The reason for the trend in the previous question is because Bromine is _________electron density from the carbon the proton is on, resulting in the proton being ___________, thus the proton nuclei is_________ effected by the applied magnetic field leading to a greater difference in energy of the nuclei's spin states.

Answer:

m=2.0mol/kg

Explanation:

Hello there!

In this case, according to the formula to compute molality, which requires moles of solute (HCl) and kilograms of solvent (water), we first compute the moles of the former with its molar mass as shown below:

[tex]n=\frac{18.2g}{36.46g/mol}= 0.50mol[/tex]

And then the kilograms of water:

[tex]\frac{250.g}{1000g/kg} =0.250kg[/tex]

Finally, the molality turns out to be:

[tex]m=\frac{0.50mol}{0.250kg}\\\\m=2.0mol/kg[/tex]

Best regards!

Answer:

Pollen

Explanation:

Pollen is a powdery substance consisting of pollen grains which are male microgametophytes of seed plants, which produce male gametes (sperm cells).

Answer:

Fractional distillation of crude oil in laboratory

Explanation:

In general, we can sort them according to their boiling point.

We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.

Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.

Answer: The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M

Explanation:

[tex]KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2[/tex]

[tex]2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI[/tex]

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]    

[tex]\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol[/tex]

1 mole of [tex]KIO_3[/tex]  produces = 3 moles of   [tex]I_2[/tex]

[tex]2.8\times 10^{-4}[/tex] moles of [tex]KIO_3[/tex] produces = [tex]\frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex]  

Now 1 mole of [tex]I_2[/tex] uses = 2 moles of [tex]Na_2S_2O_3[/tex]

[tex]8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex] uses =  [tex]\frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}[/tex]  moles of [tex]Na_2S_2O_3[/tex]

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M[/tex]

The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M  

Answer:

Explanation:

From the information given:

left half-cell = 3.00 mM     M(NO)

right half-cell = 3.00 M       M(NO)

Since the electrode are the same in both cells, then the concentration for the cell are also the same.

Negative electrode = Anode = lower concentration = 3.00 mM

Positive electrode = cathode = higher concentration = 3.00 M

Thus, right half cell will be postive electrode.

To determine the concentration cell:

[tex]Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)[/tex]

SInce [Cathode] > [anode],

[tex]R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol[/tex]

n = 3

[tex]Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}[/tex]

[tex]\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}[/tex]

Explanation is in the file

tinyurl.com/wpazsebu

Answer:

d

Explanation:

answer d makes the equation balance

Explanation:

this is the answer of your question .

hope it helped you

Answer:

V=2.33361811192L or 2.3x10

Explanation:

Using Charles law V1/T1=V2/T2 Remember to convert celcius to kelvin by using the standard temperature 273.15K

3L/(78C+273.15)=V/273.15

Answer:

3.25 moles of H2O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2HCl + Ca(OH)2 —> CaCl2 +2H2O

Now, we can obtain the number of mole H2O produced from the reaction as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 2 moles of H2O.

Therefore, 3.25 moles of HCl will also react to produce 3.25 moles of H2O.

Therefore, 3.25 moles of H2O were produced from the reaction.

Answer:

a

Explanation:

dont have to explain

Answer:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Explanation:

Hello there!

In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Best regards!

Explanation:

The general equation for an endothermic reaction is: Reactants + Energy → Products.

Hope it helps :)❤

The equation represents an endothermic reaction is reactants + energy

products.

Endothermic reactions are chemical reactions in which the reactants soak up warm strength from the surroundings to form products.

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Answer:

pH = 5.85

Explanation:

The reaction of methylamine with HCl is:

CH₃NH₂ + HCl → CH₃NH₃⁺ + Cl⁻

As the titration was made with two solutions with the same molarity, the final concentration of the CH₃NH₃⁺ ion is 0.100M ([CH₃NH₃⁺] = 0.100M)

Then, the conjugate acid will be in equilibrium with water as follows:

CH₃NH₃⁺(aq) + H₂O(l) ⇄ CH₃NH₂(aq) + H₃O⁺(aq)

And the equilibrium constant, Ka, of this reaction is:

Kw/Kb = Ka =  1.0x10⁻¹⁴ / 5.0x10⁻⁴= 2x10⁻¹¹

2x10⁻¹¹ =  [CH₃NH₂] [H₃O⁺] / [CH₃NH₃⁺]

As both CH₃NH₂ and H₃O⁺ comes from the same equilibrium we can say:

[CH₃NH₂] = [H₃O⁺] = X

And as we know [CH₃NH₃⁺] = 0.100M:

2x10⁻¹¹ =  [X] [X] / [0.100M]

2x10⁻¹² = X²

X = 1.414x10⁻⁶M = [H₃O⁺]

And as pH= -log [H₃O⁺]

Answer:

Molar mass of N3H4 name is 84.0761 g/mol

Convert between N3H4Na(CH3) weight and moles

The chemical name for the formula N₃H₄  is Trinitrogen Tetrahydride

        C , P ,  N ,  H ,  S ,  I ,  Br ,  Cl ,  O ,  F .

        So Now for N₃  =  Tri Nitogen

        and for H₄   =  Tetra Hydride

 Therefore the chemical name is Trinitogen Tetrahydride.

To know more about Chemical Compound

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Answer:

[tex]\huge\boxed{BUTANE}[/tex]

Explanation:

Since it is alkane, The suffix used will be "-ane".

Prefix for 4 carbons => "but-"

Hence, the name:

BUTANE

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

There will be a transfer of thermal energy (heat) from the hot metal plate to the surrounding air. This transfer of energy equates to a transfer of kinetic energy in the molecules. As the plate loses heat, the molecules in the plate will lose kinetic energy and slow down. As the surrounding air gains heat, the molecules will gain kinetic energy and speed up.

Answer: C

Explanation:

Answer:

The peritoneum

Explanation:

The peritoneum is the serous membrane that surrounds several organs in the abdominopelvic cavity. The tunica vaginalis is the serous membrane, which surrounds the male gonad, the testis. The two layers of serous membranes are named parietal and visceral. Between the two layers is a thin fluid filled space.

hope it helps, and pls answer this https://brainly.com/question/22410918

tysm if u do ill give brainliest :D

Answer:

standard sea- level pressure,by definition,equals 760 mm of Mercury,14.70 pounds per square inch, 1,013.25x10³ dynes per square centimetre, 1,013.25 millibars,one standard atmosphere,or 101.325 kilopascale

l hope it's helpful for u....

Answer:

answer is TE

Explanation:

Answer:

Tellurium is more reactive than Oxygen

Answer:

write the balanced chemical equation of the reaction between strong acid and weak base also mention the types of salt obtained in the reaction

Explanation:

HCl → H+(aq) + Cl−(aq) (100%)

Any acid that dissociates 100% into ions is called a strong acid. If it does not dissociate 100%, it is a weak acid. HC2H3O2 is an example of a weak acid:

HC2H3O2→ H+(aq) + C2H3O2−(aq) (~5%)

Because this reaction does not go 100% to completion, it is more appropriate to write it as an equilibrium:

HC2H3O2 ⇄ H+(aq) + C2H3O2−(aq)

As it turns out, there are very few strong acids, which are given in Table 12.2 “Strong Acids and Bases”. If an acid is not listed here, it is a weak acid. It may be 1% ionized or 99% ionized, but it is still classified as a weak acid.

Answer:

There's no single cause of depression. It can occur for a variety of reasons and it has many different triggers. For some people, an upsetting or stressful life event, such as bereavement, divorce, illness, redundancy and job or money worries, can be the cause. Different causes can often combine to trigger depression. For example, you may feel low after being ill and then experience a traumatic event, such as a bereavement, which brings on depression.

Explanation:

The reaction is

2Fe+3Cl2

→2FeCl3

So the mol ratio

Cl2÷FeCl3=3÷2

So for 14 mols of F

eCl3

we need 32×14=21

mols of Cl2

Answer:

i always wear shoes without socks

Explanation:

Answer:

It depends. what hot spot are you looking for?

Answer:

A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.

Explanation:

Hope this is what you mean be hot spot!

I hope this helps you!  

Answer:

Explanation:

The standard molar mass is:

For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol

For triphenylphosphine  = 262 g/mol

For  ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol

The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]

Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]

= 5.1235 g

thus, since 424.5 g yield produce from 162.5 g

∴

5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]

= 1.9613 g of alkyl halide (-chloro) required.

Also, since 424.5 g yield produce from 262 g phosphine

∴

5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]

= 3.1622 g of triphenylphosphine required.