Answer:
its a sure for not but i think its a 192583
What does the universe look like on very large scales?
Answer:
it looks like dots and just black space on a large scale
Explanation:
on a large scale the universe especially our milky way looks small
hope this helps
using the methos of dimensions derive an expression for the centripetal force f acting on a particle of mass m mivingv with velocity v in a circle of radius r?
According to the Question:
[tex]\footnotesize\implies F \propto [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F =k [m]^x [v]^y [r]^z \:...(i)[/tex]
K = Dimensionless ConstantNow, substituting Dimensions of each physical quantity in equation (I):
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M^1L^0T^0]^x [M^0L^1T^{-1}]^y [M^0L^1T^0]^z[/tex]
[tex]\footnotesize\implies [M^1L^1T^{-2}] =[M]^x [L]^{y + z} [T]^{ - y}[/tex]
On comparing the powers of LHS and RHS:
[tex]\implies \bf x = 1[/tex]
[tex]\implies - y = - 2[/tex]
[tex] \implies \bf y = 2[/tex]
[tex]\implies y + z = 1[/tex]
[tex]\implies z = 1 - 2[/tex]
[tex]\implies \bf z = - 1[/tex]
[tex]\footnotesize\implies F = [m]^x [v]^y [r]^z[/tex]
[tex]\footnotesize\implies F = [m]^1 [v]^2 [r]^{ - 1}[/tex]
[tex]\implies\footnotesize \underline{ \boxed{ \bf \red{ F = \frac{m {v}^{2} }{r} }}}[/tex]
An astronomer examines an emission line spectrum for a star from data recorded by a spectroscope. There are four lines: two in the blue region, one in the green region, and one in the red region of the spectrum. How does the spectrum obtained from the spectroscope help the astronomer?
The characteristics of the atomic spectrum allow to find the result so that the measured lines help the astronomer is:
The astronomer can identify the gases that are present in stars using emission lines.
The emission spectrum is the emission of light due to the atomic transition in atoms, consequently the spectrum of each chemical element is unique.
The astronomer was able to identify the chemical elements that are in stars by their emission spectrum.
In the case presented there are two lines in the blue region, a line in the green region and a line in the red region. We know that the most abundant element in stars is hydrogen.
Hydrogen has a series of well-defined spectral lines, the series that is in the visible part of the spectrum is called the Balmer series and is composed of the lines in the table.
Color wavelength (nm)
red 656.3
blue 486.1
violet 434.1
The second element in quantity in stars is helium, which has the spectrum given in the table and in the attached.
color wavelength (nm)
Red 667.8
orange 587.6
green 501.6
Blue 492.2
Blue 447.1
The astronomer compares his measured spectrum with the spectra of these two gases and finds that the element he is measuring is helium.
In conclusion, using the characteristics of the atomic spectra, we can find the result to help the astronomer with the measured lines is:
The astronomer can identify the gases that are present in stars using emission lines.
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Answer:b
Explanation:
did it
4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?
Answer:
A.)a=44.57m/s
B.)f=38,909.61
C.)f=666.4
Explanation:
A.) A=v/t 26.3/0.590=44.57
B.) 873kg x 44.57= 38,909.61
C.) 68kg x 9.8=666.4
How much work is done by a student holding a book with a force of 5N and walking forward 10 m?
Answer:
50 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 5 × 10 = 50
We have the final answer as
50 JHope this helps you
t/-15=-3. what is t?
Answer:
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1. Look at this data table
What data seems to be inconsistent with the rest? What are 2 different explanations for this data?
Using visual inspection and knowledge of linear regression , the inconsistent input is the last data point (30, 12.0).
Looking at the data, there is a negative relationship between the depth of water sample and the amount of dissolved oxygen. As the depth increases, the amount of dissolved oxygen decreases. However, the last data point does not concur with this trend. This might have been caused by imputation error or error in the measuring device used.Therefore, the inconsistent data point is (30, 12.0)
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What are 2 examples of Newton's second law in everyday life?
Answer:
kicking ball and throwing stone
Answer:
- Pushing a shopping cart
- Kicking a soccer ball
Explanation:
The second law states "It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."
So two examples would be pushing / kicking anything (shopping cart or soccer ball for example) and riding a bicycle (bike = mass and you are the force)
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
echo is experienced more in a newly constructed room than in a furnished room why??
Answer:
in a furnished room the furniture scatter the sound waves and it doesn't reach our ears in the same manner it left our mouth.
is there any difference in upthrust of water at b and c
Answer:
no picture attached
Explanation:
which chamber approves presidential nomination
Answer: The Senate provides advice and consent on presidential nominations.
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Evonne does not have a lot of time to work out during the week. She wonders if she spent half a day on the weekend getting is as many different types of exercise as possible if that would help. What is the BEST advice for Evonne?
A.
She has the right idea since variety is more important than intensity.
B.
She can do that, but should have a clear goal in mind to define her exercise.
C.
She should only focus on one type of exercise since she can do it once a week.
D.
She would be better off fitting in 15-20 minutes of exercise several times a week.
PLEASE NO LINKS
She would be better off fitting in 15-20 minutes of exercise several times a week. This t is the BEST advice for Evonne.
What are the benefits of regular exercise?Regular physical activity and exercise have many positive health effects that are difficult to deny. Everyone, regardless of age, sex, or physical ability, benefits from exercise.
Exercise can assist sustain weight loss or prevent excessive weight gain. Calorie burn occurs during physical exertion. You burn more calories when you engage in more vigorous exercise.
Numerous health issues and concerns, such as stroke, the metabolic syndrome, high blood pressure, and type 2 diabetes, can be prevented or managed with regular exercise. It can also help with cognitive improvement and reduce the danger of dying from any cause.
Exercise helps your circulatory system function more effectively and distributes oxygen and nutrients to your tissues. Additionally, you have greater energy to complete daily tasks as your heart and lung health improves.
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A cyclist is coasting at 12 m/s when she comes to a muddy stretch with an effective coefficient of friction of 0.60. Will the cyclist be able to get out of the muddy stretch without having to pedal if it lasts 10 meters
The cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
The given parameters;
speed of the cyclist, u = 12 m/scoefficient of friction, μ = 0.6length of the muddy stretch, L = 10 mThe effective acceleration of the cyclist at the given coefficient of friction is calculated as follows;
[tex]a = \ \mu g\\\\a = 0.6 \times 9.8\\\\a = 5.88 \ m/s^2[/tex]
The distance traveled by the cyclist at the give speed and acceleration is calculated as;
[tex]v^2 = u^2 + 2as\\\\12^2 = 0 + 2(5.88)s \\\\ 11.76 s = 144\\\\ s = \frac{144}{11.76} \\\\a = 12.24 \ m[/tex]
Thus, we can conclude that the cyclist will make it since the distance traveled by the cyclist is greater than the length of the muddy stretch.
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What does a larger interquartile range mean.
The _____________ experiences a temperature increase primarily due to the absorption of gamma rays and X-rays.
Answer:
The thermosphere experiences a temperature increase primarily due to the absorption of gamma-rays and X-rays.
Calculate the weight of a 2kg chicken on earth. .. (use the formulas)
Answer:
weight =m x g =2kg × 10m/s 2 = 20N
Formulas:
weight = m × gravity
=unit for weight is newtons
Mass=weight ÷ gravity
= unit for mass is kilograms
Gravity=weight ÷ mass
=unit for gravity is 10m/sec 2
. Quỹ đạo chuyển động của một vật là
Answer:
you are very kind Po lang
Which of these is a likely impact of the stronger than normal trade winds on the eastern Pacific ocean?
Warm surface water builds up, causing lower than average temperature.
Warm surface water builds up, causing higher than average temperature.
Warm surface water is reduced, causing colder conditions than normal.
Warm surface water is reduced, causing hotter conditions than normal.
Just say A B C or D which one
Answer:
b i think
Explanation:
hope this helps
Answer: A B C or D which one
Explanation:
A 16.75 g piece of iron absorbs 986.75 joules of heat energy, and it’s temperature changes from 25 degrees Celsius to 175 degrees Celsius. Calculate the specific heat capacity of iron.
Answer:
0.39 J/g°c
Explanation:
= heat / unit of mass × unit of temperature
986.75J/16.75g
= 58.9 J/g
∆T=175°c - 25°c = 150°c
986.75 / 150°c = 6.578
986.75 / 16.75g.150°c = 0.30 j/g°c
You find a rock that is about 20 grams large. This rock contains about 10 grams of Uranium-235 and 10 grams of the element it decays into (Thorium-231). The half life of Uranium-235 is 700 million years. How old is this rock?
The age of the given rock is 700 million years.
The given parameters;
original mass of the rock, = 20 gmass of the rock remaining after decay, = 10 ghalf life of Uranium, [tex]t_{1/2}[/tex] = 700 yearsage of the rock ----------------------------- mass remaining
0 [tex](t_0)[/tex] ------------------------------------------- 20 g
1 half life ([tex]1 \ t_{1/2}[/tex] ) ------------------------------ 10 g
Age of the rock [tex]= t_{1/2} - t_0 = 700 \ - 0 = 700 \ million \ years[/tex]
Thus, the age of the given rock is 700 million years.
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Calculate the charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts.
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
Potential difference is the amount of work needed to move a unit charge from one point to another. It is given by:
V = E/Q
Where V is potential difference, E is energy and Q is charge. Given that:
V = 15 V, E = 5.25 kJ = 5.25 * 10³ J.
V = E/Q
15 = 5.25 * 10³ /Q
Q = 350 Coulomb
The charge flow if the energy transferred is 5.25 kJ and the potential difference is 15 volts is 350 Coulomb
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If acceleration of a body starting from the rest is 0.5m/s^2 how long will it take the body to travel 400m(if u are genius answer this)
Answer:
[tex]\huge\boxed{\sf t = 40\ seconds}[/tex]
Explanation:
Given data:
Acceleration = a = 0.5 m/s²
Initial Velocity = Vi = 0 m/s
Distance = S = 400 m
Required:
Time = t = ?
Formulas used:
2 formulas
Third Equation of motion (2as = Vf²-Vi²)First Equation of motion (Vf = Vi + at)Solution:
Using third equation of motion firstly
2as = Vf²-Vi²
2(0.5)(400) = Vf² - 0²
400 = Vf²
Taking sqrt
Vf = 20 m/s
Now, Using First equation of motion:
Vf = Vi + at
20 = 0 + 0.5t
0.5 t = 20
Divide both sides by 0.5
t = 40 seconds
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Which wave has the highest frequency?
Answer:
e
Explanation:
It is possible to create a wave having some frequency on a rope and then gradually it will become faster. During this time wavelength becomes shorter. Here the wave 'e' is found to has highest frequency. The correct option is E.
What is frequency of a wave?The number of oscillations of a wave per unit time is defined as the frequency. It is usually measured in Hertz and the frequency is directly proportional to the pitch. Humans can hear sounds with frequencies ranging between 20-20000 Hz.
The sounds with frequencies over the human ears range are called the ultrasonic sound and sounds with frequencies less than the audible range are called infrasonic sound. The wavelength and frequency are inversely proportional to each other.
When wavelength increases, frequency decreases and vice versa. So here wave E has maximum number of vibrations.
Thus the correct option is E.
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What happens to the sound an object makes when the speed of vibrations decreases (slow down)?.
Which colour of light is refracted more by a prsim green or blue.explain
Answer:
The light waves are refracted as they enter and leave the prism. The shorter the wavelength of the light, the more it is refracted. As a result, red light is refracted the least and violet light is refracted the most - causing the coloured light to spread out to form a spectrum.
Explanation:
hope this helps
Answer: Neither, its actually violet aka purple. This is because it has the shortest wavelength. This is also why red light is refracted the least because it has the longest wavelength.
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Voltage ______
Question 1 options:
is measured in Volts
causes current
pushes free electrons around a circuit
all of the choices
all of the choices.
Explanation:
....
Which event happens in a solar cell when the photoelectric effect occurs?
A. Electromagnetic waves strike the transparent glass on the top of
the cell, removing electrons from it.
B. The wave model of light is supported, but the particle model is
not.
C. A current forms when electromagnetic waves strike a
semiconductor, removing some of its electrons.
the
D. Electrons flow from the positively charged semiconductor to
negatively charged one.
Answer:
current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.
Explanation:
Answer:
current forms when electromagnetic waves strike a semiconductor, removing some of its electrons.
trust me i just did it
Explanation:
PLS HURRY THIS IS DUE TODAY!!!
I WILL GIVE BRAINLIEST!!!!
NO LINKS AND NO STEALING POINTS,
PLS ANSWER IF YOU KNOW FOR SURE WHAT IT IS!!!
THE QUESTION IS IN THE PICTURE ATTACHED!
Answer:
B. between carbon and oxygen
Explanation:
formaldehyde has a carbon atom that has single bonds with two hydrogen atoms on both sides, and it has a double bond with oxygen.
Answer:
The placement of the double bond is between carbon atom and oxygen atom
this same question was for me so I did and got it correct
please mark me as brainliest
BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time
find distance and acceleration
PLEASEEEE HELP I HAVE A PHYSICS EXAM TOMORROW AND IM STRUGGLING
Answer:
add 44m/s and 22m/s then multiply it by 11
Explanation:
A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.
To solve this problem, it is given:
Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s
Final velocity ([tex]\(v_f[/tex] ) = 22 m/s
Time ([tex]\(t\)[/tex] ) = 11 s
We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).
1. Calculate Acceleration (a):
[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]
The negative sign indicates deceleration (slowing down).
2. Calculate Distance (d):
Using the kinematic equation:
[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]
Plugging in the values:
[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]
Calculating the first part:
[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]
Calculating the second part:
[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]
The total distance the race car moves during this time is 242 meters.
Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.
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