This question involves the concept of artificial gravity.
The effective gravitational strength at outer rims is "0.9 g".
Artificial GravityThe effective gravitational strength at the outer rims can be given by the following formula:
[tex]v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r[/tex]
where,
[tex]a_c[/tex] = effective gravitational strength = ?v = rotational speed = 1 rev/min = 0.0167 rev/sr = radius = diameter/2 = 1 mile/2 = 0.5 miles = 804.672 mTherefore,
[tex]a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g[/tex]
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The temperature of a cup of coffee varies according to Newton's Law of Cooling: dT dt equals negative k times the quantity T minus A, where T is the temperature of the coffee, A is the room temperature, and k is a positive constant. If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C, find the temperature, to the nearest degree Celsius of the coffee after 4 minutes.
74
67
60
42
Answer:
Explanation:
Writing out the Newton's Law pf Cooling:
dT/dt = -k * (T - A),
where T is the temperature of the coffee, A is the room temperature, and k is a positive constant.
If the coffee cools from 100°C to 90°C in 1 minute at a room temperature of 25°C,
T = 100
A = 25
dT = 100 - 90 = 10
dt = 1
Putting the figures into the equation:
10/1 = -k * (100 - 25)
k = -10/75°C
After 4 minutes, dT/4 = 10/75 (100 - 25) = 10
dT = 40
Temperature after 4 minutes = 100 - 40 = 60°C
The temperature of a cup of coffee varies according to Newton's Law of Cooling, the temperature of the coffee after 4 minutes is approximately 67°C.
To tackle this problem, we can apply Newton's Law of Cooling's differential equation and solve it using variable separation.
dT/dt = -k(T - A)
At t = 0 (initial condition): T = 100°C
At t = 1 minute: T = 90°C
dT/dt = -k(T - A)
At t = 0: dT/dt = -k(100 - 25)
So,
-10 = -k(75)
k = 10/75
Separating variables and integrating, we have:
1/(T - A) dT = -k dt
∫(1/(T - A)) dT = ∫(-k) dt
ln|T - A| = -kt + C
ln|100 - 25| = 0 + C
ln|75| = C
So, the equation will be:
ln|T - A| = -kt + ln|75|
ln|(T - 25)/(75)| = -kt
Now,
ln|((T - 25)/(75))| = -(10/75)(4)
|((T - 25)/(75))| = [tex]e^{(-40/75)[/tex]
T - 25 = ± 75 * [tex]e^{(-40/75)[/tex]
T = 25 ± 75 * [tex]e^{(-40/75)[/tex]
T ≈ 25 ± 42.42
Therefore, the temperature of the coffee after 4 minutes is approximately:
T ≈ 25 + 42.42 = 67.42°C
Thus, the temperature of the coffee after 4 minutes is approximately 67°C.
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What does it mean to say that mass is conserved during a physical change
Answer: When there is no change in chemical composition of a substance then it is known as physical change. When we say that mass is conserved during a physical change then it means that total mass of the substance or object will remain the same from beginning till the end
Answer:
Sample Response: When a physical change occurs, the mass of the substance is conserved. This means that the total mass of the substance remains the same from beginning to end. The physical properties of the substance, such as size and shape, may change, but the amount of matter in the substance does not change.
Explanation:
During meiosis maternal and paternal chromosomes that occur in a gamete line up and exchange segments in a process called crossing over. Then they are randomly shuffled as the cell divides. This process results in
Explanation:
Crossing over is the swapping of genetic material that occurs in the germ line. During the formation of egg and sperm cells, also known as meiosis, paired chromosomes from each parent align so that similar DNA sequences from the paired chromosomes cross over one another.
Answer:
Explanation:
After cross-over, the chromosomes are randomly shuffled to the daughter cells as the cell divides. This process results in in gametes that with unique combinations of chromosomes and is called independent assortment.
difference between text-talk novel and flash fiction?
See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c
c.h.*.t.s.
Both "text-talk novels" and "flash fiction" are forms of written literature, but they have distinct characteristics and purposes.
Text-Talk Novel:
A text-talk novel, also known as a "chat novel" or "text-message novel," is a narrative written in the style of text messages or chat conversations. These novels are typically composed of short, informal messages exchanged between characters, presented in a way that resembles conversations on messaging apps. Text-talk novels often use emojis, abbreviations, and informal language to create a sense of immediacy and relatability. They are designed to be read on mobile devices and appeal to readers who are used to communication through texting and social media platforms. Text-talk novels often cater to a younger audience and can cover various genres, from romance to mystery.
Flash Fiction:
Flash fiction, also known as "microfiction," "short-short stories," or "sudden fiction," refers to extremely short works of fiction characterized by their brevity. Flash fiction stories are typically no longer than 1,000 words, and often much shorter. Despite their limited length, flash fiction stories aim to convey a complete narrative, evoke emotions, and leave a lasting impact on the reader. Due to their concise nature, flash fiction stories often focus on a single idea, moment, or theme, and they require skillful crafting to create a meaningful story within a tight word count. Flash fiction can cover a wide range of genres and styles, and its brevity challenges writers to distill their storytelling abilities to essentials.
Hence, a "text-talk novel" is a novel written in the style of text messages or chat conversations, aiming to engage readers familiar with mobile communication. On the other hand, "flash fiction" refers to very short stories that convey complete narratives or ideas within a limited word count, challenging writers to create impactful stories in a condensed format.
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Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?
For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as
V1=4.977m/s
What is the velocity of car A after the collision?Generally, the equation for the Velocity of car A is mathematically given as
[tex]V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2[/tex]
Therefore
[tex]V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85[/tex]
V1=4.977m/s
In conclusion, The velocity of car A after the collision
V1=4.977m/s
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Answer:3.74
Explanation:
it was given same goes for bumper car b
Reuptake means that:
Answer:
it means absorption by a presynaptic nerve ending of a neurotransmitter that it has secreted.
Explanation: I hoped that helped please leave a 5 rate and thanks. Have a great day .
what were formed after the big bang theory?
Answer:
neutrons protons electrons
Explanation:
after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.
If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the change in the internal energy of the system, in kJ
The change in the internal energy of the system is 110 kJ.
What is internal energy?Internal energy is defined as the energy associated with the random, disorder motions of molecules.
calculate the change in internal energy, we apply the formula below.
Formula:
ΔU = Q-W.................... Equation 1Where:
ΔU = Change in internal energyQ = Heat absorbed from the surroundingsW = work done by the systemFrom the question,
Given:
Q = 115 kJW = 45. 0 kJSubstitute these values into equation 1
ΔU = 155-45ΔU = 110 kJHence, The change in the internal energy of the system is 110 kJ.
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Answer:
110.0kJ
Explanation:
The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.
.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.
ΔE=q+w
In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.
ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ
In order to compare the thermal conductivities of two different insulators, a scientist pours hot water into two
beakers.
The different insulators are wrapped around the beakers.
The scientist records the initial temperatures of the hot water.
a) State two factors that should be kept constant in order to make the experiment fair.
A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C. Its efficiency is
A. 13%
B. 39 %
C.61%
D. 88 %
E. 90 %
The efficiency of a carnot engine with absorb temperature and exhaust temperature is 13%. The correct option is A.
What is Efficiency?The efficiency is defined as the work done by the engine divided by the heat supplied.
So, efficiency η = 1 - T₁/T₂
Where T₁ is the lower temperature and T₂ is the higher temperature.
A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C
Substitute the value into the expression , we get
η = 1 -(77+273) / (127+273) x 100 %
η = 12.5 %
or
η = 13 %
Thus, the efficiency of the carnot engine is 13%.
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An unbalanced force of 20 N is applied to a 10 kg mass. What is the acceleration of the mass?
Answer:
2 m/s2
Explanation:
Newton's 2nd law:
F=ma
20 N= (10 kg)a
a= 2 m/s2
Select the correct answer.
What is proper technique for lifting?
A.
Bend your back
B.
Bend at your knees and lift with your legs.
C.
Focus your power from your back.
D.
None of the above
Answer:
B
Explanation:
Answer:
i think it's either B or C
Explanation:
The driver of a car steps on the brakes, and the velocity drops from 43 m/s due east to 3.38 m/s due east in a time of 70seconds. What is the acceleration?
Answer:
Explanation:
initial velocity, u = 43 m/s
final velocity, v = 3.38 m/s
time, t = 70 sec
acceleration, a = v - u / t
3.38 - 43 / 70
= -39.62/ 70
= -0.56 m/s^2
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A car driving down a street has a kinetic energy of 32,000 J. If the car has a mass of 1,600kg, at what velocity is the car moving?
Explanation:
The mechanical energy can be expressed as kinetic and potential energy, given by the equation;
ME=KE+PE
but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0
ME=KE
The equation of KE=0.5mv²
ME=0.5mv²
32 000=0.5(1600)v²
[tex]v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} [/tex]
[tex]v {}^{2} = \frac{32 \: 000}{800} [/tex]
[tex] {v}^{2} = 40[/tex]
[tex]v = \sqrt{40} = 6.324[/tex]
v=6.324 m/s :)
Why is the international system of measurement helpful?
a.
They are not in English.
c.
All scientists can use them.
b.
No scientists can use them.
d.
They are easy to remember.
Please select the best answer from the choices provided
A
B
C
D
International system of measurements in helpful because all scientists can use them
International System of measurement abbreviated SI is the modern most widely accepted system of unit of measurement
An object is pushed at an angle of 42˚ by a force of 135 N through a distance of 829 cm. Find the work done by the object.
The work done by the object is 831.69 J.
What is work?Work can be defined as the product of mass and distance.
To calculate the work done by the object, we use the formula below
Formula:
W = Fdcos∅............ Equation 1Where:
W = Work done by the objectF = Force on the object∅ = Angle.From the question,
Given:
F = 135 Nd = 829 cm = 8.29 m∅ = 42°Substitute these values into equation 1
W = 135×8.29×cos42°W = 831.69 J.Hence, The work done by the object is 831.69 J.
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A balloon with a negative charge of -2.0×10-8 C is held 2 cm (0.02 m) below a rod with a positive charge of 2.0×10-8 C. What is the force between the balloon and the rod?
The force of attraction between the balloon and the rod is 9 x 10⁻³ N.
Force of attraction between the balloon and the rodThe force of attraction between the balloon and the rod is calculated by applying Coulomb's law as shown below;
[tex]F = \frac{kq_1 q_2}{r^2}[/tex]
where;
r is the distance between the chargesk is Coulomb's constant = 9 x 10⁹ Nm²/C²F = (9 x 10⁹) x (2.0 x 10⁻⁸)²/(0.02)²
F = 9 x 10⁻³ N
Thus, the force of attraction between the balloon and the rod is 9 x 10⁻³ N.
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[tex]\:\:\:\:\:\:\:\:\:\:\star [/tex]We can calculate the force between the balloon and the rod applying "Coulomb's Law". Which states-
[tex]\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ [/tex]
[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
Where-
q₁ and q₂ are the two cahrges.r is the distance between the charges.[tex]\sf \epsilon_{0} [/tex] is the permittivity of free space.K is the Coulomb's Constant.k = 9×10⁹ Nm²/C²As per question, we are given that -
q₁= 2.0 x 10⁻⁸Cq₂= -2.0 x 10⁻⁸CDistance,r = 0.02 mNow that required values are given, so we can substitute the values into the formula and solve for Force -
[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= 9\times 10^9 \times \dfrac{-2\times 10^{-8}\times 2\times 10^{-8} }{(0.02)^2}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{4\times10^{-16}}{4\times 10^{-4}}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{\cancel{4}\times10^{-16}}{\cancel{4}\times 10^{-4}}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16} \times 10^{4}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16+4} \\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-12} \\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{9-12}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{-3}\\ [/tex]
[tex] \:\:\:\:\:\:\:\longrightarrow \sf \underline{Force_{(air)} = -9\times 10^{-3}\:N}\\ [/tex]
Therefore,the force between the balloon and the rod is -9 x 10⁻³ N.A Home Depot worker pushes a lumber cart loaded with a mass of 115 kilograms of lumber. If he accelerates the cart with an acceleration 5.6m/s^2 what is the amount of force the worker applied.
Answer:
use math.way
Explanation:
i solved it.
Stars appears to move from east to west because
A. all stars move from east to west
B. the earth rotates from west to east
C. the earth rotates from east to west
D. the background of the stars moves from west to east
Answer:
The earth rotates from West to east
Explanation:
Every planet in our solar system rotates around their axis in West to east direction.Only Venus is the only planet which rotates from east to westThe projectile motion of an object can
be described by two independent
vector components that are
______
Answer:
perpendicular
Explanation:
The projectile motion of an object can be described by two independent vector components that are horizontal and vertical motion.
What is projectile motion?The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.
The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.
The projectile's motion is divided into two parts: horizontal and vertical motion.
Because perpendicular motion components are independent of one another, these two motion components may be treated individually.
Hence two independent vector components are horizontal and vertical motion.
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An experiment is set up to determine the speed of charged particles as they move through a region that is traversed by a constant electric and a constant magnetic field. The particles are moving toward the right of the page when they encounter the region. The electric field points toward the top of the page, and the magnetic field points out of the page. Required:
Predict how the positively and negatively charged particles of various speeds will behave in this experiment
The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.
What are charged particles?Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.
Generally, the Magnetic area points internal the airplane so through fleming left hand rule is
F = q ( V x B). Ie
hence
qVB = qE
V= E/B then no deflection.
V > E/B then magnetic pressure is dominant over electric powered force.
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median of 18 24 17 21 24 16 29 18
Answer:
19.5
Explanation:
16,17,18,18,21,24,24,29
(fourth (18) and fifth(21)) ÷2=
(18+21)÷2=
39÷2=
19.5 is median
the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum
Answer:
ratio
Explanation:
Apex Verified
which types of star cluster is shown
Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.
Which of the following exerts the most pressure while resting on a floor?
a. a 25 N cube with 1.5 m sides
b. a 15 N cylinder resting vertically with a base radius of 1.0 m
c. a 25 N cube with 2.0 m sides
d. a 25 N cylinder resting vertically with a base radius of 1.0 m
The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as
P=16.6pascal, Option D is correct
Which of the following exerts the most pressure while resting on a floor?Generally, the equation for the Pressure is mathematically given as
P=force/Area
Therefore, In considering the one with the most pressure we look at the one with the most force/Area
In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides
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if a metal block has as a volume of .035 mL, and a mass of 765.0 mg, what is the density of the block in g/mL?
Given parameters:
Volume of metal block = 0.035mL
Mass of block = 765mg
Unknown:
Volume of metal block = ?
Solution:
Density is the mass per unit volume of a substance.
Density = [tex]\frac{mass}{volume}[/tex]
Mass is the amount of matter in a substance
Volume is space occupied by a substance
Mass of the block in g;
765mg = 765 x 10⁻³ g
= 0.765g
Density = [tex]\frac{0.765}{0.035}[/tex] = 21.86g/mL
The density of the metal block is 21.86g/mL
What do you need to do before you can make a hypothesis?
An astronaut weighs 104 newtons on the moon, where the strength of gravity is 1.6N/kg. What is her mass?
What does refractive index mean?
A rock weighing 250N falls from a height of 16 m and falls towards the ground. Determine the momentum of the rock prior to striking the ground.
Answer: I'm not very good at all. I need help with determine the velocity of an object just before it hits the ground, given the object's mass and the distance it falls. For example, a .060 kg (or 60 g) ball falls from a 12 meter building. Also, assume it is free falling (no air resistance) and the average time it takes to hit the ground it 1.16 seconds.
Explanation: