The temperature is -8 degrees Fahrenheit. The height pressure front increases the temperature to 7 degrees Fahrenheit. By how many degrees did the temperature increase.

(Please show work and explanation)

Answers

Answer 1

Answer:

3 dregreess 5 degrees temperature


Related Questions

PLS PLS PLS PLS HELP :D <33

Answers

Answer:

Value of x = 3

m∠HEB=27°

Step-by-step explanation:

1) CEH and HEB are complementary angles, therefore both of their angles added together will be 90 degrees

2) Set the two equations added together equal to 90 and solve for x

19x+6+9x=90

28x=84

x=3

3) Plug in x into 9x to get HEB

9(3)=27

How do I write 435 in expanded from

Answers

Answer : 400 + 30 + 5

Step - by - step explanation : To write something in expanded form means to write the number individually. " To see the math value of individual digits ".

4 --> Since it's in the hundreds place that means the number is 400 !

3 --> Since it's in the tenths place that means the number is 30 !

5 --> Since it's the first digit that means it stays as the number 5 !

Hope this helped ! <33

Take care happy holidays ! Contact me if you need more help on this ! ( If you want )

what is the output of the function when the input is −3

Answers

It depends on the function. Please add a picture or type your function.

PLS HELP!!!
Express each of these numbers, as a product of two fractions
1/15

Answers

[tex]\dfrac 13 \times \dfrac 15 = \dfrac 1{15}[/tex]

The product of the two fraction numbers whose result is 1/15 will be 1/3 and 1/5.

What is Algebra?

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The result of the product of the two fraction numbers is given below.

1/15

The factor of the number 15 is given as,

15 = 3 x 5

Then the expression is written as,

1/15 = 1/ (3 x 5)

1/15 = (1/3) x (1/5)

The multiplication of the two rational numbers whose result is 1/15 will be 1/3 and 1/5.

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

1/5 of 400 showing work

Answers

1/5 of 400 = 80
400 x 1/5 = 400/5
400/5 = 80

classify the conic section without graphing 3x^2-2xy+3y^2+2x-4y+1=0​

Answers

Circle: When x and y are both squared and the coefficients on them are the same — including the sign.

For example, take a look at 3x2 – 12x + 3y2 = 2. Notice that the x2 and y2 have the same coefficient (positive 3). That info is all you need to recognize that you’re working with a circle.

Parabola: When either x or y is squared — not both.                                              

i am big brain

For f(x) = 2(6)*, find y when x=2.
f(2)=

Answers

Answer:

I believe it is f(2) = 12

Step-by-step explanation:

I don't know if the * symbol is supposed to be an x but if it is, it would be 12x instead of 12.

The given number line shows the solutions to which inequality

Answers

Answer:

B (x-7<-6)

Step-by-step explanation:

x < 1

4х + Зу = — 15
Зу = 2х + 3

Answers

Answer:

(- 3, - 1 )

Step-by-step explanation:

4x + 3y = - 15 → (1)

3y = 2x + 3 → (2)

Substitute 3y = 2x + 3 into (1)

4x + 2x + 3 = - 15

6x + 3 = - 15 ( subtract 3 from both sides )

6x = - 18 ( divide both sides by 6 )

x = - 3

Substitute x = - 3 into (2)

3y = 2(- 3) + 3 = - 6 + 3 = - 3 ( divide both sides by 3 )

y = - 1

solution is (- 3, - 1 )

I think this is the answer

Some help please please

Answers

Answer:

[tex]8\sqrt{2}[/tex]

Step-by-step explanation:

To find the length of an isosceles triangle, you know that the angles of the triangle are 45-45-90, so let's use that triangle theorem.

Therefore, the length of the hypotenuse (BD) is [tex]x\sqrt{2}[/tex], and x is equal to 8 (length of BC).

[tex]x\sqrt{2}[/tex]

x=8

Therefore, [tex]8\sqrt{2}[/tex] would be the length of side BD.

Answer:

oh snap i have this question too sorry cant help :(

Step-by-step explanation:

but i can provide with advice bc is the side down and bd is across us this to your advantage

WARNING: I need any worker or student to be aware that there are alt accounts going around and posting gore on answers. Some of them have the picture of the devil and other disturbing types of images and things. Please be aware of your questions if you see these accounts. Ive just encountered one and I am not putting its username so others won't see his posts. Be careful and aware

Answers

Thank you for spreading this message! Very appreciated :D I’ve never encountered one but I hope not.
Thank for telling everyone about this!

Bidmass working out questions

Answers

Answer:

The answer will be 0

Step-by-step explanation:

Let me know Hope it helps

A bag of marbles has 5 blue marbles, 3 red marbles, and 6 yellow marbles. A marble is drawn from the bag at random. How many possible outcomes are there? O 3 0 5 O 6 O 14​

Answers

Answer:

I think it would be 14 I hope it is right and it helps

Helppppp pleaseee????

Answers

Answer:

Lower quartile 3, median 5, Upper quartile 7

Step-by-step explanation:

First divide the data in half  1 3 4  and 6 7 7

The median is the middle between 4 and 6, so it is 5.

The lower quartile is the median in the lower half, 3

The upper quartile is the median in the upper half, 7

I thought of a number. My friend thought of a number too. A third of my number is a half of his number. Who's number is bigger?

Answers

Answer:

yoours

Step-by-step explanation:

thanks again for your time and consideration and I am a kid I am a kid


Which relationships have the same constant of proportionality between y and x as the following table?
y
4
32
7
56
8 64
Choose 3 answers:

Answers

Answer:

C

Step-by-step explanation:

32 / 4  = 8

56 / 7 = 8

64 / 8 = 8

Solve −x−6≥−5 or −2x−5>4 and write the solution in interval notation. Note: Use improper fractions, if necessary.

Answers

Answer:

(-∞, -1]

Step-by-step explanation:

−x−6≥−5

-x≥1

x≤-1

−2x−5>4

-2x>9

x<-9/2

So x < -9/2 V x ≤ -1

Answer:

(−∞,∞)

Step-by-step explanation:

5x - 4 ≤ - 3

5x ≤ 1

x ≤ [tex]\frac{1}{5}[/tex]

4x + 6 > 0

4x > - 6

x > - [tex]\frac{3}{2}[/tex]

3x+4y+6z=15
Solve for x.​

Answers

Answer:

[tex]x = 5 - \frac{4}{3} y - 2z [/tex]

Step-by-step explanation:

Question:-To solve for x

Equation:-3x + 4y + 6z = 15

Solution:-

=> 3x + 4y + 6z = 15

[On subtracting both sides with 4y]

=> 3x + 4y + 6z - 4y = 15 - 4y

[On Simplification]

=> 3x + 6z = 15 - 4y

[On subtracting both sides with 6z]

=> 3x + 6z - 6z = 15 - 4y - 6z

[On Simplification]

=> 3x = 15 - 4y - 6z

[On dividing both sides with 3]

[tex] = > \frac{3x}{3} = \frac{15 - 4y - 6z}{3} [/tex]

[On Simplification]

[tex] = > x = 5 - \frac{4}{3} y - 2z \: (ans)[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{QUESTIONS:}[/tex]

3x+4y+6z=15 Solve for x.

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{ANSWER:}[/tex]

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

[tex]\huge\bold\orange{SOLUTION:}[/tex]

[tex]3 \orange{+ 4y + 6z = 15}[/tex]

Move the variables to the right-hand side and change their signs.

[tex]3x = 15 \orange{ - 4 - 6z}[/tex]

Divide both sides of the equation by 3

[tex]\orange{3x = 15 - 4 - 6z}[/tex]

[tex]↓[/tex]

[tex]\orange{x = 5 - \frac{4}{3} y - 2z}[/tex]

The x-intercepts of 3x+4y+6z=15 is

[tex]x = 5 - \frac{4}{3} y - 2z[/tex]

[tex]\orange{••••••••••••••••••••••••••••••••••••••••••••••••••••••••••••}[/tex]

#CarryOnlearning

Plz answer and explain. And no link please! It is appreciated.

Answers

Answer:

I think option a k.9

is correct

help plsssssssssssssssssssssssssssss

Answers

Answer:

0

the answer is 0........

It’s 0 not sure so please don’t get mad

Solve the following system of equations by elimination​

Answers

Answer:

y = -6

x = 1

Step-by-step explanation:

-x + 2y = -13

-x - 2y = 11

Sum the equations:

-x -x = -2x

+2y - 2y = 0

-13 + 11 = -2

then

-2x = -2

x = -2/-2

x = 1

from the first eq.

-x + 2y = -13

-1 + 2y = -13

2y = -13 + 1

2y = -12

y = -12/2

y = -6

check:

from the second eq.

-x -2y = 11

-1 -(2*-6) = 11

-1 -(-12) = 11

-1 + 12 = 11

what is 1*1000000*5*6/3*1757/4*45567-4-6-8*5846584*0+1+2+3+4+5+6+7+8+9+10

Answers

Answer:

2.0015305e+15 is the answer

On a piece of paper, graph f(x) = 4x. Then determine which answer choice
matches the graph you drew.

Answers

Answer:

The Correct Answer is A

Step-by-step explanation:

You are able to put the equation into Desmos Online Graphing Calculator.

When inserting the equation:

[tex]f(x) = 4 {}^{x} [/tex]

You are able to determine that the graph looks like Graph A

I hope this helps and you have a great day!

Note: I am not a professional so take my opinion with caution!

Answer:c

Step-by-step explanation:


Please help with this!

Answers

Answer:

I think this is the answer

Step-by-step explanation:

p= x+2+x+9+2x

Simplified

4xin+11in

I need Help ASAP
Please
Please!!!​

Answers

Answer:

3/4

Step-by-step explanation:

need to evaluate integral pls help me

Answers

Answer:

[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \frac{159}{10}[/tex]

General Formulas and Concepts:

Calculus

Integration

IntegralsIntegral Notation

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                     [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Splitting Integral]:                                                               [tex]\displaystyle \int\limits^c_a {f(x)} \, dx = \int\limits^b_a {f(x)} \, dx + \int\limits^c_b {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x) = \left \{ {{9x^9 ,\ 0 \leq x \leq 1} \atop {4x^3 ,\ 1 \leq x \leq 2}} \right.[/tex]

[tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \ ?[/tex]

Step 2: Integrate

[Integral] Rewrite [Integration Property - Splitting Integral]:                       [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \int\limits^1_0 {f(x)} \, dx + \int\limits^2_1 {f(x)} \, dx[/tex][Integrand] Substitute in function:                                                               [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \int\limits^1_0 {9x^9} \, dx + \int\limits^2_1 {4x^3} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]:               [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \int\limits^1_0 {x^9} \, dx + 4 \int\limits^2_1 {x^3} \, dx[/tex][Integrals] Integration Rule [Reverse Power Rule]:                                    [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \bigg( \frac{x^{10}}{10} \bigg) \bigg| \limits^1_0 + 4 \bigg( \frac{x^4}{4} \bigg) \bigg| \limits^2_1[/tex]Integration Rule [Fundamental Theorem of Calculus 1]:                            [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = 9 \bigg( \frac{1}{10} \bigg) + 4 \bigg( \frac{15}{4} \bigg)[/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^2_0 {f(x)} \, dx = \frac{159}{10}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer:

Step-by-step explanation:

[tex]\int\limits^1_0 {9x^9} \, dx +\int\limits^2_1 {4x^3} \, dx[/tex]

=[tex]\frac{9x^{10}}{10} |_0^1 + x^4|_1^2[/tex]

[tex]=\frac{9}{10}+2^4 -1 = 15\frac{9}{10}[/tex]

Is y=x/10 represent proportional relationship

Answers

Yes, because x turns to into 1/10.

Factor the expression completely: 4x - 48
-
A) 2x - 12
B) 2x - 48
C) 4(x + 12)
D) 4(x - 12)

Answers

Answer:

D

Step-by-step explanation:

D) 4(x-12) because math

Elliot spent $16.15 on ground beef at a grocery store. He purchased 3 and 2 over 5 pounds of ground beef. What is the price per pound of the ground beef at that store?

Answers

We want to know how much is the price per pound (or unit rate) of ground beef, given that we know the price for Elliot's purchase. We will see that each pound costs $4.75

So we know that (3 + 2/5) lb of ground beef costs $16.15, the cost of a single pound will be given by the quotient between the total cost and the amount purchased, then we need to solve:

[tex]P =\frac{ \$ 16.15}{(3 + 2/5)lb}[/tex]

We can rewrite the denominator as:

(3 + 2/5)lb = (15/5 + 2/5)lb = (17/5) lb

Replacing that we get:

[tex]P =\frac{ \$ 16.15}{(17/5)lb} = \frac{ \$ 16.15*5}{17lb} = \$4.75 \ per \ lb[/tex]

So each pound of ground beef costs $4.75

If you want to learn more about unit rates, you can read:

https://brainly.com/question/2375289

A linear function and an exponential function are shown below.

Over which interval does the growth rate of the exponential function exceed the growth rate of the linear function?

Answers

Answer:

x >2

Step-by-step explanation:

*The exponential function gets steeper when x is greater than 2

Answer:

D. x>2 is the answer got it right

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You need to graph thegravitational potential energy with respect to height, the mechanical kineticenergy vs height, and the velocity vs height.Lets look at the energy graphs first. In this case both kinetic energy andmechanical energy cover the same range of values. This means they can use thesame scale on the y-axis. So, you will use the left y-axis and the x-axis to graphthe kinetic energy vs height and the potential energy vs height. You will need alegend to explain which line is which. Colour coding is a nice way to highlight this.The velocity values are much different than the energy values. This means youneed a totally different scale. So, your left y-axis wont work. You need to make asecond scale on the right y-axis for your velocity values. You will plot the pointsthe same way as normal, but you will use the numbers on the right-hand scaleinstead. Again, be sure to add your velocity line to the legend with a separatecolour code.Discussion Questions:1. 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