Suppose that, for budget planning purposes, the city in Exercise 24 needs a better estimate of the mean daily income from parking fees.
a) Someone suggests that the city use its data to create a confidence interval instead of the interval first created. How would this interval be better for the city? (You need not actually create the new interval.)
b) How would the interval be worse for the planners?
c) How could they achieve an interval estimate that would better serve their planning needs?
d) How many days' worth of data should they collect to have confidence of estimating the true mean to within

Therefore , the solution of the given problem of standard deviation comes out to be the group standard deviation in order to use (b) z.

Statistics uses variance as a way to quantify difference. The image of the result is used to compute the average deviation between the collected data and the mean. Contrary to many other valid measures of variability, it includes those pieces of data on their own by comparing each number to the mean. Variations may be caused by willful mistakes, irrational expectations, or shifting economic or business conditions.

Here,

We use the z-distribution if the total standard deviation is known; otherwise, we use the t-distribution.

Additionally, for small sample sizes, the t-distribution is used, whereas for big sample sizes, the z-distribution is used.

The fact that z requires that you know the population standard deviation, and that this is frequently not known in practice, is one reason to use a distribution rather than the traditional .

Normal curve to find critical values when computing a level C confidence interval for a population mean.

You must be aware of the group standard deviation in order to use (b) z.

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In linear equation, 11.85 pounds is the weight of the wire.

What is  linear equation?

A linear equation is a first-order (linear) term plus a constant in the algebraic form y=mx+b, where m is the slope and b is the y-intercept. The variables in the previous sentence, y and x, are referred to as a "linear equation with two variables" at times.

Total weight of pool having 16 wires     =13.6 pounds

Weight of the pool                                 =1.75

Therefore the weight of the wire alone = 13.6 - 1.75

                                                             =  11.85 pounds

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Answer: 39

39 is the only answer option greater than 17

Answer:

the question is incomplete, so I looked for similar questions:

There are 3 sandwiches, 4 drinks, and 2 desserts to choose from.

the answer = 3 x 4 x 2 = 24 possible combinations

Explanation:

for every sandwich that we choose, we have 4 options of drinks and 2 options of desserts = 1 x 4 x 2 = 8 different options per type of sandwich

since there are 3 types of sandwiches, the total options for lunch specials = 8 x 3 = 24

If the numbers are different, all we need to do is multiply them. E.g. if instead of 3 sandwiches there were 5 and 3 desserts instead of 2, the total combinations = 5 x 4 x 3 = 60.

For this question's answer, there are 2 x 5 = 10 lunch specials are possible.

The number of lunch specials possible are 10.

We can use combinations for this case,

Total number of distinguishable things is m.

Out of those m things, k things are to be chosen such that their order doesn't matter.

This can be done in total of

[tex]^mC_k = \dfrac{m!}{k! \times (m-k)!} ways.[/tex]

If the order matters, then each of those choice of k distinct items would be permuted k! times.

So, total number of choices in that case would be:

[tex]^mP_k = k! \times ^mC_k = k! \times \dfrac{m!}{k! \times (m-k)!} = \dfrac{m!}{ (m-k)!}\\\\^mP_k = \dfrac{m!}{ (m-k)!}[/tex]

This is called permutation of k items chosen out of m items (all distinct).

We are given that;

Number of sandwiches=2

Number of drinks=5

Now,

To find the total number of lunch specials, we need to multiply the number of choices for sandwiches by the number of choices for drinks.

Number of sandwich choices = 2

Number of drink choices = 5

Total number of lunch specials = 2 x 5 = 10

Therefore, by combinations and permutations there are 10 possible lunch specials.

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The p-values for the observed values of the test statistic are 0.0094, 0.0628, 0.0228, 0.032 and 0.4404.

To calculate the p-value for each observed value of the test statistic, we need to find the area under the standard normal distribution curve to the right of each z-score. This is because the alternative hypothesis is one-tailed, with the inequality sign pointing to the right (i.e., H1: µ > µ0). Here are the steps to calculate the p-value for each observed value:

For z0 = 2.35, the area to the right of the z-score can be found using a standard normal distribution table or calculator. The area is 0.0094, which is the p-value.

For z0 = 1.53, the area to the right of the z-score is 0.0628, which is the p-value.

For z0 = 2.00, the area to the right of the z-score is 0.0228, which is the p-value.

For z0 = 1.85, the area to the right of the z-score is 0.0322, which is the p-value.

For z0 = -0.15, the area to the right of the z-score is 0.5596. However, since the alternative hypothesis is one-tailed with the inequality sign pointing to the right, we need to subtract this area from 1 to get the p-value. Therefore, the p-value is 1 - 0.5596 = 0.4404.

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The taylor series (centered at c) for the function f(x) = 1/x, c = 1 is f(x) = 1 - (x-1) - (x-1)^2 + (x-1)^3 + ...

The Taylor series is a representation of a function as an infinite sum of terms that involve the function's derivatives evaluated at a particular point. The Taylor series centered at a point c for a function f(x) is given by:

f(x) = f(c) + f'(c)(x-c)/1! + f''(c)(x-c)^2/2! + f'''(c)(x-c)^3/3! + ...

In this case, we want to find the Taylor series centered at c=1 for the function f(x) = 1/x. We can start by finding the derivatives of f(x):

f'(x) = -1/x^2

f''(x) = 2/x^3

f'''(x) = -6/x^4

f''''(x) = 24/x^5

We can then evaluate these derivatives at c=1 to get:

f(1) = 1/1 = 1

f'(1) = -1/1^2 = -1

f''(1) = 2/1^3 = 2

f'''(1) = -6/1^4 = -6

f''''(1) = 24/1^5 = 24

Substituting these values into the Taylor series formula, we get:

f(x) = 1 - (x-1) - (x-1)^2 + (x-1)^3 + ...

This is the Taylor series centered at c=1 for the function f(x) = 1/x. It represents an approximation of the function in the neighborhood of x=1. By adding more terms to the series, we can improve the accuracy of the approximation.

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Complete question is:

Use the definition of Taylor series to find the taylor series (centered at c) for the function. f(x) = 1/x, c = 1.

Answer:

Show your solution ( 3. ) C + 18 = 29

Step-by-step explanation:

To solve the equation C + 18 = 29, we want to isolate the variable C on one side of the equation.

We can start by subtracting 18 from both sides of the equation:

C + 18 - 18 = 29 - 18

Simplifying the left side of the equation:

C = 29 - 18

C = 11

Therefore, the solution to the equation C + 18 = 29 is C = 11.

Answer:

D

Step-by-step explanation:

the correct answer is D

We'll presume that the cash in question were initially split between two accounts since we don't know the answer to question #9: the amount that has been sitting in a savings account for 60 days is $78.00.

Because the FDIC for savings accounts and the NCUA for community bank accounts guarantee all deposit made by consumers, savings are a secure location to put your money.

Savings accounts might assist you avoid overspending by keeping the money away from your spending account. You should save emergency cash in your bank account for easy access. Savings accounts keep money secure because the Deposit Insurance Corporation of the United States insures them for up to $250,000.

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Distance from a point in space to the moon is a continuous random variable and Number of coins in a stack is a discrete random variable.

A discrete random variable is one that has a finite number of possible values or one that can be countably infinitely numerous. A discrete random variable is, for instance, the result of rolling a die because there are only six possible outcomes.

A continuous random variable, on the other hand, is one that is not discrete and "may take on uncountably infinitely many values," like a spectrum of real numbers.

1. The Name of the people in the car that crosses the bridge - Not a Variable

2. Continuous random variable measuring the interval between each car crossing the bridge.

3. The Categorical Random Variable for the type of vehicles crossing the bridge

4. The number of cars that use the bridge in one hour - Continuous Random Variable

For Question 2:

1. Type of coin - Categorical Random Variable

2. The distance from a given location in space to the moon - Continuous Random Variable

3. Number of coins in a stack - Discrete Random Variable

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Complete question is:

Label each of the following as Discrete Random Variable, Continuous Random Variable, Categorical Random Variable, or Not a Variable.

1. The Name of the people in the car that crosses the bridge Not a Variable

2. The time between each car crossing the bridge Continuous Random Variable

3. The type of cars that cross the bridge Categorical Random Variable

4. The number of cars that use the bridge in one hour Continuous Random Variable

Question 2: Which of these are Continuous and which are Discrete Random Variables?

1. Type of coin

2. Distance from a point in space to the moon

3. Number of coins in a stack

The expressiοn 5x(x²) is equal tο 5 * x¹ * x² (5 * x³ = 5x³). Thus, οptiοn (c) 5x3 is the cοrrect respοnse.

The cοefficients (the numbers in frοnt οf the variables) οf the expressiοn 5x(x²) can be multiplied, and the expοnents οf the variables can be added, tο determine the prοduct.

The first cοefficient we have is 5 times 1, giving us 5. Sο, using the secοnd x², we have x tο the pοwer οf 2 multiplied by x tο the pοwer οf 1 (frοm the first x). Expοnents are added when variables with the same base are multiplied. Sο, x¹ multiplied by x² results in x³.

Cοmbining all οf the parts, the phrase becοmes:

5x(x²) is equal tο 5 * x¹ * x² (5 * x³ = 5x³).

Thus, οptiοn (c) 5x³ is the cοrrect respοnse.

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The state in question is using a five-character license plate system, with each character having 36 possible combinations. Multiplying the possible combinations of each character gives us a total of 60,466,176 possible license plates.

Multiplication is an iterative process of addition where the multiplier is the quantity of times the multiplicand is added to itself. When a number is multiplied, it is multiplied by itself a predetermined amount of times.

This implies that each license plate will have five distinct characters, each of which can be any of the following: the 26 characters of the alphabet, the digits 1, 2, 3, or 4, or the numbers 0 through 9. It provides us with a total of 5 characters, each of which has 36 different potential combinations (4 digits + 26 letters + 10 digits).

The number of character combinations is multiplied to determine the total number of potential license plates. In this instance, the result is 36 times itself.

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270,400 license plates are possible from the combinations of each character given in the question.

Combinations are used to calculate the number of ways a certain number of items can be selected from a given set of items.

To calculate the total possible license plates in the state, we need to consider the total number of possible combinations of the five characters.

For the first character, there are four possible digits (1, 2, 3, or 4).

For the second character, there are 26 letters of the alphabet. (A-Z)

For the third character, there are again 26 letters of the alphabet.

For the fourth character, there are 10 possible digits (0 through 9).

For the fifth character, there are again 10 possible digits.

We can calculate the number of possible license plates by multiplying the number of possibilities for each character.

4 x 26 x 26 x 10 x 10 = 270,400 possible license plates.

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Answer: 2s²(39 - 74s - 280s)(s - 2)(s + 7/2)

Step-by-step explanation:

To factor the polynomial 78s - 148s³ - 560s² completely, we can first factor out a common factor of 2s²:

2s²(39 - 74s - 280s)

Then, we can factor the quadratic expression inside the parentheses using the quadratic formula:

s = [-(-74) ± √((-74)² - 4(39)(-280))] / 2(39)

s = [74 ± √(54724)] / 78

s = [74 ± 2√13681] / 78

s = [74 ± 2×117] / 78

Therefore, the roots of the quadratic expression are:

s = 2 or s = -7/2

Substituting these values back into the factored expression, we get:

2s²(39 - 74s - 280s) = 2s²(39 - 74(2) - 280(2)) = -1240s²

2s²(39 - 74s - 280s) = 2s²(39 - 74(-7/2) - 280(-7/2)) = 2450s²

So the completely factored form of the polynomial is:

2s²(39 - 74s - 280s)(s - 2)(s + 7/2)

The values of a continuous function f are given which are false is  By the Mean Value Theorem applied to f on the interval (2,5), there is a value c such that f' (c) = 10. So, the correct option is statement (B). Let f be the function defined by f (x) = r - 6x2 + 9x + 4 for 0 < 3 < 3 then f is decreasing on the interval (1,3) because f' (2) < 0 on the interval (1, 3). So, the correct option is D).

For continuous function f the statement (B) is false. Although the Mean Value Theorem guarantees the existence of a point c such that f'(c) = (f(5)-f(2))/(5-2) = 2, there is no guarantee that this value will be exactly 10.

When f (x) = r - 6x2 + 9x + 4 for 0 < 3 < 3 is statement (D) is true. We have f'(x) = -12x + 9, which is negative for x in the interval (1,3). Therefore, f is decreasing on this interval. Statement (A) is false, as f'(2) = 3 is positive, so f is increasing on the interval (0,1).

Statement (B) is also false, as f'(x) is not negative on the interval (0,1). Statement (C) is false, as f" (x) = -12 is negative everywhere, so f is concave down on the entire interval (0,3).

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Answer: 66

Step-by-step explanation:

all 3 of them should equal to 180

so 79+35 is 114

180-114 will give us the answer which is 66

For part A the 90% confidence interval for the percentage of deer carrying ticks that test positive for Lyme disease is (0.106, 0.214), or 10.6% to 21.4% (rounded to one decimal place). And for part b cut the margin of error in half, we need to quadruple the sample size.

How to solve?

a) To create a 90% confidence interval for the percentage of deer carrying ticks that test positive for Lyme disease, we can use the following formula:

CI = p ± z×(√(p×(1-p)/n))

where:

p is the sample proportion of deer carrying ticks that test positive for Lyme disease (p = 23/144 = 0.16)

z× is the critical value for a 90% confidence level, which is approximately 1.645 (from a standard normal distribution table)

n is the sample size (n = 144)

Substituting these values into the formula, we get:

CI = 0.16 ± 1.645×(√(0.16×(1-0.16)/144))

CI = 0.16 ± 0.054

Therefore, the 90% confidence interval for the percentage of deer carrying ticks that test positive for Lyme disease is (0.106, 0.214), or 10.6% to 21.4% (rounded to one decimal place).

b) To cut the margin of error in half, we need to quadruple the sample size. Since the original sample size was 144, we need to inspect 4×144 = 576 deer.

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(a) The function x as a function of t is t = 250ln(499x/998)

(b) Half the population will have heard the rumor approximately 109.86 units of time after it was started.

(a) To solve the differential equation dt/dx = kx(N−x), we can separate the variables and integrate

dt/dx = kx(N−x)

dt/(N-x) = kx dx

Integrating both sides, we get

t = -1/k × ln(N-x) - 1/k × ln(x) + C

where C is the constant of integration.

To find C, we can use the initial condition that two people start the rumor at t=0, so x=2:

0 = -1/k * ln(N-2) - 1/k * ln(2) + C

C = 1/k * ln(N-2) + 1/k * ln(2)

Substituting C back into the equation, we get:

t = -1/k * ln(N-x) - 1/k * ln(x) + 1/k * ln(N-2) + 1/k * ln(2)

Simplifying, we get

t = 1/k * [ln((N-2)x/(2(N-x)))]

Substituting k=1/250 and N=1000, we get:

t = 250ln(499x/998)

(b) We want to find the time t when half the population has heard the rumor, so x = N/2 = 500. Substituting this into the equation we obtained in part (a), we get

t = 250ln(499(500)/998) = 250ln(249/499)

t ≈ 109.86

Therefore, half the population will have heard the rumor approximately 109.86 units of time after it was started.

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The end balance is negative, so Mr. Manuel lost money.

We know that Mr. Manuel spended $800,000 in a product, and it can be sold with an extra 60% over the cost. Then the revenue here is:

$800,000*(1.6) = $1,280,000

We also know that there are costs of $75,680, $247.000 and $185.460.

Now we know that profit is defined as the difference between the revenue and the costs, so to get the profit we need to solve the equation below:

P = $1,280,000 - $800,000 - $75,680 - $247.000 - $185.460

P = -$28,140

So we can see that Mr. Manuel had a loss at the end.

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To obtain the required equation we divide the equation by sin²Ø.

The first six functions are trigonometric, with the domain value being the angle of a right triangle and the range being a number. The angle, expressed in degrees or radians, serves as the domain and the range of the trigonometric function (sometimes known as the "trig function") of f(x) = sin. Like with all other functions, we have the domain and range. In calculus, geometry, and algebra, trigonometric functions are often utilised.

The given equation is:

sin²Ø+cos²Ø=1

To obtain the required equation we divide the equation with sin²Ø:

sin²Ø/sin²Ø +cos²Ø/ sin²Ø = 1/sin²Ø

1 + cot²Ø = csc²Ø

Hence, to obtain the required equation we divide the equation by sin²Ø.

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2 gallons of blue paint are used for the walls, which cover 700 square feet.

What is surface area?

The space occupied by a two-dimensional flat surface is called the area. It is measured in square units. The area occupied by a three-dimensional object by its outer surface is called the surface area.

Let's call the surface area of the trim "T" and the surface area of the walls "W". We know that the ratio of T to W is 1:10, which means that:

T = (1/11) * W

We also know that 2 gallons of blue paint are used for the walls. Let's call the amount of white paint needed for the trim "P" (in pints).

We can use the fact that the total surface area of the room is equal to the surface area of the walls plus the surface area of the trim:

W + T = total surface area

Since T = (1/11) * W, we can substitute and simplify:

W + (1/11) * W = total surface area

(12/11) * W = total surface area

Now we can use the fact that 2 gallons of blue paint are used for the walls to find the surface area of the walls:

2 gallons = 16 pints

2 gallons = W / 350 (since 1 gallon covers 350 square feet)

W = 700 square feet

Now we can use the formula above to find the total surface area of the room:

total surface area = (12/11) * W

total surface area = (12/11) * 700

total surface area = 763.64 square feet

We know that the blue paint covers the walls, so we don't need to worry about that. We only need to find the amount of white paint needed for the trim. Let's call the amount of white paint needed per square foot of trim "p" (in pints). Then the total amount of white paint needed is:

P = p * T

We know that the ratio of the surface area between the trim and the walls is 1:10, so we can use that to find the surface area of the trim:

T = (1/11) * W

T = (1/11) * 700

T = 63.64 square feet

Now we just need to find the amount of white paint needed per square foot of trim. Since the trim is white, we don't need to worry about coverage, so we just need to find the surface area of the trim in square pints:

P = p * T

P = p * 63.64

Finally, we know that 1 gallon of paint is equal to 8 pints, so we can convert the total amount of white paint needed from pints to gallons:

P = p * 63.64

P / 8 = gallons of white paint needed

Putting it all together, we get:

2 gallons of blue paint are used for the walls, which cover 700 square feet.

The total surface area of the room is (12/11) * 700 = 763.64 square feet.

The surface area of the trim is (1/11) * 700 = 63.64 square feet.

The total amount of white paint needed is P = p * 63.64.

The amount of white paint needed in gallons is P / 8.

We don't know the value of p, so we can't solve for P directly. However, we do know that the ratio of the surface area between the trim and the walls is 1:10. This means that the surface area of the trim is 1/11 of the total surface area of the room.

Therefore, we can solve for p as follows:

T = (1/11) * W

63.64 = (1/11) * 700

p = P / T

p = P / 63.64

Hence, 2 gallons of blue paint are used for the walls, which cover 700 square feet.

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Answer: 5 standard glasses

A standard glass of wine is 5 ounces. This is typical for any dry white, red, orange, or rosé wine. A standard bottle is 750mL, or about 25 ounces of wine. So, a normal 750mL bottle has 5 standard glasses of wine.

Answer:

{y,x}={-1,1}

to leave and take

Answer: A) 1/49

Step-by-step explanation:

Since the spinner has seven equal sections numbered 1 through 7, the theoretical probability of landing on any particular number on a single spin is 1/7.

To find the theoretical probability that the spinner lands on 2 and then an odd number, we can multiply the probability of landing on 2 on the first spin by the probability of landing on an odd number on the second spin.

The probability of landing on 2 on the first spin is 1/7, and the probability of landing on an odd number on the second spin is 3/7 (there are three odd numbers among the remaining six sections).

Therefore, the theoretical probability of the spinner landing on 2 and then an odd number is:

(1/7) x (3/7) = 3/49

So the answer is A) 1/49.

Paul practiced playing the piano for one hour on Friday and for the same amount of time on Saturday. Therefore, he practiced for 1 hour on both days.

Time is a concept used to measure the duration or sequence of events, actions or processes, and to organize them into a coherent and meaningful structure. It is a fundamental aspect of the physical universe and an essential element of human experience, enabling us to make sense of our environment and our lives.

The measurement of time is typically based on the movement of objects or the cycles of natural phenomena, such as the rotation of the Earth on its axis, the orbit of the Moon around the Earth, or the vibrations of an atomic oscillator. Time is commonly expressed in units such as seconds, minutes, hours, days, weeks, months, and years.

In addition to its scientific and practical applications, time also plays an important role in culture, language, and philosophy. It has been the subject of extensive debate and speculation throughout history, with questions about its nature, meaning, and relationship to other concepts such as causality, free will, and eternity.

Paul practiced playing the piano for one hour on Friday and for the same amount of time on Saturday. Therefore, he practiced for 1 hour on both days.

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Paul practiced playing the piano for one hour on Friday and for the same amount of time on Saturday. Therefore, he practiced for 1 hour on both days.

Time is a concept used to measure the duration or sequence of events, actions or processes, and to organize them into a coherent and meaningful structure. It is a fundamental aspect of the physical universe and an essential element of human experience, enabling us to make sense of our environment and our lives.

The measurement of time is typically based on the movement of objects or the cycles of natural phenomena, such as the rotation of the Earth on its axis, the orbit of the Moon around the Earth, or the vibrations of an atomic oscillator. Time is commonly expressed in units such as seconds, minutes, hours, days, weeks, months, and years.

In addition to its scientific and practical applications, time also plays an important role in culture, language, and philosophy. It has been the subject of extensive debate and speculation throughout history, with questions about its nature, meaning, and relationship to other concepts such as causality, free will, and eternity.

Paul practiced playing the piano for one hour on Friday and for the same amount of time on Saturday. Therefore, he practiced for 1 hour on both days.

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a) F(x,y,z) = y'z'. b) F(x,y,z) = x'y'z' + x'y'z + xy'z'. c) F(x,y,z) = x'y'z'. d) F(x,y,z) = x'y'z + x'yz' + xy'z' + x'y'z'. These are the sum-of-products expansions of the Boolean function F(x, y, z) for the given conditions.

a) When x = 0, F(x,y,z) equals 1 if and only if yz = 0. This can be expressed as the sum of products: F(x,y,z) = y'z' (read as "not y and not z").

b) When xy = 0, F(x,y,z) equals 1 if and only if either x = 0 or y = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z' + x'y'z + xy'z' (read as "not x and not y and not z" OR "not x and not y and z" OR "x and not y and not z").

c) When x + y = 0, F(x,y,z) equals 1 if and only if x = y = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z' (read as "not x and not y and not z").

d) When xyz = 0, F(x,y,z) equals 1 if and only if x = 0 or y = 0 or z = 0. This can be expressed as the sum of products: F(x,y,z) = x'y'z + x'yz' + xy'z' + x'y'z' (read as "not x and not y and z" OR "not x and y and not z" OR "x and not y and not z" OR "not x and not y and not z").

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The correct standard form of the equation of the parabola is:

[tex]y = -x^2 - 1[/tex].

To find the standard form of the equation of the parabola that passes through the given points (-3, 3) and (1, -1), we can use the general form of the equation of a parabola:

[tex]y = ax^2 + bx + c[/tex] ___________(1)

Substituting the coordinates of the two given points into this equation, we get a system of two equations in three unknowns (a, b, and c):

[tex]3 = 9a - 3b + c[/tex]

[tex]-1 = a + b + c[/tex]

To solve for a, b, and c, we can eliminate one of the variables using subtraction or addition. Subtracting the second equation from the first, we get:

[tex]4 = 8a - 4b[/tex]

Simplifying this equation, we get:

[tex]2 = 4a - 2b[/tex]

Dividing both sides by 2, we get:

[tex]1 = 2a - b[/tex]___________(2)

Now we can substitute this expression for b into one of the earlier equations to eliminate b. Using the first equation, we get:

[tex]3 = 9a - 3(2a - 1) + c[/tex]

Simplifying this equation, we get:

[tex]3 = 6a + c + 3[/tex]

Subtracting 3 from both sides, we get:

[tex]0 = 6a + c[/tex]

Solving for c, we get:

c = -6a __________(3)

Substituting this expression for c into the second equation, we get:

[tex]-1 = a + (2a - 1) - 6a[/tex]

Simplifying this equation, we get:

[tex]-1 = -3a - 1[/tex]

Adding 1 to both sides, we get:

[tex]-3a =0[/tex]

Solving for a, we get:

[tex]a = 0[/tex]

Substituting this value of a into the equation(3) for c, we get:

c = 0

Substituting a = 0 into the equation(2) for b that we found earlier, we get:

[tex]1 = 0 - b[/tex]

Solving for b, we get:

[tex]b = -1[/tex]

Putting the values of a, b and c in (1), we get

[tex]y = -x^2 - 1[/tex]

Therefore, the equation of the parabola that passes through the given points (-3, 3) and (1, -1) is:

[tex]y = -x^2 - 1[/tex]

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Complete question:

A parabola goes through (-3, 3) & (1, -1). A point is below the parabola at (-3, 2). A line above the parabola goes through (-3, 4) & (0, 4). A point on the parabola is labeled (x, y).

What is the correct standard form of the equation of the parabola?

The figure is in the image attached below

There are 792 strings across a,b, and 27,720 in a,b,c.

(a) We must select five slots for a's in an alphabet of "a,b" before filling the remaining spaces with "b's." Hence, the binomial coefficient is what determines how many strings of length 12 that include precisely five as:

C(12,5) = 792

As a result, there are 792 distinct strings of length 12 that include exactly five a's across the letters a, b.

(b) We may use the same method as before for an alphabet consisting of the letters "a,b,c." The first five slots must be filled with a's, followed by three b's, and the final four positions must be filled with c's. The number of strings of length 12 that contain exactly five a's across the letters "a," "b," and "c" is thus given by:

C(12,5) * C(7,3) = 792 * 35 = 27720

Thus, there are 27,720 distinct strings.

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Answer:

Required length is 13 feet

Step-by-step explanation:

[tex]{ \rm{length = \sqrt{ {12}^{2} + {5}^{2} } }} \\ \\ { \rm{length = \sqrt{144 + 25} }} \\ \\ { \rm{length = \sqrt{169} }} \\ \\ { \rm{length = 13 \: feet}}[/tex]

According to one meaning of the phrase, it merely refers to the selling price of something. For instance, a piece of art would be sold for that amount if bids reached a record high of $10 million. Thus, option A is correct

The sale price of bananas this week is 10% off the original price of $1.40 per pound, which means the sale price is:

$1.40 - 10% of $1.40 = $1.26 per pound

To find the total cost of 6 pounds of bananas this week, we can multiply the sale price by the number of pounds:

$1.26 per pound * 6 pounds = $ [tex]7.56[/tex]

Therefore, the total price of 6 pounds of bananas this week at the grocery store is $ [tex]7.56[/tex] .

However, we need to be careful with the answer choices provided. They all differ from $7.56, so we need to double-check our calculations.

If we add a 10% discount to $1.40 per pound, we get:

$1.40 - (10/100)*$1.40 = $1.26 per pound

And the total cost of 6 pounds at $1.26 per pound is:

$ [tex]1.26 \times 6[/tex] = $ [tex]7.56[/tex]

Therefore,  $ [tex]8.19[/tex] is not a possible answer, and the other options are either miscalculated or rounded incorrectly.

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