thing, and the bullet has constant velocity, the bullet will travel 7 m in half a second, so half that distance is 3.5 m.
In reality, the bullet is decelerating (at an unknown rate) so the distance is slightly less than 3.5 m.
There is also a vertical velocity component, which means it hits the target/wall at an angle. The trajectory is such that it hits the wall above the shooter because the ricochet hits at ~the level at which it left the firearm.
If the wall was absent, the bullet would have described a parabola which brough it back to the initial level after 7m. This could be calculated, but it means that the actual distance between the shooter and the wall is slightly less than 3.5 m
In addition, the collision with the wall is not 100% elastic, so the velocity aftercthe ricochetvis further reduced.
A calculation would be complex because these confounding factors are not completely independent of each other, but all reduce the average velocity and therefore the distance.
Therefore it is only possible to say that the distance was somewhat less than 3.5 m
What temperature units
should be used when
performing calculations using
Charles's Law?
Answer:
Kelvin (K) onlyExplanation:
Kelvin is preferred for solving problems related to Charles' Law because , it is the Absolute temperature scale.
To convert Celsius to Kelvin scale, you add 273 to the temperature in the centigrade/Celsius scale.
4. Kendrick drags his bat out to play baseball. which statement best describes the science of what he did?
O Kendrick would use less energy if he dragged the bat faster.
Kendrick did not have to work to move the bat because he dragged it.
Kindrick gave the bat potential energy.
Kindrick gave the bat kinetic energy.
Explanation:
Kendrick gave the bat potential Energy
What is 797 mm hg to atm?
Answer:
797 mm hg = 1.04868 atm
Explanation:
1 atm = 760 mm hg
797 mm hg to atm is 1.0468 atm
Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area.
There are many different types of units and prefixes that may be used in general practice to reflect pressure. Thus, it is ensured that all the measurements and their respective units are in the same framework when conducting pressure calculations.
Pascal is the SI unit of pressure, and is the basic pressure unit in the SI (the International System of Units) system.
Given,
Pressure = 797 atm
1 mm Hg = 0.00131579 atm
797 mm Hg = 0.00131579 × 797
= 1.04868 atm
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What is a property of the Noble Gases? *
A. They are not reactive because their outer valence electron shell is full.
B They are very reactive
C. They can be found in the atmosphere
D. They react readily with oxygen in the atmosphere
Answer: A. They are not reactive because their outer valence electron shell is full.
Explanation:
Noble gases are group 18 elements which are Helium , Neon , Argon , Krypton , Xenon and radon.
Noble gases have general electronic configuration of [tex]ns^2np^6[/tex]
As the sub-shells of noble gases is fully filled and their octet is complete. Hence, it will not gain or lose any electron and thus is non reactive in nature.
They do not react with other elements under ordinary conditions.
Thus the correct statement is they are not reactive because their outer valence electron shell is full.
What would have a higher boiling point water or hydrocarbon ( from penny liquid stacking) and why?
Answer:
High amount of energy is required to dissociate these bonds and hence water molecules have a higher boiling point than expected.
Explanation:
PLEASE HELP
is this a chemical or physical change???
Answer:
Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.
Explanation:
What is the concentration of a solution made by diluting 35 mL of 6.0 M HCl to a final volume of 750 mL?
If 2.49g of CuNO3 is dissolved in water to make O.830M solution, what is the volume of the solution in milliliters?
How many moles of NaOH are present in 13.5mL of 0.17 M NaOH?
Answer:
1. 0.28M
2. 24mL
3. 0.002295moles of NaOH.
Explanation:
1. The 6.0M HCl solution is diluted from 35mL to 750mL, that is:
750mL / 35mL = 21.43 times
The 6.0M HCl solution is diluted 21.43 times, the final concentration is:
6.0M / 21.43 = 0.28M
2. First, we need to convert grams of CuNO3 to moles and then, as molarity is moles per liter we can solve for volume of solution in liters and convert it to mililiters:
Moles CuNO3 -Molar mass 124.9g/mol:
2.49g * (1mol / 124.9g) = 0.020 moles of CuNO3
Volume is:
0.020 moles * (1L / 0.830mol) = 0.0240L * (1000mL / 1L) = 24mL
3. In 13.5mL = 0.0135L of 0.17M NaOH the moles are:
0.0135L * (0.17mol / L) = 0.002295moles of NaOH