a) Type of research hypothesis is tested in this study is causal RH
b) Type of design is being used in this study is non-experiment
c) Type of design is being used in this study is within-subjects design
d) No, the design used in this study cannot provide an appropriate test of the research hypothesis.
(a) The research hypothesis being tested in this study is a causal hypothesis. The company president believes that the type of music listened to can predict production line output.
(b) The type of design being used in this study is a non-experiment. The researcher is not manipulating the type of music listened to; instead, the plant is naturally exposed to either country or classical music.
(c) The design being used in this study is within-subjects design, as the same group of individuals is exposed to both types of music. It is also a repeated measures design, as the same individuals are measured twice (once under country music and once under classical music).
(d) No, the design used in this study cannot provide an appropriate test of the research hypothesis. Since the researcher is not manipulating the type of music listened to, it is possible that other variables could be affecting the production line output, such as different environmental conditions on each week, or different levels of motivation.
Therefore, it is difficult to determine if any differences in production line output are actually due to the type of music listened to. A true experiment with random assignment of workers to the two music conditions would provide a better test of the research hypothesis.
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A pyramid has a triangular base with side lengths 20, 20, and 24. The three edges of the pyramid from the three corners of the base to the fourth vertex of the pyramid all have length 25. The volume of the pyramid is myn, where m and n are positive integers, and n is not divisible by the square of any prime. Find m + n. n
The volume of the pyramid is mn, where m and n are positive integers, and n is not divisible by the square of any prime then m+n is 803.
Let the triangular base be ΔABC with
AB = 24, Altitude to the side AB is 16
Area of ΔABC is 24x16/2 = 192
Let fourth vertex of Tetrahedron be P and let the midpoint of AB be M
ΔABC will pass through circumcenter of Δ ABC which we will call O
OM + OC = 16
OM = d
d = √d² + 144 = 16
2d² + 2d√d² + 144 = 112
2d(d + √d² + 144) = 112
d = 7/2
Now, we find √d² + 144 = 25/2
Theorem , on the triangle AOP, BOP, COP
25² = h² + (25/2)²
625 = h² + 625/4
h = 25√3/2
Finally the formula for volume of Pyramid from
V = Ah/3
= 192 (25√3/2) / 3
= 800√3
m + n = 800 + 3
m + n = 803
Therefore, the value of m+n is 803.
The volume of a aggregate depends upon the type of aggregate’s base, whether it's a triangle, square or cube. A aggregate is a polyhedron figure which has only one base.
The base of the aggregate is a poly sided figure. Hence, the formula to find not only volume but also the face area of a aggregate will be grounded on the structure of its base and height of the aggregate.
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Ruby read 7 books in 14 months. What was her rate of reading in books per month?
Short Answer:
Ruby's rate if reading the books is:
2 months per book.
Long Answer:
If you look at it this way, two months per book means that by the time 14 months come you should have 7 books read.
Easy check to verify:
7 (books) X( mutltiply) 2(# of books) = 14 (total of months) - This shows that the number lead back to the original numbers
Hope this helps :)
the walls are fixed to the ground which wall is the most stable when the same lateral force is applied
The wall that is most stable when the same lateral force is applied is the wall that is anchored to the ground with the most support.
The wall that is anchored to the ground with the most support is the one that is most stable when the same lateral force is applied. This could include walls that are reinforced with steel beams or are built with heavier materials such as brick or concrete.
Lateral force is a force that acts perpendicular to the direction of motion of an object. It is usually caused by friction, gravity, or air resistance. The most common example of a lateral force is the force of friction between two objects when they are in contact.
This force can cause an object to move in a different direction than the one it was initially moving in. Lateral force can also cause an object to rotate or change its direction of motion entirely.
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everybody help i just need to pass today mwa
Answer:
20
Step-by-step explanation:
Easiest way to solve is to consider the formula for the area of the trapezoid, which is 0.5h(a+b), where h is the altitude and a and b are the two bases.
Here we know the area, the altitude and one base so let's sub these in to find the other base:
92=0.5*8*(3+b)
92=4(3+b)
23=4+b
b=20
Please help me,this is proportionality theorems
Answer:
Below
Step-by-step explanation:
Line DE grows to 5 as you move to the midpoints of BC and AC....
go the the other half of the way to the end AB and it grows another 5 for a total of 10
What is the correct answer
C = 45 + 0.25t. The 45 represents the baseline amount that she is charged per month. The t represents each additional text, and the 0.25 represents how much she is charged for each additional text.
Find an autonomous differential equation with all of the following properties:equilibrium solutions at y=0 and y=3,y' > 0 for 0 y' < 0 for -inf < y < 0 and 3 < y < infdy/dx =
An autonomous differential equation with equilibrium solutions at y=0 and y=3, and y' > 0 for 0 < y < 3 and y' < 0 for -inf < y < 0 and 3 < y < inf is dy/dx = 3y(1-y).
An autonomous differential equation is a type of ordinary differential equation that does not depend on any other variable but time. It has a single variable, usually denoted as y, and a single independent variable, usually denoted as t or x. An autonomous differential equation with equilibrium solutions at y=0 and y=3, and y' > 0 for 0 < y < 3 and y' < 0 for -inf < y < 0 and 3 < y < inf is dy/dx = 3y(1-y). This equation will have two equilibrium solutions at y=0 and y=3. The derivative of the equation, y’, is greater than 0 for 0 < y < 3, which means that the equation is increasing in this range. The derivative of the equation is less than 0 for -inf < y < 0 and 3 < y < inf, which means that the equation is decreasing in this range. This equation is a type of logistic equation and is often used to model population growth. It is also used to describe other phenomena such as the spread of an epidemic or the number of species in an ecosystem. Using the initial conditions y(0) = 2 and y(1) = 3, we can calculate the values of y at other time points using the equation dy/dx = 3y(1-y). At t=0.5, the value of y is y(0.5) = 2.5; at t=1.5, the value of y is y(1.5) = 2.875; and at t=2.5, the value of y is y(2.5) = 2.9375.
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Let f be a function defined and continuous on the closed interval [a,b]. If f has a relative maximum at c and a < c < b, which of the following statements must be true? f(c) exists. If f'(c) exists, then f'(c) = 0. If f"(c) exists, then f"(c) LE 0. II only III only I and II only I and III only II and III only
Given that function f is defined and continuous on the closed interval [a,b], the correct statements are:
f(c) existsif f'(c) exists, then f'(c) = 0 (C. I and II only)From the case we know that:
function f is on the closed interval [a,b]
c = relative maximum
A function reach its relative maximum when its first derivative function is equal to zero (0). Since c is the relative maximum of function f, then:
f'(c) = 0
The third statement is wrong because when c is the relative maximum point, then its second derivative function must be lower than zero (0), or:
f''(c) < 0
When the second derivative function is greater than zero (0), it indicates that the given critical point is the relative minimum.
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david buys fruits and vegetables wholesale and retails them at davids produce. one of the more difficult decisions is the amount of bananas to buy. let us make some simplifying assumptions, and assume that david purchases bananas once a week at 10 cents per pound and retails them at 30 cents per pound during the week. bananas that are more than a week old are too ripe and are sold for 5 cents per pound. suppose the demand for the good bananas follows the same distribution as d given in the first question. assume that david buys 8 pounds of banana every week.
The expected profit per week for David is $4.25, with a standard deviation of $4.28.
Based on the given information, David purchases 8 pounds of bananas every week at 10 cents per pound, which costs $0.80 per week. The demand for good bananas follows the same distribution as d given in the first question. Using the probabilities given in d, we can calculate the expected revenue from selling the bananas. The expected revenue from selling good bananas is (0.30.6 + 0.050.3) * 8 = $1.56. The expected revenue from selling bad bananas is 0.05 * 8 = $0.40.
Thus, the expected total revenue is $1.96. The expected profit is the difference between the total revenue and the cost of purchasing the bananas, which is $1.16. The standard deviation of the profit can be calculated using the formula for the standard deviation of a linear combination of random variables, which gives a standard deviation of $4.28.
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Use the Quotient Rule to find the derivative of the given function Simplify your answers. 31. f(x) =x^4 +1/x^3 32. f(x) = x^5 -1/x^2 33. f(x) = x+1/x-134. f(x) = x - 1/x + 1 35. f(x) = 3x + 1/2+x36. f(x) = x+1/ 2x^2 +1 37. f(t) = t^2 -1/t^2 +1 38. f(t) = t^2 + 1/ t^2 - 1
By the quotient rule the derivative of all functions can be found in an easy way,
(1) [tex]f'(x)=\frac{x^6+128x^3-3x^2}{(x^3+32)^2}[/tex]
(2) [tex]f'(x)=\frac{5}{(2+x)^2}[/tex]
(3) [tex]f'(t)=\frac{4t}{(t^2+1)^2}[/tex]
The Quotient Rule in calculus is a technique for figuring out a function's derivative (differentiation) as the ratio of two differentiable functions. It is a formal rule applied to issues involving differentiation where one function is split in half by another function. The definition of the limit of the derivative is followed by the quotient rule. Keep in mind that the bottom function is where the quotient rule starts and where it finishes.
The quotient rule is similar to the product rule. A Quotient Rule is stated as the ratio of the quantity of the denominator times the derivative of the numerator function minus the numerator times the derivative of the denominator function to the square of the denominator function. In short, the quotient rule is a way of differentiating the division of functions or the quotients
We have the functions
(1) [tex]f(x)=\frac{x^4+1}{x^3+32}[/tex]
derivative with respect to x by the quotient rule.
[tex]f'(x)=\frac{(x^3+32)(4x^3)-(x^4+1)(3x^2)}{(x^3+32)^2}\\\\f'(x)=\frac{4x^6+128x^3-3x^6-3x^2}{(x^3+32)^2}\\\\f'(x)=\frac{x^6+128x^3-3x^2}{(x^3+32)^2}[/tex]
2) derivative with respect to x of the below function
[tex]f(x)=\frac{3x+1}{2+x}\\\\f'(x)=\frac{(x+2)(3)-((3x+1))}{(2+x)^2}\\\\f'(x)=\frac{5}{(2+x)^2}[/tex]
3)
[tex]f(t)=\frac{t^2-1}{t^2+1}[/tex]
derivative with respect to t,
[tex]f'(t)=\frac{(t^2+1)(2t)-(t^2-1)(2t)}{(t^2+1)}\\\\f'(t)=(2t^3+2t-2t^3+2t)/(t^2+1)^2\\\\f'(t)=4t/(t^2+1)^2[/tex]
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frank invests $2,500 in an account that has an annual interest rate of 5.4% compounded continuously. hannah invests $3,000 in an account that has an annual interest rate of 3.2% compounded quarterly. which of the following statements is true when comparing the amount of money in the two accounts after 10 years?
The statement that is true when comparing the two accounts after 10 years is: A: "Hannah's account has more money than Frank's account".
To compare the amount of money in the two accounts after 10 years, we can use the formula for continuous compound interest:
A = Pe^(rt)
where A is the amount of money in the account after t years, P is the principal (initial amount), r is the annual interest rate (expressed as a decimal), and e is the mathematical constant approximately equal to 2.71828.
For Frank's account, we have:
A = 2500e^(0.05410) = 4244.96 dollars (rounded to the nearest cent)
For Hannah's account, we have to take into account the quarterly compounding. The formula for quarterly compound interest is:
A = P(1 + r/n)^(nt)
where n is the number of compounding periods per year (4 for quarterly compounding), and t is the time in years. Thus, we have:
A = 3000*(1 + 0.032/4)^(4*10) = 4412.09 dollars (rounded to the nearest cent)
Therefore, the amount of money in Hannah's account after 10 years is greater than the amount in Frank's account.
"
Complete question
frank invests $2,500 in an account that has an annual interest rate of 5.4% compounded continuously. hannah invests $3,000 in an account that has an annual interest rate of 3.2% compounded quarterly. which of the following statements is true when comparing the amount of money in the two accounts after 10 years?
A: Hannah's account has more money than Frank's account
B: : Frank's account has more money than Hannah's account
"
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find the volume of a pyramid with height 28 and rectangular base with dimensions 2 and 7 using integration
The volume of a pyramid can be calculated using integration is [tex]V = (1/3)(7*282 - 2*282) = 224 cubic units..[/tex]
The formula for the volume of a pyramid with a rectangular base with dimensions l and w, and height h is given by V = (lwh)/3. Using this formula, the volume of a pyramid with a rectangular base with dimensions 2 and 7 and height 28 can be calculated to be 224 cubic units.
To calculate this using integration, we can use the formula V = (1/3)∫b a y2dx, where a and b are the lower and upper limits of the rectangular base, and y is the height of the pyramid. In this case, a = 2, b = 7, and y = 28. Therefore, V = (1/3)(7*282 - 2*282) = 224 cubic units.
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state the domain and range of the following function. describe the transformations to the basic function. then, write the equations of each of the function.
The equation for line 1 is y = x+6 and equation for line 2 is y= -x-4. The domain and range is as follows,
y = x+6 {(x,y)| x≤ -5 , y≤ 1}
y= -x-4 {(x,y) x≥-5, y≤1}
The line 1 passes through points (-6,0) and (-5,1).
Equation for a line is y= Ax+B
Using two points we can formulate the following equations
-6A+B =0
-5A+B =1
Subtracting the two equations,
-A = -1, so A= 1
-6A+B = 0
-6 ×1 + B = 0
B= 6
So the equation for the line by substituting values of A and B is
y= x+6
The domain is all values ≤-5 and range is all values ≤1
The line 2 passes through (0,-4) and ( -5,1)
Formulating equations using points
B= -4
-5A+B =1
A = -1
Substituting in equation for line 2
y = -x-4
The domain is all values ≥ 5 and range is all values ≤1.
So the equation, domain and range of line 1 is y = x+6 {(x,y)| x≤ -5 , y≤ 1} and for line 2 is y= -x-4 {(x,y) x≥-5, y≤1}
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The complete question is included as image
Evaluate 3y - x if x = 4 and y = 3
3(3)-4 = 5
Hope this helped
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.7 and P(B) = 0.4.
A. Could it be the case that P(A ∩ B) = 0.5? Pick one:
i. Yes, this is possible. Since B is contained in the event A ∩ B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
ii. Yes, this is possible. Since A ∩ B is contained in the event B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
iii. No, this is not possible. Since B is equal to A ∩ B, it must be the case that P(A ∩ B) = P(B). However 0.5 > 0.4 violates this requirement.
iiii. No, this is not possible. Since B is contained in the event A ∩ B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
v. No, this is not possible. Since A ∩ B is contained in the event B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
A) No, P(A ∩ B) = 0.5, is not possible. In this case that P(A ∩ B) ≤ P(B). So, the correct choice is option (iii).
B) Probability that the selected student has at least one of these two types of cards is 0.8.
The probability of an event has different properties. If two events take place at the simultaneously, then we calculate their joint probabilities. The individual probabilities are called the marginal probabilities. Let us consider two events :
A : Event that the selected student has Visa card
B : Event that selected student has Master Card
Probability of occurrence of event A, P(A) =0.7
Probability of occurrence of event B, P(B) =0.4
A) P(A ∩ B) = 0.5 ,
No, this is not possible. Since, B is contain in the event (A ∩ B), it must be the case that
P( A ∩ B)≤ P(B). However, 0.5 > 0.4, violate this requirement. So, correct choice is option (iii).
B) Now, it is specific that the probability A and B is 0.3. The probability that the selected student has atleast one of these two types of cards will be, P(A∪B)
= P(A) + P(B) − P(A∩B)
= 0.7 + 0.4v− 0.3 = 0.8
So the probability is 0.8.
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Complete question:
Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.7 and P(B) = 0.4.
A) Could it be the case that P(A ∩ B) = 0.5? Pick one:
i. Yes, this is possible. Since B is contained in the event A ∩ B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
ii. Yes, this is possible. Since A ∩ B is contained in the event B, it must be the case that P(B) ≤ P(A ∩ B) and 0.5 > 0.4 does not violate this requirement.
iii. No, this is not possible. Since B is equal to A ∩ B, it must be the case that P(A ∩ B) = P(B). However 0.5 > 0.4 violates this requirement.
iiii. No, this is not possible. Since B is contained in the event A ∩ B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
v) No, this is not possible. Since A ∩ B is contained in the event B, it must be the case that P(A ∩ B) ≤ P(B). However 0.5 > 0.4 violates this requirement.
B) From now on, suppose that P(A ∩ B)
= 0.3. What is the probability that the selected student has at least one of these two types of cards?
Select the correct answer.
Select the largest decimal.
1,238.308
1,238.83
1,283.083
1,233.38
1,283.803
Answer:1,283.803
Step-by-step explanation:
Monroe is tracking the circular path of a satellite in the sky using his telescope. He determined that the satellite has formed an arc of 32° in one hour. The satellite is 36,000 km above the earth's surface. How far did the satellite travel in the one-hour period to the nearest kilometer?
Answer Choices:
1) 1,400 km
2) 10,053 km
3)20,106 km
4)72,382 km
To calculate the distance traveled by the satellite, we need to find the circumference of the circle it traces in the sky. The circumference can be found using the formula:
C = 2 * π * r
where r is the radius of the circle (i.e., the distance from the center of the earth to the satellite), and π is pi, approximately equal to 3.14.
r = 36,000 km
C = 2 * π * 36,000 km
C = 72,000 * π km
Next, we need to find what fraction of the circumference the satellite has traveled in one hour. This is given by the fraction of the total circle the satellite has traced, which is equal to the angle it has formed divided by 360°.
fraction = 32° / 360°
Finally, we can multiply the circumference by the fraction to find the distance traveled by the satellite:
distance = C * fraction
distance = 72,000 * π * 32° / 360° km
Rounding the result to the nearest kilometer, the satellite has traveled approximately:
distance = 73,382 km
So, the satellite traveled approximately 73,382 km in one hour.
Consider two connected tanks shown below. Tank 1 initially contains 300 L of brine (with unknown concentration), while tank 2 initially contains 300 L of pure water. Pure water flows into tank 1 at the rate of 500 L/hr into tank 1. The mixture in tank 1 flows into tank 2 at the rate of 500 L/hr, and the mixture in tank 2 leaves tank 2 at the same rate.
Describe how the amount of salt in tank 1 and tank 2 change over time.
Let x1(t) and x2(t) be the mass (in oz) of salt in tank 1 and tank 2, respectively. Solve x1(t) and x2(t).
Determine when the amount of salt in tank 2 reaches its maximum. (Note that the answer does not depend on the initial concentration in tank 1!)
We have also determined when the amount of salt in tank 2 reaches its maximum, which is when[tex]e^{t/180} = 6, \text{or}[/tex] t ≈ 1,080 minutes.
A mixture is a combination of two or more substances that are physically intermingled with each other, but not chemically bonded.
To determine when the amount of salt in tank 2 reaches its maximum, we can set the derivative of x2(t) with respect to time to zero and solve for t.
[tex]dx_2(t)/dt = (x_1(t)/500) * 500 * (1/180) * e^{t/180} - (x_2(t)/300) * 500 * (1/180) * e^{t/180} = 0[/tex]
Simplifying, we get:
[tex]x_1(t) * e^{-t/180} - (300/5) = x_2(t)[/tex]
Substituting the expression for x2(t) in terms of x1(t), we get:
[tex]x_1(t) * e^{-t/180} - (300/5) = (x_1(t) - (300/5)) * e^{t/18} + (300/5)[/tex]
Simplifying, we get:
[tex]2x_1(t) * e^{-t/180} = (600/5) * e^{t/180}[/tex]
Dividing by [tex]e^{t/180}[/tex] on both sides, we get:
[tex]2x_1(t) * e^{-t/180 - t/180} = (600/5)[/tex]
Simplifying, we get:
[tex]x_1(t) = (300/5) * e^{t/180}[/tex]
Substituting this value of x₁(t) in the expression for x₂(t), we get:
[tex]x_2(t) = (300/5) * (e^{t/180} - 1)[/tex]
This expression for x₂(t) gives us the amount of salt in tank 2 at any time t, and we can see that it increases with time until it reaches its maximum value of 300 oz. This occurs when [tex]e^{t/180}=6,[/tex], or t ≈ 1,080 minutes (or 18 hours), which is independent of the initial concentration in tank 1.
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2.
Solve for x. Round to one
decimal place (nearest
tenth).
11
X
45°
5 is the measure of the value of x from the diagram
Solving triangles using trigonometry identityThe given diagram is a triangle with the following parameters
Opposite = 5
Adjacent = x
Using the trigonometry identity
tan theta = opp/adj
tan45 = 5/x
x = 5/tan45
x = 5/1
x = 5
Hence the measure of the value of x is 5.
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What informational text is an expression of an opinion on a subject?
A. Autobiography
B. Essay
C. Biography
D. Editorial
The informational text that is an expression of an opinion on a subject is an essay. That is option B
What is an essay?An essay is defined as the piece of writing or a literary write up that is used to represent the writer's opinion about a subject that is under study.
There are different types of easy written that includes the following:
argumentative essay,expository essay,narrative essay, and descriptive essay.Therefore, easy is an informational text that is an expression of an opinion on a subject.
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What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number
The difference between the highest guess and the lowest guess, in the whole number, is 120.
What is subtraction?Subtraction is a mathematical operation. Which is used to remove terms or objects in the expression.
Given:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
Here, the highest guess is 240.
And the lowest guess is 120.
The difference between the highest guess and the lowest guess,
= 240 - 120
= 120
120 is a whole number.
Therefore, 120 is the required number.
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The complete question:
A table that shows the relationship between the guessed amount and the number of weeks.
Week Amount
1 120
2 140
3 160
4 240
What was the difference between the highest guess and the lowest guess? Write your answer as a fraction, mixed number, or whole number
I need answer now 20 point d
a
if you flip it the c point will be the opposite of the original coordinates
NEED HELP FAST I WILL GIVE THE BRAINLIEST AND 15 pts
The length of PJ in the right triangle PNJ is determined as 24 inches.
How to calculate the length of PJ?The length of PJ is calculated by applying Pythagoras theorem as follows;
PJ² = PN² + NJ²
The given parameters;
NJ = 10 in
The length of PN = The length of PL = The length of PM
PL = 3x + 4
PM = 6x - 14
3x + 4 = 6x - 14
3x - 6x = -14 - 4
-3x = -18
x = 18/3
x = 6
Length PN = 3x + 4
PN = 3(6) + 4
PN = 22
Length PJ is calculated as follows;
PJ² = PN² + NJ²
PJ² = 22² + 10²
PJ² = 584
PJ = √584
PJ = 24.17 in
PJ ≈ 24 in
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Write the expression -13y+7-11-4y as a um
-13y + 7 - 11 - 4y can be written as -17y - 11.
What is expression?Expression is a way of conveying emotions, thoughts, or ideas through verbal or nonverbal means. It is often used to communicate an individual's feelings, beliefs, or opinions, and can be expressed through language, art, music, dance, and other forms of communication. Expression can be used to convey a wide range of emotions, from joy and excitement to anger and sorrow. Expression is an essential part of communication, and without it, we would not be able to effectively convey our thoughts, feelings, and desires. The way we express ourselves can also be a reflection of our personality and can give people an insight into who we are. Expression is also important for self-expression, as it allows us to explore our own thoughts and emotions, and express them in a way that may be more comfortable for us.
This can further be written as -17y × (-1) - 11. Therefore, the expression can be written as a multiplication as -17y × (-1) - 11.
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A set of scores ranges from a high of X = 96 to a low of X = 27. If
these scores are placed in a grouped frequency distribution table
with an interval width of 10 points, the top interval in the table
would be
Answer: 90-99
Step-by-step explanation:
The top interval in the table would be 90-99. This is because the highest score (X = 96) falls within this interval, and the interval width is 10 points, which means that all scores between 90 and 99 would be included in this interval.
Determine whether or not each of the following continuous-time signals is periodic. If the signal is periodic, determine its fundamental period. (a) x(t) 3 cos(4t (c) x(t) = [cos(2t--)]2 (d) x(t) &'{cos(4m)u(t)} + 풀) (b) x(t) e/m-I)
The signal, (a) x(t) = 3cos(4t) is periodic with period T = pi/2. To see this, we can compute:
x (t + T) = 3cos (4(t + pi/2)) = 3cos (4t + 2pi) = 3cos(4t)
which shows that the signal repeats itself every T = pi/2 seconds.
[tex](b) \times (t) = e^{( - t)} [/tex]
This signal is not periodic.
[tex]e^{(-t)} = e^{(-(t+T))} [/tex]
for all t.
However, this is not possible since e^(-t) approaches 0 as t approaches infinity. Therefore, the signal is not periodic.
[tex](c) \times (t) = [cos (2t - \frac{\pi}{3}] ^2[/tex]
This signal is periodic with period T = pi. To see this, we can compute:
[tex]x (t + T) = [cos (2(t + \pi) - \pi/3)] ^2 = [cos (2t + 5\pi/3)] ^2 = [cos (2t - pi/3)] ^2 = x(t) \\
(d) x(t) = cos(4t) u(t) + sin(4t) u(-t)[/tex]
This signal is not periodic. To see this, suppose that there exists a period T such that x(t) = x (t + T) for all t. Then we must have:
cos(4t) u(t) + sin(4t) u(-t) = cos(4(t+T)) u(t+T) + sin(4(t+T)) u(-(t+T)) for all t.
However, this is not possible since the two terms on the left-hand side have different signs for t < 0, whereas the two terms on the right-hand side have the same sign for t < -T.
Therefore, the signal is not periodic.
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PLEASE HELP DUE ASAP!
The graph of the function f(x) = 3√(3 - x) is at the end of the answer.
How to graph the function?We want to graph the function f(x) = 3√(3 - x)
To do so, we need to find some points on that line, to find the points we need to evaluate the function in some values of x
if x = -1
f(-1) = 3√(3 + 1) = 3*2 = 6
if x = 3
f(3) = 3√(3 - 3) = 3*0 = 0
if x = -6
f(-6) = 3*√(3 + 6) = 3*3 = 9
if x = -13
f(-13) = 3*√(3 + 13) = 3*4 = 12
Then the points are (-1, 6), (3, 0), (-6, 9), (-13, 12)
Now we can just graph these 4 points and connect them with a curve, the graph of the function is below.
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Given the diagram find the measurement of AED
A.110°
B.116°
C.118°
D.123°
Note that the measure of ∠AED is 123°. (Option D) This is arrived at using the properties of a 4 sided polygon and angles on a straight light postulate.
What is a polygon?A polygon is a planar figure characterized by a limited number of straight line segments joined to create a closed polygonal chain in geometry. A polygon is defined as a bounded planar region, a bounding circuit, or both. A polygonal circuit's segments are known as its edges or sides.
We know that the sum of angles in a polygon is 360°
Since ∠ABD = 46°
That is Sum of Angles in ΔBDC Less (79+57) =
180 - (101)
= 46°
And ∠EDB = 180-79 (angles on a straight line)
⇒ ∠EDB = 101°
And ∠BAE = 90° (Given)
Thus,
∠AED = 360 - 90-46-101; Thus
∠AED = 123°
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Set up the integral that uses the method of disks/washers to find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified lines. y = 3 root x, y = 3x A) About the y-axisB) About the line y=3
Answer:
See below for answers
Step-by-step explanation:
Part A
[tex]\displaystyle V=\pi\int\limits^d_c {(R^2-r^2)} \, dy\\=\pi\int\limits^3_0 {\biggr(\biggr(\frac{y^2}{9}\biggr)^2-\biggr(\frac{y}{3}\biggr)^2\biggr)} \, dy\\=\pi\int\limits^b_a {\biggr(\frac{y^4}{81}-\frac{y^2}{9}\biggr)} \, dy[/tex]
Make sure to write the functions in terms of y since you rotate on a vertical axis.
Part B
[tex]\displaystyle V=\pi\int\limits^b_a {(R^2-r^2)} \, dx\\=\pi\int\limits^1_0 {((3-3\sqrt{x})^2-(3-3x)^2)} \, dx\\=\pi\int\limits^1_0 {((9-18\sqrt{x}+9x)-(9-18x+9x^2))} \, dx\\=\pi\int\limits^1_0 {(-18\sqrt{x}-9x-9x^2)} \, dx[/tex]
Make sure to fix the radii so they start at y=3.
which has the lowest unit rate
$0.27: 1
$ 0.18:1
$0.21:1