The triangles shown are similar. Which side of triangle PQR corresponds to side LN in triangle MNL? Triangle L N P. Side L N is 12, N M is 10, M L is 14. Triangle P R Q. Side P R is 28, R Q is 24, Q P is 20. RQ PQ PR LM

Answer: [tex]m\angle BAM=30^{\circ}[/tex]

Step-by-step explanation:

[tex]AD=x\sqrt{3}[/tex] (Pythagorean theorem)

[tex]m\angle ACD=60^{\circ}[/tex] (30-60-90 triangle)

[tex]m\angle MCA=30^{\circ}[/tex] (angle subtraction)

[tex]m\angle MAC=30^{\circ}[/tex] (base angles theorem)

[tex]m\angle CAD=30^{\circ}[/tex] (30-60-90 triangle)

[tex]m\angle BAM=30^{\circ}[/tex] (angle subtraction)

The quantity of product that would result in the same profit is 1 thousand. Option A

Given the polynomial function as;

P(t) = –2t³ + 8t² + 2t

Where;

Let's equate the values

–2t³ + 8t² + 2t = 8

–2t³ + 8t² + 2t - 8 = 0

Factorize the expression

(-2t³ + 8t²) + ( 2t -8) = 0

- t² ( 2t - 8) + (2t -8) = 0

We take the similar factor

2t - 8 = 0

2t = 8

t = 8/2

t = 4

But we have that the company produced 4 thousand products for $8 million profit, so we have

= 4/ 4

= 1 thousand

Thus, the quantity of product that would result in the same profit is 1 thousand. Option A

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Answer:

about 19.31 years

Step-by-step explanation:

[tex]10000( {1.11}^{x} ) = 75000[/tex]

[tex] {1.11}^{x} = 7.5[/tex]

[tex]x ln(1.11) = ln(7.5) [/tex]

[tex]x = \frac{ ln(7.5) }{ ln(1.11) } = 19.31[/tex]

Distance formula ds = v(dx² + dy²) s = ? v(1 + (dy/dx)²) dx ......... s = the arc length y = 171 - x²/45

chegg

someone solved it on this

https://youtu.be/UGjXlMVdZvc

Answer:

The answer is choice C from the given alternatives.

it would take Janis 14 minutes to complete a package alone

From the information given,

Let's say that

Carol working time = x = 30 minutes

Janis working time = y

x + y = 16 minutes

Let's make 'y' the subject

30 - 16 = y

y= 14 minutes

Thus, it would take Janis 14 minutes to complete a package alone

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Step-by-step explanation:

Ig by dividing 12.50 and 250

It is possible to arrange the total of mangoes by using 20 piles of 9 mangoes, 18 piles of 10 mangoes, or 15 piles of 12 mangoes.

The conditions for mangoes to be arranged are that the piles should have either 9, 10 or 12 mangoes and reminders are not allowed. This means you need to fit all the mangoes and no mangoes can be left.

Based on the conditions and the total number of mangoes (180 mangoes), here are the possibilities that you can determine using division:

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A logarithmic function is the inverse of an exponential function.

A logarithmic function is the inverse of an exponential function.

Now we have the function;

f(x) = log(x) and the translated function f(x) = log (x-h) + k.

Similarly;

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Missing parts;

Use the graphing calculator to graph the parent function.

f(x) = log(x)

Add the translated function.

f(x) = log (x-h) + k

Plug in different values of h and k to answer the following questions.

What happens when h is positive?

What happens when h is negative?

What happens when k is positive?

What happens when k is negative?

Answer:

When h is positive: horizontal shift to the right

When h is negative: horizontal shift to the left

When k is positive: vertical shift up

When k is negative: vertical shift down

Step-by-step explanation:

got it right on Edge

Answer:

C) The volume of the prism is equal to the volume of the cylinder.

Step-by-step explanation:

volume of triangular prism = area of base × height

volume of cylinder = area of base × height

The cross sectional area are equal, so the bases have the same area.

The heights are also equal.

The volumes must be equal.

Answer: C) The volume of the prism is equal to the volume of the cylinder.

Answer:

C) The volume of the prism is equal to the volume of the cylinder.

Step-by-step explanation:

If the cross-sectional areas of the triangular prism and the right cylinder are congruent, it means that when you look at their shapes from the top or bottom, they have the same size and shape.

Since both the triangular prism and the right cylinder have a height of 5 units, and their cross-sectional areas are the same, it implies that they have the same volume as well. So, the volume of the triangular prism is equal to the volume of the cylinder.

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Answer:

70

Step-by-step explanation:

45+90=135

180-45=45

q=45

45+65=110

180-110=70

70-45=25

p=25

45+25=70

Answer: 70°

Step-by-step explanation:

We know that the sum of all 3 angles in a triangle is 180°. Hence, we can just set all measures to be equal to 180° and solve for the variables.

[tex]p+65+90=180\\p+155=180\\p=25[/tex]

[tex]45+90+q=180\\135+q=180\\q=45[/tex]

[tex]p+q=25+45=70[/tex]

The sum of p and q is 70°.

Answer:

6.2 rounds

Step-by-step explanation:

since 1 kilometer is 0.62 miles

10 kilometers is 6.2 miles

so about 6 and 1/5 rounds

Step-by-step explanation:

the third option is the answer.

Answer:

g(-1) = 3, g(2) = 6, g(5) = 4

Step-by-step explanation:

Please refer to attached photo. (Apologies for the terrible handwriting.)

From here we can see,

g(x) = x + 4 applies for values x less than or equal to 2.

g(x) = 9 - x applies for values x more than 2 (which does not include 2.)

g(-1):

Since -1 < 2,

g(-1) = -1 + 4 = 3

g(2) = 2 + 4 = 6

g(5):

Since 5 > 2,

g(5) = 9 - 5 = 4

Answer:

1±2i.

Step-by-step explanation:

1. if to evaluate the expression given, it can be written

(x-5)(x²-2x+5)=0;

2. where the nonreal roots are 1±2i.

Answer: D. slides the graph 1 unit right

Step-by-step explanation:

See attached image.

a)

b) Conditions:[tex]\sigma[/tex] is understood to have a regular distribution of weights

c) Interpretation: 80 percent of the time, this range will include the actual average weight of Allen's hummingbirds, hence its reliability may be counted on

d) sample size [tex]n \approx 27[/tex].

Generally,
Here n = 17

T= 3.15

[tex]\sigma=0.40[/tex]

confidence level =c = 0.80

Here we will usethe  z critical value.

z critical value for (1+c) /2 = (1+0.80)/2

z critical value for (1+c) /2= 0.9

Zc = 1.28

Critical value = 1.28

a) Margin of error (E) :

[tex]E = Zc*\frac{\sigma}{\sqrt{n}}\\\\\E = 1.28*\frac{0.40}{\sqrt{17}}[/tex]

E =0.124

Margin of error = E =0.124

Lower limit = x-E

L= 3.15 - 0.124

L= 3.026

Lower limit =3.026

Upper limit = x + E

U= 3.15 + 0.124

U= 3.274

Upper limit =  3.274

The following is a confidence interval with a value of 80 percent for the mean weights of Allen's hummingbirds in the area under study: (3.02,3.28)

b) Conditions:[tex]\sigma[/tex] is understood to have a regular distribution of weights

c) Interpretation: 80 percent of the time, this range will include the actual average weight of Allen's hummingbirds, hence its reliability may be counted on.

d) When is already known, the following equation may be used to determine the appropriate number of samples, n:

[tex]n=(\frac{z_c*\sigma }{E})^2[/tex]

Margin of error = 0.13

Sample size (n):

[tex]n= (\frac{z_c*\sigma }{E})^2[/tex]

[tex]n=(\frac{ 1.28*0.36}{0.09})^2[/tex]

n = 26.21

[tex]n \approx 27[/tex]

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Answer:

12705

Step-by-step explanation:

The problem could be solved in two different methods:

1:

231×(55)=12705

2.

231×40+231×15=9240+3465=12705

Answer:

[tex]\text{f}^{-1}(x)=\dfrac{x-15}{12}[/tex]

Step-by-step explanation:

[tex]\text{f}^{-1}(x)[/tex] is the notation for the inverse of a function.  

The inverse of a function is a reflection in the line y = x.

Given function:

[tex]\text{f}(x)=15+12x[/tex]

To find the inverse of the given function:

Step 1

Replace f(x) with y to get an equation for y in terms of x:

[tex]\implies y=15+12x[/tex]

Step 2

Rearrange the equation to make x the subject:

[tex]\implies y-15=15+12x-15[/tex]

[tex]\implies y-15=12x[/tex]

[tex]\implies \dfrac{y-15}{12}=\dfrac{12x}{12}[/tex]

[tex]\implies x=\dfrac{y-15}{12}[/tex]

Step 3

Replace x with [tex]\text{f}^{-1}(x)[/tex] and y with x → this is the inverse function:

[tex]\implies \text{f}^{-1}(x)=\dfrac{x-15}{12}[/tex]

Step 4 (if necessary)

The domain of the function is the range of the inverse function.

The range of the function is the domain of the inverse function.

Therefore, as the domain and range of the given function are unrestricted, so too are the domain and the range of the inverse function:

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[tex]\\ \rm\leadsto y=15+12x[/tex]

Interchange x and y

[tex]\\ \rm\leadsto x=15+12y[/tex]

Solve for y

[tex]\\ \rm\leadsto 12y=x-15[/tex]

[tex]\\ \rm\leadsto y=\dfrac{x-15}{12}[/tex]

That's the inverse

Answer:

108

Step-by-step explanation:

When the lines cut through by a transversal are parallel, alternate interior angles are congruent. angle 4 = angle 6 = 108

The solution to the given system of equation is (3, 3, 3)

Given the following system of equation expressed as:

2x-y+5z=16

X-6у +2z=-9

3x+4y- z=32

Multiply equation 2 by 2 to have:

2x-y+5z=16

2X-12у +4z=-18

Subtract

10y+z = 34 .........4

Similarly

3X-18у +6z=-27

3x+4y- z=32

Subtract

-22y+7z = -59 ........... 5

Equate 4 and 5

10y+z = 34 .........4 * 7

-22y+7z = -59 ........... 5 * 1

_______________________

70y+7z = 238

-22y+7z = -59

Subtract

92y = 297

y = 3

Recall that

10y+z = 34

10(3) + z = 34

z = 3

Since x - 6y +2z = -9

x-6(3)+2(3) = -9
x - 18 + 6 = -9
x = 3

Hence the solution to the given system of equation is (3, 3, 3)

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30 Jagged rocks are the same 3 shiny rocks using the exchange rates provided(i.e. option D)

What is an exchange rate?

Exchange rate means the rate at which one item exchanges hands with another, for instance, in this case, 6 jagged rocks are equivalent to 2 smooth pebbles.

6 jagged rocks=2 smooth pebbles

divide both sides by 2

6/2 jagged rocks=2/2 smooth pebbles

3 jagged rocks=1 smooth pebble

We can rewrite as below:

1 jagged rock=1/3 smooth pebble

30jagged rocks=1/3*30 smooth pebbles

30 jagged rocks=10 smooth pebbles

Now we need to convert 10 smooth pebbles to shiny rock equivalence

3 smooth pebbles=1 shiny rock

1 smooth pebble=1/3 shiny rock

10 smooth pebbles=1/3*10 shiny rocks

10 smooth pebbles=3 shiny rocks( even though it is 3.33, but the final answer should be rounded to a whole number)

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[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Information : The given ellipse is a horizontal ellipse, and it's centre lies on origin, as the foci are given on x - axis.

The foci of the ellipse can be written in form :

[tex]\qquad \sf  \dashrightarrow \: ( \pm ae , 0)[/tex]

So,

[tex]\qquad \sf  \dashrightarrow \: ae = 5[/tex]

and Vertex of the ellipse can be written as

[tex]\qquad \sf  \dashrightarrow \: (\pm a,0)[/tex]

Now, plug the value in first equation ~

[tex]\qquad \sf  \dashrightarrow \: ae = 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: 11e = 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: e = \cfrac{5}{11} [/tex]

Now, we have to find b (length of semi minor axis)

we can use the formula ~

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = {a}^{2} (1 - {e}^{2} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 121(1 - \frac{25}{121} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 121( \frac{121 - 25}{121} )[/tex]

[tex]\qquad \sf  \dashrightarrow \: b {}^{2} = 96[/tex]

Now, we can write the equation of ellipse as :

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {a}^{2} } + \cfrac{ {y}^{2} }{ {b}^{2} } = 1[/tex]

[ plug the values ]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ {x}^{2} }{ {121}^{} } + \cfrac{ {y}^{2} }{ {96}^{} } = 1[/tex]

Answer:

[tex]\dfrac{x^2}{121}+\dfrac{y^2}{96}=1[/tex]

Step-by-step explanation:

General equation of an ellipse:

[tex]\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1[/tex]

where:

If a > b the ellipse is horizontal, a is the major radius, and b is the minor radius.

If b > a the ellipse is vertical, b is the major radius, and a is the minor radius.

Given:

Therefore, the ellipse is horizontal with its center at (0, 0):

⇒ h = 0 and k = 0

⇒ a = 11

⇒ c = 5

To find b², use  c² = a² − b²:

⇒ 5² = 11² − b²

⇒ b² = 11² − 5²

⇒ b² = 96

Therefore, the standard form of the equation of the ellipse is:

[tex]\implies \dfrac{(x-0)^2}{11^2}+\dfrac{(y-0)^2}{96}=1[/tex]

[tex]\implies \dfrac{x^2}{121}+\dfrac{y^2}{96}=1[/tex]

Let A, B, and W denote the sets of students apply to Addis Ababa Uni (A), Bahir Dar Uni (B), or Wachemo Uni (W). Let U denote the universal set of all students in the class.

We're given the cardinalities of several sets:

• total number of students: [tex]n(U) = 60[/tex]

• A applicants: [tex]n(A) = 30[/tex]

• B applicants: [tex]n(B) = 25[/tex]

• W applicants: [tex]n(W) = 24[/tex]

• A and B applicants: [tex]n(A\cap B) = 11[/tex]

• A and W applicants: [tex]n(A \cap W) = 6[/tex]

• B and W applicants: [tex]n(B\cap W) = 9[/tex]

• non-applicants: [tex]n(U \setminus (A\cup B\cup W)) = 4[/tex]

The last cardinality tells us [tex]n(A\cup B\cup W) = 60-4 = 56[/tex] students applied anywhere at all.

We want to find [tex]n(A\cap B\cap W)[/tex], the number of students that applied to each of the three universities.

By the inclusion/exclusion principle,

[tex]n(A\cup B\cup W) = n(A) + n(B) + n(W) \\\\~~~~~~~~~~~~~~~~~~~~~~~~ - n(A\cap B) - n(A\cap W) - n(B\cap W)\\ \\~~~~~~~~~~~~~~~~~~~~~~~~ + n(A\cap B\cap W)[/tex]

That is, we count up all the students in the sets A, B, and W, then subtract the number of students in each pairwise intersection to not double-count, then add back the number of students in the intersection of all three sets since it was removed in the previous step.

Now solve.

[tex]56 = 30 + 25 + 24 - 11 - 6 - 9 + n(A\cap B\cap W)[/tex]

[tex]\implies n(A\cap B\cap W) = \boxed{3}[/tex]

75 percent of the stock are sleeveless

The given parameters are:

Blouse = 120

Sleeveless = 90

The percentage is calculated as:

Percentage = Sleeveless/Blouse * 100%

So, we have:

Percentage = 90/120* 100%

Evaluate the expression

Percentage = 75%

Hence, 75 percent of the stock are sleeveless

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Answer:

what is the monthly payment or ask for the mileage use for the car

The number of square feet of carpet needed for the rooms is 889 ft².

The total square footage of your house is 1200 square feet.

He wants to put new carpet in all rooms except for  the kitchen, dining room and bathroom.

Therefore,

total area = 1200 ft²

Area of the other rooms with no carpet  = (10 × 12) + (11 × 13) + (6 × 8)

Area of the other rooms with no carpet  = 120 + 143 + 48

Area of the other rooms with no carpet  = 311 ft²

Hence, the number of square feet for the house = 1200 - 311 = 889 ft²

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The statement that is TRUE of the rectangle is AB + BD > AD. Option A

WE have that a diagonal divides the rectangle into two equal triangles

line AD is the length of the diagonal

With the diagonal drawn, we have

AD = hypotenuse

AB  and BD are the two other sides

From the Pythagorean theorem, we have that the square root of the square sum of the other two sides fives the hypotenuse. This mean that their sum is greater than the hypotenuse

Thus, the statement that is TRUE is AB + BD > AD. Option A

The complete question is;

Which of the following statements is TRUE about rectangle ABDC.

a. AB + BD > AD

b. AB + BD < AD

c. AB + BD = AD

d. (AB) (BD) = AD

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