The thickness of the backfat in pigs is used in evaluating the quality of their flesh for consumption. To compare the backfat thickness of pigs raised on two different diets, an animal researcher randomly sampled a group of pigs raised on Diet 1 and another group raised on Diet 2:
Sample Mean Sample SD Sample Size
Diet 1 3.63 cm 0.29 cm 18
Diet 2 3.37 cm 0.25 cm 18
POOLED SE 0.09
A) After confirming all relevant assumptions, you want to test if the mean backfat thicknesses of the pigs raised on these two diets differs. What is the absolute value of the test statistic?
B) If the critical value for this test is 2.032 (confirm that it is), what would be an appropriate conclusion for this test?
A. An conclusion is not warranted for this test
B. This data provides evidence that mean backfat thickness of pigs on Diet 1 is different from pigs on Diet 2 (p<.05)
C. This data provides no evidence that mean backfat thickness of pigs on Diet 1 is different from pigs on Diet 2 (p<.05)
D. This data provides evidence that diet is independent of backfat thickness (p<.05)
E. There is no evidence that diet is independent of backfat thickness (p>.05)

Answers

Answer 1

Answer:

A) The test statistic is approximately 7.5056

B) E. There is no evidence that diet is independent of backfat thickness

Step-by-step explanation:

The given data are;

The sample mean for pigs raised on Diet 1, [tex]\overline x_1[/tex] = 3.63 cm

The sample SD for pigs raised on Diet 1, s₁ = 0.29 cm

The number of pigs in the sample for pigs raised on Diet 1, n₁ = 18

The sample mean for pigs raised on Diet 2,  [tex]\overline x_2[/tex] = 3.37 m

The sample SD for pigs raised on Diet 2, s₂ = 0.25 cm

The number of pigs in the sample for pigs raised on Diet 2, n₂ = 18

The pooled SE = 0.09

A) The test statistic is given by the following formula;

[tex]t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}[/tex]

Therefore, we have;

[tex]t=\dfrac{(3.63-3.37)}{\sqrt{\dfrac{0.29^{2} }{18}-\dfrac{0.25^{2}}{18}}} \approx 7.5056[/tex]

The test statistic, t ≈ 7.5056

B) The degrees of freedom, df = n₁ - 1 = 18 - 1 = 17

At a confidence level of 95%, the critical value is 2.11

Given that the value of the test statistics tic if larger than the critical value, the null hypothesis is rejected and there is a difference in the backfat of the pigs on different diet

Therefore, there is no evidence that diet is independent of backfat thickness


Related Questions

I GIVE BRAINLIEST FOR EXPLANATION AND CORRECT ANSWER EXTRA POINTS

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Answer:

54.85 un²

Step-by-step explanation:

Calculate the square and the circle and add them together.

[tex]2\pi[/tex]r

radius = 3

[tex]2\pi[/tex]3

Circumference = [tex]2\pi[/tex]r = 2 × [tex]\pi[/tex] × 3 = 18.84956

18.84956 rounds to 18.85

The circle's area is 18.85 un².

The square is 6 by 6.

6 × 6 = 36

The square's area is 36 un².

18.85 un² + 36 un² = 54.85 un²

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Answer:

2

Step-by-step explanation:

The two x's end up being -4 and 6, so added together that's 2

5(8-70) + 29 nt (n=4

Answers

Answer:

5 x 8 = 40

5 x -70 = -350

40 - 350

29 x 4 = 116t

therefore it would be 40 - 350 + 116t

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Post Test:Transformation answer key?

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Answer:

ur gay

Step-by-step explanation:

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Answer:

bottom half

bottom- 3 x 12.5 = 37.5

front side- 3 x 4 = 12

back side- 12

left side- 4 x 12.5 = 50

right side- 50

total: 161.5

top half

front triangle- (3x4)/2 = 6

back triangle- 6

left side- 4 x 12.5 = 50

right side- 50

total: 112

161.5 + 112 = 273.5

A path 2 m wide surrounds a large flowerbed.

Answers

Answer:

what are we supposed to do here

How could you correctly rewrite the equation 4(5 + 3) = 2(22 - 6) using the distributive property?

Answers

Answer:

We can correctly rewrite the equation: 4(5+3) = 2(22-6) by distributing each side.

4(5+3) = 2(22-6)

4(8) = 2(16)

32 = 32

Once you finish distributing each side, you can check to see if it is equal on both sides.

Step-by-step explanation:

Step-by-step explanation:

4(5 + 3) = 2(22 - 6)

4(8) = 2(16)

32 = 32

Suppose that you reach into a bag and randomly select one piece of candy from 4 chocolates, 8 caramels and 19
peppermints. Find the probability of selecting a chocolate.

Answers

Answer:

Step-by-step explanation:

4 : 31

4/31

or .129

or 12.9%

Answer:

4/31

Step-by-step explanation:

4 chocolates out of a total of 31 pieces of candy

Which equations represent exponential growth functions? Select all that apply.

Question 6 options:

f(x)=(2.6)x

g(x)=(52)x

h(x)=(0.4)x

m(x)=(13)x

Answers

All except for h(x) are exponential growth because it is over 1

A right prism has height 8 and triangular bases with sides of length 7, 8, and 9. What is the: Total surface area of the prism?

Answers

Answer:

the total surface area of the prism is 245.67

Step-by-step explanation:

Given;

height of the triangular prism, h = 8

length of the triangular bases, = 7, 8, and 9

The total surface area of the prism is calculated as;

T.S.A = ph + 2B

Where;

p is the perimeter of the base

B is area of the base

P = 7 + 8 + 9 = 24

Area of the base can be calculated using Hero's formula;

[tex]S = \frac{7+8+9}{2} = 12\\\\Base \ area (B) = \sqrt{12(12-7)(12-8)(12-9)} = 26.833[/tex]

T.S.A = (24 x 8)   +  2 x 26.833

T.S.A = 192 +  53.666

T.S.A = 245.67

Therefore, the total surface area of the prism is 245.67

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Answers

Answer:

Group one has the larger median

Step-by-step explanation:

Group One:

By taking off 8 on both ends we see that the median is 53 for group one.

33, 35, 40, 41, 43, 46, 48, 49, 53, 54, 55, 58, 58, 58, 62, 62, 67

Group two:

By taking off 8 on each end as well we get 47 and 49.

35, 38, 40, 41, 42, 43, 47, 47, 47, 49, 50, 50, 53, 54, 57, 61, 66, 69

we then take the average of the two numbers

47 + 49 = 96

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WILL MARK! please help:)
Find x and y so that ABCD will be a parallelogram.

Answers

Answer:

The answer is the first one; x = 6 y =42

the sum of -6 times a number x and 9 is at least 27. what are the possible values of the number​

Answers

5 I think 6 I think 7 I think I just want points

If a video game cost $60 and it's on sale for 10% off, how much is the discount?

Answers

Answer:

$6

Step-by-step explanation:

Percentages have a cool little trick where they can be reversed :) 10% of 60 is a little tough, but we can switch it to 60% of 10, which is much easier. 60% of 10 is 6, so the discount is $6

Find the equation of a line parallel to y - 5 = 6x – 10 that passes through the
point (4,10). (answer in slope-intercept form)

Answers

Answer:

y=6x-14

Step-by-step explanation:

y=mx+b

m=slope

b=y-intercept

add 5 on both sides to make y on the left side and the other part on the right side.

y=6x-5

IMPORTANT: Parallel lines have the same slope

if the line passes through the point (4,10) we can substitute values for x and y into y=mx+b

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y=6x-14

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Answers

Answer:

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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Decade
Mean
Standard Deviation
1910s
0.266
0.0371
1940s
0.267
0.0326
1970s
0.261
0.0317
Compute the standard units for the batting averages of Cobb,Williams, and Brett to compare how far each stood above his peers.Who is the better player of the three?

Answers

Answer:

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

George Brett is third

Step-by-step explanation:

Given the data:

Decade : 1910 __ 1940 ____ 1970

Mean, μ: 0.266 __0.267 ___ 0.261

S/dev, σ : 0.0371 _ 0.0326 __ 0.0317

To compute the standard unit for batting averages, we obtain the standardized score for each of Cobb,Williams, and Brett.

Standardized score (Zscore) : (x - μ) / σ

Cobb, x = 0.420

Ted Williams, x = 0.406

George Brett, x = 0.390

COBB:

Zscore = (0.420 - 0.266) / 0.0371 = 4.1509

Ted Williams :

Zscore = (0.406 - 0.267) / 0.0326 = 4.2638

George, Brett = (0.390 - 0.261) / 0.0317 = 4.0694

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

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using the formula for the sum of interior mangles for a polygon:

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combine like terms:

9x + 243° = 540°

9x = 297°

x = 33°

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I am ready to help you.ask question.

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x=6
y=6
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Answers

If the listed answers are
A: x=6
B: y=6
C: y=x
D: y=2

Then I believe your answer is x=6, or A.

The line of reflection is a line which divides the graph so that both sides essentially represent a mirror; so both sides should look like they’re reflected across one point. This point is your line of reflection, in this problem you simply have to look for where that line would be, draw a line straight down; you go through 6 on the X axis. Usually Y=[number] is a line going across whereas X=[number] is a line going up and down so from there you know it has to be the up-and-down line, x.

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Use pi in the equation to get the answer and for the work but dividends on the sheet

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The answer to your question is: 2
The answer is to this equation is 2

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Answers

Answer:

Two events are dependent if the outcome of the first event affects the outcome of the second event, so that the probability is changed.

Step-by-step explanation:

Answer:

A.

You get a head and a tail in two coin tosses with two different coins.

Step-by-step explanation:

I took the test and got it right!

8. Determine the area of a sector
with a central angle of 42° in a
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NEED IT ASAP

Answers

Answer:

[tex]\boxed {\boxed {\sf A \approx 3.3 \ in^2}}[/tex]

Step-by-step explanation:

Since we are given the central angle in degrees, we should use the following formula for sector area.

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[tex]\theta= 42 \\r=3 \ in[/tex]

[tex]A=\frac {42}{360} * \pi (3 \ in)^2[/tex]

Solve the exponent.

(3 in)²= 3 in*3in = 9 in²

[tex]A=\frac {42}{360} * \pi (9 \ in^2)[/tex]

Multiply all three numbers together.

[tex]A= 0.116666666667* 3.14159265359 * 9 \ in^2[/tex]

[tex]A=3.29867228627 \ in^2[/tex]

Let's round to the tenth place. The 9 in the hundredth place tells us to round the 2 up to a 3.

[tex]A \approx 3.3 \ in^2[/tex]

The area of the sector is approximately 3.3 square inches.

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