Three identical train cars, coupled together are rolling east at 2.0 m/s. A fourth car traveling east at 4.0 m/s catches up with the three and couples to make a fourcar train. A moment later the train cars hit a fifth car that was at rest on the tracks, and it couples to make a five car train. What is the speed of the five car train?

Answers

Answer 1

Answer:

The value is  [tex]v = 2 \ m/s[/tex]

Explanation:

From the question we are told that

   The velocity of the each of the three cars is [tex]u_1 = u_2 = u_3 = 2 \ m/s[/tex]

    The velocity of the fourth car is  [tex]u_4 = 4 \ m/s[/tex]

    The initial velocity of the fifth car [tex]u_5 = 0 \ m/s[/tex]

Generally from the law of momentum conservation we have that

    [tex]m_1 u_1 + m_2 u_2 + m_3 u_3 +m_4u_4 + m_5u_5 = [m_1 + m_2 + m_3 +m_4+ m_5]v[/tex]

Given that the cars are identical then their mass will be the same

i.e

    [tex]m_1 =m_2 = m_3 = m_4 = m_5 = m[/tex]

=>   [tex][u_1 + u_2 + u_3 +u_4 + u_5]m = 5mv[/tex]

=>   [tex]2+ 2 + 2 +4 + 0 = 5v[/tex]

= >   [tex]v = 2 \ m/s[/tex]


Related Questions

A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mfrom the bulb, the light intensity is I0, the average energy density of the waves is u0, and the rms electric and magnetic field values are E0 and B0, respectively.
At 2.0 m from the bulb, what is the light intensity?

Answers

Answer:

I0/4

Explanation:

If the difference is increasedby a factor of two(i.e twice it's original value), then the light intensity happens to get reduced by one-fourth. This means that the light intensity would be:

I0/4

3. A cart (m= 10.0 kg) is currently traveling with a velocity of 3.0 m/s. The cart then gains speed,
achieving a new velocity of 7.0 m/s after 8.0 seconds. Calculate the magnitude of the net force acting
on the cart.
A 0.0 N
B. 1.25 N
C. 5.0 N
D. 80N

Answers

First we calculate the acceleration of the cart:

a = (v₂ - v₁) / (t)

a = (7 m/s - 3 m/s) / (8 s)

a = 4 m/s / 8 s

a = 0.5 m/s²

Using the Newtons Second Law:

F = m×a

F = (10 kg)(0.5 m/s²)

F = 5 N

The correct option is C

A quantity of hot water at 91°C and another cold one at 12°C.
How much kilogram of each one is needed to make an 800 liter of water bath
at temperature of 35°C.

Answers

Answer:

[tex]m_{cold}=567kg\\\\m_{hot}=233kg[/tex]

Explanation:

Hello!

In this case, since equilibrium temperature problems involve the mass, specific heat and temperature change for the substances at different temperatures, we can write:

[tex]m_{cold}C_{cold}(T_{eq}-T_{cold})=-m_{hot}C_{hot}(T_{eq}-T_{hot})[/tex]

Thus, since we are talking about water and they both have the same specific heat, we can write:

[tex]m_{cold}(T_{eq}-T_{cold})=-m_{hot}(T_{eq}-T_{hot})[/tex]

Now, we plug in the temperatures to obtain:

[tex]m_{cold}(35-12)+m_{hot}(35-91)=0\\\\23m_{cold}-56m_{hot}=0[/tex]

Next, since the total volume of water is 800 L, since it has a density of 1kg/L, we infer the total mass is 800 kg; that is why we can write a 2x2 system of simultaneous equations:

[tex]\left \{ {{23m_{cold}-56m_{hot}=0} \atop {m_{cold}+m_{hot}=800}} \right.[/tex]

Thus, the masses of both cold and hot water turn out:

[tex]m_{cold}=567kg\\\\m_{hot}=233kg[/tex]

Best regards!

What is the slope of the line that passes through the points (-8, -3)(−8,−3) and (-12, -3) ?(−12,−3)? Write your answer in the simplest form.
single black dude

Answers

Notice that both of those points are 3 units below the x-axis. So the line is horizontal ... its slope is zero.

give an example of a normal force. type below.

Answers

Normal force is the force exerted when an object is on an surface. So an example could be a pile of books on top of a table.

The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which change would make this electromagnet weaker?

A. Reverse the direction of the battery

B. Rap more coils around the nail

C. Replace the steel nail with a wooden stick

D. Replace the battery with a 3V battery

Correct answer is C

Answers

If an electromagnet is made with copper wire, a steel nail, and a 1.5 V battery then replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.

What is electromagnetic force?

It is a type of force that occur between electrically charged particles. The electromagnetic force is the combination of all the electrical and magnetic forces generated by any charged particle.

As given in the problem statement diagram shows an electromagnet made with copper wire, a steel nail, and a 1.5 V battery, then we have to find out which change would make this electromagnet weaker,

Hence, By replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.

To learn more about electromagnetic forces, refer to the link;

brainly.com/question/13191643

#SPJ5

you are driving at 18m/s down Lyndale​ avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part​ problem with constant speed and braking.

Answers

Hello!

For this, first let's calculate time of stop:

t = (V - Vi) / a

Replacing:

t = (0 m/s - 18 m/s) / -5,4 m/s^2

Resolving:

t = -18 m/s / -5,4 m/s^2

t = 3,33 s + 0,25 s = 3,58 s

Now lets calculate distance traveled, with formula:

d = Vi*t + (a*t^2)/2

Replacing:

d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2

Resolving:

d = 64,44 m + (-34,604 m)

d = 29,83 m

Then, the vehicle will CRASH

A car moving initially at 20 m/s accelerates up to 60 m/s during the
course of 5 seconds. The average acceleration of the car is m/s2

Answers

Gain in velocity = 60 - 30 = 30 m/s.

Time taken for this gain = 5 seconds

Average acceleration = 30 / 5 = 6 m/s/s.

So, 6 metres per second squared.
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Related Questions (More Answers Below)

How fast should a rocket ship move for its mass to be dilated to 167% of its rest
mass?​

Answers

Answer:

The two forces acting on rockets at the moment of launch are the thrust upwards and the weight downwards. Weight is the force due to gravity and is calculated (at the Earth’s surface) by multiplying the mass (kilograms) by 9.8.The resultant force on each rocket is calculated using the equation resultant force = thrust – weight.

Hopefully, this answer helps you! :)

HELP ASAP!! i’ll mark you the brainliest!!

Answers

Answer:

yes

Explanation:

You have to move your 100 N couch before a delivery company drops off your new one. Unfortunately your roommate is passed out on it. The coefficient of friction between the couch and floor is .43. It takes 250 N of force to get the couch moving. a) How much does your roommate weigh in Newton’s? b) After you get the couch moving it only takes 200 N to keep it moving at a constant speed, what is the coefficient of kinetic friction?

Answers

Answer:

a) Weight of Roommate = 481.4 N

b) μk = 0.34

Explanation:

a)

The force required to move the couch must be equal to the force of friction:

F = frictional force

F = μW

W = F/μ

where,

W = Total Weight of Couch and Roommate

F = Force Required start to move couch = 250 N

μ = coefficient of static friction between couch and floor = 0.43

Therefore,

[tex]W = \frac{250 N}{0.43}\\\\W = 581.4 N[/tex]

So, the total weight is given as:

W = Weight of Couch + Weight of Roommate

Weight of Roommate = W - Weight of Couch

Weight of Roommate = 581.4 N - 100 N

Weight of Roommate = 481.4 N

b)

Now, the force required to keep the couch moving can be given as equal to the kinetic friction force:

F = kinetic friction

F = μk*W

μk = F/W

where,

μk = coefficient of kinetic friction = ?

F = Force required to keep the couch moving = 200 N

Therefore,

μk = 200 N/581.4 N

μk = 0.34

Where are you atera11

Answers

Answer:

? who is atera11?

Explanation:

ASAP
What is elastic potential energy?

Answers

Answer:

Elastic potential energy is stored when materials stretch or compress. Examples of it include springs, rubber bands, and slingshots.

Explanation:

Look at this model of an atom. Where are the electrons located and how many are there?

Answers

Answer:

The electrons are on the outer shell, there are 10 of them.

Explanation:

There are two in the inner shell and eight in the outer shell, giving us a total of 10 electrons

Which term best describes the motion of the rope particles in relation to the motion of the rope wave shown in the photograph

Answers

Answer:

A: Perpendicular

Explanation:

The question is incomplete as it lacks the image of the rope wave motion.

However, as found on "estudyassistant", the options are;

A) Perpendicular

B) Circular

C) Longitudinal

D) Parallel

From all that, we can say that;

The rope's are moving simultaneously in the same pattern without touching each other.

This is therefore a mechanical wave being created with the motion having oscillations that are perpendicular to the direction of energy transfer of the ropes.

This is a definition of transverse waves because the rope particle motion is perpendicular to the wave motion.

Answer:

A: Perpendicular

Explanation:

Read above explanation.

A block with a mass of 0.30 kg is attached to a horizontal spring. The block is pulled back from its equilibrium position until the spring exerts a force of 1.2 N on the block. When the block is released, it oscillates with a frequency of 1.1 Hz.
How far was the block pulled back before being released?

Answers

Answer:

The value is  [tex]x = 0.084 \ m[/tex]

Explanation:

From the question we are told that

   The mass of the block is  [tex]m = 0.30 \ kg[/tex]

   The force exerted is  [tex]F = 1.2 \ N[/tex]

   The  frequency is  [tex]f = 1.1 \ Hz[/tex]

Generally the spring constant of the spring is mathematically represented as

       [tex]k = (2 \pi f)^2 * m[/tex]

=>    [tex]k = (2 * 3.142 * 1.1 )^2 * 0.30[/tex]

=>    [tex]k = 14.33 \ N/m[/tex]

Generally the spring constant is also mathematically represented as

      [tex]k = \frac{ F }{x }[/tex]

=>   [tex]14.33 = \frac{ 1.2 }{x }[/tex]

=>   [tex]x = 0.084 \ m[/tex]

What is the main difference between analog anddigital technology?a. Digital technology reproduces sound more faithfullythan analog technology.b. Analog technology stores information as soundwaves; digital technology stores it as strings of onesand zeroes.c. Analog technology can be used to record sound andimages; digital technology can only be used to recordsound.d. Analog technology is based on binary code; digitaltechnology is based on electromagnets

Answers

Answer:

Answer b)

Explanation:

The correct answer is that analog technology stores information as sound-waves, while digital technology stores it as strings of ones and zeroes. So pick answer b)

In specific heat capacity experiment, the ammeter in circuit is connected in

Answers

Answer:

In series

Explanation:

In such experiment, the ammeter is connected in series with the heater, in order to measure the circulating current.

By the way, ammeters are always connected in series in circuits to measure the running current in it.

ASAP DUE TO DAY PLS HELP MEEEEEE

1. Kinetic energy is the energy of:
A. potential
B. objects at rest
C. objects in motion
D. accelerating objects
--------------------------------------------------------------------------------------------

Answers

i believe it is c, objects in motion. i apologize i’m im wrong.


The weight of the bricks is 5000N. Calculate the mass of the bricks.
(1 kg weighs 10N)

Answers

Answer:

500kg

Explanation:

....................

Answer:

500Kg

Explanation:

1 kg = 10N

? =5000N

5000N÷10N * 1Kg = 500Kg

If you add a light bulb to the circuit, the filament in the bulb will resist the flow of
electrons and convert energy into____and_____

a.)light and heat
b.)electrons and neutrons
c.)energy and matter
d.)electrons and protons

Answers

Answer:

Light and heat!

Explanation:

This is correct<3

Answer:

light and heat

Explanation:

i love science

a book falls off a 1-meter tall table. how long will it take for the book to hit the floor ?

Answers

Answer:

0.45 s

Explanation:

Step 1: Given and required data

Displacement of the book (s): 1 mInitial velocity of the book (u): 0 m/s (rest)Acceleration due to the gravitational force of Earth (a): 9.8 m/s²

Step 2: Calculate the time that it will take for the book to hit the floor (t)

The book undergoes a Uniformly Accelerated Motion. We can calculate the time required to reach the floor using the following suvat equation.

s = u × t + 1/2 × a × t²

s = 0 m/s × t + 1/2 × a × t²

s = 1/2 × a × t²

t = √(2s/a)

t = √(2 × 1 m/9.8 m/s²)

t = 0.45 s

Based on the law of conservation of energy, which statement is correct?
A.
Energy is always being added to all parts of the Universe.
B.
Energy is often destroyed in some parts of the Universe.
C.
Energy in a closed system cannot change forms.
D.
Energy in an isolated system remains constan

Answers

Answer:

D

Explanation:

Nothing can enter or leave so it remains constant

The answer is D because nothing can leave

As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.60 cm2 and the woman's mass is 54.0 kg. Express the force in N/m2 and lb/in2. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to resist such large pressures.)

Answers

Answer:

P = 3.3075 x 10⁶ N/m² = 479.71 lb/in²

Explanation:

In order to find the pressure , we first need to find the force exerted by the lady. The force must be equal to the weight of the lady:

Force = F = Weight = mg

F = mg = (54 kg)(9.8 m/s²)

F = 529.2 N

Now, we convert area to S.I unit:

Area = A = (1.6 cm²)(1 m/100 cm)²

A = 1.6 x 10⁻⁴ m²

Now, the pressure can be calculated as:

Pressure = P = F/A

P = 529.2 N/1.6 x 10⁻⁴ m²

P = 3.3075 x 10⁶ N/m²

Now, we convert this into lb/in²:

P = (3.3075 x 10⁶ N/m²)[(0.000145038 lb/in²)/(1 N/m²)

P = 479.71 lb/in²

Which of the following cars have the most kinetic energy

Answers

Hey There!_____________________________________Answer:

[tex]\huge\boxed{OptionA}[/tex]

_____________________________________DATA:Blue Car:

mass = 4 kg

velocity = 5 m/s^2

Orange truck:

Mass= 2kg

Velocity = 7m/s^2

Grey Car:

mass = 6 kg

velocity = 4m/s^2

Green Car:

Mass = 8 kg

Velocity = 3 m/s^2

_____________________________________SOLUTION:

By the equation of kinetic energy,

                                       

                                         K.E = [tex]\frac{1}{2} mv^2[/tex]

Where,

            K.E is kinetic energy

            m is mass

            v is velocity

_____________________________________Kinetic energy of Blue car:

 

Directly substitute the variables in the equation,

                                       

                                       K.E = [tex]\frac{1}{2}x4x5^2[/tex]

Simplify the equation,

                                       K.E = 50 J

_____________________________________Kinetic Energy of Silver Car:

                                           

 Directly substitude the variable in the equation,

                                                           

                                        K.E = [tex]\frac{1}{2}x6x4^2[/tex]

Simplify the equation,

                                        K.E = 48J

_____________________________________Kinetic Energy of Green Car:

Substitute the variables in the equation,

                                         

                                         K.E = [tex]\frac{1}{2}x8x3^2[/tex]

Simplify the Equation,

                                         

                                         K.E = 36J

_____________________________________Kinetic Energy of Orange Truck:

Substitute the variable,

                                        K.E = [tex]\frac{1}{2}x 2x7^2[/tex]

Simplify the equation,

                                     

                                        K.E = 49J

_____________________________________

As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.

_____________________________________Best Regards,'Borz'

A Ferris wheel with 60 spokes has a diameter of 100 m. It makes one rotation every 60 seconds. Find the speed of the passengers when the Ferris wheel is rotating at this rate.

Answers

Answer:

The speed of the passengers is 5.24 m/s

Explanation:

Uniform Circular Motion

It occurs when an object in a circular path travels equal angles in equal times.

The angular speed can be calculated in two different ways:

[tex]\displaystyle \omega=\frac{v}{r}[/tex]

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

[tex]\omega=2\pi f[/tex]

Where:

f = frequency

Since the frequency is calculated when the number of revolutions n and the time t are known:

[tex]\displaystyle f=\frac{n}{t}[/tex]

The Ferris wheel has a diameter of 100 m and makes n=1 rotation in t=60 seconds, thus the frequency is:

[tex]\displaystyle f=\frac{1}{60}\ Hz[/tex]

The angular speed is:

[tex]\displaystyle \omega=2\pi \frac{1}{60} =\frac{\pi}{30} \ rad/s[/tex]

Now we calculate the tangential speed, solving this formula for v:

[tex]\displaystyle \omega=\frac{v}{r}[/tex]

[tex]v=\omega . r[/tex]

The radius is half the diameter, r=100/2=50 m:

[tex]\displaystyle v=\frac{\pi}{30} . 50[/tex]

Calculating:

v = 5.24 m/s

The speed of the passengers is 5.24 m/s

2/3


If the crate has a mass of 80 kg, how much would it weigh?

Answers

are you asking if what it would weigh in lbs?

What is food called when it enters the pharynx?

A.Bile
B.bolus
C. Food
D. Feces

Answers

Answer:

its food this was easy

2.14x10^-7. What is the answer. Write in standered form

Answers

0.000000214 give me brainliest plz

a 2kg block is attached to a horizontal ideal spring with a spring constant of 200 Newton per minute. when the spring has its equillibrium length of block is given a speed of 5mps. what is the maximum elongation of the spring

Answers

Answer:

The maximum elongation of the spring is 0.5 meters.

Explanation:

The statement is incorrect. The correct form is:

A 2-kg block is attached to a horizontal ideal spring with a spring constant of 200 newton per meter. When the spring has its equillibrium length, the block has a speed of 5 meters per second. What is the maximum elongation of the spring?

The block experiments a simple harmonic motion, where there are no non-conservative forces and the total energy is the sum of translational kinetic energy of the mass and the elastic potential energy of the spring. The maximum elongation of the spring is done when elastic potential energy reach its maximum. By the Principle of Energy Conservation, the maximum elastic potential energy is equal to the maximum translational kinetic energy, which corresponds to the instant when the mass reaches the equilibrium position. Then, the equation modelling the system is:

[tex]U_{max} = K_{max}[/tex] (1)

Where:

[tex]U_{max}[/tex] - Maximum elastic potential energy of the spring, measured in joules.

[tex]K_{max}[/tex] - Maximum translational kinetic energy of the mass, measured in joules.

By definitions of the maximum elastic potential energy of the spring and the maximum translational kinetic energy of the mass, the expression above is expanded and simplified:

[tex]\frac{1}{2}\cdot k\cdot x_{max}^{2} = \frac{1}{2}\cdot m \cdot v_{max}^{2}[/tex]

[tex]x_{max} = \sqrt{\frac{m}{k} }\cdot v_{max}[/tex] (2)

Where:

[tex]x_{max}[/tex] - Maximum elongation of the spring, measured in meters.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]k[/tex] - Spring constant, measured in newtons per meter.

[tex]v_{max}[/tex] - Maximum speed of the mass, measured in meters per second.

If we know that [tex]m = 2\,kg[/tex], [tex]k = 200\,\frac{N}{m}[/tex] and [tex]v_{max} = 5\,\frac{m}{s}[/tex], then the maximum elongation of the spring is:

[tex]x_{max} = \sqrt{\frac{2\,kg}{200\,\frac{N}{m} } }\cdot \left(5\,\frac{m}{s} \right)[/tex]

[tex]x_{max} = 0.5\,m[/tex]

The maximum elongation of the spring is 0.5 meters.

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