Two S-year old girls, Alyse and Jocelyn, have been training to run a mile racc Alyse's I mile A is approximately Normally distributed with a mean of 13.5 minutes and a standard deviation of 2.5 minutes. Jocelyn's I mile time approximately Normally distributed with a mean of 12 minutes and a standard deviation of 1.5 minutes. Assuming A and J are independent random variables, what is the probability that Alyse has a smaller time than Jocelyn in a 1 sile race on a randomly selected day?

Answer:

6

Step-by-step explanation:

Answer:

Will has completed the Most.

Step-by-step explanation:

Madelyn has completed 50%

Adam has completed 75%

Will has completed 80%

I hope this helps!!! Please Mark Me Brainliest!!!!!!

Answer: Will

Step-by-step explanation:

Madelyn = 50%. 10/20 = 50%, because 10/20 is half, and 50% is half

Will = 80%

Adam = 75%. 3/4 x 25 = 75/100, which equals 75%.

So in conclusion, Will has finished the most problems, 2nd is Adam, and last is Madelyn.

Hope this helps!

Answer:

1:2

Step-by-step explanation:

because there are 9 stars and 18 squares giving you 9:18 but when you simplyfi you get 1:2

Answer: 9:18

Step-by-step explanation:

Count the amount of stars which is 9, then count the amount of circles which is 18. So therefore the answer would be 9:18

Answer:

D

Step-by-step explanation:

It has all the flashlight colors and sizes.

Answer:

The height of the third bounce is 10.8 feet

Step-by-step explanation:

Let us solve the question

∵ A ball is dropped from a height of 50 feet

∵ The function f(x) = 50[tex](0.6)^{x}[/tex] gives the height in feet of each bounce

∵ x is the bounce number

∵ We need to find the height of the third bounce

∴ x = 3

→ Substitute x by 3 in the function above

∵ f(3) = 50(0.6)³

∴ f(3) = 50(0.126)

∴ f(3) = 10.8

∴ The height of the third bounce is 10.8 feet

Answer:

1

Step-by-step explanation:

[tex] \tan \: 60 \degree. \cot \: 60 \degree \\ \\ = \cancel{\sqrt{3}} \times \frac{1}{\cancel{ \sqrt{3} }} \\ \\ = 1[/tex]

Answer:

J'(-2, 5), K'(2, 6), L'(1, 2) and M'(-3, 1)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation is reflection, rotation, dilation and translation.

Translation is the movement of a point either up, down, left or right on the coordinate plane. If a point A(x,y) is translated a units right and b units up, the new point is at A'(x + a, y + b) while a point A(x,y) is translated a units left and b units down, the new point is at A'(x - a, y - b).

Rhombus JKLM has vertices at J(-4,7), K(0,8), L(-1, 4), and M(-5,3). If a transformation of (x, y) ------> (x + 2, y - 2) is done, i.e. 2 units right and 2 units down, the new points would be at:

J'(-2, 5), K'(2, 6), L'(1, 2) and M'(-3, 1)

Answer:

2m - 6

Step-by-step explanation:

Combine the two m's in the equation to get 2m in which each m is 1.  Combine -9 and 3 together to get -6 since you are adding 3 to -9.  You should get 2m-6 as your final answer.

Answer:

X= - 10/57

Step-by-step explanation:

Answer:

I am really not sure bout this answer so please let me know if I'm wrong thank you (◍•ᴗ•◍)

Step-by-step explanation:

6v-10=2v-26

6v-10+10=2v-26+10

6v=2v-16

6v-2v=-16

4v=-16

v=-16/4

v=-4

Answer:

£3.57

Step-by-step explanation:

£2.95 + £3.48 = £6.43

£10.00 - £6.43 = £3.57

Answer:

I would say the answer is A

Answer:

Step-by-step explanation:

A

Answer:

Question a:

[tex]\frac{(2^3)^6 \times 9^3}{4^2 \times 27}\\= \frac{2^{18} \times 3^6}{2^4 \times 3^3}\\=2^{14} \times 3^3[/tex]

Question b:

[tex]\frac{35 \times 7^3}{5^2 \times 343}\\= \frac{7 \times 5^1 \times 7^3}{5^2 \times 7^3}\\= \frac{5^1 \times 7^4}{5^2 \times 7^3}\\=\frac{7^1}{5^1} = \frac{7}{5}[/tex]

Question c:

Note that this one is particularily simple as anything to the power of zero is equal to 1

[tex]((\frac{2^4 \times 3^6}{12^2})^0)^3\\= 1^3\\ =1[/tex]

Question d:

[tex]\frac{13^3 \times 7^0}{((65 \times 49)^2)^1}\\\frac{13^3}{(65 \times 49)^2}\\\frac{13^3}{(13 \times 5 \times 49)^2}\\\frac{13^3}{13^2 \times 5^2 \times 7^4}\\\frac{13}{5^2 \times 7^4}[/tex]

Answer:

I can't see any boxes??

Answer:

25 yards

Step-by-step explanation:

Subtract 15 from 40.

Hope this helped :)

Answer:

25 yards

Step-by-step explanation:

Arithmetics

Imagine a straight line divided into 1-yard marks.

Danny runs for 40 marks and locates at mark 40.

He later loses 15 yards and his new position is 40 - 15 = 25 yards

Therefore, the end result is that Danny is at the 25-yard mark.

the answer is circle in blue

Answer:

There are 32 cookies left

Step-by-step explanation:

There are c cookies when we started

c* 20% = 8 cookies

Change to decimal form

c * .20 = 8

Divide each side by .2

c * .2 / .2 = 8/.2

c =40

There are 40 cookies when we started

40 -8 = 32

There are 32 cookies left

Answer:

I got c

Step-by-step explanation:

sorry if im wrong!

Answer:

I got C or B

Step-by-step explanation:

Not sure, Im not great at this stuff

Answer:

1.5% x 412 = 618?

Step-by-step explanation:

Answer:

103/50

Step-by-step explanation:

Simplify

1/2

100

(412)

Answer:

and

Step-by-step explanation:

ok is a great resource for this year

Answer:

2.1 in decimal or 2 1/10 in mixed fraction.

Answer:

[tex]\huge\boxed{\sf 3.5}[/tex]

Step-by-step explanation:

Distance = [tex]\sf 6 \frac{1}{2} \ units = 6.5 \ units[/tex]

Here X is -3

So,

Point Y = -3 + 6.5 = 3.5

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

B

Step-by-step explanation:

so we know x is -3

we also know that the number has to be 6.5 units away from -3

so, -3 plus 6.5 is 3.5

-3 minus 6.5 is -9.5

Either 3.5 or -9.5 would work but 3.5 is the only listed option, so the answer is B

Answer:

...............................4650

Answer:

56

Step-by-step explanation:

68-12=56

Answer:

56

Step-by-step explanation:

56

Answer:1

Step-by-step explanation:

Answer: 6

Step-by-step explanation:

Let the number be x

If I increase twice my number by 5, the result is the same as if I triple my number and subtract 1. This can be formed into an equation as:

(2 × x) + 5 = (3 × x) - 1

2x + 5 = 3x - 1

5 + 1 = 3x - 2x

x = 6

The number you are thinking of is 6

Answer:

[tex] \huge{ \boxed{ \tt{1 }}}[/tex]

❁ Question : Simplify :

❁ Solution :

First , Use power law of indices.

Remember : If [tex] \sf{ {a}^{m} }[/tex] is an algebraic term , then

[tex] \sf{( {a}^{m} ) ^{n} } = {a}^{m \times n} = {a}^{mn} [/tex] , where m and n are positive integers.

➝ [tex] \sf{ {x}^{a(b - c)} \times {x}^{b(c - a)} \times {x}^{c(a - b)}} [/tex]

➝ [tex] \sf{ {x}^{ab - ac} \times {x}^{bc - ba} \times {x}^{ca - cb}} [/tex]

Now , Use product law of indices :

Remember : If [tex] \sf{ {a}^{m} }[/tex] and [tex] \sf{ {a}^{n}} [/tex] are the two algebraic terms , where m and n are the positive integers then [tex] \sf{ {a}^{m} \times {a}^{n} = {a}^{m + n}} [/tex]

➝ [tex] \sf{ {x}^{ab - ac + bc - ba + ca - cb}} [/tex]

Since two opposites adds up to zero , remove them :

➝ [tex] \sf{ {x} \: ^{ \cancel{ab} \: - \cancel{ac} \: + \cancel{bc} \: - \cancel{ba} \: + \cancel{ca} \: - \cancel{cb} } }[/tex]

➝ [tex] \sf{ {x}^{0} }[/tex]

Use Law of zero index

Remember : If [tex] \sf{ {a}^{0}} [/tex] is an algebraic term , where a ≠ 0 , then [tex] \sf{ {a}^{0} = 1}[/tex]

➝ [tex] \boxed{ \sf{1}}[/tex]

And we're done !

Hope I helped ! ♡

♪ Have a wonderful day / night ツ

~~

Answer:

46, 11/25, 45%

Step-by-step explanation:

Answer:

14.8

Step-by-step explanation:

Answer:

[tex]m=\frac{-3}{5}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Point (4, 3)

Point (-1, 6)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Answer:

[tex]m=-\frac{3}{5}[/tex]

Step-by-step explanation: