Solve for x. 60(cos 50) = x

Answers

Answer 1

Answer:

x=38.56725658

Explanation:

Answer 2

Answer:

x=38.56725658

Explanation:


Related Questions

A psychologist wants to identify how the holiday season impacts the anxiety levels of Americans. She wants to get results on the feelings of anxiety from over one million Americans in the next month. What design should she use and why?

Answers

Answer: survey

Explanation:

A survey can be an interview or a questionnaire which is given to a particular group in order to know their characteristics or opinions, towards certain issues.

Since the psychologist wants to get results on the feelings of anxiety from over one million Americans in the next month, the survey should be used.

A merry go round exerts a force of 1000 N on a rider on the
outer ring of animals when it takes 15 seconds to make a
complete revolution. If the person weighs 750 N, the radius
of the circle he is making is m. Round your answer to
the nearest tenth.

Answers

Answer:

The radius of the circle made by the person on the merry go round is 74.55 meters

Explanation:

The given parameters are;

The force the merry go round exerts on the rider = 1000 N

The time it takes the merry go round to make one complete revolution = 15 seconds

The weight of the person = 750 N

The radius of the circle made by the person on the merry go round = r

We have;

[tex]F_c = \dfrac{m \cdot v^2}{r} = m \cdot \omega ^2 \cdot r[/tex]

Where;

m = The mass of the person

v = The velocity of the person

[tex]F_c[/tex] = The centrifugal force acting on the person = 1,000 N

r = The radius of the circle made by the person on the merry go round

ω = Angular velocity = 2·π/15 rad/s

We have;

The mass of the person = The weight/(The acceleration due to gravity, g)

∴ The mass of the person = 750/9.81 ≈ 76.45 kg

By substituting the calculated and known values into the equation for  the centripetal force, we have;

[tex]F_c[/tex] = m × ω² × r

1000 = 76.45 × (2·π/15)² × r

r = 1000/(76.45 × (2·π/15)²) = 74.55 m

The radius of the circle made by the person on the merry go round = r = 74.55 m.

which internal energy source produces heat by converting gravitational potential energy into thermal energy

Answers

Accretion and differentiation

Choose the answer that is most descriptive of the Solar System. Sun, planets, moons, asteroids, comets Nebulas, star clusters, super nova, black holes, binary stars Jupiter, Neptune, Saturn, Uranus, dwarf planets Jupiter, Great Red Spot, 8 regular moons, ±58 irregular moons

Answers

Answer:

The correct option is;

Sun, planets, moons, asteroids, comets

Explanation:

The Solar System consists of the system of celestial bodies bound gravitationally to the Sun, which includes the 8 regular planets, 2 dwarf planets, 796, 354 known minor planets, 4,143 comets, moons, which are natural satellites, an asteroid belt, which consists of a belt of rock and metal containing celestial bodies moving in a belt round the Sun

Please answer ASAP!!!! Which statement describes the factors that affect the force of a spring?
A. The spring force depends on the spring constant, and increases as displacement
increases
B. The spring force only depends on the spring constant
C. The spring force gets weaker as displacement increases, and is in the same
direction as the displacement
D. The spring force depends on gravity and friction

Answers

Answer:

d

Explanation:

the spring depends on gravity and friction

Alkali metals _____.
A. only react with other metals in Group 1
B. react with other elements by losing one electron
C. react with other elements by gaining one electron
D. do not react with other elements under normal conditions

Answers

I think the answer is C

a traveller covers 1.2km distance in 5mins find it's average velocity​

Answers

Explanation:

Average Velocity = Displacement / Time

= 1.2km / 5 min

= 1200m / 300s

= 4m/s.

The average velocity of a moving body is the distance covered by time. The average velocity of the traveler covers 1.2 km in 5 min is 4 m/s.

What is velocity ?

Velocity is a physical quantity which measures the distance travelled per unit time. Velocity is a vector quantity thus having both magnitude and direction.

Velocity is the ratio of distance to the time. Given that the distance travelled by the man = 1.2 km = 1200 m

time = 5 min = (5 × 60 s) = 300 s.

Thus, velocity = distance/ time

                       = 1200 m / 300 s

                       = 4 m/s.

Therefore, the velocity of the traveler is  4 m/s.

To find more on velocity, refer here:

https://brainly.com/question/18084516

#SPJ2

A go-cart and rider have a mass of 14 kg. If the cart accelerates at 6m/s^2 during a 40 m sprint in 100 seconds, how much power did the cart do? MUST SHOW ALL WORK!!!!!!!!!

Answers

Answer:

P = 33.6 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

[tex]F = 14*6\\F = 84 [N][/tex]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

[tex]W = F*d[/tex]

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

[tex]W = 84*40\\W = 3360 [J][/tex]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

[tex]P=W/t\\[/tex]

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

Now replacing:

[tex]P=3360/100\\P=33.6[W][/tex]

The power is given in watts

A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.

Answers

Answer:

Explanation:

It is still using F = m*a -- just in a disguised form.

Givens

F = 900 N

vf = 360 m/s

vi = 0

t = 40 second

Formulas

a = (vf - vi)//t

F = m * a

Solution

a = (360 - 0)/ 40

a = 9

F = m * a

900 = m * 9

m = 900/9

m - 100 kg.          Doesn't seem high enough.

Answer:

a= V- u/t

a= 360 - 0 /40 = 9 m/sec2

F = MA

900 = M * 9

M = 900/9

M= 100 kg

Do you think solar roofs and energy storage batteries will become widespread in the future? Why or why not?
2. In your opinion, do the potential benefits of electric vehicles outweigh the potential costs? Explain.



Answers

Answer:

yes and I think there will be solar windows aswell

A 45 kg swimmer starting from rest can develop a maximum speed of 12 m/s over a distance of 20 m How much net force must be applied to do this ?

MUST SHOW WORK!

Answers


F = ma = mΔv/t = m(vf - vi)/t = mvf/t (since vi = 0)

⇒ a = vf/t


While accelerating from rest to vf, the distance d the swimmer traveled satisfies

d = (1/2)at2

Then

d = (1/2)(vf/t)t2 = vf t/2 ⇒

t = 2d/vf

F = ma = mvf/t = mvf / (2d/vf) = mvf2 / (2d)

F = [45 * 122 / (2 * 20)] N = 162 N

If you also want to know how long the swimmer took to accelerate to vf,

t = 2d/vf = (2 * 20 / 12) s = 3.33 s
55m got it right on edg

If y is inversely proportional to x and y = 4 and x=10, find y when x = 20

Answers

Answer:

Y=8

Explanation:

Y=4

X=10

if x is 20 it means it is doubled frm the previous therefore it means even y has to be doubled

first. now

x=10. x=20

y=4. y=8

a spy satellite of mass of 1000 kg is orbiting the earth at an altitude of 300 km/s

a) what is its period
b) what is its orbital speed​

Answers

Answer:

a) The period of the satellite is approximately 5,425.305 seconds (1.507 hours)

b) The orbital velocity of the satellite is approximately 7,725.8565 m/s

Explanation:

The given parameters are;

The mass of the satellite, m = 1,000 kg

The altitude at which the satellite is orbiting, h = 300 km

a) The period of the satellite is given as follows;

[tex]T = 2 \times \pi \times \sqrt{\dfrac{(R + h)^3}{g \times R^2} }[/tex]

Where;

R = The radius of the Earth = 6.371 × 10⁶ m

g = The acceleration due to gravity = 9.81 m/s²

h = The altitude of the orbit of the satellite = 300 km = 300,000 m

By substitution, we have;

[tex]T = 2 \times \pi \times \sqrt{\dfrac{((6.371 + 0.3)\times 10^6)^3}{9.81 \times (6.371 \times 10^6)^2} } \approx 5,425.305[/tex]

T ≈ 5,425.305 seconds ≈ 1.507 hours

b) The orbital velocity of the satellite is given as follows;

[tex]v_0 = \sqrt{\dfrac{G \times M_{central}}{R + h} } = \sqrt{\dfrac{g \times R^2}{R + h} }[/tex]

Where;

v₀ = The orbital velocity of the satellite

Which by substitution gives;

[tex]v_0 = \sqrt{\dfrac{9.81 \times (6.371 \times 10^6)^2}{(6.371 + 0.3) \times 10^6} } = 7,725.8565[/tex]

The orbital velocity, v₀ = 7,725.8565 m/s.

By what process are surface materials removed and transported from one location to another?
O erosion
O cementation
O weathering
O deposition

Answers

the answer is erosion
Erosion would be an answer, but if referring to the exact amount of one location and taking about a figure, it could be deposition !!

11 A car is driven on a long journey along a flat, horizontal road. The car stops several times on the
journey and its engine becomes hot.
Which type of energy does not change during the journey?
A the chemical energy in the fuel tank
the gravitational energy of the car
c the internal (thermal) energy of the engine
B
D the kinetic energy of the car

Answers

Answer:

A

Explanation:

Because the gravity is the one pulling the car to the ground so it doesnot change

The same same thing happens to the chemical energy in the engine it doesnot change as it is the one that makes the car to move from one place to another

Option B is correct that is the gravitational energy of the car does not change.

(A) The chemical energy in the fuel tank gets converted into thermal energy heating up the engine and mechanical energy which helps moving the car.

(B) Gravitational energy is due to the force of gravitation between the car and the earth and depends on their respective masses which does not change as the car moves.

(C) The internal energy is proportional to thermal energy. the thermal energy of the engine increases which means its internal energy also increases.

(D) The kinetic energy of the car changes as it moves and stops.

Learn more about gravitational energy:

https://brainly.com/question/19768887?referrer=searchResults

Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance and displacement
covered by Asha.(a) (Numbering problem)_​

Answers

Answer:

Asha traveled a distance of 50 m

The displacement is 20 m north.

Explanation:

Distance and Displacement

A moving object constantly travels for some distances at defined periods of time. The total moved distance is the sum of each individual distance the object traveled. It can be written as:

dtotal=d1+d2+d3+...+dn

This sum is obtained independently of the direction the object moves.

The displacement only takes into consideration the initial and final positions of the object while moving. The displacement, unlike distance, is a vectorial magnitude and can even have magnitude zero if the object starts and ends the movement at the same point.

Asha walks 15 m west, 20 m north, and 15 m east. The total distance is

dt=15 m + 20 m + 15 m = 50 m

Asha traveled a distance of 50 m

Note the final position is 20 m above the initial position since she goes 15 m west and 15 m east. Thus the displacement is 20 m north.

How do the summer monsoons of India affect the hydrosphere, geosphere, and biosphere?

Answers

Answer:

Explanation:

The monsoon rains are the main source of water for 55 percent of the country’s arable land. This means the rains are crucial — not only for India’s farmers, but for its economy as a whole. Now, that’s a good thing when the monsoon arrives on time and brings the right amount of rain. But when it’s late or weak, it leads to drought.

an object weighs 150N on earth. what is the mass of the object?

Answers

Answer:

450 g =0.9921 lb

Explanation:

A(n) ____________ stretch is one done where antagonist muscles are used to stretch the muscles. But the _____________ stretch is one that is done that the muscle needs help from something or someone to stretch the muscle.

Answers

Answer: Dynamic - Static Flexibility

Explanation:

It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone? ​

Answers

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

[tex]Work=Power\times time[/tex]

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

[tex]Work=342J/s\times 59s=20178J[/tex]

Thus the work done on the flagstone is 20178 J

When two ocean plates come together, one ocean plate __________________
under the other, causing a chain of ________________ __________________
to form.

Answers

Answer:

A subduction zone is also generated when two oceanic plates collide — the older plate is forced under the younger one — and it leads to the formation of chains of volcanic islands known as island arcs.

Explanation:


When the net force on an object is zero, what do we know about the motion of that object

Answers

Answer:

The objects speed or motion does not change if the net force is 0.

Explanation: There basically doesn't have anything acting on it so it stays put.

I need help with the questions when it says what is the topic and rest

Answers

It should be a and f would I you like me to explain

The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7 x 10 to the -9th power coulombs what is the distance between the two charges

Answers

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above

Answers

Answer:

Explanation:

Hell im good dude

HELP ASAP!! WILL TRY TO GIVE BRAINLIEST

Explain how receptor-mediated endocytosis is more specific than pinocytosis or phagocytosis

Answers

Answer:

it selects what molecules to engulf, whereas pinocytosis or phagocytosis engulf anything in the vicinity

Trust!

samantha walked 5km/h . how long did it take to her to travel 15 km? ​

Answers

Answer:

3hrs is the answer

Explanation:

time=d/t

t=15/5 hrs

t=3 hrs

3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
What is the mass of the bus?

Answers

Answer:

does this have picture so I can solve

The mass is 12,000

144,000 divided by 12 = 12,000

Momentum = mass × velocity

Brainliest would be appreciated. :)

1. Photosynthesis is a chemical reaction that occurs inside green plant cells. Which sentence describes
one important energy conversion that occurs as a result of photosynthesis?
A. Light is converted to chemical energy.
B. Carbon dioxide is converted to light energy.
C. Oxygen is converted to chemical energy.
D. Chlorophyll is converted to light energy.

Answers

I don’t know I think I would say A) or B) if I’m correct

Answer:oxygen is converted to chemical energy

Explanation:

I got it right

A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it

Answers

Answer:

F = -8820 N

Explanation:

Given that,

The weight of a car, W = 19600 N

Initial speed of the car, u = 30 m/s

It is brought to rest, final velocity, v = 0

Distance, d = 100 m

We need to find the average friction force acting on it.

Firstly we find the acceleration of the car using third equation of motion. Let it is a.

[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]

Average frictional force,

F = ma

m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]

F = 1960 kg × -4.5 m/s²

= -8820 N

So, the average friction force acting on it is 8820 N.

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