Answer:
work out 8^2 and then ×1/4
[tex] \frac{1}{4} (8)^{2} = 16 \: not \: 8[/tex]
therefore
[tex] \frac{1}{4} ({8})^{2} (12) = 192[/tex]
A movie theater sells matinee tickets for $6 each and has a capacity of 100 people. The function M(x) = 6x represents the amount of money the movie theater makes from ticket sales,
where x is the number of customers. What would be the most appropriate domain for the function? (1 point)
Whole numbers less than or equal to 100
Whole numbers that are multiples of 6
All real numbers
All whole numbers
Answer:
A. Whole numbers less than or equal to 100
Step-by-step explanation:
The domain is the set of x numbers that can be plugged in to a certain equation.
Since the capacity of this movie theater is 100, x can be between 0 and 100, inclusive.
Answer choice A makes sense because whole numbers are definitionally positive integers and this choice caps out at 100.
A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600. On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score. What is the percentile rank of sales for this day
Answer:
Tuesday's z-score was of -1.325.
The percentile rank of sales for this day was the 9.25th percentile.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
A department store, on average, has daily sales of $21,000. The standard deviation of sales is $3600.
This means that [tex]\mu = 21000, \sigma = 3600[/tex]
On Tuesday, the store sold $16,230 worth of goods. Find Tuesday's z score.
This is Z when X = 16230. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{16230 - 21000}{3600}[/tex]
[tex]Z = -1.325[/tex]
Tuesday's z-score was of -1.325.
What is the percentile rank of sales for this day
This is the p-value of Z = -1.325.
Looking at the z-table, this is of 0.0925, and thus:
The percentile rank of sales for this day was the 9.25th percentile.
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
(a) P(X >10)
(b) P(X >20)
(c) P(X <30)
(d) Find the value of x such that P(X
Answer:
a) P(X > 10) = 0.6473
b) P(X > 20) = 0.4190
c) P(X < 30) = 0.7288
d) x = 68.87
Step-by-step explanation:
Exponential distribution:
The exponential probability distribution, with mean m, is described by the following equation:
[tex]f(x) = \mu e^{-\mu x}[/tex]
In which [tex]\mu = \frac{1}{m}[/tex] is the decay parameter.
The probability that x is lower or equal to a is given by:
[tex]P(X \leq x) = \int\limits^a_0 {f(x)} \, dx[/tex]
Which has the following solution:
[tex]P(X \leq x) = 1 - e^{-\mu x}[/tex]
The probability of finding a value higher than x is:
[tex]P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}[/tex]
Mean equal to 23.
This means that [tex]m = 23, \mu = \frac{1}{23} = 0.0435[/tex]
(a) P(X >10)
[tex]P(X > 10) = e^{-0.0435*10} = 0.6473[/tex]
So
P(X > 10) = 0.6473
(b) P(X >20)
[tex]P(X > 20) = e^{-0.0435*20} = 0.4190[/tex]
So
P(X > 20) = 0.4190
(c) P(X <30)
[tex]P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288[/tex]
So
P(X < 30) = 0.7288
(d) Find the value of x such that P(X > x) = 0.05
So
[tex]P(X > x) = e^{-\mu x}[/tex]
[tex]0.05 = e^{-0.0435x}[/tex]
[tex]\ln{e^{-0.0435x}} = \ln{0.05}[/tex]
[tex]-0.0435x = \ln{0.05}[/tex]
[tex]x = -\frac{\ln{0.05}}{0.0435}[/tex]
[tex]x = 68.87[/tex]
[tex] {x}^{2} + 2x = 0[/tex]
Answer:
[tex]\textbf{Hello!}[/tex]
[tex]\Longrightarrow2^2+2z=0[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}[/tex]
[tex]\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2-0}[/tex]
[tex]\Longrightarrow =\sqrt{2^2}[/tex]
[tex]\Longrightarrow=2[/tex]
[tex]\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow\frac{-2+2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{0}{2}[/tex]
[tex]=0[/tex]
[tex]\Longrightarrow\frac{-2-2}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2\cdot \:1}[/tex]
[tex]\Longrightarrow =\frac{-4}{2}[/tex]
[tex]\Longrightarrow =-\frac{4}{2}[/tex]
[tex]=-2[/tex]
[tex]x=0,\:x=-2\Longleftarrow[/tex]
[tex]\underline{HOPE ~IT~HELPS}[/tex]
The Coast Starlight Amtrak train runs from Seattle to Los Angeles. The mean travel time from one stop to the next on the Coast Starlight is 129 mins, with a standard deviation of 113 minutes. The mean distance traveled from one stop to the next is 108 miles with a standard deviation of 99 miles. The correlation between travel time and distance is 0.636.
Required:
a. Write the equation of the regression line from predicting travel time.
b. Interpret the slope and the intercept in this context.
c. Calculate R2 of the regression line for predicting travel time from distance traveled for the Coast Starlight, and interpret R2 in the context of the application.
Solution :
a).
Given :
R = 0.636, [tex]$S_x = 99$[/tex], [tex]$S_y=113, M_x=108, M_y=129$[/tex]
Here R = correlation between the two variables
[tex]$S_x , S_y$[/tex] = sample standard deviations of the distance and travel time between the two train stops, respectively.
[tex]$M_x, M_y$[/tex] = means of the distance and travel between two train stops respectively.
The slope of the regression line is given by :
Regression line, [tex]b_1[/tex] [tex]$=R \times \left(\frac{S_y}{S_x}\right)$[/tex]
[tex]$=0.636 \times \left(\frac{113}{99}\right)$[/tex]
= 0.726
Therefore, the slope of the regression line [tex]b_1[/tex] is 0.726
The equation of the regression line is given by :
[tex]$\overline {y} = b_0+b_1 \overline x$[/tex]
The regression line also has to pass through the two means. That is, it has to pass through points (108, 129). Substituting these values in the equation of the regression line, we can get the value of the line y-intercept.
The y-intercept of the regression line [tex]$b_0$[/tex] is given by :
[tex]$b_0=M_y-(b_1 \times M_x)$[/tex]
= 129 - (0.726 x 108)
= 50.592
Therefore, the equation of the line is :
Travel time = 20.592 + 0.726 x distance
b).[tex]\text{ The slope of the line predicts that it will require 0.726 minutes}[/tex] for each additional mile travelled.
The intercept of the line, [tex]$b_0$[/tex] = 0.529 can be seen as the time when the distance travelled is zero. It does not make much sense in this context because it seems we have travelled zero distance in 50.529 minutes, but we could interpret it as that the wait time after which we start travelling and calculating the distance travelled and the additional time required per mile. Or we could view the intercept value as the time it takes to walk to the train station before we board the train. So this is a fixed quantity that will be added to travel time. It all depends on the interpretation.
c). [tex]$R^2=0.404$[/tex]
This means that the model accounts for around 40.4% variation in the travel time.
Choose the correct Set-builder form for the following set written in Roster form: { − 2 , − 1 , 0 , 1 , 2 }
Step-by-step explanation:
{x:x is an integer where x>-3 and x<3}
What is the equation, in point-slope form, of the line that
is perpendicular to the given line and passes through the
point (-4,-3)?
Answer:
The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.
Step-by-step explanation:
Equation of a line:
The equation of a line, in point-slope form, is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which m is the slope and the point is [tex](x_0,y_0)[/tex]
Perpendicular lines:
If two lines are perpendicular, the multiplication of their slopes is -1.
Passes through the point (-4,-3)
This means that [tex]x_0 = -4, y_0 = -3[/tex]
So
[tex]y - y_0 = m(x - x_0)[/tex]
[tex]y - (-3) = m(x - (-4))[/tex]
[tex]y + 3 = m(x + 4)[/tex]
The equation of the line is [tex]y + 3 = m(x + 4)[/tex], in which m is found as such [tex]am = -1[/tex], considering a the slope of the given line.
use the rules of exponents to evaluate or simplify.write without negative exponents. 1/4^-2=?
9514 1404 393
Answer:
4² = 16
Step-by-step explanation:
The applicable rule of exponents is ...
1/a^-b = a^b
So, ...
[tex]\dfrac{1}{4^{-2}}=\boxed{4^2 = 16}[/tex]
_____
Additional comment
If you were to evaluate this using the Order of Operations, you would evaluate the exponent first:
1/4^-2 = 1/(1/16)
Then, you would do the division.
1/(1/16) = 16
__
We sometimes find it convenient to manipulate exponential terms to the form with the smallest positive exponents before we begin the evaluation.
In a geometric sequence, the term an+1 can be smaller than the term ar O A. True O B. False
9514 1404 393
Answer:
True
Step-by-step explanation:
In a geometric sequence, the terms a[n+1] and a[n] are related by the common ratio. If the sequence is otherwise unspecified, two sequential terms may have any a relation you like.* Either could be larger or smaller than the other.
__
* If one is zero, the other must be as well. Multiplying 0 by any finite common ratio will give zero as the next term.
sketch a system of linear equation whose solution is (3,6)
Answer: x+y = 9, 2x+3y = 24
Step-by-step explanation:
Find the sum of: 7a² - 9a + 5 and 11a + a² + 8
Answer:
Add them:
Squares to squares, a to and number to number:
8a^2+3a+13
The simplified sum of the given expressions 7a² - 9a + 5 and 11a + a² + 8 is 8a² + 2a + 13.
To find the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8, we simply combine like terms.
The given expressions contain terms with different powers of "a."
Combining the terms with the same powers, we have:
7a² + a² = 8a² (the coefficient for the "a²" term is 7 + 1 = 8)
-9a + 11a = 2a (the coefficient for the "a" term is -9 + 11 = 2)
Finally, we combine the constant terms:
5 + 8 = 13
Putting it all together, the sum of the expressions 7a² - 9a + 5 and 11a + a² + 8 is:
8a² + 2a + 13
To learn more about polynomials click on,
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HELP ASAP WILL GIVE BRAINLIST
Consider the sequence {5,10,15,20,…}. Find n if an = 4875. Show all steps including the formulas used to calculate your answer.
Answer:
n = 975
Step-by-step explanation:
[tex]a_1 = 5 = 5 \times 1\\a_2 = 10 = 5 \times 2\\\\Therefore, \ a_n = 5 \times n\\[/tex]
[tex]Given \ a_n = 4875\\\\So, a_n = 5 \times n \\\\=> 4875 = 5 \times n\\\\=>\frac{4875}{5} = n\\\\=> 975 = n[/tex]
In grade 6, there are 40 students. There are 8 girls, find the percentage of the boys?
Answer:
[tex]40 - 8 = 32 \\ \frac{32}{40} \times 100 \\ = 80\%[/tex]
Given:
p: 2x = 16
q: 3x – 4 = 20
RE
Which is the converse of p - q?
ООО
If 2x + 16, then 3x - 47 20.
If 3x - 420, then 2x + 16.
If 2x = 16, then 3x – 4 = 20.
If 3x - 4 = 20, then 2x = 16
Given:
The given statements are:
[tex]p:2x=16[/tex]
[tex]q:3x-4=20[/tex]
To find:
The converse of [tex]p\to q[/tex].
Solution:
The statement [tex]p\to q[/tex] means if p, then q and the converse of this statement is [tex]q\to p[/tex].
[tex]q\to p[/tex] means if q , then p.
We have, [tex]p:2x=16[/tex] and [tex]q:3x-4=20[/tex].
So, the converse of given statement is:
[tex]q\to p:[/tex] If [tex]3x-4=20[/tex], then [tex]2x=16[/tex].
Therefore, the correct option is D.
Answer: Therefore, the correct option is D.
Step-by-step explanation:
Given:
p: 2x = 16
q: 3x – 4 = 20
RE
Which is the converse of p - q?
ООО
If 2x + 16, then 3x - 47 20.
If 3x - 420, then 2x + 16.
If 2x = 16, then 3x – 4 = 20.
If 3x - 4 = 20, then 2x = 16
To find:
The converse of .
Solution:
The statement means if p, then q and the converse of this statement is .
means if q , then p.
We have, and .
So, the converse of given statement is:
If , then .
Therefore, the correct option is D.
Find the area of the circle. Leave your answer in terms of T.
Answer:
4.2025 [tex]\pi m^{2}[/tex]
Step-by-step explanation:
Prove that sinxtanx=1/cosx - cosx
[tex] \sin(x) \tan(x) = \frac{1}{ \cos(x) } - \cos(x) [/tex]
Answer:
See below
Step-by-step explanation:
We want to prove that
[tex]\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}[/tex]
Taking the RHS, note
[tex]\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}[/tex]
Remember that
[tex]\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)[/tex]
Therefore,
[tex]\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}[/tex]
Once
[tex]\dfrac{\sin(x)}{\cos(x)} = \tan(x)[/tex]
Then,
[tex]\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)[/tex]
Hence, it is proved
Find the length of the missing side. Leave your answer in simplest radical form.
Hyp = 15yd
Leg = 13yd
Leg = X
Answer:
The other side is 7.48 yards.
Step-by-step explanation:
Given that,
Hypotenuse = 15 yards
One leg = 13 yards
We need to find the length of the other leg. We can use the Pythagoras theorem to find it such that,
[tex]H^2=b^2+h^2[/tex]
Where
h is other leg
Put all the values,
[tex]h=\sqrt{H^2-b^2} \\\\h=\sqrt{(15)^2-(13)^2} \\\\h=7.48\ yd[/tex]
So, the other side is 7.48 yards.
17.
What is the value of the expression
2a + 5b + 3c for a = 12, b = 6, and
C=3?
A 10
B 21
C49
D 63
D. 63
2a+5b+3c
2(12)+5(6)+3(3)
24+30+9=63
Hope this helps! :)
Simplify (5 square root 2 - 1 ) ^2
Answer:
576
Step-by-step explanation:
5 square root 2 is 25
25 minus 1 is 24
24 square root 2 is 576
Answer:
25
Step-by-step explanation:
[tex](5\sqrt{(2-1)} ^{2}[/tex]
[tex](5\sqrt{1}) ^{2}[/tex]
Help is appreciated
Answer:
m = 6
n = 2√3
Step-by-step explanation:
Reference angle = 30°
Hypotenuse = 4√3
Opposite = n
Adjacent = m
✔️To find m, apply CAH:
Cos θ = Adj/Hypo
Substitute
Cos 30° = m/4√3
4√3 × Cos 30° = m
4√3 × √3/2 = m (cos 30 = √3/2)
(4*3)/2 = m
6 = m
m = 6
✔️To find n, apply SOH:
Sin θ = Opp/Hypo
Substitute
Sin 30° = n/4√3
4√3 × Sin 30° = n
4√3 × ½ = n (Sin 30 = ½)
2√3 = n
n = 2√3
Am I correct if not plz fix it ASAP I have 4 minutes left
Answer:
no not correct it should be horizontally left 2 units and vertically down 5 units
Which relationship is always true for the angles x,y and z of triangle ABC
Answer:
B. y + z = x
Step-by-step explanation:
x is an exterior angle of the triangle.
y and z are the opposite angles opposite the exterior angle.
The exterior angle theorem of a triangle states that the measure of an exterior angle equals the measure of the sum of the two angles opposite the exterior angle.
Thus:
y + z = x
In a regression analysis involving 30 observations, the following estimated regressionequation was obtained.y^ =17.6+3.8x 1 −2.3x 2 +7.6x 3 +2.7x 4For this estimated regression equation SST = 1805 and SSR = 1760. a. At \alpha =α= .05, test the significance of the relationship among the variables.Suppose variables x 1 and x 4 are dropped from the model and the following estimatedregression equation is obtained.y^ =11.1−3.6x 2 +8.1x 3For this model SST = 1805 and SSR = 1705.b. Compute SSE(x 1 ,x 2 ,x 3 ,x 4 )c. Compute SSE (x2 ,x3 ) d. Use an F test and a .05 level of significance to determine whether x1 and x4 contribute significantly to the model.
Answer:
(a) There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
(b) [tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
(c) [tex]SSE_{(x_2,x_3)} = 100[/tex]
(d) [tex]x_1[/tex] and [tex]x_4[/tex] are significant
Step-by-step explanation:
Given
[tex]y = 17.6+3.8x_1 - 2.3x_2 +7.6x_3 +2.7x_4[/tex] --- estimated regression equation
[tex]n = 30[/tex]
[tex]p = 4[/tex] --- independent variables i.e. x1 to x4
[tex]SSR = 1760[/tex]
[tex]SST = 1805[/tex]
[tex]\alpha = 0.05[/tex]
Solving (a): Test of significance
We have:
[tex]H_o :[/tex] There is no significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
[tex]H_a :[/tex] There is a significant relationship between y and [tex]x_1, x_2, x_3, x_4[/tex]
First, we calculate the t-score using:
[tex]t = \frac{SSR}{p} \div \frac{SST - SSR}{n - p - 1}[/tex]
[tex]t = \frac{1760}{4} \div \frac{1805- 1760}{30 - 4 - 1}[/tex]
[tex]t = 440 \div \frac{45}{25}[/tex]
[tex]t = 440 \div 1.8[/tex]
[tex]t = 244.44[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 244.44[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Solving (b): [tex]SSE(x_1 ,x_2 ,x_3 ,x_4)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1760[/tex] ----------- [tex](x_1 ,x_2 ,x_3 ,x_4)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4)} = 1805 - 1760[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
Solving (c): [tex]SSE(x_2 ,x_3)[/tex]
To calculate SSE, we use:
[tex]SSE = SST - SSR[/tex]
Given that:
[tex]SSR = 1705[/tex] ----------- [tex](x_2 ,x_3)[/tex]
[tex]SST = 1805[/tex]
So:
[tex]SSE_{(x_2,x_3)} = 1805 - 1705[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
Solving (d): F test of significance
The null and alternate hypothesis are:
We have:
[tex]H_o :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are not significant
[tex]H_a :[/tex] [tex]x_1[/tex] and [tex]x_4[/tex] are significant
For this model:
[tex]y =11.1 -3.6x_2+8.1x_3[/tex]
[tex]SSE_{(x_2,x_3)} = 100[/tex]
[tex]SST = 1805[/tex]
[tex]SSR_{(x_2 ,x_3)} = 1705[/tex]
[tex]SSE_{(x_1 ,x_2 ,x_3 ,x_4) }= 45[/tex]
[tex]p_{(x_2,x_3)} = 2[/tex]
[tex]\alpha = 0.05[/tex]
Calculate the t-score
[tex]t = \frac{SSE_{(x_2,x_3)}-SSE_{(x_1,x_2,x_3,x_4)}}{p_{(x_2,x_3)}} \div \frac{SSE_{(x_1,x_2,x_3,x_4)}}{n - p - 1}[/tex]
[tex]t = \frac{100-45}{2} \div \frac{45}{30 - 4 - 1}[/tex]
[tex]t = \frac{55}{2} \div \frac{45}{25}[/tex]
[tex]t = 27.5 \div 1.8[/tex]
[tex]t = 15.28[/tex]
Next, we calculate the p value from the t score
Where:
[tex]df = n - p - 1[/tex]
[tex]df = 30 -4 - 1=25[/tex]
The p value when [tex]t = 15.28[/tex] and [tex]df = 25[/tex] is:
[tex]p =0[/tex]
So:
[tex]p < \alpha[/tex] i.e. [tex]0 < 0.05[/tex]
Hence, we reject the null hypothesis
Find the perimeter of the figure below, in feet.(Note: diagram is NOT to scale)
Lines DE and AB intersect at point C.
What is the value of x?
А.
|(2x + 2)
с
(5x + 3)
Given:
Lines DE and AB intersect at point C.
To find:
The value of x.
Solution:
In the given figure it is clear that the angles and are lie on a straight line AB.
[Linear pair]
Subtract 5 from both sides.
Divide both sides by 7.
Therefore, the correct option is B.
How many lakhs are there in 4 million?
Now,
1 million = 10 lakhs
4 millions = 10 * 4
= 40 lakhs
There are 40 lakhs in 4 millions.
I hope it's help you...
Mark me as brainliest...
Answer: There are 40 lakhs in 4 million.
Step-by-step explanation:
A lakh is 1,00,000. We can divide 4 million by 1,00,000 to get our answer.
[tex]\frac{4,000,000}{1,00,000}[/tex]
The 5 zeros on the 4 million and on 1,00.000 cancel each other out giving us
[tex]\frac{40}{1} \\40[/tex]
a scalene triangle has angles of 53 degree and 69 degree .what is the measure of it third angles?
Answer:
x+53+69=180
x+122=180
x=180-122
x=58
According to the tables used by insurance companies, a 48-year old man has a 0.169% chance of
passing away during the coming year. An insurance company charges $217 for a life insurance policy
that pays a $100,000 death benefit.
What is the expected value for the person buying the insurance?
Answer:
The expected value for the person buying the insurance is of -$48.
Step-by-step explanation:
Expected value:
0.169% = 0.00169 probability of earning the death benefit of $100,000, subtracting 217, 100000 - 217 = $99,783.
100 - 0.169 = 99.831% = 0.99831 probability of losing $217.
What is the expected value for the person buying the insurance?
[tex]E = 0.00169*99783 - 0.99831*217 = -48[/tex]
The expected value for the person buying the insurance is of -$48.
A right triangle has side lengths 8, 15, and 17 as shown below. Use these lengths to find tanĄ, sind, and cos 4. (GIVING POINTS AND BRAINLEST TO BEST ANSWER)
Answer:
Tan A = 8/15
Sin A = 8/17
Cos A = 15/17
I start feeling tired now
What is the area of the irregular polygon shown below?
6
6
4.1
6
6
10
A. 121.5 sq. units
B. 108 sq. units
C. 56 sq. units
O D. 216 sq. units
The area of the irregular polygon is 121.5 units squared.
How to find the area of an irregular polygon?
The irregular polygon can be divided into a rectangle and a pentagon.
Therefore, the area is the sum of the area of the pentagon and the rectangle.
Therefore,
area of the rectangle = 6 × 10 = 60 units²
area of the pentagon = 1/ 2 × perimeter × apothem
area of the pentagon = 1 / 2 × 30 × 4.1
area of the pentagon = 123 / 2
area of the pentagon = 61.5 units²
Therefore,
area of the irregular polygon = 61.5 + 60 = 121.5 units²
learn more on irregular polygon here: https://brainly.com/question/12879526
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