The length of a rectangular parking lot is 32 meters and the width is 20 meters. The parking lot is surrounded by a sidewalk that is x meters wide. Find the expression that represents the area of the parking lot, including the sidewalk.

Answers

Answer 1
The expression is:
32 X 20 + x

Hope that will help :)

Related Questions

Help!
What is the answer to this question?

Answers

Answer:

b = 73°

Step-by-step explanation:

They are vertical angles to each other.

In January, the depth of a lake was 1,178 feet. In August, the depth of the lake was 1,001.3 feet. What is the percentage decrease of the depth of the lake from January to August?

Answers

Answer:

15%

Step-by-step explanation:

decrease in depth = 1,178 - 1,001.3 = 176.7

percentage decrease = 176.7/1,178 = 0.15 = 15%

The perimeter of a rectangular garden is 90m its breadth is 17m find its length

Answers

Answer:

28 m

Step-by-step explanation:

Length = x

90 = 2(17 + x)

17 + x = 90/2 = 45

so

x = 45 - 17 = 28 m

All the prime numbers

Answers

Answer:

13 23 43

Step-by-step explanation:

Prime numbers are numbers that are divisible by 1 and itself or numbers that have only 2 factors which is 1 and itself.

Please i need your help

Answers

Answer:

it okay I can help you with that

What is 2.95 expressed as a fraction?


5920

11880

33640

40118

Answers

2.95 expressed as a fraction is 59/20.

What is the fraction equivalent?

The decimal is made up of a whole number and a non-integer. In order to convert the decimal to a fraction, divide the non-integer by 100 and add it to the whole number.

2 + 95/100

2 19/20

Now multiply the whole number by the denominator, add the numerator and then divide by the denominator. The result is:

59/20

To learn more about decimals, please check: https://brainly.com/question/15287678

The sum of two numbers that are at the ratio of 3:4 is 1001. Find these numbers.

Answers

Step-by-step explanation:

x - the part

3x one part(first number)

4x second part (second number)

so u have

3x + 4x = 1001

7x= 1001

x = 1001/7

x= 143. First number : 3x = 3• 143 = 429

Second number : 4x = 4• 143= 572

So, 429 and 572 are the numbers

What's a non-included angle?

Answers

Answer:

It is the side where the rays of the angles overlap. The "non-included" side in AAS can be either of the two sides that are not directly between the two angles being used.

A parabola has an axis of symmetry at x = 0.5 and one of the x-intercepts is at x=-3. Where is
the other x-intercept?

Answers

Answer:

4

Step-by-step explanation:

distance from .5 to -3 is 3.5

now add the same distance to the other side

.5 plus 3.5 is 4

The 16th term of an AP is three times the 5th term.If the 12th term is 20 more the 7th term.Find the first term and the common difference​

Answers

Answer:

First term = 6Common difference= 4

Solution:

Let's take the first term as a and the common difference be d

The formula to find the nth term of an arithmetic progression is given by :

an = a + ( n - 1 ) d

According to question, we have :

16th term of an AP is three times the 5th term.

a16 = 3 ( a5 )

a + ( 16 - 1 )d = 3 ( a + ( 5 - 1 )d )

a + 15d = 3 ( a + 4d )

a + 15d = 3a + 12d

15d - 12d = 3a - a

3d = 2a

2a = 3d

a = 3d/2‎ㅤ‎ㅤ‎ㅤ⸻ ( 1 )

And, the 12th term is 20 more the 7th term.

a12 - ( a7 ) = 20

a + ( n - 1 )d -( a + ( n - 1 )d ) = 20

a + ( 12 - 1 )d - + a + ( 7 - 1 )d ) = 20

a + 11d - ( a + 6d ) = 20

a - a + 11d - 6d = 20

5d = 20

d = 20/ 5

d = 4

Using equation ( 1 )

a = 3d / 2

a = ( 3 × 4 ) / 2

a = 12 / 2

a = 6

A campsite provides a locking, rectangular box with the dimensions shown to secure
food from bears. What is the volume?

(PUT NUMBER ONLY)
3 feet
2 feet
5 feet

Answers

Answer:

30 feet^3

Step-by-step explanation:

2*5*3=30

V= bhw

what is the elapse time between 10:35am and 1:10pm

Answers

2 hours, 35 minutes, and 0 second

Step-by-step explanation:

10 am to 1 pm is 2 hours  

and you have the 35 in which you add there for giving you the answer 2 hours, 35 minutes, and 0 second

Answer:

2 hours 35 minutes

Step-by-step explanation:

Consider the following expressions: A. 34÷23 B. 710÷45 C. 78÷12 D. 34÷13 E. 15÷1115 a. Which expression(s) will result in a quotient that is greater than one? 34÷23 710÷45 78÷12 34÷13 15÷1115

Answers

Answer:

A, B, C, and D

Step-by-step explanation:

Please help me with this I need it now :)

Answers

Answer:

reverse it x-15=4 do 15+4=x

Step-by-step explanation:

factorise [8x^{2}-30x-27=0

Answers

Answer:

Step-by-step explanation:

8x² - 30x - 27 = 0

8 = 4 * 2

-27 = -9 * 3

-30 = 4*(-9) + 2*3

so (4x + 3)(2x - 9) = 0

In Table 2, at this rate, how much would it cost to buy 9 books?

Answers

Answer:

There is no table attached, if you attach is I will gladly help :)

Step-by-step explanation:

HELPPP PLEASEEE

Point P is the center of the cirlce and ∠BDC= 60°. Determine:

a. ∠DBC
b. ∠DAC
c. ∠ACD
d. ∠AEB
e. ∠APB

Answers

Answer:

Step-by-step explanation:

Angle CDB=angle BAC=42°(angles subtended by same chord)

CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°)

In triangle CBA ,angle ACB=48°[angle

sum property]

Please explain how to do this
Show working

Answers

Answer:

a = 3b/b-3

because combined the expression and leaving alone the variable

Answer:

  (A, B) = (4, 12) or (12, 4)

Step-by-step explanation:

An Egyptian fraction is the sum of distinct unit fractions. Here, we're asked to decompose 1/3 into an Egyptian fraction sum of two fractions. There are formulas available when the sum has a numerator value of 2.

Here, the sum is a unit fraction. A reasonable approach is to use 1/(n+1) as the larger portion of 1/n. Then the other portion is 1/(n(n+1)). That is effectively what we end up with here.

__

Multiplying by 3AB gives ...

  AB = 3B +3A

Solving for B, we find ...

  AB -3B = 3A

  B(A -3) = 3A

  B = 3A/(A -3)

In order for A-3 to be a factor of A, or equal to 3, we must have ...

  A-3 = 1  ⇒  A = 4

  A-3 = 3  ⇒  A = 6

  A-3 = 3×3  ⇒  A = 4×3

This will give integer values for B when A is one of 4, 6, or 12. In the case of A=6, the two fractions are equal, which is not what you want

The two solutions are ...

  (A, B) = (4, 12) or (12, 4)

How many pairs does a liminal have?

Answers

Answer:the answer to your intresting question is 3

Step-by-step explanation:

add me to brainiest if you want

In Ben's apartment complex, residents are fined $9 per day each day the rent is late. Last month, Ben wrote the apartment complex a check for $702 when his monthly rent is only $585. How many days late was Ben's rent?

Answers

Answer:

13 days late-poor guy

Step-by-step explanation:

(702-585)/9

117/9

13

“Firms will loss _?_ if the firm shuts down in the short run”

Answers

Answer:

The correct answer was C!

Step-by-step explanation:

Solve for m please I will give brainliest

Answers

Answer:

m-4n=8 divide both sides by 4.

m-n=2

There are two variables, so this is the simplest form.

Are all sides equal in an Isosceles triangle?

Answers

Answer:

No

Step-by-step explanation:

An isosceles triangle is a triangle with two equal/congruent sides. An equalateral triangle has all three sides equal.

No. Only 2 sides are equal in an Isosceles Triangle. A scalene has 0, and a equilateral has 3 same sides.

9,874.35 - 6490.02

step by step​

Answers

Answer:

[tex]9874.35 \\ 6490.02 \\ 3384.33[/tex]

A cylinder has a radius of 3 feet and a height of 7 feet. Which of the following can be used to calculate the volume of a cone that fits exactly inside the cylinder?
(3.14)(7%)(3)
03(3.14373)(3)
(3.14)(3)(7)
O
0|(3.1413307

Answers

Volume of a cylindre = area base x height

Volume of a cone = 1/3 x area base x height

V cone = 1/3 x pi x r² x h = 1/3 x 3,14 x 3² x 7

Griffin bought 1.2 pounds of almonds for $6.60. His friend, Sam, bought almonds for $0.70 per pound cheaper. Which equation represents the cost, c, Sam paid for x pounds of almonds?

A.c = 4.80x

B. c = 5.50x

C. c = 5.90x

D. c = 7.30x

Answers

Answer:

Step-by-step explanation:

A

Answer: C

Step-by-step explanation:

0.70 divided by 1.2=0.59

0.59*1.2= 0.70

c=5.90x

A small can contain 2 cups of soup. do 3 small cans have a greater amount than a 1 - quart container of soup.

Answers

Answer:

quarts. 11. fluid ounces = —. 1. 4. — quart. 12. quarts = 6 gallons. 13. 16 pints = gallons. 14. ... How many times must a 1-cup measuring cup be filled to equal 4 pints? 2. Leroy has 2 containers. ... can hold. Write cup, pint, quart, or gallon. 15. a bathtub. 16. a container of orange juice. 17. a juice box. 18. a small milk carton. 1

Step-by-step explanation:

Patrick usually jogs 1 1/2 miles each day but yesterday he jogged only 1/3 as far. How far did he run yesterday?

Answers

Answer:

You need to divide 11/2 by 1/3 and you will have you answer

Step-by-step explanation:

Verify the linear approximation at (0, 0) for

f(x, y) = 7x + 4
5y + 1
â 4 + 7x â 20y

Let f(x, y) = 7x + 4 5y + 1 . Then fx(x, y) = ________

Answers

You need to plug in the (0,0) that’s it

Ejercicio Nº 4 Desde la parte superior de un acantilado de 80 metros de altura se dispara horizontalmente una piedra a razón de 8m/s. Calcular: g = 10m/s? 1) el tiempo que permanece en el aire. 2) la distancia horizontal que el cuerpo alcanza. 3) la velocidad con que la piedra alcanza el suelo​

Answers

Answer:

1) La piedra permanece en el aire en 4 segundos.

2) La piedra alcanza una distancia horizontal de 32 metros.

3) La velocidad de la piedra con la que alcanza el suelo es aproximadamente 40.792 metros por segundo.

Step-by-step explanation:

El problema nos indica un caso de tipo parabólico, el cual consiste en la suma de un movimiento horizontal a velocidad y un movimiento uniforme acelerado por la gravedad desde el reposo.

1) El tiempo total que la piedra permanecería en el aire es tiempo requerido entre la parte superior del acantilado y el fondo. La ecuación cinemática que vamos a utilizar es la siguiente:

[tex]y = y_{o} + v_{o,y}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex] (Ec. 1)

Donde:

[tex]y_{o}[/tex] - Altura inicial, medida en metros.

[tex]y[/tex] - Altura final, medida en metros.

[tex]v_{o,y}[/tex] - Velocidad vertical inicial de la piedra, meadida en metros por segundo.

[tex]g[/tex] - Aceleración gravitacional, medido en metros por segundo al cuadrado.

[tex]t[/tex] - Tiempo, medido en segundos.

Si sabemos que [tex]y_{o} = 80\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] y [tex]g = -10\,\frac{m}{s^{2}}[/tex], entonces encontramos la siguiente función cuadrática:

[tex]-5\cdot t^{2}+80 = 0[/tex] (Ec. 2)

El tiempo en el que la piedra permanece en el aire es:

[tex]t = 4\,s[/tex]

La piedra permanece en el aire en 4 segundos.

2) La distancia horizontal es descrita por la siguiente fórmula cinemática:

[tex]x = x_{o}+v_{o,x}\cdot t[/tex] (Ec. 3)

Donde:

[tex]x_{o}[/tex] - Posición horizontal inicial, medido en metros.

[tex]x[/tex] - Posición horizontal final, medido en metros.

[tex]v_{o,x}[/tex] - Velocidad horizontal inicial de la piedra, medida en metros por segundo.

Si sabemos que [tex]x_{o} = 0\,m[/tex], [tex]v_{o,x} = 8\,\frac{m}{s}[/tex] and [tex]t = 4\,s[/tex], entonces la distancia horizontal alcanzada por la piedra es:

[tex]x = 0\,m + \left(8\,\frac{m}{s}\right)\cdot (4\,s)[/tex]

[tex]x = 32\,m[/tex]

La piedra alcanza una distancia horizontal de 32 metros.

3) En primer lugar, determinamos los componentes vertical y horizontal de la velocidad final de la piedra por medio de las siguientes fórmulas cinemáticas:

Velocidad final horizontal ([tex]v_{x}[/tex]), medida en metros por segundo.

[tex]v_{x} = \frac{x-x_{o}}{t}[/tex] (Ec. 4)

Velocidad final vertical ([tex]v_{y}[/tex]), medida en metros por segundo.

[tex]v_{y} = v_{o,y}+g\cdot t[/tex] (Ec. 5)

Si [tex]x = 32\,m[/tex], [tex]x_{o} = 0\,m[/tex]. [tex]t = 4\,s[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex] y  [tex]g = -10\,\frac{m}{s^{2}}[/tex], los componentes de la velocidad final de la piedra son:

[tex]v_{x} = \frac{32\,m-0\,m}{4\,s}[/tex]

[tex]v_{x} = 8\,\frac{m}{s}[/tex]

[tex]v_{y} = 0\,\frac{m}{s}+\left(-10\,\frac{m}{s^{2}} \right) \cdot (4\,s)[/tex]

[tex]v_{y} = -40\,\frac{m}{s}[/tex]

Por último, determinamos la velocidad final de la piedra por Teorema de Pitágoras:

[tex]v = \sqrt{v_{x}^{2}+v_{y}^{2}}[/tex] (Ec. 6)

[tex]v = \sqrt{\left(8\,\frac{m}{s} \right)^{2}+\left(-40\,\frac{m}{s} \right)^{2}}[/tex]

[tex]v \approx 40.792\,\frac{m}{s}[/tex]

La velocidad de la piedra con la que alcanza el suelo es aproximadamente 40.792 metros por segundo.

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