Susie leaves to go shopping driving 45 miles per hour toward the Happy Shopper Grocery Store. Susie is originally 20 miles due west of the store. Sammie leaves for the Happy Shopper Grocery Store at the same time driving 50 miles per hour on the same road but she is 25 miles due East

If they keep driving and do not stop at the store, how long (in hours) will it take for them to pass on the road? Where relative to the store is this (please state a distance and whether they are East or West of the store). Round the time (in hours) to the nearest thousandth and the distance to the nearest tenth if needed.

Answers

Answer 1

Answer:

Step-by-step explanation:

when they meet, time taken are same.

total distance they travel=20+25=45mile

total speed=45+50=95mile/hour

time=45/95=0.474hour

0.47*45=21.4mile>20mile so they meet at east of store.


Related Questions

Need help will give thanks and brainliest

Answers

Answer:

6in x 4in = 24in

and for the second one

6in x 2in= 12in

Evaluate 2(x+ 1 - 3 when x = 6 O Ο Α. 11 OB. 5 O C. 8 ( D. 10

whoever answers this first will get 25 points ​

Answers

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {A. \:11}}}}}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

[tex]2 \: ( \: x + 1 \: ) - 3[/tex]

Plugging in the value "[tex]x\:=\:6[/tex]" in the above expression, we have

[tex] = 2 \: ( \: 6 + 1 \: ) - 3[/tex]

[tex] = 2 \: ( \: 7 \: ) - 3[/tex]

[tex] = 14 - 3[/tex]

[tex] = 11[/tex]

Note:-

[tex]\sf\red{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]


Why does the congruency of all angles not prove the congruency of two triangles?

Answers

Draw an equilateral triangle with side lengths 5 inches each. Each interior angle is 60 degrees (this is true of any equilateral triangle).

Now draw an equilateral triangle of 10 inches each. The angles will be the same as before. We can see that the triangles are not congruent. Congruent triangles must have the same side lengths, but clearly the second one is larger than the first.

This is an example of why knowing solely the congruency of the angles is not enough to prove the triangles congruent or not. We would need to know something about the sides (whether they are congruent or not) to be able to determine overall triangle congruency.

Answer:

Because even though the angles may be the same, the lengths can be different. In an isosceles triangles, this may be the case.

Step-by-step explanation:

18. Given that g(x) = -(x^2)/4, what is the value of g(+8) ?
F. -16
G. 4
H. -1
J. 4
K. 16

Answers

Answer:

F. -16

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

FunctionsFunction Notation

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle g(x) = -\frac{x^2}{4}[/tex]

Step 2: Evaluate

Substitute in x [Function g(x)]:                                                                         [tex]\displaystyle g(-8) = -\frac{(-8)^2}{4}[/tex]Exponents:                                                                                                        [tex]\displaystyle g(-8) = -\frac{64}{4}[/tex]Divide:                                                                                                               [tex]\displaystyle g(-8) = -16[/tex]

What is another word for zeros?​

Answers

Answer:

nothing

Step-by-step explanation:

Zero is a number without a value so nothing could be another word for it

Another word for zeros is null

If you place a 20 ft ladder 4ft from the base of the wall. How high up will it reach? Round answer to the nearest tenth

Answers

Answer:

h = 19.6 ft

Step-by-step explanation:

Given that,

A 20 ft ladder 4ft from the base of the wall.

The height of the ladder, H = 20 ft

The base distance, b = 4 ft

We need to find the height of the reach. Let it is P.

Using Pythagoras theorem,

[tex]H^2=b^2+P^2\\\\P=\sqrt{H^2-b^2}\\\\P=\sqrt{20^2-4^2}\\\\=19.59\ ft[/tex]

or

P = 19.6 ft

So, the height is 19.6 ft.

Find the value of x
3x+2=23​

Answers

Answer:

x = 7

Step-by-step explanation:

23 - 2 = 21

21 / 3 = 7

x = 7

Answer:

x = 7

Step-by-step explanation:

3x + 2 = 23

3x = 23 - 2

3x = 21

x = 21/3

x = 7

I hope you understand...

This is Right answer...

I’m begging you too pls pls pls pls help! I’d appreciate it so much. This is independent work and I have no clue of what this means so pls comment as fast as u can because according to my teacher this was supposed to be due yesterday and I’m just doing it today. Pls help thank you so so so much! Pls don’t waste time thanks again!

Answers

Answer:

1. 160 min

2. 84 min

3. 5:12 p.m.

4. 6:40 p.m.

5 a 4:44 p.m.

b 7:14 p.m.

pls answer this. its easy but for me nah

Answers

Answer:

1. acute

2. Right

3. maybe acute

4. obtuse

5. acute

6. obtuse

7. straight

8. obtuse

9. acute

10. obtuse

11. acute

12. acute

13. obtuse

14. obtuse

Which expression is equivalent to (-7) (-7) (-7)

Answers

I think the answer is -7x(-7)x(-7)

Solve −1/4x=7 please

Answers

Answer:

x = -28

Step-by-step explanation:

−1/4x=7

Multiply each side by -4 to isolate the variable

-4 *  −1/4x= -4*7

−1/4x=7

the quotient of 55 and x

Answers

Answer:

the should be one more piece of information..

Step-by-step explanation:

may be your answer is

55/x

PLEASE HELP AT YOUR EARLIEST CONVINECE CORRECT ANSWER GET BRAINLIEST AND 50 POINTS PLEASE HELP
The data set below shows the weights of some puppies, in pounds, at a kennel:

10, 11, 12, 12, 13, 13, 14, 15, 15

Which histogram represents the data set?

A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 2, the bar for the second range goes to 4, the bar for the third range goes to 3.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 3, the bar for the second range goes to 4, the bar for the third range goes to 2.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 2, the bar for the second range goes to 3, the bar for the third range goes to 4.
A histogram is shown with title Puppy Weight. On the horizontal axis, the title is Pounds. The title on the vertical axis is Puppies. The range on the horizontal axis is 10 to 11, 12 to 13, and 14 to 15. The values on the vertical axis are from 0 to 6 at intervals of 1. The bar for the first range goes to 4, the bar for the second range goes to 2, the bar for the third range goes to 3.
I ATTACHED A PICTURE OF THE GRAPH ANSWER CHOICES FOR BETTER UNDERSTANDING
Thank you have a wonderful day :) (dont stress over this just try your hardest)

Answers

Answer:

the last graph

Step-by-step explanation:

Answer:

Putting an answer so you can give the other person brainly.

Step-by-step explanation:

Also is it really D) ???

Cause I thought it was A)

En el subnivel basica superior de la unidad manuela cañizares el numero de estudiantes que se alimentan de forma inadecuada ( grasa saturada ) el triple del numero de estudiantes que consumen alimentos saludables menos 8. Si existen 392 estudiantes entre los que consumen alimentos sludables y los que no se alimentan de forma adecuada palntea una ecuacion y determina ¿cuantos estudiantes se alimentan de manera saludable y cuantos estudiantes se alimentan inadecuadamente?

Answers

Answer:

La cantidad de estudiantes que se alimentan de manera saludable es 100 y la cantidad de estudiantes que se alimentan inadecuadamente es 292.

Step-by-step explanation:

Existen 392 estudiantes entre los que consumen alimentos saludables y los que no se alimentan de forma adecuada. Esto es:

Estudiantes que se alimentan adecuadamente + Estudiantes que no se alimentan adecuadamente= 392

El numero de estudiantes que se alimentan de forma inadecuada es el triple del número de estudiantes que consumen alimentos saludables menos 8. El triple de un número se calcula multiplicando el número por 3. Entonces, siendo x la cantidad de estudiantes que se alimentan adecuadamente, la cantidad de estudiantes que no se alimentan adecuadamente se puede calcular como: 3*x - 8

Por lo que:

x + 3*x - 8= 392

Resolviendo:

x + 3*x= 392 + 8

4*x= 400

x= 400÷4

x= 100

Entonces: 3*x - 8= 3*100 -8= 300 - 8= 292

La cantidad de estudiantes que se alimentan de manera saludable es 100 y la cantidad de estudiantes que se alimentan inadecuadamente es 292.

If f(x) = 4x − 6 and g(x) = 6x − 4, what is f · g?

Answers

Answer:

f · g = 24x² - 52x + 24

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Terms/CoefficientsExpand by FOILFunctionsFunction Notation

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 4x - 6

g(x) = 6x - 4

Step 2: Find f · g

Substitute in function values:                                                                          f · g = (4x  - 6)(6x - 4)Expand [FOIL]:                                                                                                  f · g = 24x² - 16x - 36x + 24[Subtraction] Combine like terms:                                                                   f · g = 24x² - 52x + 24

by first considering the angles on line abc show that ac is parallel to df​

Answers

Answer:

so you have to use interior and exterior angles to solve

Mrs. Johnson has 159 chickens that she puts in shelters at night to keep safe. She places 12 chickens in a shelter and continues putting this number of chickens in each shelter until she comes to the last one. How many chickens will Mrs. Johnson put in the last shelter?

Answers

Answer:

3 chickens will Mrs. Johnson put in the last shelter

Step-by-step explanation:

According to the question,

Given,Mrs. Johnson has 159 chickens that she puts in shelters at night to keep safe. She places 12 chickens in a shelter .

thus,If she put 12 chickens in each 13 shelters ( 12×13=156 chickens) adjusted in shelters .

Then, the remaining 159-156 = 3 chicken will Mrs. Johnson put in the last shelter .

the perimeter of one rectangle is 120cm. another rectangle with twice the length amd and one third the width has a perimeter of 170 cm. what are the dimensions of the two rectangles?​

Answers

Answer:

Dimensions of 1st rectangle,

length = 39 cm, width = 21 cm.

Dimensions of the 2nd rectangle,

length = 78 cm, width = 7 cm.

Step-by-step explanation:

Let the dimensions of the 1st rectangle be,

Length = x, width = y

so the dimensions of the 2nd rectangle becomes,

Length = 2x, width = y/3

perimeter of the first rectangle,

2(x+y)=120 --------- (i)

perimeter of the 2nd rectangle,

2(2x+y/3)=170 ---------(ii)

if we solve equation (i) and (ii), we'll get,

x = 39

y = 21

for the other rectangle, 2x = 78, y/3 = 7.

Answered by GAUTHMATH

If the bearing of B from A is 302, what is the bearing of a from B ?​

Answers

Answer:

The bearing of A from B is 122°

pls help I was sick from school and have some much more work to do have a good day yall​

Answers

Answer:

3 hours :)

Step-by-step explanation:

5 km x 3 = 15km

also i hope you can catch up on ur work :)

HELP! ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! Ty ty ty ty tysmmmmm! I hope you have a amazing day!.

Answers

Answer:

(1)1 hour 15 minutes

(2)4:07

(3) 30 minutes

(4) 8:35

Step-by-step explanation:

1.We are given that

Trey and Na'Asia played basketball from 10:30-11:45

We have to find the time  they play basketball.

11:45-10:30

11-10=1 hour

45-30=15 minutes

They played basketball for duration=1 hour 15 minutes

(2)

School left at 3:15

I got home 52 minutes later.

Then, I got home at =3:15+52 minutes

15 minutes+52 minutes=67 minutes

67 minutes=1 hour 7 minutes

Therefore, I got home at 4:07.

(3)

He begins making Macaroni and chees at 6:35

He finished at 7:05.

He cook his food for time =25+5=30 minutes

(4)

Mahkiya and  Madison went to Cheerleading at 7:15

It was over 1 hour and 20 minutes later .

Therefore, time=7:15+1 hour 20 minutes

=(7+1) : (15+20) minutes

=8:35

Hence, it was over at 8:35.

Tasha is planning an expansion of a square flower garden in a city park. If both the length and the width of the original garden are each increased by *3m*, the new total area of the garden will be *49* squared meters. Find the length of each side of the original garden.

Answers

Answer:

4 m

Step-by-step explanation:

Since the flower garden is square :

Both length and width are equal :

Let :

Original side length = x

Increased length = x + 3

Area of square = s² (s = side length)

New area = 49 m²

That is ;

(x + 3)² = 49

Original length, x can be calculated thus ;

Take square root of both sides

x + 3 = √49

x + 3 = 7

x = 7 - 3

x = 4

Hence, original length of each side = 4 m

Members at a gym pay $9 per class plus a one-time $120 membership fee. Non-members pay $15 per class. How many classes would a member have to take to save money compared to taking classes as a non-member?

Pls help I have only a few for mins and I need step by step equation :) pls pls pls

Answers

Answer:

the answer is 45 dollars

Step-by-step explanation:

its because:

Answer:

25 dollors hope this helps

Step-by-step explanation:

If b=3-2s and A= -2s^2+2s+3 find an expression that equals 2b+2A in standard form

Answers

2(3-2s)+2(-2s^2+2s+3)

I think this might be the answer you’re looking for so best of wishes and good luck!!

Using √6241=79, Find the value of √62.41

Answers

Answer:

[tex] \blue{7.9} [/tex]

Step-by-step explanation:

[tex] \sqrt{6241} = 79 [/tex]

[tex] \sqrt{62.41} = [/tex]

[tex] = \sqrt{\dfrac{6241}{100} [/tex]

[tex] = \dfrac{79}{10}[/tex]

[tex] = \blue{7.9} [/tex]

factorise fully the following expression (x2-3x-10)​

Answers

Answer:

(x - 5)(x + 2)

Step-by-step explanation:

The correct answer should be (x-5)(x+2)

The equation a + b + c = 180 describes the sum of the angles in a triangle.
Use this formula to find the values of a, b and c when b = 2a and c = 3a​

Answers

Answer:

a=30 b=60 c=90

Step-by-step explanation:

you replace b with 2a and c with 3a and you get

a+2a+3a=180

6a=180

a=30

from here you replace a with 30 and find b and c

b=2a=2*30=60

c=3a=3*30=90

Choose the function that is a "parent function". O f(x) = x=3 o f(x) = (x - 3)2 O o f(x)= X O f() = x-31​

Answers

Answer:

option D is the correct answer I think so

The pyramid ABCDE has a square base. the pyramid is 20cm high and each sloping edge measures 30cm. calculate the length of the sides the base

Answers

Answer:

44.8 cm

Step-by-step explanation:

Vertical height (h) = EM = 20 cm

Slant height (l) = 30 cm

This two heights form a right angle at the interception at the base. Thus, we have a right angle triangle.

The length of the sides of the base = 2 × the base of the right triangle

✔️Use Pythagorean theorem to find the base of the right triangle formed. Thus: c² = a² + b²

a = base of the triangle

b = h = 20 cm

c = l = 30 cm

Plug in the values

30² = a² + 20²

a² = 30² - 20²

a² = 500

a = √500

a = 22.4 cm

✔️length of the sides of the base = 2 × the base of the right triangle

= 2 × a

= 2 × 22.4

= 44.8 cm

What would be a sound, simple, straightforward way to describe IQR (Interquartile range)

Answers

Answer:

IQR: is the length of the middle 50% of that interval of space

Step-by-step explanation:

In order to find IQR, subtract the third interquartile range - the first interquartile range

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