Two objects of same material are travelling near you. Object A is a 1.1 kg mass traveling 10.2 m/s; object B is a 2 kg mass traveling 5 m/s. Which object would make you feel worse if you are hit by it

Answer: the intensity of the light that passes through the set of polarizers is  0.7285 S₀

Explanation:

based on the data in the question;

As the first polarizer lets all the light through because its plane of polarization is not different from light.

The second polarizer has 2 effects;

firstly, it reduces the intensity by a factor cos²0.3927^c; if you switch the calculator to radians mode, this will give you 0.85355

Secondly; it changes the plane of polarization of the light to be the same as the polarizer; therefore the light now has a plane of polarization of 0.3927 rad to the horizontal.

Hence;

after the second effect, the light enters the third polarizer at 0.3927 rad to the plane of polarization of third polarizer. So the intensity is again reduced by a factor 0.85355.

Therefore

the Overall reduction is by a factor of 0.85355 × 0.85355 S₀

= 0.7285 S₀

Therefore the intensity of the light that passes through the set of polarizers is  0.7285 S₀

Answer:

correct order 2,4,3,1

Explanation: correct on edge

Answer:

10

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

Answer:

a collision occuring between two objects in an isolated system, the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2.

thank you.

Explanation:

Fnet = 12.0N - 5.0N = 7.0N

a = Fnet/m = 7.0N/6.5kg = 1.07m/s².

Answer:

One bulb could go out and the strand will stay on.

Explanation:

In series circuit, there is only one path provided for the current to flow. So, all the lights are required to be in working condition, for the others to work. And if anyone light bulb goes out, the circuit will become incomplete and the rest of the strand will also go out. Because there is only one path for current flow which is now broken.

On the other hand, in parallel circuits, each light bulb has a separate connection with the source. Current path to each bulb is independent of the others. Therefore, if one bulb goes out, the rest of the strand will stay on.

So, the correct option is:

One bulb could go out and the strand will stay on.

Answer:

f = 0 N

Explanation:

It is given that,

A horse pulls a wagon with 2000N of at constant velocity.

We need to find the friction acting on the wagon.

As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.

Hence, the correct option is (a).

Answer:

18.58 mm

Explanation:

Formula for the fringe width is;

β = λL/d

We are given;

λ = 568 nm = 568 × 10^(-9) m

L = 3.5 m

d = 0.107 mm = 0.107 × 10^(-3) mm

β = (568 × 10^(-9) × 3.5)/(0.107 × 10^(-3))

β = 0.01858 m = 18.58 mm

Answer:

E = - 2*E₀*sinθ*i

V = V = 2*E₀*sinθ /r

Explanation:

First situation: a quarter-circle rod produces at the origin

E₀      and  V₀

We know that    E  =  K *  Q/r      and

E  =  E₀           Q = L*λ           Q = 1/4 * 2*π*r*λ       Q = (1/2)*π*r*λ

where:

r is the radius of the circle which at the same time is the distance between the rod quarter of the circle and the origin.

λ is the longitudinal density of charge, and

k = 1/4*π*ε₀

Then    E₀ =  (1/2)* k*π*λ        and   V₀  = - E₀/Q         V₀  = - E₀/r

E₀  =  E₀ₓ  +  E₀y      E₀ₓ  = E₀*cosθ    E₀y = - E₀*sinθ  

θ the angle between E₀  and the x-axis

Second situation half of a circle ( first quarter +Q and fourth -Q )

In that configuration, the components in the x-axis cancel each other ( by symmetry) and the y-axis components of +Q  and -Q  are to be added then

E = Eₓ   +  Ey     but by inspection we find Eₓ  = 0 ( the components of the        

the electric field produced of the two quarters canceled each other)

and we have to add the two identical y-axis components of the two quarters therefore

E = 2*E₀y

each component of   E₀y = - E₀*sinθ    

Then the new electric field becomes

E = - 2*E₀*sinθ*i

The new V  = - (- 2*E₀*sinθ /r)

V = 2*E₀*sinθ /r

(Note remember that V is a scalar )

An object that absorbs all radiation falling on it, at all wavelengths, is called a black body. When a black body is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. Its emission is called black-body radiation

hope it helps

Answer: D. 6.1 m/s^2

Explanation:

Answer:

1. t = 5.89 s

2. h = 170 m

3. Vf = 57.8 m/s

Explanation:

1.

First, we analyze the horizontal motion of the golf ball. Assuming the air friction to be negligible, the horizontal motion will be uniform. So, e can use the following equation:

[tex]s = vt[/tex]

where,

s = horizontal distance covered by the golf ball = 471 m

v = horizontal speed of golf ball = 80 m/s

t = time taken by the golf ball in air = ?

Therefore,

[tex]471\ m = (80\ m/s)t\\\\t = \frac{471\ m}{80\ m/s}\\\\[/tex]

t = 5.89 s

2.

Now, we analyze the vertical motion. Using 2nd equation of motion:

[tex]h = v_{i}t + \frac{1}{2}gt^2[/tex]

where,

h = height of cliff = ?

vi = vertical component of initial speed of ball = 0 m/s(ball was shot horizontally)

g = acceleration due to gravity = 9.81 m/s²

t = time of flight = 5.89 s

Therefore,

[tex]h = (0\ m/s)(5.89\ s) + \frac{1}{2}(9.81\ m/s^2)(5.89\ s)^2[/tex]

h = 170 m

3.

Now, we can use 1st equation of motion:

[tex]v_{f} = v_{i} + gt\\v_{f} = 0 m/s + (9.81\ m/s^2)(5.89\ s)\\[/tex]

Vf = 57.8 m/s

Answer:

a. Weight of Object in Water = 20 N

b. Up thrust = 20 N

c. Weight of Water Displaced = 20 N

Explanation:

a.

The weight of the object remains same in the water as well. Because, the same force of gravity is acting there as well. Hence,

Weight of Object in Water = 20 N

b.

Since, the object floats on the water. Therefore, according to Archimedes' principle the up thrust force acting on the object must be equal to the weight of object:

Up thrust = Weight of object

Up thrust = 20 N

c.

From Archimedes' Principle, we know that the up thrust or the Buoyant force is equal to the weight of the water displaced by the object. therefore:

Weight of Water Displaced = Up thrust

Weight of Water Displaced = 20 N

Answer: 67 how much candy does nick have

Explanation:

Answer:

The frequency stays the same and the wavelength decreases.

Explanation:

When sound wave enters a new medium where sound travels faster, its frequency will remain same because it depends only on the source.

The relation between wavelength and speed is inverse, it means when the speed of sound increases, its wavelength will decrease.

So, the frequency stays the same and the wavelength decreases. Hence, the correct option is (d).

Answer:

see below

Explanation:

alluminium is,

1.lustrous

2.highly malleable

3.reactive metal

4.some times acts as non metal

5.good conductor

6.obtained from bauxite

7.Atomic number 13 so electrons and protons are 13

8.neurons are 14

9.ductile

10.melting point is very high approximately 660 degree celsius.

Answer:

It has low density, is non-toxic, has a high thermal conductivity, has excellent corrosion resistance and can be easily cast, machined and formed.

Explanation:

Answer:

A

Explanation:

OKAY REAL QUICK A NOTE REPRESENTS THE 12 TONES ON THE CHROMATIC SCALE WHICH IN TURN REPRESENTS THE WHOLE OF SOUND IN ALL MUSIC- EACH NOTE HAS A PITCH THAT REPEATS IN EVERY OCTAVE.

Answer:

0.462kg

Explanation:

Density = Mass/Volume

Given

Density of the wood = 0.390 g/cm^3

Volume of the wood = Length * Width * Height

Volume = 21 * 9.53 * 5.92

Volume = 1,184.7696cm³

Get the mass m;

mass = density * volume

mass = 0.390 * 1,184.7696

mass = 462.060144g

The mass in kg is 0.462kg

Answer:

I am going to answer you just wait a little bit.

Answer:

TRUE THE ANSWER IS TRUE

Explanation:

Speed is the distance an object travel per unit of time

Answer:I think it’s because both can provide heat and cold

Explanation:

Answer:

Answer:

Explanation:

1400 m/s2

The acceleration of the ball when it hits the vertical wall is -1,400 m/s²

The given expression:

velocity of the ball, v = 28 m/s

time of  motion of the ball, t = 0.02 s

To find:

The acceleration of the ball is calculated as follows:

[tex]acceleration = \frac{\Delta velocity}{\Delta time} = \frac{Final \ velocity\ - \ initial \ velocity }{time} \\\\final \ velocity \ of \ the \ ball \ when \ it \ hits \ the \ wall = 0\\\\acceleration = \frac{0 - 28}{0.02} \\\\acceleration = - \ 1,400 \ m/s^2[/tex]

Thus, the acceleration of the ball when it hits the vertical wall is -1,400 m/s²

Learn more here: https://brainly.com/question/14109204

Answer:

the central nervous system

Answer: C. central

Explanation:

Answer:

2.35 seconds

Explanation:

Remark

This is a question where direction matters.  Let us call down + and up minus. It won't matter. The answer will be the same.

Formula

a = (vf - vi)/t

Givens

a = 9.8 m/s^2

vi = - 15 m/s

vf = 8m/s

Solution

9.8 = (8 - - 15)/t                 Multiply both sides by t

t * 9.8 = 23                       Divide by 9.8

t = 23/9.8

t = 2.35 s

Explanation:

When the Javelin is at rest on the ground, Potential Energy and Kinetic Energy are zero.  immediately the Athlete picks the javelin up from the ground, there is an increase in the Kinetic Energy this increase continues until the javelin comes to a halt. Potential Energy also increases.

As the Athlete throws javelin, there is a decrease in the Potential Energy, the Kinetic Energy increases simultaneously until the javelin hits the ground.

after which Potential Energy  and Kinetic Energy becomes zero.

Answer:

a) The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].

b) The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].

Explanation:

a) The hoop yo-yo can be modelled as a tours with a minor radius [tex]a[/tex], related with the thickness, and with a major radius [tex]b[/tex], related with the diameter, and with an uniform mass. The momentum of inertia about its center of mass ([tex]I_{g}[/tex]), measured in kilogram-square meters, which is located at the geometrical center of the element, is determined by the following formula:

[tex]I_{g} = \frac{1}{4}\cdot m \cdot (4\cdot b^{2}+3\cdot a^{2})[/tex] (1)

[tex]b = 0.5\cdot D[/tex] (2)

[tex]a = 0.5\cdot t[/tex] (3)

Where:

[tex]D[/tex] - Diameter, measured in meters.

[tex]t[/tex] - Thickness, measured in meters.

[tex]m[/tex] - Mass, measured in kilograms.

If we know that [tex]m = 0.332\,kg[/tex], [tex]D = 0.359\,m[/tex] and [tex]t = 9.5\times 10^{-3}\,m[/tex], then the moment of inertia of the hoop yo-yo is:

[tex]a = 0.5\cdot (9.5\times 10^{-3}\,m)[/tex]

[tex]a = 4.75\times 10^{-3}\,m[/tex]

[tex]b = 0.5\cdot (0.359\,m)[/tex]

[tex]b = 0.180\,m[/tex]

[tex]I_{g} = \frac{1}{4}\cdot (0.332\,kg)\cdot [4\cdot (0.180\,m)^{2}+3\cdot (4.75\times 10^{-3}\,m)^{2}][/tex]

[tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex]

The moment of inertia of the hoop yo-yo rotating about its center of mass is [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex].

b) The hoop yo-yo rotate at a point located at a distance of half diameter from the center of mass of the element, whose moment of inertia is determined by the Theorem of Parallel Axes:

[tex]I_{O} = I_{g} +m\cdot r^{2}[/tex] (4)

Where:

[tex]r[/tex] - Distance between parallel axes, measured in meters.

If we know that [tex]I_{g} = 0.0108\,kg\cdot m^{2}[/tex], [tex]m = 0.332\,kg[/tex] and [tex]r = 0.180\,m[/tex], then the moment of inertial of the hoop yo-yo rotating about the point where the tension force is applied is:

[tex]I_{O} = 0.0108\,kg\cdot m^{2}+(0.332\,kg)\cdot (0.180\,m)^{2}[/tex]

[tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex]

The moment of inertial of the hoop yo-yo rotating about its center of mass is [tex]I_{O} = 0.0216\,kg\cdot m^{2}[/tex].

Speed =distance/time

Speed=300/5=60 km/h

mark brainliest please

Answer:

2361.6N

Explanation:

Mass of player = 82kg

Velocity = 1.2m/s

Kinetic energy of player:

= 1/2mv²

= 1/2*82*1.2²

= 41x1.44

= 59.04J

Final kinetic energy = 0

Change in kinetic energy

|∆k| = |0-59.04|

= 59.04

Workdone by the feet = fd

d = 0.025

Fd = 59.04

F = 59.04/0.025

= 2361.6N

This is his average force.