What are the answers to these two ? HELP PLEASE

Step-by-step explanation:

Magnesium chloride (MgCl2).

Answer:a

A

Step-by-step explanation:

Edge 2021

Answer:

56

Step-by-step explanation:

Answer:

56

Step-by-step explanation:

got it from person above me have nice day

Answer:

In real the wall will be: 96 ft

Step-by-step explanation:

Given that the scale is

It means 1 inch will represent 4 ft.

so

1 inch = 4ft

Given that the measurement of the “ridge” of your new house on blueprints is 24 inches.

Thus,

24 inches = 24 × 4ft           ∵ 1 inch = 4ft

                = 96 ft              

Therefore, in real the wall will be: 96 ft

Answer:

[tex]w=-9/8[/tex]

Step-by-step explanation:

We are given the equation [tex]-2 \frac{1}{4} = 2w[/tex]. To solve this equation, we can divide both sides by 2 to get that [tex]w = -2\frac{1}{4} \div 2 = -\frac{9}{8}[/tex].

Answer:

w = - [tex]\frac{9}{8}[/tex]

Step-by-step explanation:

Given

- 2 [tex]\frac{1}{4}[/tex] = 2w ( change the mixed number to an improper fraction )

- [tex]\frac{9}{4}[/tex] = 2w ( multiply both sides by 4 to clear the fraction )

- 9 = 8w ( divide both sides by 8 )

- [tex]\frac{9}{8}[/tex] = w

Answer:

Find the asymptotes.

Vertical Asymptotes:

x

=

−

2

Horizontal Asymptotes:

y

=

0

No Oblique Asymptotes

Answer:

= 4.4591 × 1010

(scientific notation)

= 4.4591^10

= 44.591 × 109

Its actually pretty hard, so I don't really want to show my explanations with words, but there is a number explanation. Sorry if this is wrong. It is pretty hard, since you asked lots of times, I tried to give it a go.

6 X 10^-5 is 2*10^3 times the value of 3 X 10^-8.

6 X 10^-5 is how many times the value of 3 X 10^-8 is to be determined.

Fraction is defined as the number of compositions that constitute the whole.

Let 6 X 10^-5 is x  times the value of 3 X 10^-8.

[tex]6 * 10^{-5}= x 3 * 10^{-8}\\\\x = \frac{6 * 10^{-5}}{3 * 10^{-8}} \\\\x = 2 *10^3[/tex]

Thus, 6 X 10^-5 is 2*10^3  times the value of 3 X 10^-8.

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Answer:

x=2.51

Step-by-step explanation:

-2.49=-5+x

-5+x=-2.49

-5+x+5=-2.49+5

x=2.51

Answer:

(3)     [tex]  \dfrac{P_1V_1}{V_2} [/tex]

Step-by-step explanation:

[tex] P_1V_1 = P_2V_2 [/tex]

Divide both sides by V2.

[tex] \dfrac{P_1V_1}{V_2} = P_2 [/tex]

[tex]P_2 =\dfrac{P_1V_1}{V_2}[/tex]

Answer:

1. The percentage change is 74% and it is a percentage decrease

2. The percentage change is 15% and it is a percentage decrease

3. The percentage change is 20% and it is a percentage decrease

4. The percentage change is 43% and it is a percentage increase

5. The percentage change is 40% and it is a percentage decrease

6. The percentage change is 39% and it is a percentage decrease

Step-by-step explanation:

Given

[tex]1.\ Original = 5; New = 1.3[/tex]

[tex]2.\ Original = 160; New = 136[/tex]

[tex]3.\ Original = 15; New = 12[/tex]

[tex]4.\ Original = 7; New = 10[/tex]

[tex]5.\ Original = $30; New = $18[/tex]

[tex]6.\ Original = 9.6; New = 5.9[/tex]

Required

Determine the percentage change and state whether it's an increase or decrease

Percentage change is calculated as:

[tex]\%Change = \frac{New - Original}{Original} * 100\%[/tex]

[tex]1.\ Original = 5; New = 1.3[/tex]

[tex]\%Change = \frac{1.3 - 5}{1.3} * 100\%[/tex]

[tex]\%Change = \frac{-3.7}5} * 100\%[/tex]

[tex]\%Change = \frac{-3.7 * 100\%}{5}[/tex]

[tex]\%Change = \frac{-370\%}{5}[/tex]

[tex]\%Change = -74\%[/tex]

The percentage change is 74% and it is a percentage decrease

[tex]2.\ Original = 160; New = 136[/tex]

[tex]\%Change = \frac{136 - 160}{160} * 100\%[/tex]

[tex]\%Change = \frac{-24}{160} * 100\%[/tex]

[tex]\%Change = \frac{-24 * 100\%}{160}[/tex]

[tex]\%Change = \frac{-2400\%}{160}[/tex]

[tex]\%Change = -15\%[/tex]

The percentage change is 15% and it is a percentage decrease

[tex]3.\ Original = 15; New = 12[/tex]

[tex]\%Change = \frac{12- 15}{15} * 100\%[/tex]

[tex]\%Change = \frac{-3}{15} * 100\%[/tex]

[tex]\%Change = \frac{-3* 100\%}{15}[/tex]

[tex]\%Change = \frac{-300\%}{15}[/tex]

[tex]\%Change = -20\%[/tex]

The percentage change is 20% and it is a percentage decrease

[tex]4.\ Original = 7; New = 10[/tex]

[tex]\%Change = \frac{10- 7}{7} * 100\%[/tex]

[tex]\%Change = \frac{3}{7} * 100\%[/tex]

[tex]\%Change = \frac{3* 100\%}{7}[/tex]

[tex]\%Change = \frac{300\%}{7}[/tex]

[tex]\%Change = 43\%[/tex] -- (approximated)

The percentage change is 43% and it is a percentage increase

[tex]5.\ Original = $30; New = $18[/tex]

[tex]\%Change = \frac{18- 30}{30} * 100\%[/tex]

[tex]\%Change = \frac{-12}{30} * 100\%[/tex]

[tex]\%Change = \frac{-12* 100\%}{30}[/tex]

[tex]\%Change = \frac{-1200\%}{30}[/tex]

[tex]\%Change = -40\%}[/tex]

The percentage change is 40% and it is a percentage decrease

[tex]6.\ Original = 9.6; New = 5.9[/tex]

[tex]\%Change = \frac{5.9- 9.6}{9.6} * 100\%[/tex]

[tex]\%Change = \frac{-3.7}{9.6} * 100\%[/tex]

[tex]\%Change = \frac{-3.7* 100\%}{9.6}[/tex]

[tex]\%Change = \frac{-370\%}{9.6}[/tex]

[tex]\%Change = -39\%[/tex] -- (approximated)

The percentage change is 39% and it is a percentage decrease

Answer:

-4 < x < -8

Step-by-step explanation:

Given solve -x > 8 or -x < 4.

Solve each inequality first

-x > 8

Divide both sides by -1

-x/-1 > 8/-1

x < -8

Also if -x < 4

Divide both sides by -1

-x/-1 < 4/-1

x > -4

Combine both inequality x < -8 and x > -4

-4 < x < -8

Hence the solution set is -4 < x < -8

Answer:

the original price would be $800

Step-by-step explanation:

800-75% = 200

just use a calculator

Answer:

-3 {3}

Step-by-step explanation:

:D

Answer:

132

Step-by-step explanation:

you have to reduce the expression by solving 0.09 divided by 1.21 bc of the PEMDAS rule you do 1st parentheses first which is 0.1089 then do the second set of () which is 0.000825 then divide the 2 answers for 132

Answer:

8

Step-by-step explanation:

you have to add 25 on both sides then you get 5x<40 then you divide 40 by 5 and you get 8

hope this helps dont 4get to like and star

-mercury

Given :

A submarine started at the surface of the water and was moving at -15 meters per minute.

The submarine traveled at this rate for 48 minutes before coming to rest on the ocean floor.

To Find :

The change in the submarine position.

Solution :

We need to find the position of submarine position from the surface of water.

Distance travelled =  Speed × Time

Distance travelled = -15 m/min × 48 min

Distance travelled = 720 m

Therefore, the position of submarine is 720 m below the surface of ocean.

Answer:

Answer is 9

Step-by-step explanation:

Remember PEMDAS???

"parenthesis, exponents, multiplication, division, addition, subtraction"

you would first solve the addition inside of the parentheses (1 + 2 = 3), and from there finish the equation as it's written from left to right.

Answer:

9

Step-by-step explanation:

First, we have to solve inside the parentheses because of PEMDAS or GEMDAS, whichever you know. When we add 1+2 we get 3 inside the parentheses and it looks like this: 6/2(3).

Then, we have to divide 6 by 2 before we do anything else. When we divide 6/2, we get 3 and it will look like this: 3(3).

Finally, we have to multiply 3 by 3 because when something is in parentheses, you have to multiply it by the number right before it (next to it). Once we multiply 3*3, we will get our answer of 9.

(sorry if this is confusing but I hope it helped anyway)

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

Answer:

The answer is 6.75 calories or [tex]6 \frac{3}{4}[/tex]

Step-by-step explanation:

First, we need to find out how many calories per 1/3 minute.

4 1/2 divided by 2 = 2 1/4 or 2.25

2 1/4 or 2.25 x 3 = [tex]6 \frac{3}{4}[/tex] or 6.75 calories

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Answer:  The density of the second substance = [tex]1.7\text{ g cm}^{-3}[/tex]

Step-by-step explanation:

[tex]\text{Relative density }=\dfrac{\text{Density of substance}}{\text{Density of reference}}[/tex]

Given: Density of a substance is [tex]3.4 \text{ g cm}^{-3}[/tex] .

Its relative density relation to another substance = 2.0

Substitute all values in the formula , we get

[tex]2=\dfrac{3.4}{\text{Density of reference}}\\\\\Rightarrow\ {\text{Density of reference}=\dfrac{3.4}{2}\\\\\Rightarrow\ {\text{Density of reference}=1.7 \text{ g cm}^{-3}[/tex]

Hence, the density of the second substance = [tex]1.7\text{ g cm}^{-3}[/tex]

Answer:

x=8

Step-by-step explanation:

1. Subtract the 3 from both side so the new equation states 4x=32

2. Divide both sides by 4 for the final answer of x=8

Answer:

Step-by-step explanation:

Answer:

I'm so sorry I don't know this answer but good luck

Answer: since it doesn't tell you how you get it.

Since the mode of the ages is 35 we know that at least two of the ages are 35. Since the range is 14 we know the third sister is not also age 35. Let x be the age of the third sister. Then we know either 35 - x = 14 or x-35 = 14 (depending if x is younger or older, respectively). Solving both of these gives x = 21 or x = 49. But all the sisters are under the age of 45, so x = 21. Hence, the ages of the sisters are

21, 35, 35.

So, the mean is (35+35+21)/3 = 91/3 =~ 30.3333 ...

The median is 35.

Answer:

3

Step-by-step explanation:

Given that:

Larger square is a dilation of smaller square

Dimension of smaller square (5 - 3) units by (5 - 3) units = 2 by 2

Dimension of larger square (7 - 1) units by (7 - 1) units = 6 by 6

Hence, the scale factor used to create the larger square from the smaller square will be:

Scale factor (x) * side of smaller square = side of larger square

x * 2 = 6

2x = 6

x = 6/2

x = 3

Hence, scale factor used to generate larger square is 3

Answer:

4 is D = 23

Step-by-step explanation:

the coefficient is the number before the letter

Answer:

yes constant; 65

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{5^{-2} }{4^{6} } =\frac{1}{5^{2} 4^{6} }[/tex]

Answer:

a>12.5.

Step-by-step explanation:

you need to look at the discriminant in the quadratic formula:

[tex]b^{2} -4ac[/tex]

coming from the quadratic polynomial

[tex]ax^{2} +bx+c=0[/tex]

In our case, b=10 and c=2, hence, the discriminant is

[tex]10^2-4*a*2 \\100-8a[/tex]

We will obtain non-real values if the discriminant is less than zero.

Therefore, this condition is written as

[tex]100-8a<0[/tex]

and we must solve for a. It yields

[tex]100<8a\\a>\frac{100}{8} \\a>12.5[/tex]

Hence, the answer is a>12.5.

The values of a that will result in this equation having non-real solutions must e greater than 12.5

Given the quadratic equation  ax^2 + 10x + 2 = 0

For the equation to have non-real solutions, then b^2 - 4ac < 0

From the given equation;

a = a

b = 10

c = 2

Substitute the given parameters into the formula;

10^2 - 4a(2) < 0

100 - 8a < 0

-8a < -100

8a > 100

a > 12.5

Hence the values of a that will result in this equation having non-real solutions must e greater than 12.5

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Answer:

Answer:  The correct option is (D) P″(9, -12) and Q″(15, -3).

Step-by-step explanation:  Given that triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 to form triangle P″Q″R″.

The co-ordinates of vertices P and Q are (3, -4) and (5, -1) respectively.

We are to find the co-ordinates of the vertices P″ and Q″.

Case I :  ΔPQR dilated to ΔP'Q'R'

The co-ordinates of P' and Q' are given by

Case II :  ΔP'Q'R' dilated to ΔP''Q''R''

The co-ordinates of P'' and Q'' are given by

Thus, the co-ordinates of the vertices P'' and Q'' are (9, -12) and (15, -3).

Option (D) is CORRECT.

Step-by-step explanation:

Answer:

Length is 32. 6 cm and width is 5.9 cm

Step-by-step explanation:

width(w)=w

perimeter(p)=78 cm

length(L) = 4w+9

p=2L+2w

78=2(4w+9)+2w

78=8w + 19 + 2w

10w=59

w=5.9 cm

L=4w+9

L=4(5.9)+9

L=32.6 cm

Therefore length is 32.6 cm and width is 5.9 cm

Answer:

x=2.2

Step-by-step explanation:

6X - 2 + 5x + 7

add like terms

11x+5

divide 5 on both sides

x=2.2

Hope this helps dont 4get to like and star

-mercury

Answer:

11x+5

Step-by-step explanation:

6X - 2 + 5x + 7

Group like terms=6x+5x-2+7

Add similar elements=11x-2+7

Add Subtract the numbers=11x+5