Answer:
The less energy a wave has, the smaller the amplitude
Explanation:
Hope this helps!!!
If a satellite is launched to a distance of 1000000m above the earth’s surface, what is the gravitational field strength on the satellite from the earth?
Explanation:
A 620 kg satellite above the earth's surface experiences a gravitational field strength of 4.5 N/kg.
Knowing the gravitational field strength at Earth’s sur-
face and Earth’s radius, how far above Earth’s surface
is the satellite? (Use ratio and proportion.)
A race starts and finishes a race that is 50,000m. (30miles). The time is 23 minutes. The final velocity is 67m/s. What is the average acceleration ?
Use acceleration formula
Answer:
a = 0.0505 [m/s^2]
Explanation:
In order to solve this formula we must use the following formula of kinematics.
[tex]x=(v_{o} *t)+(\frac{1}{2} )*a*t^{2}[/tex]
where:
x = distance = 50000 [m]
Vo = initial velocity = 0
a = acceleration [m/s^2]
t = time = 23 [min] = 1380 [s]
Note: the positive sign in the above equation shows that the car accelerates.
50000 = (0*1380) + (0.5*a*1380^2)
a = 0.0525 [m/s^2]
But we can calculate the acceleration using the following formula:
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 67 [m/s]
67 = 0 + (a*1380)
a = 0.0485 [m/s^2]
We can see that by means of kinematics and with the given values we can find two values of accelerations, however, we can determine the average acceleration, by means of the mathematical average.
a = (0.0485 + 0.0525) / 2
a = 0.0505 [m/s^2]
A student is investigating magnetic fields. The student places four different objects near identical magnets and observes what happens. The student records her observations in the table below. Using data from the table, which argument can the student make about magnetic fields?
a. The effect that a magnetic field has on an object depends on the mass of the object.
b. The effect that a magnetic field has on an object depends on the material of the object.
c. The effect that a magnetic field has on an object depends on the type of magnet used.
d. The effect that a magnetic field has on an object depends on the distance to the object.
Answer:
B. The effect that a magnetic field has on an object depends on the material of the object.
Explanation:
Just makes sense
Based on the data given in the table, the best argument the student can make about magnetic fields is that b. The effect that a magnetic field has on an object depends on the material of the object.
Why can this argument be made?Certain objects have properties that make them easier to be magnetizable than other materials. Crayons and wooden toothpicks for instance, are not magnetizable.
The conclusion that can be made therefore is that the effect of a magnet on an object depends on the material of the object.
In conclusion, option B is correct.
Find out more on magnetic fields at https://brainly.com/question/14411049.
Object A has a charge of -1 C. Object A has a charge of -1 C. At a given distance, the object with which
charge would be most strongly attracted by object A?*
+1 C
-1 C
+2 C
-2 C
The positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.
Attraction of opposite charges
Opposite charges have the ability to attract each other while, similar charges repel each other.
The given charge of object A is negative, and it will be strongly attracted to a positive charge.
The greater the positive charge, the greater the force of attraction of object A.
From the given options, the positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.
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I need to know the answer to this and I do not need an explanation
Answer:
3rd sentence
Explanation:
100 POINTS QUESTION. PLEASE PROVIDE EXPLANATION
Answer:
t = 0, p = 12.0, v = 6.00
t = 20, p = 112, v = 56.0
t = 25, p = 62.0, v = 31.0
Explanation:
Impulse = change in momentum
J = Δp
FΔt = mΔv
The impulse equals the area under the F vs t graph.
At t = 0 s, the initial velocity is 6.00 m/s, so the momentum is:
p = (2.00 kg) (6.00 m/s)
p = 12.0 kg m/s
From t=0 s to t=20 s, the impulse is:
J = (20 N) (5 s) + ½ (20 N) (5 s) + ½ (-10 N) (10 s)
J = 100 Ns
So the new momentum is:
p = 12.0 kg m/s + 100 kg m/s
p = 112 kg m/s
And the new velocity is:
v = (112 kg m/s) / (2.00 kg)
v = 56.0 m/s
From t=20 s to t=25 s, the impulse is:
J = (-10 N) (5 s)
J = -50 Ns
So the new momentum is:
p = 112 kg m/s − 50 kg m/s
p = 62.0 kg m/s
And the new velocity is:
v = (62.0 kg m/s) / (2.00 kg)
v = 31.0 m/s
What are two differences and two similarities between applied force and tension force
Answer:
similarities: They are both members of an action reaction-pair and are produced by electromagnetic forces between the particles. In the case of tension a force is acting to separate the molecules from their equilibrium position, the tension is the resistance to this separatio; that is the electrical attraction among the charged particles that opposes the action of the applied force. In the case of the normal force when gravity pulls an object downward, the electrons of the two surfaces are pulled so close that they mutually reject each other. This rejection between the electrons of the 2 surfaces produces the normal force, acting in opposition to gravity.
Differences: The main difference between tension and force is the direction of force. ... Tension is a force pulling something apart, such as a force pulling apart on the ends of a rope. You often calculate tension in pulley problems. A force is a more general term applying to pushing or pulling on something.
Explanation:
i hope this helps you :)
long narrow uniform stick of length ! and mass m lies motionless on ice (assume the ice provides a frictionless surface). The center of mass of the stick is the same as the geometric center (at the midpoint of the stick). The moment of inertia of the stick about its center of mass is lcm . A puck (with putty on one side) has same mass m as the stick. The puck slides without spinning on the ice with a speed of v0 towards the stick, hits one end of the stick, and attaches to it. You may assume that the radius of the puck is much less than the length of the stick so that moment of inertia of the puck about its center of mass is negligible compared to Icm . (a) How far from the midpoint of the stick is the center of mass of the stick-puck combination after the collision?
Answer:
the answer would be 0 as known to the lengthExplanation:
0m x96 would put as an mass of 900 into 0 so there for your answer would be 0
Through an orbit what remains constant ?
a. Kinetic energy
B. Potential energy
C. Total energy
D. Work
Answer:
c. Total energy
Explanation:
An "orbit" is a path for an object to follow. An example of an object is the "satellite."
At certain points in the orbit, the satellite increases its speed and decreases its speed in relation to the gravity caused by the Earth. As it moves farther away from the Earth, its speed slows down. So, this means that the kinetic energy changes. It also gains and loses height which is responsible for the changes occurring regarding potential energy. This is true for elliptical motion of satellites.
However, the total mechanical energy (TME) of the satellite remains the same or is unchanged (elliptical/circular).
11. The measurement of an object's mass is a
a. physical change
b. physical property
c. chemical
d. chemical property
change
the center of mass is located a distance x from the less-dense end. Explain how Blake can determine the location of the center of mass
Blake can determine the center mass by dividing the product of less dense and its position by the sum of the two end densities.
What is center mass?The center mass of an object is the point on the object where the weighted relative position of the distributed mass sums to zero.
Blake can determine the location of the center mass as follows;
Let the end position of the high dense = 0Let the density of the "high dense end" = ρ₁Let the density of the "less dense end" = ρ₂[tex]C_{xm }= \frac{\rho_1 (0) + \rho(x)}{\rho_1 + \rho_2} \\\\C_{xm }= \frac{\rho(x)}{\rho_1 + \rho_2}[/tex]
Thus, Blake can determine the center mass by dividing the product of less dense and its position by the sum of the two end densities.
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If a person weighs 692 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that planet?
Answer:
Approximately [tex]75.3\; \rm m \cdot s^{-2}[/tex]. (Approximately [tex]7.69\, g[/tex], where [tex]g[/tex] denotes the acceleration due to gravity on the surface of the earth.)
Explanation:
The weight of an object is the size of the overall gravitational pull on that object. If the mass of this person is [tex]m[/tex], the weight of this person at a point with gravitational acceleration [tex]g[/tex] would be [tex]m \cdot g[/tex].
Let [tex]g_{0}[/tex] denote the gravitational acceleration on the surface of the earth. The weight of this person on the surface of the earth would be [tex]m \cdot g_0[/tex].
Let [tex]g_1[/tex] denote the gravitational acceleration on the surface of that "nearby planet". The weight of this person on the surface of that planet would be [tex]m \cdot g_1[/tex].
According to the question:
Weight of this person on the surface of the earth: [tex]692\; \rm N[/tex]. Therefore, [tex]m \cdot g_0 = 692\; \rm N[/tex].Weight of this person on the surface of that nearby planet: [tex]5320\; \rm N[/tex]. Therefore: [tex]m \cdot g_1 = 5320\; \rm N[/tex].Take the quotient of these two equations:
[tex]\displaystyle \frac{m\cdot g_1}{m \cdot g_0} = \frac{5320 \; \rm N}{692\; \rm N}[/tex].
[tex]\displaystyle \frac{g_1}{g_0} \approx 7.6879[/tex].
[tex]g_1 \approx 7.6879 \, g_0[/tex].
In other words, the gravitational acceleration on the surface of that nearby planet is approximately [tex]7.6879[/tex] times the gravitational acceleration on the surface of the earth.
The gravitational acceleration on the surface of the earth is approximately [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex]. Therefore, the gravitational acceleration on the surface of that planet would be approximately [tex]7.6879\, g \approx 7.8679 \times 9.8\; \rm m \cdot s^{-2} \approx 75.3\; \rm m \cdot s^{-2}[/tex].
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left and then 6 units to the
right. What is the displacement of the object?
1
5
7
13
Answer:
5
Explanation:
when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because
a number line also has negative numbers.Then if you move 6 units your object is at 5
if i got rolled over and then survided and then i would go home then i died what happened
Answer:
you had probably died from the impact
Explanation:
because you got rolled over you would probably died due to your organs being damage and wouldn't function properly
A baseball is batted. It's a long fly ball. 4 seconds later the ball reaches the outfield 100 meters away and returns to the height from which it left the bat. Determine the horizontal component of the ball's initial velocity in magnitude, in m/s,
Answer:
25 m/s
Explanation:
First we should define the variables
T=4
Dx = 100
ay=-9.8
ax=0
We can use formula 1 from the BIG 5
x=(v+v0)t/2
By plugging in our variables we can get 100=4(v+v0)/2
Which is 50=v+v0
v=v0 since horizontal acceleration always equals zero
so 2v0 = 50
v0 = 25
A cat, which mass 2.5 kg walks on a uniform plank of 4.0m long and mass 6.0kg. Two sawhorses at 0.3m and 2.4m from its right end to support the plank as shown in figure. The cat walks on it from right to the left until a certain position where the plank just begin to tip. Calculate the position of the cat from the left sawhorse when the plank just begin to tip .
Answer:
Explanation:
Let when cat reaches the point L distance from the right end , the plank starts turning about the left sawhorse.
The weight of the plank will at at middle point , ie at 2 m from the right end .
The plank will turn about the left sawhorse . Taking torque about this point of weight of the plank and weight of the cat , we have
2.5 g x ( L - 2.4 ) = 6 x g x ( 2.4 - 2.0 )
2.5 L - 6 = 14.4 - 12
2.5 L = 8.4
L = 3.36
position from left sawhorse = 3.36 - 2.4 = .96 m to the left of left sawhorse.
list clown the advantages and disadvantages
of the micrometer screw guage
Caliper?
over Vernier
Answer:
Micrometers provide very accurate measurements
The micrometer is one of the most accurate types of measuring device.
Most micrometers can measure up to 0.001mm or 0.0001 inches.
-------
Ratchet speeder helps to provide reliable measurements
The ratchet speeder/stop mechanism ensures that uniform pressure is applied to the thimble so that measurements are reliable and repeatable.
-------
Explanation:
The kinetic energy k of an object in joules is given by the formula k= 1 over 2mv^2 where m is the object’s mass in kilograms and v is it’s velocity in meters per second. An object’s velocity in meters per second, and it’s kinetic energy is 48,000 joules..If it speeds up to 40 meters per second, what is its new kinetic energy
Answer:
Ek = 192000 [J]
Explanation:
Originally missing speed data to solve this problem, we must assume that the original speed is 20 [m/s]. In this way, we can calculate the mass of the object.
48000 = (1/2)*m*(20)^2
m = 240 [kg]
The mass is conserved since it does not change only changes the speed of the body so we can calculate a new kinetic energy.
Ek = (1/2)*240*(40)^2
Ek = 192000 [J]
You walk out to the edge of a 2,384 m. cliff and you toss a rock down to watch it drop. What is the rocks acceleration?
Answer:
9.8m/s
Explanation:
Wherever you're on the earth's surface, gravitational force remains the same and it does not matter either its a rock that's being tossed or a sheet of paper, the acceleration remains 9.8m/s only. *Condition applied=air resistance neglected
PLEASE HELP AND I WILL GIVE U BRAINLY
a south african white rhinoceros weighs 22658 N and has a top speed of 14 m/s. a bullet from a barrett 0.50 caliber rifle has a weight of 0.4 N and travels with a velocity of 884 m/s. Which object has more momentum in its motion?
Answer:
it is the white rhinoceros because it weighs more then the bullet all though the bullet travels faster once the rhino gets running it is hard to stop because it weighs so much
Pls help me
What is the acceleration of a 10 kg mass pushed by a 5 N force?
Answer:
The answer is 0.5m/s²
Explanation:
Acceleration=Force ÷mass
= 5÷10=0.5m/s²
the diagram below shows the movement of matter in a portion of the water cycle.
what does p most likely represent
rivers
lakes
infiltration
precipitation
Answer:
Infilteration
1-1 A carpet is to be installed in a room whose length is measured to be 12.71 m and whose width is measured to be 5.46 m. Find the area and error in the area of the room. (∆L=0.01)
Answer:
Explanation:
Area of the room = Length × Width
Given
Length = 12.71m
Width = 5.46m
Area of the room = 12.71m×5.46m
Area of the room = 69.3966m²
To get the area of the error, we will use the relationship;
∆A/A = {∆L/L + ∆W/W}
∆A/A = {0.01/12.71 + 0.01/5.46}
∆A/A = {0.0007868+ 0.001832}
∆A/A = 0.0026182
∆A = 0.0026182A
Since Area A = 69.3966m²
∆A = 0.0026182(69.3966)
∆A ≈ 0.1817m²
Hence error in the area of the room is 0.1817m²
The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational field constant g = 9.8 N/kg. Calculate the maximum pressure created by brick
Answer:
[tex]P=3.61\times 10^{-3}\ Pa[/tex]
Explanation:
Given that,
Mass of a brick, m = 3.1 kg
The dimensions of the brick 225 m x 112 m x 75 m
We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :
[tex]P=\dfrac{F}{A}[/tex]
F = mg
A = area with minimum dimensions i.e. 112 m x 75 m
Pressure is maximum when the area is least.
So,
[tex]P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa[/tex]
So, the maximum pressure created by brick is [tex]3.61\times 10^{-3}\ Pa[/tex].
the filament of an electric lamp, which draws a current of 0.5 a is used for 2 hours. calculate the amount of charge flowing through the circuit
Answer:
I = 0.25 AND T= 4 HOURS, Q = ??
multiply both min and sec , 240 and 60
we get 1400 sec
the formula for current is I = Q/T
substitute the given data in the formula and simplify it
so , Q = 3600C
the force F is given in terms of time 'y'all and displacement 'X' by the equation F=AsinBx+CsinDt. what is the dimension of D/B?
Answer:
D/B ahs units of Length over Time
Explanation:
Notice that B is multiplying "x" (displacement) as argument of the sine function, therefore it has to have units of the reciprocal of Length.
Also the constant D is multiplying "t" as argument of the sine function, and as such, it must have units of the reciprocal of time.
Therefore, the quantity D/B must have units of Length over Time.
If a system does 63.0 kJ of work on its surroundings and releases 105 kJ of heat, what is the change in the internal energy of the system, in kJ
Answer:
-42 kJ
Explanation:
Q = ΔE + W
W = -63.0 kJ
Q = -105 J
so -105 = ΔE + (-63)
ΔE = 63 - 105 = -42 kJ
A system does the work of 63 kJ and releases 105 kJ of heat, then the change in internal energy will be -42 kJ.
What is heat?When a thermodynamic system's boundary is crossed by a form of energy due to a temperature differential, that form of energy is referred to as heat. Heat is not present in thermodynamic systems.
In the right-hand image, a metal bar is "conducting heat" from its hot end to its cold end. However, if the metal bar is thought of as a thermodynamic system, then the energy moving within the metal bar is what is being described as "conducting heat" instead is called internal energy.
Q = Δ E + W
W = -63.0 kJ
Q = -105 J
Then,
-105 = Δ E + (-63)
ΔE = 63 - 105 = -42 kJ
Therefore, the change in internal energy will be -42 kJ.
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Please help 50 points: A ball is thrown straight up, from 3 m above the ground, with a velocity of 14m/s. When does it hit the ground? Use vertical motion formula.
Projectile Motion for an Object Launched at an Angle
When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.
Explanation:
and Thais
Projectile Motion for an Object Launched at an Angle
When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.
Projectile Motion for an Object Launched at an Angle
When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.
What is the name of the area around a charged object where the object can exert a force on other charged objects?
A) electric field
B) electric charge
C) electric induction
D) electric force
The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field. Option A is correct.
What is an electric field?An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.
The electric field formula is as follows:
E = F /Q
Where,
The electric field is denoted by the letter E.
F is the electric force
The charge is Q.
The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field.
Hence option A is correct.
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In which soil layer do plant seeds germinate and plant roots thrive?
subsoil
organic
bedrock
topsoil
Answer: Topsoil
Explanation:
Bio
Answer:
topsoil
Explanation: