Answer:
A team may contact the ball a total of three (3) times before it is sent over the net.
How long would it take a 500 w electric motor to do 150,000 j of work
Explanation:
300 second = 5 minutes
details
500 watts = 500 joules per second
Time = (1.50 x 10^5 joules)/(5 x 10^2 joules per second) = .3 x 10^3 seconds =300 second
An object is in equilibrium. Which force vector diagram could represent the force(s) acting on the object
Answer:
velocity and force
Explanation:
Velocity and force vector diagram represent the force acting on the object.
What is vector diagram?Diagrams are called vector diagrams to use a vector arrowhead to show the magnitude or direction of a vector quantity. The velocity of an item in motion could be represented in vector diagrams. A vector diagram might be used, for instance, to depict the motion of an automobile traveling down a road.
What is force?A force was an influence that will have the power to alter an object's motion.
Therefore, velocity and force vector diagram represent the force acting on the object.
To know more about vector and force.
https://brainly.com/question/11643003
#SPJ3
2Cu + 02 —> 2Cuo
In the equation above, what is the
coefficient of the oxygen molecule?
A) O
B) 1
C) 2.
D) 4
Answer:
C
Explanation:
What is equilibrium?
Answer:
Balance is the ability to maintain body balance when placed in various positions.
----------------------------------------
[tex] \green{ \boxed{ \boxed{ \sf{Lusi \: Adriana} } } } [/tex]
Hope it is Useful..Answer:
A state of physical balance.
I hope this helps you!!!
What is the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod
Answer:
C) 5ML^2
Explanation:
2 Spheres of mass M
Bug's mass 3M
Rod length 2L, radius L
Find Rotational Inertia I
I=Σmr^2
I=(3M+M+M)L^2
I=5ML^2
The rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Rotational inertia of the systemThe rotational inertia of the system is determined by summing all the masses together and multiply with the radius.
I(t) = Σmr²
Where;
m is the massr is the radiusI(t) = Inertia of the 2 spheres + inertia of the bug
I(t) = (M + M)L² + (3M)L²
I(t) = 2ML² + 3ML²
I(t) = 5ML²
Thus, the rotational inertia of the bug-rod-spheres system about the horizontal axis through the center of the rod is 5ML².
Complete question is below:
There are 2 Spheres of mass M and Bug's mass 3M. The Rod length is 2L, radius L.
Learn more about rotational inertia here: https://brainly.com/question/14001220
PLS HELP ASAP it's just 2 questions and they are multiple choice!
Составьте правильное соответствие:
1. А. Лавуазье
А. Он говорил: «Знание – сила»
2. Д. Дальтон
Б. Изучал теорию газов.
3. Д.И. Менделеев
В. Опубликовал труд «Методы наименования химических элементов»
4. Р. Броун
Г. Работы посвящены морфологии и систематике растений.
5. М. Смолуховский
Д. Работы посвящены броуновскому движению.
6. Р. Бойль
Е. Ввел понятие «атомный вес»
7. Ф. Бэкон
Ж. Открыл периодический закон химических элементов.
1. good morning mam going to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for me to be a long day for
if a substance changes from a vapor to a liquid it ____ HELP FAST
Answer:
Explanation:
Condensing is the word used to indicate the change of state of a substance from vapor to liquid, as in this case. During condensation, the substance releases thermal energy to the environment, therefore the kinetic energy of the molecules in the vapor decreases until they become closer to each other and they start to be affected by the intermolecular forces and so the substance becomes a liquid.
Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. She can drive her car, ride her bike, walk, or charter a helicopter.
Independent variable
Dependent variable
Controlled variables
Hypothesis
Based on the question, the following applies:
Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster. VARIABLES IN AN EXPERIMENT:The following are definitions of some variables in an experiment:
Independent variable in an experiment is the variable that is altered or changed by the experimenter. Dependent variable is the variable that is measured or recorded in an experiment. Controlled variable is the variable that is kept constant or unchanged throughout the experiment.According to this question, Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. The following are the variables in this experiment:
Independent variable: Time Dependent variable: Mode of transportationControlled variable: Distance traveledHypothesis: IF Bella charters a helicopter, THEN she will get to the grocery store faster.Learn more about experimental variables at: https://brainly.com/question/10415158
how long does it take saturn to rotate on its axis
Answer:
Orbit and Rotation
One day on Saturn takes only 10.7 hours (the time it takes for Saturn to rotate or spin around once), and Saturn makes a complete orbit around the Sun (a year in Saturnian time) in about 29.4 Earth years (10,756 Earth days).
Explanation:
Name 3 things you have in your home that you could use to make an electromagnet.
Answer:
radio TV set and telephone
Which of these is a likely impact of the stronger than normal trade winds on the eastern Pacific ocean?
Warm surface water builds up, causing lower than average temperature.
Warm surface water builds up, causing higher than average temperature.
Warm surface water is reduced, causing colder conditions than normal.
Warm surface water is reduced, causing hotter conditions than normal.
Just say A B C or D which one
Answer:
b i think
Explanation:
hope this helps
Answer: A B C or D which one
Explanation:
2. All objects contain both what and what charges.
Answer:
All objects are composed of these atoms. ... Charged objects have an imbalance of charge - either more negative electrons than positive protons or vice versa. And neutral objects have a balance of charge - equal numbers of protons and electrons.
Explanation:
31. TRUE or FALSE A cheese puff must contain C since CO2 was produced when it was burned,
I
Answer:
True
Explanation:
In the experiment shown below, which is greater, the force of gravity on the pith balls (Fg) or the electrostatic force between them (Fq)?
Answer:
Electronic force
Explanation:
Maybe because its warmer and may have more force
solar power generates electricity from what source
Dark matter is inferred to exist because Select one: a. we can observe its gravitational influence on visible matter. b. it explains how the expansion of the universe is accelerating. c. we see lots of dark patches in the sky. Clear my choice
Answer:
(a) the gravitational influence on visible matter can not be explained by matter that can be seen.
What happens to the sound an object makes when the speed of vibrations decreases (slow down)?.
A catamaran with a mass of 5.44×10^3 kg is moving at 12 knots. How much work is required to increase the speed to 16 knots? (One knot = 0.51 m/s.)
show all steps
The work that is required to increase the speed to 16 knots is 14,176.47 Joules
If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;
5.44×10^3 kg = 12 knots
For an increased speed to 16knots, we will have:
x = 16knots
Divide both expressions
[tex]\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\[/tex]
To get the required work done, we will divide the mass by the speed of one knot to have:
[tex]w=\frac{7230}{0.51}\\w= 14,176.47Joules[/tex]
Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules
Learn more here: https://brainly.com/question/25573786
which chamber approves presidential nomination
Answer: The Senate provides advice and consent on presidential nominations.
What are the variables that affect the force of gravity between objects?
A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The work done in the given case is 0
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
For calculating the work done by an object we apply the formula, that is ~
[tex]f \times s \times \cos( \theta) [/tex]where f represents force applied, and s represents displacement.
but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get
[tex]f = 0 \times s \times \cos( \theta) [/tex]hence,
[tex]work \: done = 0[/tex]So therefore, we can conclude that the man hasn't done any work.
Hope it helps.
Do comment if you have any query.
If an automobile slows from 26 m/s to 18 m/s in a period of 4.0 s, what was the average acceleration?
Answer: -2m/s²
Explanation:
Each second, the acceleration decreases of 2m/s²
N.B.: in physics, deceleration is also acceleration.
A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)
(a) The normal force on the block is 50.92 N.
(b) The horizontal force on block keeping it in equilibrium is 29.4 N.
The given parameters;
mass of the block, m = 6 kgangle of inclination, θ = 30.0°The normal force on the block is calculated as follows;
[tex]F_n = W \times cos(\theta)[/tex]
where;
W is the weight of the block[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]
The horizontal force on block keeping it in equilibrium is calculated as follows;
[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]
Learn more here:https://brainly.com/question/24860178
t/-15=-3. what is t?
Answer:
[tex]\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
[tex]\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}\red{\rule{40pt}{999999pt}}[/tex]
The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant
Voltage ______
Question 1 options:
is measured in Volts
causes current
pushes free electrons around a circuit
all of the choices
all of the choices.
Explanation:
....
PLS HURRY THIS IS DUE TODAY!!!
I WILL GIVE BRAINLIEST!!!!
NO LINKS AND NO STEALING POINTS,
PLS ANSWER IF YOU KNOW FOR SURE WHAT IT IS!!!
THE QUESTION IS IN THE PICTURE ATTACHED!
Answer:
B. between carbon and oxygen
Explanation:
formaldehyde has a carbon atom that has single bonds with two hydrogen atoms on both sides, and it has a double bond with oxygen.
Answer:
The placement of the double bond is between carbon atom and oxygen atom
this same question was for me so I did and got it correct
please mark me as brainliest
What unit of pressure in ideal gas law.
BEFORE COLLISION
MASS = 4200 kg
MASS = 990 kg
V = 10 m/s
AFTER COLLISION
V = ?
V = 2 m/s
What is the velocity after the crash?
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.