The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing

Answers

Answer 1

Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off


Related Questions

Look up the specs on a c6 rocket engine. How many C6 engines would it take to launch Mr. Blazey (90kg)
from the elevation of Boulder to the elevation of longs peak? (3 points) What would the max power be? (3
points) The max acceleration? (3 points) For all 12 points, you'll need to account for the mass of the added
rockets (you can assume their mass declines linearly over their burn and is O after they finish burning).

Answers

Answer:

The Estes C6-0 engine is a booster stage engine designed for model rocket flight and has to be used with a standard engine. This engine is for flights in rockets weighing less than 4 ounces, including the engines. Each package includes 3 engines, 4 starters and 4 plugs.

7.2
8
How is kinetic
molecular
model of matter helpful in
differentiating various states
of matter?
V

Answers

Answer:

The kinetic molecular theory of matter asserts that: Matter is made up of particles that are continually moving. All particles contain energy, however the energy fluctuates depending on the temperature the sample of matter is in. This in turn decides whether the material exists in the solid, liquid, or gaseous form.

Explanation:

Hope it helps:)

Because it helps us figure out differences of

What is the effect of erosion?

A. New land forms at the mouth of a river.
B. New land forms at the top of a mountain.
C. A mountain forms.
D. A fossil is created.

Answers

The answer is A new land forms at the mouth of a river

On clear day, sunlight delivers approximately 1000 J each second to a 1 m2 surface; smaller areas receive proportionally less--half the area receives half the energy. A 12% efficient solar cell, a square 12 cm on a side, is in bright sunlight.

How much electric power does it produce?

Answers

The direct proportions rule allows to find the result for the energy produced by a solar cell is:

        E = 1,728 J

       

The efficiency of a solar cell is the percentage of incident energy that transforms into electricity.

The direct  proportions rule or three rule stable that if two quantities are proportional the product remains constant.

They indicate that the length of the solar cell is l = 12 cm = 0.12m. Let's find the area of ​​the solar cell.

        A = l²

        A = 0.12²

        A = 1.44 10⁻² m²

Let's use a direct proportion rule. If 1 m² receives 1000J of energy, how much does an area of ​​1.44 10⁻² m² receive?

        Energy_cell = 1000 J ( [tex]\frac{1.44 \ 10^{-2}}{1}[/tex] )

        Energy_ cell = 14.4 J

Let's use another direct ratio rule for efficiency.

       [tex]Energy_{produced} = Energy_{cell} \frac{12}{100} \\Energy_{produced} = 14.4 0.12 \\Energy_{produced} = 1.728 J[/tex]

   

In conclusion using the direct proportions rule we can find the result for the energy produced by a solar cell is:

        E = 1,728 J

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When an alpha particle is emitted from an unstable nucleus, what happens to the atomic number of the nucleus

Answers

Answer:

The answer to your question is the number decreases by 4.

Explanation:

I hope this helps and have a great day!

a wave travels at a constant speed. how does the wavelength change if the frequency is reduced by a factor of 3? assume the speed of the wave remains unchanged.
A. the wavelength decreases by a factor of 3
B. the wavelength does not change
C. the wavelength increases by a factor of 3
D. the wavelength increases by a factor of 9

Answers

Answer:

b

Explanation:

when the wavelength increase it doesnt affect the frequency of a wave.

Answer: The wavelength increases by a factor of 3

Explanation:

3. What can you infer about the position of the galaxies 100 million years before this telescope photo was taken

Answers

The galaxies are in constant motion so it can be inferred that their position will not be the same as a hundred million years ago.

A galaxy is a term to refer to the set of stars, gas clouds, planets, cosmic dust, dark matter, and energy gravitationally united in a more or less defined structure in the universe.

Galaxies are in constant motion because the elements that make them up are not static at any time; The galaxies rotate around the center of the galaxy. If they were still, the gravitational attraction would cause them to immediately fall towards the center of the galaxy: it is the same that would happen to the Earth and the other planets if they stopped rotating around the Sun, they would fall towards the Sun.

According to the above, it can be inferred that the galaxies after a while have moved from the place where they were last seen.

Note: This question is incomplete because there is some missing information. However, I can answer based on my general prior knowledge.

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A 5 kg bowling ball travelling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of larger ball after the collision? Hint: Use the conservation of momentum equation to solve this problem.

Answers

Answer:

  1.5 m/s

Explanation:

Conservation of momentum means the momentum of the system before the collision is the same as after.

The before, after momentum of each ball is ...

  5 kg ball: (5 kg)(2 m/s), (5 kg)(-1 m/s)

  10 kg ball: (10 kg)(0 m/s), (10 kg)(v)

The sum of the "before" products is the same as the sum of the "after" products:

  (5 kg)(2 m/s) +0 = (5 kg)(-1 m/s) +(10 kg)v

  (10 +5) kg·m/s = (10 kg)·v . . . . . add (5 kg)(1 m/s) to both sides

  v = (15 kg·m/s)/(10 kg) = 1.5 m/s

The speed of the larger ball will be 1.5 m/s. Its direction of motion will be the opposite of that of the 5 kg ball after the collision.

2. Match the term to the definition
1. Reversibility
a. A break between activities during a workout.
2. Overload
3. Progression
4 Duration
5. Rest
b. Length of an individual workout.
c. The Improvement seen when you are training will be lost if you stop
training.
d. Moving forward through a sequence to gradually build up the body.
e Number of training sessions per week.
f. Level of difficulty of your workout.
9. Improvements will only be seen in the areas that you work on.
h The time between workouts that allows your body to heal and adapt to
the stress from your workout.
6. Recovery
7. Frequency
8. Specificity
1. Increase the amount of stress you put on your body.
9. Intensity

Answers

A is rest
B is duration
C is reversibility
D is progression
E is frequency
F is intensity
G is specificity
H is recovery
I is overload
Reversibility is the over load of the progression

Over half the global population faces a shortage of clean water. Which example is a point source water pollutant? pesticide run-off from farmers’ fields a sewer pipe draining directly into a river road oil washing into sewer drains, and eventually reaching waterways erosion from a denuded slope after a heavy rainfall

Answers

An example of a point source water pollutant is a sewer pipe draining directly into a river.

According to the United States Environmental Protection Agency, a  point source pollution is defined as;  “any single identifiable source of pollution from which pollutants are discharged, such as a pipe, ditch, ship or factory smokestack.”

Hence, an example of a point source water pollutant is a sewer pipe draining directly into a river. The pollution is coming from an easily identifiable source which is a sewer pipe connected to a river directly.

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To become a healthy individual, a person must have a properly executed routine to achieve his/her fitness goals. On the contrary, in what instance does a person become unhealthy

Answers

unhealthy meals & skipping workouts

The force of earth’s gravity is 10N downward. What us the acceleration of a 15kg backpack if lifted with a a 15N force?

Answers

Answer:

F-F(gr) = ma

a= {F-F(gr)}/m =

=(15-10)/15=0.33 m/s² (upward)

describe the forces acting on a car as it movies along a level highway in still air at a constant speed

Answers

Answers

The car's forward motion is opposed by the friction between the road and the tires and by the resistance of the air.


The axis of the earth is
Tilted about 23.5 degrees
Vertical
Vertical

Answers

Answer:

The axis of rotation of the Earth is tilted at an angle of 23.5 degrees away from vertical, perpendicular to the plane of our planet's orbit around the sun. The tilt of the Earth's axis is important, in that it governs the warming strength of the sun's energy.

Explanation:

can i get brainliest

HELP ASAP!!!!! Choose all the answers that apply. Technology A)influences science
B)helps scientists observe fast phenomena
C)is the same as science
D) influences history
E)helps scientists observe slow phenomena​

Answers

A, C, D, but there’s a possible point where b and e could be up there

PLEASE HELP I NEED TO PASS THIS CLASS ​

Answers

Can you please tell me what is the problem that we need to answer?

Answer:

I think that the answer is 4.318 as a=f/p

An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg. If this force serves as the action force, what is the reaction force in the action–reaction pair?

Answers

Answer:

Equal reaction from the pair in every action there's an equal and opposite reaction

The item will keep moving at a consistent speed if the object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

What is gravitational force?

All mass-bearing objects are attracted by gravitational force. Because it consistently attempts to bring masses together rather than push them apart, the gravitational force is referred to as attractive.

As we know, the gravitational force is given by:

[tex]\rm F = \dfrac{Gm_1m_2}{r^2}[/tex]

Where G is the gravitational constant.

m1 and m2 are masses.

r is the distance between the masses.

It is given that:


An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

As we know,

An object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg and the item will keep moving at a consistent speed.

Thus, the item will keep moving at a consistent speed if the object is at rest on a tabletop. Earth pulls downward on this object with a force equal in magnitude to mg.

Learn more about the gravitational force here:

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#SPJ2

If you were told an atom was an ion, you would know the atom must have a?
A neutral charge
B charge
C negative charge
D positive charge

Answers

Answer:

its b it must be charge

Explanation:

A rod of length 0.82 m, rotating with an angular speed, 4.2 rad/s, about axes that pass perpendicularly through one end, has a mass of 0.63 kg, which is distributed uniformly along its length. Find the kinetic energies of the rod.

Answers

Answer:

Explanation:

KE = ½Iω²

ΚΕ = ½(mL²/3)ω²

ΚΕ = ½(0.63(0.82²)/3)4.2²

ΚΕ = 1.24541928

KE = 1.2 J

A magnet is located above circular current. What is the direction of the magnetic force on the magnet

Answers

The magnet is attracted to the ring since the north pole of the current loop is above the ring and the south pole is below the ring.

6. A 15.53 kg bag of soil falls 5.50 m at a construction site. If all the energy is retained by the soil in the bag, how much will its temperature increase

Answers

The increase in the temperature of the soil when bag fall from the given height is 0.065 ⁰C.

The given parameters:

mass of the bag, m = 15.53 kgheight of fall, h = 5.5 mspecific heat capacity of soil, C = 0.200 kcal/kg ⁰C

Apply the principle of conservation of energy as follows;

[tex]mgh = mC \Delta T\\\\gh = C \Delta T\\\\\Delta T= \frac{gh}{C}[/tex]

Convert the value of C in kcal/kg ⁰C  to  J/kg ⁰C

1 kcal = 4180 J

[tex]0.200 \ kcal/kg ^0 C= 0.2 \times 4180 (J/kg ^0C) = 836 \ J/kg^0 C[/tex]

The increase in the temperature of the soil is calculated as follows;

[tex]\Delta T= \frac{gh}{C}\\\\\Delta T= \frac{9.8 \times 5.5}{836} \\\\\Delta T= 0.065 \ ^0C[/tex]

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what is the acceleration of a 10 kg mass pushed by a 5N force?

Answers

Answer:

0.5

Explanation:

F = ma

5 = 10 a

a = 5/10

a = 0.5

We have seen in earlier readings how to determine the speed of a wave on a string. What will happen to the wavelength of a sinusoidal wave on a string if the tension in the string is increased (assuming we keep the frequency of the wave the same)

Answers

This question involves the concepts of tension in a string and the wavelength of the wave in a string.

The wavelength of a sinusoidal wave will "increase by square power" on a string if the tension in the string is increased when the frequency is kept constant.

The speed of a wave on a string is given by the following formula:

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where,

v = speed of wave = fλ

f = frequency of the wave

λ = wavelength of the wave

T = tension force

μ = linear mass density of the string

Therefore,

[tex]f\lambda=\sqrt{\frac{T}{\mu}}\\\\T = f^2\lambda^2\mu[/tex]

It is given that the frequency is kept constant. The linear mass density is also constant for a string. Therefore,

[tex]T=(constant)\lambda^2\\T\ \alpha\ \lambda^2[/tex]

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An Olympic skier glides down a hill, inclined at 25° to the horizontal, at 18 m/s.

How long did it take for her to ski 800 m to the bottom of the hill?

44.4 s

10.5 s

4.0 s

1.6 s

Answers

Divide total meters by meters per second:

800 m / 18 m/s = 44.4 seconds

Answer: 44.4

The Greek root astro means "stars." Use the context clues to choose the correct definition of the word astronomer. According to the astronomer, the bigger the telescope, the more detail we can see in the images. O A. a person who studies astronauts O B. a person who studies the stars O C. a person who tells the future O D. a person who studies other people​

Answers

Answer:

b, it's a pretty easy explanation

What is the maximum height above ground a projectile of mass 0.79 kg, launched from ground level, can achieve if you are able to give it an initial speed of 80.3 m/s?

Answers

From kinematic, the maximum height above ground a projectile of mass 0.79 kg, launched from ground level can achieve is 329 meters approximately.

The parameters given from the question are

mass m = 0.79kg

initial speed U = 80.3 m/s

Maximum height H = ?

The object will be going up under the influence of gravity. Acceleration due to gravity g = -9.8m/[tex]s^{2}[/tex]

At maximum height, final velocity V = 0  

From kinematic formula, the best formula to use is

[tex]V^{2} = U^{2} - 2gH[/tex]

Substitute all the parameters into the equation

0 = [tex]80.3^{2}[/tex] - 2 x 9.8 x H

19.6H = 6448.09

H = 6448.09 / 19.6

H = 328.98 m

Therefore, the maximum height above ground a projectile of mass 0.79 kg, launched from ground level can achieve is 329 meters approximately.

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Over a period of 3 seconds, a speedboat accelerates uniformly from 20 m/s
to 50 m/s. What is the acceleration of the speedboat relative to the shore?

Answers

The acceleration of the speedboat relative to the shore is 10m/s²

Acceleration is the change in velocity of an object with respect to time. Mathematically;

Acceleration = change in velocity/Time

Change in velocity = 50 - 20

Change in velocity = 30m/s

Time = 3secs

Substitute into the formula to have:

acceleration = 30/3

acceleration = 10m/s²

Hence the acceleration of the speedboat relative to the shore is 10m/s²

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a police finds skid marks 60m long on a highway showing where a car made an emergency stop. assuming that the acceleration was -10m/s2. how fast was the car going and did it exceed the sooed limit of 80km/h?​

Answers

the answer is 029 and 177 hours later i’m going on my grandma to

Answer:

029 and 177

simple luv:)

Explanation:

II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizontal surface. If the cord will break when the tension in it exceeds 60 N, what i~ the maximum speed the ball can have

Answers

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

mv²/r = T

Solve for v:

v = √rT/m

v = 13.96 m/s

A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the gas is the difference between these two masses. The gas is squeezed out of the bag to determine its volume by the displacement of water. What is the actual weight of the gas

Answers

The actual weight of the gas = apparent weight + weight.

The actual weight = [tex]W_{A}[/tex] + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = [tex]W_{A}[/tex]

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/[tex]m^{2}[/tex]

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  [tex]W_{A}[/tex] + W

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