The highest temperature ever recorded for a person with a fever who survived was 115 degrees. Alternatively, the lowest temperature ever recorded on a patient who survived was 56.7 degrees. If the average temperature is 98.6 degrees, which extreme temperature was furthest from the norm? How much further?
(PLEASE HELP ME DUE IN TODAY)
TYSM FOR THE TIME!!!!!!!

Answer:

y = 21

Step-by-step explanation:

When x is directly proportional to y:

When x increases, y also increases.

In this case, it is so you write,

1. Write down the formula: y=kx

k being the constant.

Let's use "When x = 4, y = 7" to work out the constant.

2. Substitute the 'when' values: 7=k×4

3. Rearrange to find the constant: 7÷4=k

4. Find k: k=1.75

Now let's see the new problem, 'what is y when x = 12'.

5. Substitute the values now but keep the constant: y = 1.75 × 12

6. Rearrange if needed.

7. Find the missing value: y = 21

Hope this helped and if you require further assistance from me please comment below! :)

Ps: If it was inversely proportional then the formula would be y = k / x

with k still being the constant.

Answer:

H = 12cm

b

I hope I was able to help

The probability that a certain rope will break before being subjected to 120 pounds is 89.4%.

The probability is calculated as follows:

Mean = 100

Standard deviation = 16

The probability is obtained from the z-score.

x = mean + z-score * standard deviation

120 = 100 + z-score * 16

z-score = 20/16

z-score = 1.25

From normal distribution table, the probability with a z-score of 1.25 is 89.4%

In conclusion, the probability is obtained from the z-score.

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Firstly changing mixed fraction.

[tex] \frac{3}{2} - \frac{5}{4} + \frac{23}{4} [/tex]

By taking the LCM

[tex] \frac{6 - 5 + 23}{4} [/tex]

-5 + 23 (-) (+) = (-)

[tex] \frac{6 + 18}{4} [/tex]

[tex] \frac{24}{4} [/tex]

[tex]6[/tex]

Hope it helps you, any confusions you may ask!

Answer:

6 (work below)

Step-by-step explanation:

1 1/2 = 3/2

1 1/4 = 5/4

5 3/4 = 23/4

The least common multiple of the denominators is 4, so 3/2 will become 6/4.

6/4 - 5/4 = 1/4 + 23/4 = 24/4 = 6

Brainliest, please :)

The time he spent running is 13.80 seconds.

The equation that can be used to represent the time he gets to the tree is:

Time he gets to the tree = (time of each spin x total spins) + time he spent running

21 = (6 x 1.2) + r

21 = 7.20 + r

r = 21 - 7.20

r = 13.80 seconds

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Put brackets equal 0

(2x + 1) (x - 1) = 0

(2x + 1) = 0

-1, then ÷2

x = - 1/2 or - 0.5

(x - 1) = 0

+1

x = 1

So, x = - 0.5 & x = 1

Hope this helps!

Answer:

x = -0.5

x = 1

Step-by-step explanation:

Hello!

We can set each factor to 0 and solve for x in both.

There are 2 solutions for x, -0.5 and 1.

The dimension that would give the maximum area is 20.8569

Let the shorter side be = x

Perimeter of the semi-circle is πx

Twice the Length of the longer side

[tex][70-(\pi )x -x][/tex]

Length = [tex][70-(1+\pi )x]/2[/tex]

Total area =

area of rectangle + area of the semi-circle.

Total area =

[tex]x[[70-(1+\pi )x]/2] + [(\pi )(x/2)^2]/2[/tex]

When we square it we would have

[tex]70x +[(\pi /4)-(1+\pi)]x^2[/tex]

This gives

[tex]70x - [3.3562]x^2[/tex]

From here we divide by 2

[tex]35x - 1.6781x^2[/tex]

The maximum side would be at

[tex]x = 35/2*1.6781[/tex]

This gives us 20.8569

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The graph that includes the possible values for the number of people who still need to sign up for the team is:

Number line with closed circle on 5 and shading to the right.

Researching this problem on the internet, a team currently has 4 players, and needs at least 9.

When x players are signed, the number of players will be of 4 + x. Since the team needs at least 9 players, the inequality is:

[tex]4 + x \geq 9[/tex]

The solution is:

[tex]x \geq 9 - 4[/tex]

[tex]x \geq 5[/tex]

Which is represented as follows:

Number line with closed circle on 5 and shading to the right.

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The function g(x) is g(x)= (3x)^2

The complete question is in the image

From the graph in the image, we have:

f(x) = x^2

The function f(x) is stretched by a factor of 3 to form g(x).

This means that:

g(x) = f(3x)

So, we have:

g(x)= (3x)^2

Hence, the function g(x) is g(x)= (3x)^2

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(a) The particle's distance from O when it first started to move is 24 m.

(b) The time when the particle first reaches O is 15 mins.

(c) The particle's speed when it has been moving for 3 minutes is 0.2 m/s.

D = 24 + 15 - t²/2

when the time, t  = 0

D = 24 m

When the object reaches O, its final velocity, v = 0

v = dD/dt

v = 15 - t

0 = 15 - t

t = 15 mins

v = 15 - t

v = 15 - 3

v = 12 m/min

v = 12 m/min x 1min/60s = 0.2 m/s

Thus, the particle's distance from O when it first started to move is 24 m.

The time when the particle first reaches O is 15 mins.

The particle's speed when it has been moving for 3 minutes is 0.2 m/s.

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The total surface area of the tower composed of a prism with a square base and a pyramid is 3600 + 400√2 m²

Total surface area of the tower = area of the base + 4(area of the rectangular surface) + 4(area of the triangular surface)

Therefore,

area of the base = 20² = 400 m²

4(area of the rectangular surface)  = 4(40 × 20) = 3200 m²

4(area of the triangular surface) = 4(1 / 2 × 10√2 × 20) = 4(100√2) = 400√2 m²

Therefore,

total surface area = 400 + 3200 + 400√2

total surface area = 3600 + 400√2 m²

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Answer:

a)400V2 plus 3,600 m2

Step-by-step explanation:

Answer:

-1.5

Step-by-step explanation:

To work out the gradient of the line, we use this equation:

[tex] \frac{y2 - y1}{x2 - x1} [/tex]

Substituting in, we get:

[tex] \frac{5 - ( - 4)}{ - 2 - 4} [/tex]

Which simplifies to:

[tex] \frac{9}{ - 6} = \frac{3}{ - 2} = - \frac{3}{2} = - 1.5[/tex]

The domain of a function is the range of its inverse, and vice versa.

So, the domain is [tex]x > 1[/tex] and the range is [tex]y > 3[/tex].

Answer:

The ratios are not equal, so this is not a dilation.

Step-by-step explanation:

4/3 is the first ratio

3/4 is the second ratio

Since these ratios are not equal there is not a dilation.

Answer:

Step-by-step explanation:

A=6x²

[tex]\frac{dA}{dt} =6\times 2x \times \frac{dx}{dt} \\\frac{dA}{dt}=12x \frac{dx}{dt}[/tex]

The probability of selecting from the platter a chocolate cupcake and then a yellow cupcake is  0.10.

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability of selecting a chocolate cupcake and then a yellow cupcake = (number of chocolate cupcake / total number of cupcakes) x (number of yellow cupcakes / total number of cupcakes - 1)

(13 / 38) x (11 / 37) = 0.10

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The value of (p*q)(5) and (q*p)(5) is 288

The functions are given as:

p(x)=x+1

q(x)=2x^2-2

Calculate p(5) and q(5)

p(5)=5+1 = 6

q(5)=2(5)^2-2 = 48

The functions are then calculated as:

(p*q)(5) = p(5) * q(5)

(p*q)(5) = 6 * 48

(p*q)(5) = 288

Also, we have:

(q*p)(5) = (p*q)(5)

(q*p)(5) = 288

Hence, the value of (p*q)(5) and (q*p)(5) is 288

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Complete question

Suppose that the functions p and q are defined as follows. p(x)=-x-1 q(x)=-2x^2-2 Find the following. (p*q)(5) (q*p)(5)

Answer:

There are 3 lbs of candy in the box.

The caramels are $8 per pound.

12y represents the total cost of truffles in the box.

8x + 12y + 1 represents the cost of caramels in the box + the cost of truffles in the box + the cost of the box.

Step-by-step explanation:

x = the number of pounds of caramels

y = the number of pounds of truffles

x + y = total lbs. and we know x + y = 3

We know x is the number of pounds of caramels.

8x = (cost per pound of caramels) × (number of pounds of caramels)

So 8 = cost of caramels

We know y = number of pounds of truffles. So 12 is the cost of truffles by pound, and 12y is the total cost of truffles in the box.

Based on all the above,

The cost of caramels in the box + the cost of truffles in the box + the cost of the box is = total cost of the box. 8x + 12y + 1 = 30

Answer:

6

Step-by-step explanation:

no calculator at hand ?

really ? you are using us a simple calculator ?

Answer:

6

Step-by-step explanation:

what is the sum of .74+.19+3.09+1.98=​

0.74+

0.19+

3.09+

1.98=

-----------------

6

The y-values of the two functions f(x) = 3x² -3 and g(x) = 2* - 3 has the minimum y-value of g(x) approaches -3 and f(x) contains the smallest possible y-value.

It exists described as a special kind of relationship and they contain a predefined domain and range according to the function every value in the domain exists connected to just one value in the range.

Given: f(x) = 3x² -3

As we can see in the graph the first term exists 3x² and exists still positive for all x.

The range for f(x) ∈ [-3, ∞)

When x = 0 then f(x) = -3

The above value exists as the smallest possible value on the y-axis.

Given:  [tex]g(x) = 2^x - 3[/tex]

[tex]2^x[/tex] exists also a positive quantity and it exists as an exponential function.

The range for the g(x) ∈ (-3, ∞)

It signifies that g(x) never touches the y-axis at -3.

We can express the minimum value of g(x) approaches -3.

Therefore, the correct answer is option B. The minimum y-value of g(x) approaches -3 and option D. f(x) has the smallest possible y-value.

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The solution to the system of equation is (0, 1)

Given the following system of equation as shown below

2^(x)+3^(y)=5,

2^(x+2)+3^(y+1)=18

Rewrite

2^(x)+3^(y)=5,

2^x*2^2 + 3^y*3^1 = 18

___________

2^(x)+3^(y)=5,

4(2^x) + + 3(3^y) = 18

Let a = 2^x and b = 3^y

Substitute

a + b = 5

4a + 3b = 18

a = 5 - b

Substitute

4(5-b) + 3b = 18

20 - 4b + 3b = 18

-b = -2

b = 2

since a = 5 - b

a = 5 - 2

a = 3

Recall that a = 2^x and b = 3^y

2^x = 2

x = 0

Similarly

3^y = 3

y =1

Hence the solution to the system of equation is (0, 1)

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Similar: yes

Similarity statement: [tex]ADCB \sim SVUT[/tex]

Scale factor: 1/3

The expression for a in terms of c is [tex]a^{2}= \sqrt{c^{2} -9}[/tex]. The correct option is the third option [tex]a^{2}= \sqrt{c^{2} -9}[/tex]

From the question, we are to determine the expression for a in terms of c

In the given right triangle, we can write that

[tex]c^{2} = a^{2} +3^{2}[/tex] (Pythagorean theorem)

Thus,

[tex]c^{2} = a^{2} +9[/tex]

[tex]a^{2}= c^{2} -9[/tex]

[tex]a^{2}= \sqrt{c^{2} -9}[/tex]

Hence, the expression for a in terms of c is [tex]a^{2}= \sqrt{c^{2} -9}[/tex]. The correct option is the third option [tex]a^{2}= \sqrt{c^{2} -9}[/tex]

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{(2,0),(-5,-2),(10,8),(6,0),(-9,-2)} is the correct answer (D)

Answer:

  (d)  {(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}

Step-by-step explanation:

The domain is the list of x-values. The range is the list of y-values. You are looking for the set that matches the given lists.

The list of x-values is {-9, -2}. The list is too short.

The list of x-values is {-9, -5, 2, 6, 10}. This matches the required domain.

The list of y-values is {-2, 0, 8, 5, 9}. The list is too long.

The list of x-values is {-2, 8, 0, -2, 0}. The list does not match the given domain list.

The list of x-values is {2, -5, 10, 6, -9}. This matches the given domain.

The list of y-values is {0, -2, 8, 0, -2}. This matches the given range.

The function of interest is ...

   {(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}

Answer: i+96

Step-by-step explanation:

Note that [tex]i^{4k}[/tex], where k is an integer, is equal to 1.

This means that [tex]i^{4!}=i^{5!}=i^{6}=\cdots=i^{99!}+i^{100!}=1[/tex]

So, we can rewrite the sum as [tex]i^{1}+i^{1}+i^{2}+i^3+97(1)=i+i-1-i+97=i+96[/tex]

[tex]n![/tex] is divisible by 4 for all [tex]n\ge4[/tex]. This means, for instance,

[tex]i^{4!} = \left(i^4\right)^{3!} = 1^{3!} = 1[/tex]

[tex]i^{5!} = \left(i^4\right)^{5\times3!} = 1^{5\times3!} = 1[/tex]

etc, so that [tex]i^{n!} = 1[/tex] for all [tex]n\ge4[/tex].

Meanwhile,

[tex]i^{0!} = i^1 = i[/tex]

[tex]i^{1!} = i^1 = i[/tex]

[tex]i^{2!} = i^2 = -1[/tex]

[tex]i^{3!} = i^6 = (-1)^3 = -1[/tex]

Then the sum we want is

[tex]i^{0!} + i^{1!} + i^{2!} + i^{3!} + 97\times1 = i + i - 1 - 1 + 97 = \boxed{95+2i}[/tex]

Answer:

>>   [tex]6\frac{5}{18}[/tex]

Step-by-step explanation:

1) Add the whole numbers first.

[tex]5+\frac{5}{6} +\frac{4}{9}[/tex]

2) Find the Least Common Denominator (LCD) of [tex]\frac{5}{6} ,\frac{4}{9}[/tex] . In other words, find the Least Common Multiple (LCM) of [tex]6,9[/tex].

Method 1: By Listing Multiples

1. List the multiples of each number.

Multiples of 6 : 6, 12, 18, ...

Multiples of 9 : 9, 18, ...

2. Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 18

3. Make the denominators the same as the LCD.

[tex]5+\frac{5\times 3}{6\times 3}+\frac{4\times 2}{9\times 2}[/tex]

4. Simplify. Denominators are now the same.

[tex]5+\frac{15}{18}+\frac{8}{18}[/tex]

5.  Join the denominators.

[tex]5+\frac{15+8}{18}[/tex]

6. Simplify.

[tex]5+\frac{23}{18}[/tex]

7. Convert [tex]\frac{23}{18}[/tex] to mixed fraction.

[tex]5+1\frac{5}{18}[/tex]

8. Simplify.

[tex]6\frac{5}{18}[/tex]

Decimal Form: 6.277778

Cheers.

The addition of 3 5/6 + 2 4/9  is 113/18

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

3 5/6 + 2 4/9

Now, writing it into normal fraction

3 5/6 + 2 4/9

= 23/ 6 + 22/9

= 23/6 x 3/3 + 22/9 x 2/2

= 69/ 18 + 44/18

= 113/18

Hence, the addition is 113/18

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Answer:

y = 0.8425   or   y = -0.8425

Step-by-step explanation:

All points in the Cartesian coordinate system have an x and y coordinate, defined by two perpendicular measurements.

If the point is on the unit circle, then the radius of the circle is defined to be 1 unit, and the corresponding right triangle follows the Pythagorean Theorem.

[tex]a^2+b^2=c^2[/tex]

For a unit circle:

[tex]x^2+y^2=1^2[/tex]

Substituting the known value for x, and simplifying...

[tex](-0.5387)^2+y^2=(1)^2[/tex]

[tex]0.29019769+y^2=1[/tex]

Subtracting 0.29019769 from both sides to begin to isolate "y"...

[tex]y^2=1-0.29019769[/tex]

[tex]y^2=0.70980231[/tex]

Applying the square root property...

[tex]\sqrt{y^2}=\pm \sqrt{0.70980231}[/tex]

[tex]y=\pm 0.8424976171...[/tex]

So, (to 4 decimal places), the y coordinate could be either 0.8425 or -0.8425.

With only the given information, either result is a valid answer.

The surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]

The volume of cuboid or box can be given as,

Volume = l × b × h

Here, (l) is the length, (b) is the width of the box and (h) is the height of the box.

A closed box has a square base with side length l feet and height h feet.  Therefore, the length and width will be the same.

Then the volume of the box is 29 cubic feet. Thus,

29 = l × l × h

29 = [tex]l^2 h[/tex]

[tex]h = \frac{l^2}{29}[/tex]

The surface area of the square base box is,

Area = [tex]2l^2 + 4lh[/tex]

Substitute the value of h

Area = [tex]2l^2 + 4l\frac{29}{l^2}[/tex]

Area =  ,[tex]2l^2 + \frac{116}{l}[/tex]

Therefore, the surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]

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