The largest size of a team according to the task content is; 20 kids.
What is the largest size of a team?It follows from the task content that the population is; 20 students in Mrs. Tanya's class and 24 kids in Mrs. Olga's class.
However, since, the team forming condition states that students be placed on teams of equal size with students from only their own class.
It therefore follows that the largest size of a team is 20 as only 20 students are in Mrs. Tanya's class hence leaving 4 kids in Mrs. Olga's class without a team.
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Which of the following sets of numbers could not represent the three sides of a triangle?
Answer:
Step-by-step explanation:
A
C
Which choice correctly shows the line y
= -X?
NHH
1
-4-3-2-1 1 2 3 4
W23
-2
-3
31
2
1
#
B
D
31
21
2
1
-4-3-2-11 2 3 4
123
-2
The graph is shown in the attached image.
Find all primes p, q such that p^2-p=37q^2-q
The pairs of prime numbers (p,q) such that p^2-p=37q^2-q is (43, 7)
How to determine the pairs of numbers?The expression is given as:
p^2 - p=37q^2 - q
The boundary or range of numbers of p and q is not given.
So, we make use of numbers between 2 (because 1 is not a prime number) and a very large number (say 1000000)
i.e. 2 ≤ p ≤ 1000000 and 2 ≤ b ≤ 1000000
Using the above range, we have the following program to determine the pairs of prime numbers (p, q).
for a in range(2,1000000):
for b in range(2,1000000):
if ((a* *2) - a) == (37 * (b* *2) - b):
print(str(a)+","+str(b))
The output of the above program is:
(43, 7)
The above represent all pairs of prime numbers (p,q) such that p^2 - p=37q^2 - q
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Find the z-scores for the two normally distributed random variables, measured using different units of length.
a) x = 22 in, where X comes from N (15, 2.5)
b) y = 55.88 cm, where Y comes from N (38.1, 6.35)
Using the normal distribution, the z-scores are given as follows:
a) Z = 2.8.
b) Z = 2.8.
Normal Probability DistributionThe z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.Item a:
The parameters are:
[tex]\mu = 15, \sigma = 2.5[/tex]
Hence the z-score is:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{22 - 15}{2.5}[/tex]
Z = 2.8.
Item b:
The parameters are:
[tex]\mu = 38.1, \sigma = 6.35[/tex]
Hence the z-score is:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{55.88 - 38.1}{6.35}[/tex]
Z = 2.8.
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How many liters each of a 35% acid solution and a 80% acid solution must be used to produce 60 liters of a 65% acid solution? (Round to two decimal places if necessary.)
Solving a system of equations we will see that we need to use 40 liters of the 80% acid solution, and the other 20 liters are of the 35% acid solution.
How many liters of each solution do we need to use?
First, we need to define the variables:
x = liters of the 35% acid used.y = liters of the 80% acid used.We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use 40 liters of the 80% acid solution, and the other 20 liters are of the 35% acid solution.
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PLEASE ANSWER PLEASE ANSWER
2. The spread of the Ebola virus in Africa in 2014 could be modeled by where C(1) represents the number of cases, and t represents the number of days since May 1, 2014). (source: http://www.geert.io/exponential-growth-of
ebola.html) a. [3 pts] Approximately how many cases were there on May 1, 2014 (round to two decimal places)?
b. [3 pts] How many cases were projected by November 24, 2014 (round to 2 decimal places)?
c. [4 pts] Find C(92) and explain what it means in the context of the problem.
(a) The number of cases on May 1, 2014, was approximately 188.59.
(b) The number of cases on November 24, 2014, was approximately 27107.76.
(c) C(92) = 1715.70.
This means that on the 92nd day from May 1, 2014, the number of Ebola cases in Africa was approximately 1715.70.
Computed using the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].
We are given that the spread of the Ebola virus in Africa in 2014 could be modeled by the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex], where C represents the number of cases and t represents the number of days since May 1, 2014.
(a) In the question, we are asked for the approximate number of cases on May 1, 2014.
Since, the date is May 1, 2014, t = 0.
Thus, the number of cases, C, can be calculated by putting t = 0, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].
[tex]C(0) = 188.59e^{0.024*0}\\\Rightarrow C(0) = 188.59e^0\\\Rightarrow C(0) = 188.59[/tex]
Thus, the number of cases on May 1, 2014, was approximately 188.59.
(b) In the question, we are asked for the approximate number of cases on November 24, 2014.
Since, the date is November 24, 2014, t = 207.
Thus, the number of cases, C, can be calculated by putting t = 207, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].
[tex]C(207) = 188.59e^{0.024*207}\\\Rightarrow C(207) = 188.59e^{4.968}\\\Rightarrow C(207) = 188.59*143.739121458\\\Rightarrow C(207) = 27107.76[/tex]
Thus, the number of cases on November 24, 2014, was approximately 27107.76.
(c) We are asked to find C(92).
This can be found by putting t = 92, in the exponential equation, [tex]C(t) = 188.59e^{0.024t}[/tex].
[tex]C(92) = 188.59e^{0.024*92}\\\Rightarrow C(92) = 188.59e^{2.208}\\\Rightarrow C(92) = 188.59*9.09750317953\\\Rightarrow C(92) = 1715.70[/tex]
Thus, C(92) = 1715.70.
This means that on the 92nd day from May 1, 2014, the number of Ebola cases in Africa was approximately 1715.70.
The complete question is:
"The spread of the Ebola virus in Africa in 2014 could be modeled by [tex]C(t) = 188.59e^{0.024t}[/tex] where C represents the number of cases and t represents the number of days since May 1, 2014. (source: http://www.geert.io/exponential-growth-of-ebola.html)
a. [3 pts] Approximately how many cases were there on May 1, 2014?
b. [3 pts] How many cases were projected by November 24, 2014?
c. [4 pts] Find C(92) and explain what it means in the context of the problem.
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Bill is towing a water tank and needs to know how heavy it will be when filled. If 1 gallon of water weighs 8.5 lbs., how much will the 250-gallon tank weigh? Responses 386 lbs. 386 lbs. 2,125 lbs. 2,125 lbs. 4,003 lbs. 4,003 lbs. 1,954 lbs.
Answer:
2125 lbs
Step-by-step explanation:
1 gallon = 8.5 lbs
we know 1 gallon * 250 = 250 gallons
multiply both sides by 250 to get 250 gallons on one side
250 gallons = 8.5* 250 lbs = 2125 lbs
How much would you need to deposit in an account in order to have $3000 in five years assume the account earns 6% interest compounded monthly
There are $2224.12 need to deposit in an account in order to have $3000 in five years.
What is future value?
Future value is the worth of a financial asset or investment on a specific future date. In other words, future value is the amount of money an investment will be worth, assuming a specific rate of return, after a specific amount of time (interest rate).
Given:
Future value = FV = $3000
Number of years = t = 5
Interest rate = r = 6% = 0.06
Compounding period = n = 12
We have to find the present value form given problem.
Consider, the Future value formula,
[tex]FV = PV(1 + \frac{r}{n})^n^*^t[/tex]
Plug the values in the above formula.
[tex]3000 = PV(1+\frac{0.06}{12})^1^2^*^5\\ 3000 = PV(1+0.005)^6^0\\3000 = PV(1.005)^6^0\\PV = 2224.11658[/tex]
PV = $2224.12
Hence, there are $2224.12 need to deposit in an account in order to have $3000 in five years.
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The graph below shows the amount of money charged by two electricity providers per month, depending on the amount of electricity used. a) Catherine uses 240 kWh of electricity per month. Which provider would be cheaper for Catherine? b) Stephanie uses 140 kWh of electricity per month. How many more kWh of electricity would Stephanie have to use per month to mean that she would be charged the same amount of money by provider A as by provider B? If your answer is a decimal, give it to 1 d.p. y Cost per month (£) 0 Provider A y = 72 +15 Provider B y = 26 +25 Electricity usage per month (kWh)
Watthours are the units used to measure the amount of electricity used over time.
The amount of power utilized is determined by what?Watthours are the units used to measure the amount of electricity used over time.Kilowatts produced or used for one hour are measured as one kWh. For instance, if you use a 40-Watt (0.04 kW) light bulb for five hours, you've used 200 Wh (or 0.2 kWh) of electricity.It seems to reason that energy use increases with the number of residents in a house. An individual uses 909 kWh a month on average. There are 1,818 kWh used each month if there are at least two occupants in the house. The typical American family uses 4,312 kWh year or 3,636 kWh each month, which is the number of people living in the household.To learn more about electricity refer to:
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Answer:
Step-by-step explanation:
solve the given differential equation by variation of parameters. xy'' − 8y' = x8
The given differential equation has the answer C₁ +C₂ 1/81 -x⁹ +1/9 x⁹ln(x). It has been solved using the variation of parameters method below.
We have the differential equation xy'' − 8y' = x^8. In order to solve any differential equation using the variation of parameters method, we first write the equation as and solve -
= xy'' − 8y' = 0
After solving this, we get the Auxiliary equation-
so CF is y = 1/9 x⁹ + C₁ +C₂
Now, we write -
y1 (x) = 1/9 x⁹
y2 (x) = 1
y1'(x) = x^8
y2'(x) = 0
now, using wronskian formula
= W = -x^8
Now, applying the formulas -
= u = [tex]- \int{\frac{f(x)y2(x)}{W(x)} } \, dx[/tex] and v = [tex]\int{\frac{f(x)y1(x)}{W(x)} } \, dx[/tex]
= u = log(x) and v = -x⁹/81
now particular integrals are
PI = 1/81 -x⁹ +1/9 x⁹ln(x)
total solution
y = C.F+P.I
y = C₁ +C₂ 1/81 -x⁹ +1/9 x⁹ln(x)
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Solve the equation below for x. Enter your answer as a fraction in lowest
terms, using the slash mark (/) as the fraction bar.
7/20 + 3/16 = x
x=
Answer:
Step-by-step explanation:
7/20 + 3/16 = x
x = 7/20 + 3/16
LCM of 20 and 16 = 80
x = 28/80 + 15/80
x = 43 /80
Answer:
x = 0.5375
Step-by-step explanation:
=7/20 + 3/16 = x
=LCM = 80
=80×7/20 + 80×3/16 = x × 80
=4×7 + 5×3 = x × 80
=28 + 15 = 80x
=43 = 80x
=43/80 = 80x/80
=43/80 = x
=0.5375 = x.
Sorry but I don't know how to use the slash mark (/).
The diagram below shows the dimensions of a can of tomatoes. HELP!! TYY
A can of tomatoes is shown. A dashed line across the top of the can is labeled nine centimeters. The height of the can is labeled twelve and four tenths centimeters.
How much tin was used to make the can rounded to the nearest square centimeter? Use 3.14 for π.
Enter the correct answer in the box.
_______cm^2
The amount of tin used to make the can is about 478 cm².
To find the amount of tin used to make the can, we need to calculate the total surface area of the can. A can is a cylinder, so we can use the formula for the total surface area of a cylinder to calculate it:
Surface area = 2πr² + 2πrh
Where r is the radius of the can and h is the height of the can.
Given that the height of the can is 12.4 cm, we can use the information that the dashed line across the top of the can is labeled 9 cm to calculate the radius of the can.
r = dashed line / 2 = 9cm / 2 = 4.5 cm
Now we can substitute the values of r and h in the formula:
Surface area = 2π (4.5 cm)² + 2π (4.5 cm) (12.4 cm) = 477.594 cm²
Rounding to nearest square centimeter: 478 cm²
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Which equations are examples of the Distributive Property of Multiplication over Addition? (Choose 2)
Answer: 5(5 + 9). This expression can be solved by multiplying 5 by both the addends. So, 5(5) + 5(9) = 25 + 45 = 70.
Step-by-step explanation:
Find the surface area of the figure. For calculations involving π give both the exact value and an approximation to the nearest hundredth of a unit. Let r = 5 and h = 5
Answer:
100 pi = about 314.16
Step-by-step explanation:
the surface area of a cylinder: SA = 2πrh+2πr^2
we plug in the values of r and h, and get
SA = 50pi + 50pi = 100 pi, which is approximately 314.16
What is the ones digit in the number 3^2091?
Answer:
7
Step-by-step explanation:
Let's look at powers of 3 and if a pattern forms for the ones digit.
3^0 = 1
3^1 = 3
3^2 = 9
3^3 = 27
3^4 = 81
3^5 = 243
3^6 = 729
3^7 = 2187
3^8 = 6561
3^9 = 19683
3^10 = 59049
3^11 = 177147
etc.
Using the table above, we see a repeating pattern for the ones digit:
1, 3, 9, 7, 1, 3, 9, 7, 1, 3, 9, 7, etc.
Now let's look at the exponent of 3 compared to the ones digit.
exponent, ones digit
0, 1
1, 3
2, 9
3, 7
4, 1
5, 3
6, 9
7, 7
etc.
Let's write the exponent of 3 as a multiple of 4 plus an integer followed by the ones digit.
4 × 0 + 0, 1
4 × 0 + 1, 3
4 × 0 + 2, 9
4 × 0 + 3, 7
4 × 1 + 0, 1
4 × 1 + 1, 3
4 × 1 + 2, 9
4 × 1 + 3, 7
etc.
When the exponent is a multiple of 4, the ones digit is 1.
When the exponent is 1 added to a multiple of 4, the ones digit is 3.
When the exponent is 2 added to a multiple of 4, the ones digit is 9.
When the exponent is 3 added to a multiple of 4, the ones digit is 7.
Now let's look at out exponent, 2091.
2091/4 = 522.75
2091 = 4 × 522 + 3
2091 is 3 added to a multiple of 4, so the ones digit is 7.
The angle of depression from a boat to a fish swimming inside the lake is 60 The fish is 17sqrt(3) * m below the surface. How far is the fish from the boat?
What is M?
When the angle of depression from a boat to a fish swimming inside the lake is 60, then 17 meters separate the fish from the boat.
What is a depression angle?The angle at which a line drawn from one point on a horizontal line to cross another point below the line would intersect is referred to as the angle of depression, as opposed to the angle of elevation. The angle at which the object can be observed from the horizontal line and the horizontal line is called the angle of depression. It is primarily used to determine the distance between two points where we know the angles and an object's distance from the ground.
Evaluating :
Let's take the point on the water where the boat touches as A;
let's take the point below the water where the fish's axis and the boat's axis meet as B;
let's take the point where the fish is C.
Since angle C is an alternative angle, we can solve the equation by using tan.
The depth of fish in the water = 17√3m
Angle C = 60° (alternative angle)
So , by using tan we get the equation,
17√3/x
= tan 60°
= 17√3/x
= √3
X = 17 m
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You are offered two different sales jobs. The first company offers a straight commission of 5% of the sales.
The second company offers a salary of $ 210 per week plus 2% of the sales. How much would you have to
sell in a week in order for the straight commission offer to be at least as good?
Answer:
The offers are equal at $7,000, after $7,000 more money will be made with a straight commission.
Step-by-step explanation:
.05x = .02x + 210 Subtract .02x from both sides.
.03x = 210 Divide both sides by .03
x = $7,000.
If you start at -4,3 move 8 units to the right and 10 units down, at what point on the graph would he end up? Which quadrant is the new point in?
Answer:
If you start at (-4,3) and move 8 units to the right and 10 units down, you would end up at the point (4,-7).
The point is located in the 3rd quadrant, where the x-coordinates are negative and the y-coordinates are negative.
It's important to note that moving 8 units to the right means moving to the positive direction on x-axis and moving 10 units down means moving to the negative direction on y-axis.
Find the equation of an ellipse satisfying the given conditions.
Foci: (-4, 0) and (4, 0); length of major axis: 14?
The equation of the ellipse is [tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]
How to determine the ellipse equation?The given parameters are:
Foci: (-4, 0) and (4, 0)Length of major axis = 14The above means that:
c = 4 and
The semi-major axis, a = 7 i.e 14/2
Calculate b using
[tex]b = \sqrt{c^2 + a^2[/tex]
So, we have:
[tex]b = \sqrt{4^2 + 7^2[/tex]
[tex]b = \sqrt{65[/tex]
Square both sides
[tex]b^2 = 65[/tex]
The standard form of the ellipse is represented as:
[tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex]
This gives
[tex]\frac{x^2}{7^2} + \frac{y^2}{65} = 1[/tex]
Evaluate
[tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]
Hence, the equation of the ellipse is [tex]\frac{x^2}{49} + \frac{y^2}{65} = 1[/tex]
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48.5 x 8.78
show your work ;)
The line segment AB has the endpoints (-21, -7) and (-6,3) Point C are partitions the line at a ratio of 4;1 What are the coordinates of point C?
The coordinates of point C are (-9, 1)
How to determine the coordinates of point C?The points are given as:
A = (-21, -7)
B = (-6, 3)
m : n = 4 : 1
The coordinates of point C is calculated as:
[tex]C = \frac{1}{m+n} *(mx_2 + nx_1, my_2+ ny_1)[/tex]
So, we have:
[tex]C = \frac{1}{4+1} *(4 * -6 + 1 * -21, 4 * 3+ 1 * -7)[/tex]
This gives
[tex]C = \frac{1}{5} *(-45, 5)[/tex]
This gives
C = (-9, 1)
Hence, the coordinates of point C are (-9, 1)
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1. Based on the circular
angle below. What is the
best measurement
the angle?
for
a. less than 90°
b. more than 90°
C. more than 180°
d. less than 60°
Answer:
B. More than 90
Step-by-step explanation:
Hope this helps!
Which expression is equivalent to √2+4?
OA. (2+4)²
OB. (2+4)²
OC. 6
D. 62
A solid cylinder of iron whose diameter is 18 cm and height 12 cm is melted and turned into a solid sphere. Find the diameter of the sphere so formed
Answer:
Diameter of sphere = 18 cm
Step-by-step explanation:
Volume of Cylinder and Sphere: Cylinder:Diameter = 18 cm
r = 18÷ 2 = 9 cm
h = 12 cm
[tex]\sf \boxed{\bf Volume \ of \ cylinder = \pi r^2h}[/tex]
= π * 9 * 9 * 12 cm³
Sphere:[tex]\sf \boxed{\text{\bf Volume of sphere = $\dfrac{4}{3} \pi r^3$}}[/tex]
Solid cylinder is melted and turned into a solid sphere.
Volume of sphere = volume of cylinder
[tex]\sf \dfrac{4}{3}\pi r^3 = \pi *9*9*12[/tex]
[tex]\sf r^{3}= \dfrac{\pi *9*9*12*3}{4*\pi }\\\\ r^{3}=9 * 9 *3 *3\\\\\\r = \sqrt[3]{9*9*9}\\\\ r = 9 \ cm\\\\diameter = 9*2\\\\\boxed{diameter \ of \ sphere = 18 \ cm}[/tex]
A jar of tickets for a drawing contains 22 winning tickets and 63 non-winning tickets. What are the odds against winning in the drawing? please help
Answer: 22/85
Step-by-step explanation:
Answer:
22/85
Step-by-step explanation:
E and F are two events and that P(E)=0.2 and P(F/E)=0.6 what is P(E and F)
The probability of E and F expressed as P(E and F) equals;0.12
How to solve Conditional Probability?We are given;
P(E) = 0.2
P(F|E) = 0.6
Now, P(F/E) is known as conditional probability and it means the probability of event F given the probability of another event E. This can be expressed as; P(F|E) = P(E and F)/P(E)
Thus;
P(E and F) = 0.2 * 0.6
P(E and F) = 0.12
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Given AB=10cm, CD=11cm, and AD=39cm, find the length of BC
Answer:
BC = 18 cm
Step-by-step explanation:
As we can see from the diagram:
AB + BC + CD = AD
⇒ 10 cm + BC + 11 cm = 39 cm
⇒ BC + 21 cm = 39 cm
⇒ BC = 39 cm - 21 cm
⇒ BC = 18 cm
NEED IN HELP ASAP!!! OFFERING points
Answer: 140
Step-by-step explanation:
20+10+10+50+35+15
50+20+35+10+15=130
-
What is the unit price of a Mt. Dew if a six packs costs $2.70
Answer:
270 uits
Step-by-step explanation:
Evaluate 2-(-4)+(-y)2−(−4)+(−y)2, minus, left parenthesis, minus, 4, right parenthesis, plus, left parenthesis, minus, y, right parenthesis where y = 7y=7y, equals, 7.
(on khan academy)
The value of the expression [tex]2-(-4)+(-y)^2-(-4)+(-y)^2[/tex] after substituting y = 7 is 108
Evaluation of ExpressionThe given expression is:
[tex]2-(-4)+(-y)^2-(-4)+(-y)^2[/tex]
Simplifying the expression, we have:
[tex]2+4+y^2+4+y^2\\\\2y^2+10[/tex]
Substitute y = 7 into the simplified expression
[tex]2(7)^2+10\\\\=2(49)+10\\\\=98+10\\\\=108[/tex]
Therefore, after substituting y = 7, into the expression [tex]2-(-4)+(-y)^2-(-4)+(-y)^2[/tex], the resulting value is 108
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Answer: -1
Step-by-step explanation: khan academy