The diagram shows squares arranged around the edge of a right triangle. What is the area of square B

Answer:

Step-by-step explanation:

Not sure what you mean by quotient but 2956?0.03

=98,533.3333333333333333333333

Answer:

a = 3b/b-3

because combined the expression and leaving alone the variable

Answer:

  (A, B) = (4, 12) or (12, 4)

Step-by-step explanation:

An Egyptian fraction is the sum of distinct unit fractions. Here, we're asked to decompose 1/3 into an Egyptian fraction sum of two fractions. There are formulas available when the sum has a numerator value of 2.

Here, the sum is a unit fraction. A reasonable approach is to use 1/(n+1) as the larger portion of 1/n. Then the other portion is 1/(n(n+1)). That is effectively what we end up with here.

__

Multiplying by 3AB gives ...

  AB = 3B +3A

Solving for B, we find ...

  AB -3B = 3A

  B(A -3) = 3A

  B = 3A/(A -3)

In order for A-3 to be a factor of A, or equal to 3, we must have ...

  A-3 = 1  ⇒  A = 4

  A-3 = 3  ⇒  A = 6

  A-3 = 3×3  ⇒  A = 4×3

This will give integer values for B when A is one of 4, 6, or 12. In the case of A=6, the two fractions are equal, which is not what you want

The two solutions are ...

  (A, B) = (4, 12) or (12, 4)

The negative solution is [tex]-\frac{3}{5}[/tex]

First, add 3 on both sides.

[tex]-2|5x-1|=-8[/tex]

Then, Divide both sides by -2

[tex]|5x-1|=4[/tex]

We know 5x-1 = 4     or 5x-1=-4

[tex]x=1[/tex]             (positive)

[tex]x=-\frac{3}{5}[/tex]          (negative)

Answer:

Step-by-step explanation:

Angle CDB=angle BAC=42°(angles subtended by same chord)

CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°)

In triangle CBA ,angle ACB=48°[angle

sum property]

Answer:

[tex]9874.35 \\ 6490.02 \\ 3384.33[/tex]

Answer:

1) La piedra permanece en el aire en 4 segundos.

2) La piedra alcanza una distancia horizontal de 32 metros.

3) La velocidad de la piedra con la que alcanza el suelo es aproximadamente 40.792 metros por segundo.

Step-by-step explanation:

El problema nos indica un caso de tipo parabólico, el cual consiste en la suma de un movimiento horizontal a velocidad y un movimiento uniforme acelerado por la gravedad desde el reposo.

1) El tiempo total que la piedra permanecería en el aire es tiempo requerido entre la parte superior del acantilado y el fondo. La ecuación cinemática que vamos a utilizar es la siguiente:

[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex] (Ec. 1)

Donde:

[tex]y_{o}[/tex] - Altura inicial, medida en metros.

[tex]y[/tex] - Altura final, medida en metros.

[tex]v_{o,y}[/tex] - Velocidad vertical inicial de la piedra, meadida en metros por segundo.

[tex]g[/tex] - Aceleración gravitacional, medido en metros por segundo al cuadrado.

[tex]t[/tex] - Tiempo, medido en segundos.

Si sabemos que [tex]y_{o} = 80\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] y [tex]g = -10\,\frac{m}{s^{2}}[/tex], entonces encontramos la siguiente función cuadrática:

[tex]-5\cdot t^{2}+80 = 0[/tex] (Ec. 2)

El tiempo en el que la piedra permanece en el aire es:

[tex]t = 4\,s[/tex]

La piedra permanece en el aire en 4 segundos.

2) La distancia horizontal es descrita por la siguiente fórmula cinemática:

[tex]x = x_{o}+v_{o,x}\cdot t[/tex] (Ec. 3)

Donde:

[tex]x_{o}[/tex] - Posición horizontal inicial, medido en metros.

[tex]x[/tex] - Posición horizontal final, medido en metros.

[tex]v_{o,x}[/tex] - Velocidad horizontal inicial de la piedra, medida en metros por segundo.

Si sabemos que [tex]x_{o} = 0\,m[/tex], [tex]v_{o,x} = 8\,\frac{m}{s}[/tex] and [tex]t = 4\,s[/tex], entonces la distancia horizontal alcanzada por la piedra es:

[tex]x = 0\,m + \left(8\,\frac{m}{s}\right)\cdot (4\,s)[/tex]

[tex]x = 32\,m[/tex]

La piedra alcanza una distancia horizontal de 32 metros.

3) En primer lugar, determinamos los componentes vertical y horizontal de la velocidad final de la piedra por medio de las siguientes fórmulas cinemáticas:

Velocidad final horizontal ([tex]v_{x}[/tex]), medida en metros por segundo.

[tex]v_{x} = \frac{x-x_{o}}{t}[/tex] (Ec. 4)

Velocidad final vertical ([tex]v_{y}[/tex]), medida en metros por segundo.

[tex]v_{y} = v_{o,y}+g\cdot t[/tex] (Ec. 5)

Si [tex]x = 32\,m[/tex], [tex]x_{o} = 0\,m[/tex]. [tex]t = 4\,s[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] y  [tex]g = -10\,\frac{m}{s^{2}}[/tex], los componentes de la velocidad final de la piedra son:

[tex]v_{x} = \frac{32\,m-0\,m}{4\,s}[/tex]

[tex]v_{x} = 8\,\frac{m}{s}[/tex]

[tex]v_{y} = 0\,\frac{m}{s}+\left(-10\,\frac{m}{s^{2}} \right) \cdot (4\,s)[/tex]

[tex]v_{y} = -40\,\frac{m}{s}[/tex]

Por último, determinamos la velocidad final de la piedra por Teorema de Pitágoras:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex] (Ec. 6)

[tex]v = \sqrt{\left(8\,\frac{m}{s} \right)^{2}+\left(-40\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 40.792\,\frac{m}{s}[/tex]

La velocidad de la piedra con la que alcanza el suelo es aproximadamente 40.792 metros por segundo.

Answer:

quarts. 11. fluid ounces = —. 1. 4. — quart. 12. quarts = 6 gallons. 13. 16 pints = gallons. 14. ... How many times must a 1-cup measuring cup be filled to equal 4 pints? 2. Leroy has 2 containers. ... can hold. Write cup, pint, quart, or gallon. 15. a bathtub. 16. a container of orange juice. 17. a juice box. 18. a small milk carton. 1

Step-by-step explanation:

Answer:

5.4

Step-by-step explanation:

Using the distance formula:

[tex] \sqrt{ {( - 7 - ( - 2))}^{2} + {(3 - 1)}^{2} } [/tex]

[tex] \sqrt{ {( - 5})^{2} + {2}^{2} } [/tex]

[tex] \sqrt{25 + 4} [/tex]

[tex] \sqrt{29} [/tex]

[tex]5.4[/tex]

Answer:

What are the answer choices? I would help but you didn't attach or write them.

Step-by-step explanation:

Answer:

m-4n=8 divide both sides by 4.

m-n=2

There are two variables, so this is the simplest form.

Answer:

There is no table attached, if you attach is I will gladly help :)

Step-by-step explanation:

Answer:

You need to divide 11/2 by 1/3 and you will have you answer

Step-by-step explanation:

Answer: 405 calories

Step-by-step explanation:

2.95 expressed as a fraction is 59/20.

The decimal is made up of a whole number and a non-integer. In order to convert the decimal to a fraction, divide the non-integer by 100 and add it to the whole number.

2 + 95/100

2 19/20

Now multiply the whole number by the denominator, add the numerator and then divide by the denominator. The result is:

59/20

To learn more about decimals, please check: https://brainly.com/question/15287678

The expression sin2x is a trigonometric expression

The equivalent of sin2x is (d) 2sinxcosx

The expression is given as:

sin2x

Rewrite properly as:

sin(2x)

To solve the expression, we make use of the following double angle ratio

sin(2a) = 2sin(a)cos(a)

Substitute x for a in the above equation

sin(2x) = 2sin(x)cos(x)

Rewrite the equation as

sin2x = 2sinxcosx

Hence, the equivalent of sin2x is (d) 2sinxcosx

Read more about trigonometric expressions at:

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Answer:

D

Step-by-step explanation:

A P E X

Answer:

No

Step-by-step explanation:

An isosceles triangle is a triangle with two equal/congruent sides. An equalateral triangle has all three sides equal.

2 hours, 35 minutes, and 0 second

Step-by-step explanation:

10 am to 1 pm is 2 hours  

and you have the 35 in which you add there for giving you the answer 2 hours, 35 minutes, and 0 second

Answer:

2 hours 35 minutes

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

distance from .5 to -3 is 3.5

now add the same distance to the other side

.5 plus 3.5 is 4

Answer:

A, B, C, and D

Step-by-step explanation:

Step-by-step explanation:

x - the part

3x one part(first number)

4x second part (second number)

so u have

3x + 4x = 1001

7x= 1001

x = 1001/7

x= 143. First number : 3x = 3• 143 = 429

Second number : 4x = 4• 143= 572

So, 429 and 572 are the numbers

Answer:

28 m

Step-by-step explanation:

Length = x

90 = 2(17 + x)

17 + x = 90/2 = 45

so

x = 45 - 17 = 28 m

Answer:

Vertex A'  (-8,4)

Vertex B'  (-12,12)

Vertex C'  (-4,12)

Step-by-step explanation:

Multiply all the coordinates by 4!

Answer:

[tex]A'(-8,4)\\B'(-12,12)\\C'(-4,12)[/tex]

Step-by-step explanation:

** Scale and/or dilate signal the operation symbol to be multiplication.

Definitions

[tex]A=(-2,1)\\B=(-3,3)\\C=(-1,3)[/tex]

Formulas

[tex]A'=A4\\B'=B4\\C'=C4[/tex]

Solve

[tex]A'=(-2,1)(4)=(-8,4)\\B'=(-3,3)(4)=(-12,12)\\C'=(-1,3)(4)=(-4,12)[/tex]

Volume of a cylindre = area base x height

Volume of a cone = 1/3 x area base x height

V cone = 1/3 x pi x r² x h = 1/3 x 3,14 x 3² x 7

Answer:

Step-by-step explanation:

A

Answer: C

Step-by-step explanation:

0.70 divided by 1.2=0.59

0.59*1.2= 0.70

c=5.90x

Let's take the first term as a and the common difference be d

The formula to find the nth term of an arithmetic progression is given by :

According to question, we have :

➝ a16 = 3 ( a5 )

➝ a + ( 16 - 1 )d = 3 ( a + ( 5 - 1 )d )

➝ a + 15d = 3 ( a + 4d )

➝ a + 15d = 3a + 12d

➝ 15d - 12d = 3a - a

➝ 3d = 2a

➝ 2a = 3d

➝ a = 3d/2‎ㅤ‎ㅤ‎ㅤ⸻ ( 1 )

➝ a12 - ( a7 ) = 20

➝ a + ( n - 1 )d -( a + ( n - 1 )d ) = 20

➝ a + ( 12 - 1 )d - + a + ( 7 - 1 )d ) = 20

➝ a + 11d - ( a + 6d ) = 20

➝ a - a + 11d - 6d = 20

➝ 5d = 20

➝ d = 20/ 5

➝ d = 4

➝ a = 3d / 2

➝ a = ( 3 × 4 ) / 2

➝ a = 12 / 2

➝ a = 6

Answer:the answer to your intresting question is 3

Step-by-step explanation:

add me to brainiest if you want

Answer:

Step-by-step explanation:

8x² - 30x - 27 = 0

8 = 4 * 2

-27 = -9 * 3

-30 = 4*(-9) + 2*3

so (4x + 3)(2x - 9) = 0

Answer 80

Step-by-step explanation:

If the line is a straight line through two parallel lines then the angles of the two intersections should be the same. Basically because they are both on the bottom right they will be the same.

The value of 'y' is 80 degrees. option B

Note that alternate angles are equal

The intersections of a transversal with two parallel lines forms various types of pairs of angles such as

In this case, the transverse line forms alternate angles of line c and b

Angle at line c = 80 degrees

Angle at line b = y

Since they are alternate angles, y = 80 degrees

Therefore, the value of 'y' is 80 degrees. option B

Learn more about transverse lines here:

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