This is a math assignment due tomorrow! Need tonight please! :)

1. If a standard die is rolled twice, find each probability.
a) P (add both times)
b) P (even, less than 5)
c) P (the same number both times)

2. A coin is tossed, then a letter from the word INDIANAPOLIS is selected randomly. Find each probability.
a) P (heads, then P)
b) P (tails, then N)

3. A jar contains 8 green, 4 blue, 10 red, and 2 yellow Skittles. A Stittle is randomly drawn, replaced, then another is drawn. Find each probability.
a) P (red, then yellow)
b) P ( both blue)

4. A piggy bank contains 4 quarters, 18 dimes, 10 nickles, and 8 pennies. A coin is chosen randomly, not replaced, then another is chosen. Find each probability.\
a) P (penny, then dime)
b) P (silver coin, then penny)
c) P (both dimes)

5. If a coin is tossed seven times, what is the probability of it landing on heads each time?

6. While golfing, Kevin made 16 out of his last 21 putts. His friend Mike made 9 out of his last 14 putts. What is the probability that they both make their next putt?

7. If the probability that it will snow on Monday is 8/9 and the probability that it will snow on Tuesday is 3/16, find the probability that it does not snow either day.

8. A pop quiz contains five questions: two multiple choice questions with four options each and three true-false questions. If Brad randomly guesses, what is the probability that he gets all five answers correct?

The probabilities include:

1a) To find the probability of adding both times, use the formula: P(A and B) = P(A) × P(B)

There are 6 possible outcomes for each roll, so the sample space for rolling a die twice is 6 × 6 = 36.

There are 6 ways to get a sum of 7:

Each of these outcomes has probability 1/36, so the probability of getting a sum of 7 is 6/36 = 1/6.

Therefore, P(add both times) = P(sum of 7 or 8) = P(sum of 7) + P(sum of 8) = 1/6 + 1/6 = 1/3.

b) To find the probability of rolling an even number less than 5;

There are 2 even numbers less than 5: 2 and 4.

Each of these outcomes has probability 1/6, so the probability of rolling an even number less than 5 is 2/6 = 1/3.

c) To find the probability of getting the same number both times;

There are 6 possible outcomes where the same number is rolled both times: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), and (6, 6). Each of these outcomes has probability 1/36, so the probability of getting the same number both times is 6/36 = 1/6.

2a) The probability of getting heads on the first toss is 1/2. The probability of selecting a P from INDIANAPOLIS is 2/11 (since there are 2 P's in the word and 11 letters total). Therefore, P(heads, then P) = P(heads) × P(P) = 1/2 × 2/11 = 1/11.

b) The probability of getting tails on the first toss is 1/2. The probability of selecting an N from INDIANAPOLIS is 2/11 (since there are 2 N's in the word and 11 letters total). Therefore, P(tails, then N) = P(tails) × P(N) = 1/2 × 2/11 = 1/11.

3a) P(red, then yellow) = P(red) x P(yellow) = (10/24) x (2/24) = 5/144

b) P(both blue) = P(blue) x P(blue) = (4/24) x (4/24) = 1/36

c) P(both dimes) = P(dime) x P(dime) = (18/40) x (17/39) = 153/780

4a) P(penny, then dime) = P(penny) x P(dime) = (8/40) x (18/39) = 36/390 = 6/65

b) P(silver coin, then penny) = 2 x (P(quarter) x P(penny) + P(dime) x P(penny) + P(nickel) x P(penny)) = 2 x [(4/40) x (8/39) + (18/40) x (8/39) + (10/40) x (8/39)] = 64/390 = 32/195

c) P(both dimes) = P(dime) x P(dime without replacement) = (18/40) x (17/39) = 153/780

5. The probability of getting heads on a single toss of a fair coin is 1/2. Since each coin toss is independent, the probability of getting heads on seven tosses in a row is (1/2)⁷ = 1/128.

6. The probability that both Kevin and Mike make their next putts is the product of their individual probabilities: (16/21) x (9/14) = 48/98 = 24/49.

7. The probability that it does not snow on Monday is 1 - 8/9 = 1/9. The probability that it does not snow on Tuesday is 1 - 3/16 = 13/16. Since the events are independent, the probability that it does not snow on either day is (1/9) x (13/16) = 13/144.

8. The probability of guessing a multiple choice question correctly is 1/4 and the probability of guessing a true-false question correctly is 1/2. Since each question is independent, the probability of guessing all five answers correctly is (1/4)² x (1/2)³ = 1/128.

Find out more on probability here: https://brainly.com/question/24756209

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