Suppose TD=SG and what additional information is needed to prove the two triangles congruent SAS
a)


PLEASE HELP

Answer: the y intercept form is y= 4x-1

Step-by-step explanation: let me know if you need to know how I got it

Answer:

Area = (Length * (a + a * (sin(Angle γ) / sin(Angle γ + Angle β)) + a * (sin(Angle β) / sin(Angle γ+Angle β)))) + a * ((a * sin(Angle γ)) / sin(Angle γ + Angle β)) * sin(Angle β)

Answer:

Step-by-step explanation:

i think it true if right mark me as brainiest and thank

The week in which Evie would have more money than Weston is the 18th week.

Let this equation represent the amount of money Weston would have in x weeks be: $4000 - $30x

Let this equation represent the amount of money Evie would have in x weeks be: $2800 +$40x

The first step is to determine when they would have the same amount of money:

$4000 - $30x = $2800 +$40x

$4000 - $2800 = $40x + $30x

1200 = $70x

x = 1200 / 70 = 17.14 weeks

After 17 weeks, Evie would have more money than Weston.

Here is the complete question: Weston has $4,000 in his bank account and withdraws $30 a week. Evie has $2,800 in her  bank account and deposits $40 a week. When will Evie have more money than Weston (in

weeks)?

A similar question was answered here: https://brainly.com/question/25711114

Answer:

44 Step-by-step explanation:

first you want to put the Question like this in the calculator

2244÷51=44

Answer:

y=x + 6

Step-by-step explanation:

G1=G2

so G2 =1

y-3 /x+3 =1/1

y-3 = x +3

y=x + 6

Step-by-step explanation:

We have that

[tex](x + \frac{1}{x} ) {}^{2} = 3[/tex]

We are trying to find the number value so that we can apply in the later equation.

Qe first simplify.

Remeber that

[tex](a + b) {}^{2} = a {}^{2} + 2ab + {b}^{2} [/tex]

Also remeber that

[tex] \frac{1}{x} = {x}^{ - 1} [/tex]

so

[tex](x + x {}^{ - 1} ) {}^{2} = {x}^{2} + 2x {}^{0} + {x}^{ - 2} = 3[/tex]

We then simply remeber that x^0=1 so

[tex] {x}^{2} + 2 + \frac{1}{ {x}^{2} } = 3[/tex]

Multiply both sides by x^2.

[tex] {x}^{4} + 2 {x}^{2} + 1 = 3 {x}^{2} [/tex]

Subtract both sides by 3x^2

[tex] {x}^{4} - {x}^{2} + 1 = 0[/tex]

Notice that x^4= (x^2)^2.

So our reformed equation is

[tex]( {x}^{2} ) {}^{2} - {x}^{2} + 1 = 0[/tex]

Let a variable , w equal x^2. This means that we subsitute variable, w in for x^2.

[tex]w {}^{2} - w + 1 = 0[/tex]

Now we use the quadratic formula

[tex] w = \frac{ - b + \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

and

[tex]w = - b - \frac { \sqrt{b {}^{2} - 4ac } }{2a} [/tex]

Let a=1 b=-1 and c=1.

[tex]w = \frac{1 + \sqrt{1 - 4(1)} }{2} [/tex]

[tex]w = \frac{1 - \sqrt{1 - 4} }{2} [/tex]

Now, we get

[tex]w = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex]w = \frac{1}{2} - \frac{ i\sqrt{3} }{2} [/tex]

Now since we set both of these to the x^2 we solve for x.

and

[tex] {x}^{2} = \frac{1}{2} + \frac{i \sqrt{3} }{2} [/tex]

and

[tex] {x}^{2} = \frac{1}{2} - \frac{i \sqrt{3} }{2} [/tex]

We can represent both of these as complex number in the form of a+bi. Next we can convert this into trig form which is

[tex] {x}^{2} = 1( \cos(60) + i \: \sin(60) [/tex]

and

[tex] {x}^{2} = 1( \cos(300) + i \: sin(300))[/tex]

Next we take the sqr root of 1 which is 1, and divide the degree by two.

[tex] {x} = 1( \cos(30) + i \: sin \: 30)[/tex]

and

[tex]x = 1( \cos(150) + i \: sin(150)[/tex]

We are asked for the 2nd root so just add 180 degrees to this and we have

[tex]x = 1 \cos(210) + i \: sin \: 210)[/tex]

and

[tex]x = 1( \cos(330) + i \: sin(330)[/tex]

which both simplified to

[tex]x = - \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

and

[tex]x = \frac{ \sqrt{3} }{2} - \frac{1}{2} i[/tex]

Now we must find

x^18+x^12+x^6+1.

We just use demovire Theorem. Which is a complex number raised to the nth root is

[tex] {r}^{n} (cos(nx) + i \: sin(nx)[/tex]

So let plug in our first root.

[tex]1( \cos(330 \times 18)) + i \: sin \: (330 \times 18))) + 1( \cos(12 \times 330)) + i \: sin(12 \times 330) + 1( \cos(6 \times 330) + i \: sin(6 \times 330))) + 1[/tex]

To save time we multiply the angle and use rules of terminals angle and we get

[tex]1( \cos(180) + i \sin(180) ) + 1( \cos(0) + i \: sin \:( 0) + 1( \cos(180) + i \: sin(180) + 1[/tex]

And we get

[tex] - 1 + 1 + - 1 + 1 = 0[/tex]

So one of the answer is x=0

And the other, let see

[tex]1 \cos(210 \times 18) + i \: \sin(210 \times 18) + 1 \: cos(210 \times 12) + i \: sin(210 \times 12) + 1 \cos(210 \times 6) + \:i sin(210 \times 6) + 1[/tex]

[tex] \cos(180) + i \: sin(180) + 1 \cos(0) + i\sin(0) +1( \cos(0) + i \sin(0) + 1[/tex]

We get

[tex] - 1 + 1 + 1 + 1 = 2[/tex]

So our answer are 2.

So the answer to the second part is

0 and 2.

A) -3

B) 5

C) -2

D)-6

i have to write 20 characters so sisiasskklsa

Answer:

a) -3

b)5

c)-2

d)-6

Step-by-step explanation:

4 - 7 =-3

4 is positive and 7 is negative

a positive minus a negative is equal to a negative

3 is negative and 8 is positive, but 8 is bigger than 3, so take the sign of the bigger number which is 8.

c) is the same as question b

same signs rule

a negative + a negative is = to negative

positive and a positive is = to a positive

a negative +/_ a positive = a negative

Answer:

9√10

Step-by-step explanation:

3√15 x 6  = √90

3√90 = 3 x √9 x √10

3 √90 = 3 x 3 √10 = 9√10

Answer:

An isosceles triangle has two side lengths the same and one different.

Step-by-step explanation:

Lin should aim the ball at 7.8 feet away from point  B

From the question (see attachment), we have the following equivalent ratios:

[tex]AB : BE = DC :CE[/tex]

This is so because triangles ABE and DCE are similar triangles.

Such that:

[tex]BE + CE = 20[/tex]

[tex]AB = 16[/tex]

[tex]DC = 16 + 9 = 25[/tex]

So, we have:

[tex]AB : BE = DC :CE[/tex]

[tex]16 : BE = 25: CE[/tex]

Make CE the subject in [tex]BE + CE = 20[/tex]

[tex]CE=20 - BE[/tex]

Substitute 20 - BE for CE in [tex]16 : BE = 25: CE[/tex]

[tex]16 : BE = 25: 20 - BE[/tex]

Express as ratio

[tex]\frac{16 }{ BE} = \frac{25}{ 20 - BE}[/tex]

Cross multiply

[tex]16(20 - BE) = 25BE[/tex]

Open bracket

[tex]320 - 16BE = 25BE[/tex]

Collect like terms

[tex]25BE + 16BE = 320[/tex]

[tex]41BE = 320[/tex]

Divide both sides by 41

[tex]BE = 7.8[/tex]

Hence, she should aim at 7.8 feet away from point  B

Read more about similar triangles at:

https://brainly.com/question/14285697

Answer:You want to make a bank shot. Sketch the path of the cue ball so it will bounce off of the bottom side and knock the yellow stripe 9 ball into the top middle pocket.

Step-by-step explanation:

2(4+3)  yw     OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO

Answer: D) 10 jerseys

Step-by-step explanation:

Let j represent the number of jerseys and C for total cost

Local company eqn: C = 5.25j + 45

Online company eqn: C = 7.75j + 20

Set both sides equal to solve:

5.25j + 45 = 7.75j + 20

5.25j - 7.75j = 20 -45

- 2.5j = -25

[tex]\frac{-2.5j}{-2.5}=\frac{-25}{-2.5}[/tex]

j = 10

Therefore, the cost is the same for both companies when 10 jerseys are sold

Answer:

f(x) =x2 3x 5?

c = 5

therefore the solpe = 5

Answer:

reflection over the y axis

Step-by-step explanation:

Answer:

4 hours · Speed = 50 mph · distance = time x speed · Time = 200 / 50 = 4 hours.

Step-by-step explanation:

Answer:

2 - n

Step-by-step explanation:

2 decreased by n means n less than 2.

Answer:

Write each phrase as an algebraic expression. Phrase, Expression. nine increased by a number x, 9 + x. fourteen decreased by a number p, 14

Step-by-step explanation:

2-n       Plz mark brainliest if correct

Answer:

Step-by-step explanation:

11)  y = -1x - 2

12)  y = -(3/2)x + 3

13)  y = 3x - 2

14)  y = (3/4)x + 1

15)  y = (1/2)x + 1

16)  y = -(2/5)x

17)  y = 7x + 2

18)  y = (4/3)x - 4

Attached graph for 19 and 20

Answer:

18

Step-by-step explanation:

Substitute x = - 3 into the expression

2x²

= 2(- 3)²

= 2 × 9

= 18

Answer:

hi this should be your answer (-2,4),(0,0),(2,-4)

Step-by-step explanation:

hope this helps!

Answer:

F

Step-by-step explanation:

open circle at (-9,3) means the symbol must be either < or >

closed circle at (2,-6) means the symbol must be either ≤ or ≥

the x-values of each ordered pair above represent the domain {-9 and 2}

Answer: the height of a triangle can be determined in many different ways depending on whether it's a right triangle, isosceles triangle (a triangle with two equal sides), or equilateral triangle.

Step-by-step explanation:

Step-by-step explanation:

The formula for the Area of a triangle is A = (1/2)bh where b is the base an h is the height. Since the triangle is a right triangle, the base and height are the two shorter sides

The accurate statements are:

The given parameters are:

[tex]n = 12[/tex] --- number of parts

[tex]r = 10[/tex] --- the radius

(a) The central angle

Between points 1 and 3, there are 2 sections, each of which has a measure of 30 degrees.

So, the measure of the two sections is:

[tex]\theta = 30^o \times 2[/tex]

[tex]\theta = 60^o[/tex]

Hence, (a) is false

(b) The circumference

This is calculated using:

[tex]C = 2\pi r[/tex]

So, we have:

[tex]C = 2 \times 3.14\times 10[/tex]

[tex]C = 62.8[/tex]

Hence, (b) is true

(c) The measure of the minor arc

Between points 12 and 4, there are 4 sections, each of which has a measure of 30 degrees.

So, the measure of the four sections is:

[tex]\theta = 30^o \times 4[/tex]

[tex]\theta = 120^o[/tex]

Hence, (c) is true

(d) The length of the major arc

Between points 3 and 10, there are 7 sections, each of which has a measure of 30 degrees.

So, the measure of the seven sections is:

[tex]\theta = 30^o \times 7[/tex]

[tex]\theta = 210^o[/tex]

The length of the arc is:

[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]

So, we have:

[tex]L = \frac{210}{360} \times 2 \times 3.14 \times 10[/tex]

[tex]L = \frac{13188}{360}[/tex]

[tex]L = 36.3[/tex]

Hence, (d) is false

(e) The length of the minor arc

There is only one section between points 6 and 7

So, the measure of the section is:

[tex]\theta = 30^o[/tex]

The length of the arc is:

[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]

So, we have:

[tex]L = \frac{30}{360} \times 2 \times 3.14 \times 10[/tex]

[tex]L = \frac{1884}{360}[/tex]

[tex]L = 5.2[/tex]

Hence, (e) is true

Read more about segments and arcs at:

https://brainly.com/question/14965059

Answer:

-B

-C

-E

Step-by-step explanation:

just took the test...

I got them right

Here, the y-axis represents different sports in which players are in.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Step-by-step explanation:

Total Students = 450 (Everything within the sample/rectangle)

Choir = 110

Band = 240

Both = 60 (Where both circles overlap)

110+240+60 = 410 (Total students in Choir or Band or Both)

410 ÷ 450 = 0.91111111

Therefore the probability that a student chosen at random is in the choir, band or both out of the sample is 91%

Answer:

Consider a big number 3,400,000. To convert this number into scientific notation:

Place a decimal by counting the steps to the left until the coefficient of the number is between 1 and 9.

Count the number of steps moved. This will be the power of the base 10.

In this case, the coefficient is 3.4 and the 6 steps are moved.

Multiply the coefficient by 106,

Therefore, the answer is 3. 4 x 10 6

Step-by-step explanation:

Given that:

CI = ₹408

years = 2 years

Rate of interest = 4%

A = P{1+(R/100)}^

A-P = p{1+(R/100)}^n - P

I = P[1+(R/100)}^n - 1]

408 = P[{1+(4/100)²} - 1]

= P[{1+(1/25)²} - 1]

= P[(26/25)² - 1]

= P[(676/625) - 1]

= P[(676-625)/625]

408 = P(51/625)

P = 408*(625/51)

= 8*625 = 5000

Sum = 5000

Simple Interest (I) = (P*R)/100

= 5000*2*(4/100)

= 50*2*4 = 400

From the given above options, option (a) ₹400 is your correct answer.

Answer:

6

Step-by-step explanation:

The LCM of 6 and 2 is 6.