Three sisters are saving for a special trip . The ratio of Nora​'s savings to Helga​'s savings is 8:3 and the ratio of Helga​'s savings to ​Maurice's savings is 3:4. Together all 3 have saved ​$60. How much has each ​saved?

Answers

Answer 1

Answer:

X = 10.588

Y = 28.2

Z = 21.176

Step-by-step explanation:

Consider Nova savings as X

Helga is Y

Maurice is Z

As per first ratio we conclude 8X=3Y

Second ratio we conclude 3Y = 4Z

We deduce 8X = 4Z

Last sentence => X+Y+Z=60 multiple it by 3

=> 3X + 3Y + 3Z= 180 but 8X = 4Y

=> 3X + 8X + 3Z =180 => 11X + 3Z=180 multiple the equation by 4/3

44/3 X + 4Z = 240 but 4Z = 8X

=> 44/3 X + 8 X = 240

=> 68/3 X = 240

=> 68X = 720

=> X =10.588

And Y=8/3 X =28.2

And Z=3/4 Y = 21.176


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If this answered help you then please consider marking it as brainliest to help me level up to expert

jo jo has a total amount of $12.45 in quarters and dimes in his pocket. he has a total of 60 coins. how many quarters and dimes does jo jo have?

a. 42 quarters and 18 dimes b. 43 quarters and 17 dimes
c. 44 quarters and 16 dimes d. 41 quarters and 19 dimes
e. 40 quarters and 20 dimes

NEED ANSWERED ASAPP!!!

Answers

Given:

Total number of coins (Quarters and dimes) = 60

Total amount = $12.45

To find:

The number of quarters and dimes.

Solution:

Let x be the number of quarters and y be the number of dimes.

We know that,

1 quarter = 0.25 dollar

1 dime = 0.10 dollar

Total coins: [tex]x+y=60[/tex]               ...(i)

Total amount: [tex]0.25x+0.10y=12.45[/tex]             ...(ii)

From (i), we get

[tex]y=60-x[/tex]          ...(iii)

Putting this value in (ii), we get

[tex]0.25x+0.10(60-x)=12.45[/tex]

[tex]0.25x+6-0.10x=12.45[/tex]

[tex]0.25x-0.10x=12.45-6[/tex]

[tex]0.15x=6.45[/tex]

Divide both sides by 0.15.

[tex]x=\dfrac{6.45}{0.15}[/tex]

[tex]x=43[/tex]

Putting x=43 in (iii), we get

[tex]y=60-43[/tex]

[tex]y=17[/tex]

So, the number of quarters is 43 and the number of dimes is 17.

Therefore, the correct option is b.

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Answers

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here are some websites you can use:

mathpapa .com

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