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Question 11
The table shows the relationship between y, the cost to rent a boat, and the amount of time the boat is rented,
Boat Rental Costs
Time, X Cost, v
(hours) (dollars)
1
3
5
80
7
104
Which graph best represents the relationship between x and y shown in the table

Answer:

the total number of stickers is 24

Step-by-step explanation:

The computation of the total number of stickers is shown below

Let us assume the total no of stickers be x

Now as per the question, the equation is

3(x - 20) = 12

3x - 60 = 12

3x = 12 + 60

3x = 72

x = 24

Hence, the total number of stickers is 24

Answer:

4/5

Step-by-step explanation:

I believe this is looking for a fraction? 4 over 5 or 4/5 means 4 out of 5.

Answer:

24

Step-by-step explanation:

First we need to find the area on one square which is 2*2 which is 4. So now we have 5 more cubes like this and we have to add all their areas to find the surface area so we make a multiplicaction sentence :

4*6=24

Answer:

-8

Step-by-step explanation:

Its actually simple once you get the basics

Find out the difference between the first two digits given e.g 8,6: the difference is 2 so you check if it's the same difference e.g 6,4: the difference is also 2 so you keep subtracting or adding 2 as the case may be.

Answer:

i think he payed 34 since 40 percent of 85 is 34.

Step-by-step explanation:

To find the discount price, multiply the original price ($85) by the discount ( 100-40=60): 85 x 0.6= $51 is what he paid.

Answer:

-3

Step-by-step explanation:

it might not be correct, the site I use for math glitches sometimes

Answer:

x=1

Step-by-step explanation:

its right :)

Answer:

$21

Step-by-step explanation

65/100 = .65

60 * .65 = $39

60 - 39 = $21

Answer:

60ft

Step-by-step explanation:

multiply all the #

Answer:

£8.10

Step-by-step explanation:

Divide £10.80 by 4 to find the cost of 1 Kg, then multiply this by 3

£10.80 ÷ 4 = £2.70 ← cost of 1 Kg , then

cost of 3 Kg = 3 × £2.70 = £8.10

Answer:

it may helps......

Step-by-step explanation:

we can solve it by unitary method....So,

Cheese (in Kg). Cost (in Rs)

4kg 10.80

3kg X

Now, 4×x = 3×10.80

X=3×10.80/4 (by transposing)

X=2.7×3

X= 8.1 Answer

Mark it as brainlist

Answer:

C. Your team plays 3 preseason games.

Step-by-step explanation:

In the equation y = 2x + 3, y represents the total number of preseason and regular season games that your softball team played this summer.  The variable x represents the number of weeks in the regular season.  Which statement is true?  

A. The regular season lasts 2 weeks.  

B. The preseason lasts 2 weeks.  

C. Your team plays 3 preseason games.  

D. Your team plays 3 regular season games each week.

Solution:

The equation for a linear function is given as:

y = mx + b;

where m is the rate of change and b is the y intercept (that is initial value of y at x = 0), y and x are variables.

Given that y = 2x + 3;

The slope (m) = 2 and the y intercept (b) = 3

This slope means 2 games are played every week during the regular season games. The y intercept means that at before the regular games have start, 3 games have been played. Therefore, the team plays 3 preseason games.

Answer:

69.89-exact

70-rounding up

Answer:

She spent $69.98

Step-by-step explanation:

49.99 + 19.99 = 69.98 because people place .99 at the end of the cost in order to try to confuse customers that they are getting a better price then they really are, this is true because since many people read left to right, they  will see the smaller number first, and they see the bigger number last, makin them believe its a better price. when at the end of a number lies a .99 it only counts as .99 not 1.00, thus this information is what helped me find my answer.

Answer:

!. Scale factor = 5

2. Scale factor = [tex]\frac{1}{5}[/tex]

Step-by-step explanation:

scale = [tex]\frac{length in drawing}{actual length}[/tex]

1. To increase the numbers, let the scale factor be [tex]\frac{5}{1}[/tex] = 5. So that;

0.05 x 5 = 0.25

[tex]\frac{1}{2}[/tex] x 5 = 0.5 x 5 = 2.50

7 x 5 = 35.00

13 x 5 = 65.00

25 x 5 = 125.00

102 x 5 = 510.00

2. To decrease the numbers, let the scale factor be [tex]\frac{1}{5}[/tex]. So that;

0.05 x [tex]\frac{1}{5}[/tex] = 0.01

[tex]\frac{1}{2}[/tex] x [tex]\frac{1}{5}[/tex] = 0.5 x [tex]\frac{1}{5}[/tex] = 0.10

7 x [tex]\frac{1}{5}[/tex] = 1.40

13 x [tex]\frac{1}{5}[/tex] = 2.60

25 x [tex]\frac{1}{5}[/tex] = 5.00

102 x [tex]\frac{1}{5}[/tex] = 20.40

Answer:

am gonna need more imformation

Step-by-step explanation:

Answer:

1) x = 18 2) x = 7

Step-by-step explanation:

Edit: Decided to solve the second too! :)

1)

12/16 = x/(x+6)

12x + 72 = 16x

72 = 4x

x = 18

2)

(-4 + 4x)/64 = 27/72

-288 + 288x = 1,728

288x = 2,016

x = 7

Answer:

3

Step-by-step explanation:

Answer: 225 square feet

Step-by-step explanation:

We find the area of the 4 triangle and the area of the rectangle and thereafter we add everything together.

Area of triangle 1 = 1/2 base × height

= 1/2 × 12 × 8

=96/2

=48

Area of triangle 2 = area of triangle 1= 48( because the opposite triangle are congruent so they have equal base and height)

Area of triangle 3 = 1/2×base×height

= 1/2 × 6 ×9.5

= 57/2

=28.5

Area of triangle 4=Area of triangle 3 = 57 (the opposite triangle are congruent and so they have the same base and height hence the same area)

Area of the rectangle = length×breadth

=12 × 6 =72

Total surface area = addition of all the areas of the triangles and the rectangle

Total surface area= 48+48+57+57+72 = 225

Therefore, the total surface area is 225 square feet

Answer:

The one-fourth of one round of cheddar cheese

Step-by-step explanation:

Because if we cut every round in 4 equal pieces, 4x3=12, we will have 12 equal pieces of cheddar cheese.

Answer:

2 and 3, -5 and -6, -3 and -4

Step-by-step explanation:

list all of your perfect squares

[tex]\sqrt{1}, \sqrt{4} ,\sqrt{9} , \sqrt{16} , ...\\[/tex]

So [tex]\sqrt{5}[/tex] is between [tex]\sqrt{4} and \sqrt{9}[/tex] so it is between 2 and 3

If that is a negative [tex]\sqrt{30}[/tex] then it is between square root of 25 and 36, which would be -5 and -6

-[tex]\sqrt{15}[/tex] is between  [tex]\sqrt{9} and \sqrt{16}[/tex] so -3 and -4

Answer:

3

Step-by-step explanation:

when a division crosse's an equal sin it becomes a multiplication

Answer:

x = 5

Step-by-step explanation:

Because the factor of the polynomial is x - 5, we can infer that the zero would be the solution of this equation: x - 5 = 0

Therefore, the zero is x = 5.

Answer:

the answer is a. The population is all words in the book report and the sample is the random sample of 20 words.

Step-by-step explanation:

got it right on edge

Answer: a. The population is all words in the book report and the sample is the random sample of 20 words.

Step-by-step explanation:

Answer:

55

Step-by-step explanation:

Answer : 55

Step by step explanation use PEMDAS

55/1 = 55

Answer

Calculator.net

i hope you use this it will help a lot

So first you would have to find the slope using the two points and the equation: y2-y1/x2-x1, which in this case means you take 6+4/3+1, which would be a slope of 10/4 or 5/2, or 2.5. Using this, we can take a point, use point slope form, and rearrange it. So:

y-6=2.5(x-3)

y-6=2.5x-7.5

-2.5x+y=1.5

Answer:

1.86 m

Step-by-step explanation:

11 cm = 0.11 m

1.75 + 0.11 = 1.86

Answer:

Step-by-step explanation:

by phythagoras theorm

AB² + BC² = AC²

5² + BC² = 13²

25 + BC² = 169

BC² = 169 - 25

BC² = 144

BC = √144

BC = 12cm

The deer population in 5 years is approximately 294 deer.

A rise in the resultant quantity for a given quantity is referred to as exponential growth, and a decrease in the resultant quantity for a given quantity is referred to as exponential decay. Over time, exponential functions monitor constant growth. Examples from the actual world include radioactive decay, compound interest, and bacterial proliferation.

a. To solve the differential equation dP/dt = −0.1P, we can separate the variables and integrate:

dP/P = −0.1 dt

Integrating both sides gives:

ln|P| = −0.1t + C

where C is the constant of integration. To solve for C, we can use the initial condition that P = 495 when t = 0:

ln|495| = −0.1(0) + C

C = ln|495|

Substituting this value of C back into the equation gives:

ln|P| = −0.1t + ln|495|

Simplifying using logarithm properties, we get:

ln|P/495| = −0.1t

Exponentiating both sides gives:

|P/495| = e^−0.1t

Taking the absolute value off and multiplying both sides by 495, we get:

P = 495e^−0.1t

To find the deer population in 5 years, we can substitute t = 5 into the equation:

[tex]P = 495e^{-0.1(5)} = 294[/tex] deer (rounded to the nearest deer).

Therefore, the deer population in 5 years is approximately 294 deer.

b. To find an equation for the deer population P(t) in terms of t and k for the period after 5 years, we can use the differential equation:

dP/dt = k(650−P)

Separating the variables and integrating, we get:

∫dP/(650−P) = ∫k dt

Using partial fraction decomposition and integrating, we get:

ln|650−P| = −kt + C

where C is the constant of integration. To solve for C, we can use the initial condition that P = 294 when t = 5:

ln|650−294| = −k(5) + C

C = ln|356| + 5k

Substituting this value of C back into the equation gives:

ln|650−P| = −kt + ln|356| + 5k

Simplifying using logarithm properties, we get:

ln|(650−P)/356| = −kt

Exponentiating both sides gives:

[tex]|(650-P)/356| = e^{-kt[/tex]

Taking the absolute value off and multiplying both sides by 356, we get:

[tex]650-P = 356e^{-kt[/tex]

Solving for P gives:

[tex]P = 650-356e^{-kt[/tex]

Therefore, the equation for the deer population P(t) in terms of t and k for the period after 5 years is P = 650−356e^−kt.

c. Using the growth model from part b), if the deer population is 350 one year later, we can substitute t = 1 and P = 350 into the equation and solve for k:

350 = 650−356e^−k

Solving for [tex]e^{-k[/tex] gives:

[tex]e^{-k = (650-350)/356 = 3/2[/tex]

Taking the natural logarithm of both sides gives:

−k = ln(3/2)

Solving for k gives:

k = −ln(3/2) ≈ 0.4055

Therefore, k ≈ 0.4055.

d. Using the growth model from part b) and the value of k from part c), the long-term behavior of the deer population as t → ∞ is determined by the limit:

lim P(t) as t → ∞

We can use the fact that [tex]e^{-kt[/tex]approaches 0 as t →

Learn more about exponential growth and decay here:

https://brainly.com/question/17161065

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