Taylor is buying a new flashlight. He can choose from red, blue, and silver flashlights that come in both a large size and a small size.
Which list shows all the possible flashlights that Taylor can choose?
A large, small

B. red, blue, silver

c. small red, small blue, large red, large silver

D small red, large red, small blue, large blue, small silver, large silver

Answer:

56

Step-by-step explanation:

Answer:

20x²+5x+5

Step-by-step explanation:

any more help just ask

Answer:

D

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos CBA = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{3}{9}[/tex] , thus

∠ CBA = [tex]cos^{-1}[/tex] ([tex]\frac{3}{9}[/tex] ) ≈ 70.53° ( to 2 dec. places )

Answer:

D; 85 leaves

Step-by-step explanation:

From what we can see, each 4 days there is a growth of an additional 9 leaves

So for the 20th day, we can see 58

The difference between the 20th and 32nd day is 12

The number of 4s we can see here is 12/4 = 3

For each 4, we can count extra 9 leaves

So for the 12, the number of leaves we can count is 3 * 9 = 27

we proceed to add this to 58

That will yield 58 + 27 = 85

It's c Bye bye have a amazing day

Answer:

3. 72= (x)+(x+1)+(x+2) where x= the smallest number

72=3x+3

-3        -3

69=3x

/3   /3

x=23

x+1=24

x+2=25

smallest is 23

4. 48= (x)+(x+2)+(x+4)

48= 3x+6

-6        -6

42=3x

/3    /3

x=14

x+2=16

x+4=18

smallest is 14

5. all erasers were the same cost

25= 4x+5 (x= cost of erasers)

-5         -5

20=4x

/4   /4

x=5

each cost  $5

6. b= boxes

22= b/2 +7

-7            -7

15=b/2

multiply both sides by 2 to cancel the denominator

30=b

30 boxes originally

7. 40= total

8= left

2= balls given to each

x=number of friends

40= 2x+8

-8         -8

32=2x

/2   /2

x=16

she has 16 friends

8.  12= left

a= total allowance

12= (a/2) +4

-4            -4

8= a/2

multiply both sides by 2 to cancel the denominator

a= $16

she had an allowance of $16

9.  4 (2) = amount that her four children recieved

10=amount she took for herself

x= original

x= 4(2) + 10

x= 8 +10

x=18

she started with 18 candies

10. a= age

244= 400 - 2a

-400 -400

-156= -2a

/-2     /-2

a= 78

they are 78 years old

11. c= comic books

36=  c/2 + 16

-16           -16

20=c/2

multiply both sides by 2 to cancel the denominator

c=40

she started with 40 comic books

12.  b= students in buses

472= 9b + 4

-4             -4

468=9b

/9     /9

b= 52

52 students went in each bus

13. h= hats

17= h/2 +5

-5          -5

12=h/2

multiply both sides by 2 to cancel the denominator

h=24

she had 24 hats on monday

14. p= pies the club made

60= (p+4)/5

multiply both sides by 5 to cancel the denominator

300=p+4

-4         -4

p= 296

the club made 296 pies

Step-by-step explanation:

Answer:

it's 4

Step-by-step explanation:

big brainnnnnnnnnn

Answer:

5(2+xy)

Step-by-step explanation:

10+5xy

Factor out 5 from the expression

thus,the answer is 5(2+xy)

The number [tex]\log_9(81)[/tex] means: which exponent we have to give to 9 in order to get 81?

Since [tex]81=9^2[/tex], the answer is 2.

Answer:

Forma exacta:

x= −37/30

Forma decimal:

x=−1.23

Forma numérica mixta:

x=−17/30

Answer:

The table with the missing number

1       5

2     10

5      25

10    50

Step-by-step explanation:

The form of the equivalent ratios is [tex]\frac{a}{b}[/tex] = [tex]\frac{c}{d}[/tex] , where a, b, c, and d are integers

From the given table, we will use the first row in all cases (a = 1 and c = 5)

∵ a = 1 and b = 2

∵ c = 5

→ By using the form of the equivalent ratios above

∴ [tex]\frac{1}{2}[/tex] = [tex]\frac{5}{d}[/tex]

→ By using the cross multiplication

∵ 1 × d = 2 × 5

∴ d = 10

∴ The first missing is 10

∵ a = 1

∵ c = 5 and d = 25

→ By using the form of the equivalent ratios above

∴ [tex]\frac{1}{b}[/tex] = [tex]\frac{5}{25}[/tex]

→ By using the cross multiplication

∵ 5 × b = 1 × 25

∴ 5b = 25

→ Divide both sides by 5

∴ b = 5

∴ The second missing is 5

∵ a = 1 and b = 10

∵ c = 5

→ By using the form of the equivalent ratios above

∴ [tex]\frac{1}{10}[/tex] = [tex]\frac{5}{d}[/tex]

→ By using the cross multiplication

∵ 1 × d = 10 × 5

∴ d = 50

∴ The third missing is 50

∴ The equivalent ratios are [tex]\frac{1}{5}[/tex] = [tex]\frac{2}{10}[/tex] = [tex]\frac{5}{25}[/tex] = [tex]\frac{10}{50}[/tex]

The table with the missing numbers

1       5

2     10

5      25

10    50

Answer:

B

Step-by-step explanation:

Distributing the right side, the equation becomes

6-x=16+4x

Add x to both sides and subract 16

5x=-10

Divide by 5

x=-2

Complete question is;

Arrange the systems of equations that have a single solution in Increasing order of the x-values in their solutions.

1) 2x + y = 10

x - 3y = -2

2) x + 2y = 5

2x + y = 4

3) x + 3y = 5

6x - y = 11

4) 2x + y = 10

-6x - 3y = -2

Answer:

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Step-by-step explanation:

1) 2x + y = 10 - - - (eq 1)

x - 3y = -2 - - - (eq 2)

Multiply eq 1 by 3 to get;

6x + 3y = 30

Add it to eq 2 to get;

7x = 28

x = 28/7

x = 4

2) x + 2y = 5 - - - (eq 1)

2x + y = 4 - - - (eq 2)

Multiply eq 2 by 2 to get;

4x + 2y = 8

Subtract eq 1 from it to get;

3x = 3

x = 3/3

x = 1

3) x + 3y = 5 - - - (eq 1)

6x - y = 11 - - - (eq 2)

Multiply eq 2 by 3 to get;

18x - 3y = 33

Add to eq(1) to get;

19x = 38

x = 38/19

x = 2

4) 2x + y = 10 - - - (eq 1)

-6x - 3y = -2 - - - (eq 2)

Make y the subject in eq 1 to get;

y = 10 - 2x

Put in eq (2);

-6x - 3(10 - 2x) = -2

-6x - 30 + 6x = -2

0 = 0

Thus,no solution exists.

Arranging the systems in increasing value of x gives;

System 2, system 3, system 1

Answer:

The person above me is correct.

Step-by-step explanation:

Answer:

food, video games, sports, naps, music  

Step-by-step explanation:

Answer:

2 sq rt 33

Step-by-step explanation:

1st step:  subtract one, each side

(radical 2/3)r = 22

2nd step:  set up a proportion

(radical 2/3)r = 22

3rd step:  cross-multiply

radical 2*r = 66

4th step:  solve for 'r'

r = 66 / radical 2

5th step:  rationalize the denominator

multiply numerator and denominator by radical 2

6th step:  simplify

(66[tex]\sqrt{2}[/tex]) / 2 = 33 [tex]\sqrt{2}[/tex]

Answer:

There are no real solutions to this equation

Step-by-step explanation:

Answer:

bob

Step-by-step explanation:

ask your teacher

Answer:

The answer is A

Step-by-step explanation:

Count all the x's. They add up to 8.

Hope this helped.

Answer:

A. There were 8 people who rode in the bicycle race.

Step-by-step explanation:

The line plot in the picture shows the distance in miles raced by Sophie's friends.

It's required to select one of the following options:

A. There were 8 people who rode in the bicycle race.

Since each x represents one person, and there are 8 x's, this statement is true.

B. More people rode 3/4 of a mile than 1/4 of a mile. There is only one x in 3/4 and 3 x's in 1/4. This is false

C. This option is false also, there were 5 people who rode 1/4 of a mile or 2/4 of a mile.

D. There were 2 people who rode 1 mile. False

Answer:

a true

Step-by-step explanation:

hope this helps please give me brainliest

I hope this helps you.

Answer:

I. The point (6, -2) is not a solution for the given equation

II. The slope of the line going through (-4, 1) and (-7, -5) is 2

III. The slope of the line x = -7 is ∞

IV The slope of the line y = -6 is 0

V. The coordinate of the x-intercept is (12.5, 0)

The coordinate of the y-intercept is (0, 25)

VI. The equation of the line is y = 17·x + 59

Step-by-step explanation:

I. The given equation is -4·x - 5·y = 32

The given point = (6, -2)

Therefore;

The x-coordinate value of the point = 6

The y-coordinate value of the point = -2

Plugging in the x and y-coordinate values into the given equation gives;

-4 × (6) - 5 × (-2) = -14 which does not correspond to the given equation, therefore, the point (6, -2) is not a solution for the given equation;

We can also show, by making y the subject of the formula of the given equation, weather the point is a solution of the given equation as follows;

-4·x - 5·y = 32

y = (-4/5)·x - 32/5

For x = -2, we have;

y = (-4/5) × (-2) - 32/5 = - 4.8

Therefore, the point (6, -2) where y = 6 when x = -2 is not a solution of -4·x - 5·y = 32

II. The slope of a straight line, given two points on the line is given as follows;

[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Where the two points are (-4, 1), and (-7, -5), we have;

x₁ = -4, y₁ = 1, x₂ = -7, and y₂ = -5

[tex]Slope, \, m =\dfrac{-5-1}{-7-(-4)} =2[/tex]

The slope, m, of the line going through (-4, 1) and (-7, -5) is m = 2

III. The slope of the line x = -7 = ∞ because, the difference in the x-value which is the denominator of the slope equation = 0 for all differences in the y-coordinate values

IV The slope of the line y = -6 is 0 because, the difference in the y-values which is the numerator of the slope equation = 0 for all differences in the x-coordinate values

V. The x and y-intercept of an equation is found by finding the values of the variable, x or y, in the equation, when the other variable, y or x is equal to zero respectively, which is given as follows;

The given equation is y = -2·x + 25

When y = 0, we have the x-intercept as 0 = -2·x + 25

∴ 2·x = 25

x = 25/2 = 12.5

Therefore, the coordinate of the x-intercept is (12.5, 0)

When x = 0, we have the x-intercept as y = -2·x + 25 = -2 × 0 + 25 = 25

The coordinate of the y-intercept is (0, 25)

VI. The general equation of a straight line is y = m·x + c

Where;

m = The slope of the line

c = The y-intercept

For the  line that goes through the points (-3, 8) and (-4, -9), we have;

[tex]The \ slope, \, m =\dfrac{-9-8}{-4- (-3)} = \dfrac{-9-8}{-4+3} = 17[/tex]

The equation in point and slope form is y - 8 = 17 × (x - (-3))

∴ y  = 17·x + 51 + 8 = 17·x + 59

The equation of the line is y = 17·x + 59

Answer:

40 + 7 = 47.    47 x 8  = 376

8 x 40 = 320      8 x 7 = 56

320 + 56 = 376

They equal the same.

Step-by-step explanation:

8x(40+7)=(8x40)+(8x7)

Answer:

1 Expand by distributing terms.

10-80x+710−80x+7

2 Collect like terms.

-80x+(10+7)−80x+(10+7)

3 Simplify.

-80x+17−80x+17

Step-by-step explanation:

Answer:

a(31) =125

Step-by-step explanation:

d=9-5=13-9=4

then it is an arithmetic sequence

a(n) = a1 +(n-1)d

a(n) = 5 +(n-1)4

a(31) = 5 +(31-1)4

      =125

hope this helps

Step-by-step explanation:

Gradient of line AB = 6/2 = 3.

Gradient of line CD = 10/2 = 5.

Gradient of line AD = 12/8 = 1.5.

Answer:

1) -13/8

Step-by-step explanation:

decimal form is -1.625

Answer: 1/2x+2

Step-by-step explanation:

I just simplified

Answer:

the risk free rate of return is 4.86%

Step-by-step explanation:

The computation of the risk free rate is shown below;

As we know that

Expected return = Risk free rate of return + Beta × (Market rate of return - risk free rate of return)

10.5% = Risk free rate of return + 1.55 × (8.5% - Risk free rate of return)

10.5% = Risk free rate of return + 13.175% - 1.55 Risk free rate of return

10.5% - 13.175% = -0.55 risk free rate of return

-2.675% = -0.55 risk free rate of return

So, the risk free rate of return is

= 2.675% ÷ 0.55

= 4.86%

Hence, the risk free rate of return is 4.86%

Answer:

$100,000

Step-by-step explanation:

Let the total income of the store = [tex]\$x[/tex]

Total spends on salaries = [tex]\frac{1}{4}[/tex] of total income

Total spends on advertising = [tex]\frac{1}{6}[/tex] of total income

Also, we are given that:

Total money paid as salaries = $150,000

To find:

Total spends on advertising ?

Solution:

As per question statement, we can write the following equation:

[tex]\dfrac{1}{4}x =\$150000\\\Rightarrow x =\$150000\times 4\\\Rightarrow x = \$600000[/tex]

Now, as per the given statement, total spends on advertising are:

[tex]\dfrac{1}{6}x =\dfrac{1}{6}\times 600000 = \bold{\$100,000 }[/tex]

Therefore, the answer is $100,000