Think about a hot summer afternoon at the beach
or a lake. How do the temperatures of the sand
and water compare?
A. The sand is hot; the water is cool.
B. The sand is hot; the water is hot.
C. The sand is cool; the water is cool.
D. The sand is cool; the water is hot.

Answers

Answer 1
A. Would be the correct answer :-)
Answer 2

Answer:

D

Explanation:

I say this because of this that I read. There was a study shown

"Our experiment was a success. We obtained data that answered our problem, “Which substance absorbs the most heat on a hot day? Sand, water, or sand with water?” The results showed that from the twenty-five trials: the cup of sand temperature ranged from 63-68°C, cup of water temperature ranged from 71-77°C, and the cup of sand with water temperature ranged from 66-71°C. Based on our data, our hypothesis was incorrect. We hypothesized that the sand would absorb the most heat since it is darker and less reflective than water; but from our data, water absorbed the most heat. In conclusion, sand absorbed the least amount of heat and water absorbed the most. Next time we want to cool down at the beach, we’ll know where to go!"

This was an experiment that was performed and this is the conclusion

Hope that helps


Related Questions

Help pls ASAP thank you!!

Answers

Answer:

Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.

Explanation:

They interact from the life cycle they eat each other...

What is the mole ratio of iron (III) chloride (FeCl3) to zinc chloride (ZnCl2) ?
2 FeCl3 + 3 Zn → 2 Fe + 3 ZnCl2


a.2:2
b.2:3
c.3:3
d.3:2

Answers

Answer:C

Explanation:

Use the balanced equation in the image below. How many moles of
ammonia (NH3) will be produced if 2.22 moles of nitrogen (N2) are used?
(Assume there is excess hydrogen gas.) SHOW YOUR WORK TO RECEIVE
CREDIT. *
N2 + 3H2 → 2 NH3

Answers

Since there is excess hydrogen, that means that the concentration of hydrogen is not limiting.

According to the balanced chemical equation:

every mole of N2 and every 3 moles of H2 we obtain 2 moles of NH3. Since we have the amount of N2 and excess of hydrogen, we only need to work with the amount of N2.

1 mol of N2 will produce 2 moles of NH3

so now we can get a conversation tool :

moles of N2 * (2 moles of NH3/ 1 mole of N2) = moles of NH3

(2.22 mol of N2 x 2) ÷ 1 = 4.44 mol of NH3

How do the causes of surface and deep water currents differ?
A. Surface currents are caused by wind deep water currents are caused by difference in water density
B. Surface currents are caused by the Coriolis effect deep water currents are caused by differences in water density
C. Surface currents are caused by differences in water salinity deep water currents are caused by differences in water temperature
D. Surface currents are caused by differences in water density deep water currents are caused by wind

Answers

Answer:

The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.

A student plans a two-step synthesis of 1-ethyl-3-nitrobenzene from benzene. The first step is nitration of benzene to give nitrobenzene, and the second step is a Friedel-Crafts alkylation using CH3CH2Cl and AlCl3. The plan is flawed because: A : When the alkyl halide interacts with AlCl3, the resulting carbocation can rearrange before it has a chance to react with the aromatic ring. B : Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation. C : The nitro group will direct the incoming alkyl group para position, rather than to the meta position. D : A blocking group is required to achieve this synthesis.

Answers

Answer:

Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

Explanation:

The benzene ring in itself does not easily undergo electrophilic substitution reaction. Some groups activate or deactivate the benzene ring towards electrophilic substitution reactions.

-NO2 ia a highly deactivating substituent therefore, Friedel-Crafts alkylation of nitrobenzene does not take place under any conditions.

This reaction scheme is therefore flawed because Nitrobenzene is too deactivated (by the nitro group) to undergo a Friedel-Crafts alkylation.

What is the IUPAC name for the following compound?
CH3-CH2-CH2-CH2-CH2-CH2 -CH2-CH3
Enter the name of the molecule.

Answers

8 carbon chain, octane

As the [h+] in a solution decreases, what happens to the [OH^-]?

А. It increases and the pH increases.

B. It increases and the pH decreases.

C. It increases and the pH stays constant.

D. It decreases and the pH increases.

E. It decreases and the pH decreases.

Answers

Explanation:

as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.

Gravitational potential energy depends on the

Answers

Answer:

Gravitational potential energy depends on basically two factor;

Object’s position Mass of object

Explanation:

The distances between both the bodies, as well as the mass within each object, are factors that influence gravitational potential energy.

HELP PLEASE I NEED HELP THANKS I LOVE U

How many moles of potassium nitrate (KNO3) are there in 0.300 L of a 2 molar solution?

Answers

Answer:

0.500-Molarity solution

Explanation:

The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol

What is molarity?

The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.

The molarity can be expressed as:

[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]

The given potassium nitrate solution has, molarity = 2 M

The volume of the solution is 0.3 L.

Substituting the values for the moles of the compound:

[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]

The moles of potassium nitrate in 2 M solution is 0.6 mol.

Learn more about moles, here:

https://brainly.com/question/15209553

Joan wants to test if salt lowers the temperature at which water boils. In two or more complete sentences, describe the best way for Joan to develop a hypothesis for this situation. Write your answer in the essay box below.


Answers

Put a thermometer in the water and wait until it boils. When it boils record the temperature and compare it to the normal water boiling point.

Answer:

Joan's hypothesis should make a prediction about the answer to the question. A hypothesis is just an educated guess on what you think the outcome will be on the experiment. The prediction must be testable and stated in if-then form. For example, a good hypothesis for Joan's experiment could be, I think that 1/2 cup of salt will make the water boil quicker, than water without salt.

Explanation:

Hope it helped!

Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many milliliters of 1.00 M sodium acetate solution would you need to add? The pKa for acetate buffer is 4.75.

Answers

Answer:

Explanation:

Molarity of NaOAc needed

Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.

pH = pKa + log [NaOAc]/[HOAc]

5.00 = 4.75 + log[NaOAc]/[1.00M]

5.00 - 4.75 = log [NaOAc] - log[1.00M]

log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78

Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.

Determine Volume of Base Needed

(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base

Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.

Checking Results:

5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00    QED.

The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.

We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:

[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex]   (1)  

Where:

[CH₃COOH] = 1.00 M                      

[CH₃COONa] =?

pH = 5.00

pKa = 4.75

From equation (1), we have:

[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]

[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]

Now, the volume of the acetate solution is:

[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]  

Since the total volume is the same, we have:

[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]  

[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]  

Solving for Vb

[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]

Therefore, we need to add 17.8 mL of sodium acetate solution.

Find more here:

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I hope it helps you!  

PLEASE HELP ME! I beg you :(

Answers

The answer is the second one from what i remember

2. What is one effect of convection currents in the mantle?
A. forming deep-water currents in oceans B. cooling the rocks of the crust
C. providing energy to drive the water cycle
D. transferring heat from Earth's interior to the crust​

Answers

Answer:

D no. is the answer of your question

find the number of molecules in 35.20 g of nitrogen dioxide

Answers

Answer:

4.584*10^23 molecules

Explanation:

Find molar mass of nitrogen and oxygen on periodic table.

find molar mass of nitrogen dioxide

use this to find moles of nitrogen dioxide

multiply by avagadros number

find molar mass by dividing grams by molar mass of nitrogen dioxide, then multiple by avogadro’s number to find number of molecules. 4.61 x 10^23 molecules. 3 sf

What is the formula of A^4 +b^4​

Answers

Answer:

A^4 +b^4

(a²)²+(b²)²

(a²+b²)²-2a²b²

or

(a²-b²)²+2a²b²

You have 0.531 L of gas in a container. What is the volume in mL?

Answers

Answer:

531 mL is the volume in mL

         

Answer:

Hi there!

I hope you are having an outstanding day.

I believe the answer to your question is 531!

Please adress me if I am incorrect. :)

Much love,

     Pandora

Explanation:

The equivalence point in a titration refers to the point when

A. the mł of the acid equals the mL of the base.

B. the molarity of the acid used in the reaction equals the molarity of the base used in the reaction.

C. the number of moles of one reactant reacts completely with the moles of the other reactant.

D. the acid in the flask turns clear.

Answers

Answer:

C) the number of moles of one reactant reacts completely with the moles of the other reactant.

Explanation:

it's right put it

Answer:

C

Explanation:

What unit of time is based on the revolution of Earth around the sun?
A. month
B. year
C. day
D. hour​

Answers

Years . The earth revolving around the sun takes 365 days which equals a year

______ occur between molecules that have permanent intramolecular differences in elecronegativity.
A. Dipole-dipole interactions
B. Dispersion forces
C. Hydrogen bonds​

Answers

The answer is dipole dipole interactions

Answer:

Dipole-dipole interactions

Explanation:

What is N for ClO3, the
chlorate ion?

Answers

Answer:

Explanation: There is no molecule or ion as ClO3. The correct formula of chlorate ion is ClO3-. bolivianouft and 4 more users found this answer helpful.

Explanation:

What is the mole fraction of KCI in a
mixture of 0.564 g NaCl, 1.52 g KCI,
and 0.857 g LiCl?
Molar Mass
NaCl: 58.44 g/mol
KCI: 74.55 g/mol
Lici: 42.39 g/mol

Answers

Answer:

Mole fraction of KCl = 0.4056

Explanation:

We'll begin by calculating the number of mole of each compound. This can be obtained as follow:

For NaCl:

Mass NaCl = 0.564 g

Molar mass of NaCl = 58.44 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 0.564 / 58.44

Mole of NaCl = 0.0097 mole

For KCl:

Mass KCl = 1.52 g

Molar mass of KCl = 74.55 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1.52 / 74.55

Mole of KCl = 0.0204 mole

For LiCl:

Mass LiCl = 0.857 g

Molar mass of LiCl = 42.39 g/mol

Mole of LiCl =?

Mole = mass /Molar mass

Mole of LiCl = 0.857 / 42.39

Mole of LiCl = 0.0202 mole

Next, we shall determine the total mole in the mixture. This can be obtained as follow:

Mole of NaCl = 0.0097 mole

Mole of KCl = 0.0204 mole

Mole of LiCl = 0.0202 mole

Total mole =?

Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl

Total mole = 0.0097 + 0.0204 + 0.0202

Total mole = 0.0503 mole

Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:

Mole of KCl = 0.0204 mole

Total mole = 0.0503 mole

Mole fraction of KCl =?

Mole fraction of KCl = Mole of KCl /Total mole

Mole fraction of KCl = 0.0204 / 0.0503

Mole fraction of KCl = 0.4056

Answer:

.4 is correct

Explanation:

"A 4.75-kg cell phone is dropped from your second floor balcony (from rest). It hits the
ground at a speed of 40 m/s. Assuming air resistance can be ignored, calculate the
gravitational potential energy of the cell phone before it was dropped."

Answers

Yo this is 45 and the second one is 2

How much does the Earth weigh?​

Answers

5.972 × 10^24 kg

hope it helps

Answer:

5.972 × 10^24 kg

hope this helps

Which of these elements has the lowest ionization energy?
A. Si
B. CI
C. S
D. Na

Answers

Answer:

D . Na

Explanation:


How many moles of hydrogen are in a 200. mg tablet of naproxen sodium, C14H13NaO3, the active ingredient in Aleve? Please show your work to receive full credit. MM = 252

Answers

Answer:

0.0103 mol

Explanation:

Step 1: Given data

Mass of the naproxen sodium tablet (m): 200. mgMolar mass of naproxen sodium (M): 252 g/mol

Step 2: Convert "m" to grams

We will use the conversion factor 1 g = 1000 mg.

200. mg × 1 g/1000 mg = 0.200 g

Step 3: Calculate the moles (n) of naproxen sodium

We will use the following expression.

n = m/M = 0.200 g / (252 g/mol) = 7.94 × 10⁻⁴ mol

Step 4: Calculate the moles of hydrogen in 7.94 × 10⁻⁴ moles of naproxen sodium

According to the chemical formula, the molar ratio of naproxen sodium to H is 1:13. The moles of H are 13/1 × 7.94 × 10⁻⁴ mol = 0.0103 mol.

2) Calculate the percent composition of each element in Mgso,

3) Calculate the percentage of each element in Ag,o.

Answers

Answer:

2)

[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]

3)

[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]

Best regards!

All forms of energy can be traced back to

Answers

the answer is the sun

Help me with my homework plzy

Answers

Answer:

the second answer choice i think

Explanation:

If I’m correct, the answer is C) current electricity would become static electricity.

Five different substances added breakers of water. Each substance begins as a white, solid powder. Which substances do not dissolve in water? Salt,sugar,starch,chalk, and bakeing powder

Answers

Answer:

Chalk is does not dissolve in water

Explanation:

i had the same question as you

what is the structure of methane​

Answers

Answer:

CH4

Explanation:

if it is wrong, i blame my brain

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