Use your TI-83 to determine the necessary t* value for a 90% confidence interval
based on a sample size of 55 and a sample standard deviation of 7.42.

2.005
1.669
1.96
1.645
2.67

The area of a rectangle is l*w. We have the length as 4.5 in and we can find the width by doing 3+2+4.5 = 9.5 in.

Then, we multiply them. 4.5*9.5 = 42.75 inches²

45. 0 square units.

The area of the kite is 40.5 unit square.

The side of the kite inscribed in square is 9

We have to find the area of the kite

The area of a kite is,

[tex]A = (d_1d_2) / 2[/tex]

Where [tex]d_1[/tex] and [tex]d_2[/tex] are the diagonals of the kite.

The kite is inscribed in the square, and the sides of the square are 9 units, the diagonals of the kite are both 9 units.

Therefore we get,

[tex]d_1 = 9 units[/tex]

[tex]d_2 = 9 units[/tex]

[tex]A = (9units \times 9units) / 2[/tex]

[tex]A = 81units^2 / 2[/tex]

[tex]A = 40.5 units^2[/tex]

So the third option is correct .

Therefore ,The area of the kite is 40.5 unit square.

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Answer:

it actually equals 5

Step-by-step explanation:

the reason it equals 5, is because there are 5 variables in there, so because of the addition sign, it becomes 1+1+1+1+1=5. you cannot prove me wrong.

Answer:

the correct answer is 4

Step-by-step explanation:

2 + 2 = 4

hope this helps

have an awesome day -TJ :)

The area of waffle in the cone is the amount of space covered by the waffle

The cone has 5630 square millimeter of waffle

The surface area of a cone is calculated using:

A = πr * (r+[tex]\sqrt{[/tex](h^2 + r^2))

For the complete 72 mm tall cone, we have:

Height (h) = 72 mm

Radius (r) = 42 mm/2 = 21 mm

So, the surface area is:

A = πr * (r+[tex]\sqrt{[/tex](h^2 + r^2))

A = 3.142 * 21 * (21+[tex]\sqrt{[/tex](72^2 + 21^2))

Evaluate

A = 3.142 * 21 * (21+75)

A = 6334.272

When the cone is cut at the top, we have:

Height (h) = 24 mm

Radius (r) = 14 mm/2 = 7 mm

So, the surface area is:

A = πr * (r+[tex]\sqrt{[/tex](h^2 + r^2))

A = 3.142 * 7 * (7+[tex]\sqrt{[/tex](24^2 + 7^2))

Evaluate

A = 3.142 * 7 * (7 + 25)

A = 703.808

Calculate the difference (d) between the areas

d = 6334.272 - 2.5*703.808

Evaluate

d = 5630.464

Approximate

d = 5630

Hence, the cone has 5630 square millimeter of waffle

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Answer:

C

Step-by-step explanation:

because density equal all the rest

Answer:

56

Step-by-step explanation:

(84÷3) · 2 = x

28 · 2 = 56

Hope that helps!

Answer:

28 ft²

Step-by-step explanation:

area of the desk = (5×4) + (4×2) = 20 + 8 = 28 ft²

Answer:

28

Step-by-step explanation:

5 times 4 = 20

4 times 2= 8

20 plus 8=28

Answer:

y intercept:(0,-13)
x intercept: (13/5,0)

Step-by-step explanation:

The way we find intercepts (both x and y) is to plug in zero.

x int:

We set y to 0:

0=5x-13

add thirteen to both sides

13=5x

x=13/5

y int:

set x to zero

y=5(0)-13

y= - 13

Answer:

60 days.

Step-by-step explanation:

This is  a proportion question. You compare two ratios. Unfortunately it is an inverse ratio.

12 = k/100                   Multiply both sides by 100

1200 = k

20 = k/x                       Multiply both sides by x

20x = k

20x = 1200                 Divide by 20

20x/20 = 1200/20

x = 60 days.  

An inverse proportion works by making a constant k. The  constant k makes the days shorter when the number of people increases. You should expect that. More people , less time.

Answer:

Substitute P=7500, r=0.053 and t=1 in equation (1). Therefore, the balance of the loan be after one year is $7897.5

The expression that represents waste reduction is w - 0.35x.

The paper waste produced now is 5.2 pounds per month.

The exression that represents waste production is the total amount of waste generated less athe reduction in waste.

w - 0.35x

Waste now produced = 8 - 0.35 x 8 = 5.2 pounds

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Answer:

1572864

Step-by-step explanation:

the nth term of a geoemtric series can be calculated using the following rule : [tex]a_n=a_1(r)^n^-^1[/tex]

where an = nth term, a1 = first term , r = common ratio and n = term position.

here, the first term is 6, the common ratio is 4 and the term position is 10 ( because we want to find the 10th term )

so a1 = 6 , r = 4 and n = 10

using these values we plug them into the rule

recall rule : [tex]a_n=a_1(r)^n^-^1[/tex]

==> plug in a1 = 6 , r = 4 and n - 10

[tex]a_1_0=6(4)^1^0^-^1[/tex]

==> subtract 10 and 1

[tex]a_1_0=6(4)^9[/tex]

==> simplify exponent

[tex]a_1_0=6(262144)[/tex]

==> simplify multiplication

[tex]a_1_0=1572864[/tex]

and we are done!

Note:

the common ration was found by dividing the first term by the next term

Answer:

11,682 the answer is that hope you get a A!

531

×22

+1062

+1062  

=11682

Therefore:

531 × 22 = 11,682

The rectangular point that represents (4, - pi/3) is the one in option b: (2, -2√3).

For a point (x, y), the polar coordinates are:

Then we must have:

R = 4 =  √(x^2 + y^2)

Notice that for all the given points we have the radius equal to 4, so the only part that we care is the angle one:

-pi/3 = Atan(y/x)

tan(-pi/3) = y/x = -1.73

So, y and x must have different signs, and because the angle is negative, we will say that the y-component must be negative.

So the correct option will be b: (2, -2√3)

y/x = -2*√3/2 = √3 = -1.73

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Answer: Quiz answer Unit 4 lesson 6

all answers are right

Step-by-step explanation:

1.) Given the polar coordinates (4,-pi3)which of the following rectangular coordinate pairs represents the same point?

Answer is B: (2,-2sqrt3)

2.) Given the rectangular coordinates (-5 5) which of the following polar coordinate pairs in, radians, represent the same points?

the correct option is D. (5√2,3π4)

3.)Rewrite in rectangular form: r=8 sin theta -2 cos theta.

Answer:

The equation in rectangular form is:

4.)Rewrite in polar form: x^2+y^2-6y-8=0

the  Answer is B. r^2=6r sin 0+8

5.)The graph of r=-9 cos theta has which of the following characteristics?

Answer:

"circle; diameter of 9; center at (-4.5,0)"

6.)Which conic section is represented by the polar equation r=1/4-6 cos theta?

Answer:

Option 2 - Hyperbola

7.)Identify the horizontal and vertical intercepts of the limaçon represented by the equation r=7+3 cos theta ?

Answer:

vertical intercepts: (7, pi/2) and (-7, pi/2)

horizontal intercepts: (10,0) and (-4,0)

8.) Classify the limaçon represented by the equation r=1/2-1/2 sin theta.

A. Cardioid

9.)Write the equation for the graph of the rose curve.

answer C: r=9 sin 4 theta

10.) Write the equation for the graph of the lemniscate.

answer D: r^2=-49 sin 2theta

(pls don't report for me not explain it took a lot of time typing this and im just trying to help people have less stress on their shoulders :p )

1 glass..........1/4 liter

n glass.......... 5 liters

n = 1 x 5 : 1/4

n = 5 x 4

so there are 20 glasses

Step-by-step explanation:

a) 2y = 3x + 4

b) given the perpendicular

3x + 5y = 1

5y = 1 - 3x

y = 1/5 - 3x/5

m¹ = -3/5

perpendicular

m¹m² = -1

-3m²/5 = -1

m² = 5/3

so (1,8)

x¹ = 1 y¹ = 8

m² = (y - y¹)/(x - x¹)

5/3 = (y - 8)/(x - 1)

5x - 5 = 3y - 24

3y - 5x + 5 - 24 = 0

3y = 19 + 5x

Answer:

C. 7/20

Step-by-step explanation:

There are 20 arrival times on the table.

7 of those twenty are before 8:20.

p(before 8:20) = 7/20

Answer: C. 7/20

The correct transformation of P(x) to get I(x) is I(x) = 2P(x)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

From the graph of I(x) and P(x), we can see that:

I(x) = 2P(x)

The correct transformation of P(x) to get I(x) is I(x) = 2P(x)

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Using the normal distribution and the central limit theorem, it is found that there is a 0.24 = 24% probability of observing a difference this large or larger.

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem, for each sample, the mean and standard error are given by:

[tex]\mu_I = 0.4, s_I = \sqrt{\frac{0.4(0.6)}{75}} = 0.0566[/tex]

[tex]\mu_{II} = 0.4, s_{II} = \sqrt{\frac{0.4(0.6)}{90}} = 0.0516[/tex]

Hence, for the distribution of differences, the mean and the standard error are given by:

[tex]\mu = \mu_I - \mu_{II} = 0.4 - 0.4 = 0[/tex]

[tex]s = \sqrt{s_I^2 + s_{II}^2} = \sqrt{0.0566^2 + 0.0516^2} = 0.0766[/tex]

The probability of observing a difference this large or larger is given by P(|Z| > Zx), in which Zx is the z-score when X = 0.0766. Hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{0.09 - 0}{0.0766}[/tex]

Z = 1.175.

Hence the probability is P(|Z| > 1.175), which is 2 multiplied by the p-value of Z = -1.175. Then:

2 x 0.12 = 0.24.

0.24 = 24% probability of observing a difference this large or larger.

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the line passes through the point ( - 8 ; - 2)

so f(-8) = - 2

Using the Central Limit Theorem, it is found that the mean of the sampling distribution is of 78 and the standard deviation is of 2.84.

It states that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

In this problem, for the population, we have that [tex]\mu = 78, \sigma = 11[/tex].

Then, considering samples of n = 15, we have that the standard deviation is given by:

[tex]s = \frac{11}{\sqrt{15}} = 2.84[/tex].

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Answer:  called tthe term of an algebraic expression.

Examples of algebraic expressions and their terms:

(i)  x + 10

We observe that the number of terms used in the expression x + 10 is 2. The terms are x and 10.

(ii)  5m + 2n - 7

We observe that the number of terms used in the expression 5m + 2n – 7 is 3. The terms are 5m, 2n and 7.

(iii)  3a/b

We observe that the number of term used in the expression 3a/b is 1. The term is 3a/b.

(iv) 3xy + 7xz + 2yz - 6

We observe that the number of terms used in the expression 3xy + 7xz + 2yz - 6 is 4. The terms are 3xy, 7xz, 2yz and 6.

)  2abc + 1

We observe that the number of terms used in the expression 2abc + 1 is 2. The terms are 2abc and 1.

Therefore, the algebraic expressions are either simple or compound.

(i) Simple algebraic expressions consist of one term.

(ii) Compound algebraic expressions consist of two or more terms.

The valid conclusions for the manager based on the considered test is given by: Option

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

Forming hypotheses:

where [tex]\mu_0[/tex] is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

[tex]z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094[/tex]

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

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Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

there are 3 feet in a yard

1 foot = 12 inches

3 feet = 36 inches

36/12 = 3 feet

Answer: 11/2

Reciprocal: 2/11

Step-by-step explanation: 11/2 is 5.5 (between 5 and 6) the reciprocal or 11/2 is 2/11

Answer:

Perhaps 2/5, if I understand your question.

Step-by-step explanation:

i don't understand the format of your question:

"3 6

Х

4 5

OL

Х

?"

Is this meant to be (3/6)*(4/5)  ??

If so:

(3/6)*(4/5) = (12/30)

(12/30) = 6/15

6/1`5 = 2/5

Answer:

x=74

Step-by-step explanation:

if angle ABE = 148. then, angle EBC = 32

and for angle ECB an BEC,

180-32 = 148

148/2 = 74

so, angle ECB and angle BEC  = 74

we know, angle BCE and angle CEF are equal because they are alternate angles

so, x = 74

Answer:

A

Step-by-step explanation:

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

100° is an exterior angle of Δ MLN , then

∠ LMN + 60° = 100° ( subtract 60° from both sides )

∠ LMN = 40°