Answer:
Informal education is important because it can help individual to learn how to react and control situations.
It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.
Explanation:
Informal education is a type of education that is learned from different life experiences, happenings outside a structured curriculum.
Informal education is important because it can help individual to learn how to react and control situations.
It help individual to improve on its existing knowledge, new skills or ideas. This kind of education can happen any where and it can add values to the learner.
Where are you atera11
Answer:
? who is atera11?
Explanation:
ASAP
What is elastic potential energy?
Answer:
Elastic potential energy is stored when materials stretch or compress. Examples of it include springs, rubber bands, and slingshots.
Explanation:
What makes metal a good conductor?
Answer:
It is one of the strongest materials in the world and can hold anything
Which term best describes the motion of the rope particles in relation to the motion of the rope wave shown in the photograph
Answer:
A: Perpendicular
Explanation:
The question is incomplete as it lacks the image of the rope wave motion.
However, as found on "estudyassistant", the options are;
A) Perpendicular
B) Circular
C) Longitudinal
D) Parallel
From all that, we can say that;
The rope's are moving simultaneously in the same pattern without touching each other.
This is therefore a mechanical wave being created with the motion having oscillations that are perpendicular to the direction of energy transfer of the ropes.
This is a definition of transverse waves because the rope particle motion is perpendicular to the wave motion.
Answer:
A: Perpendicular
Explanation:
Read above explanation.
Ultimate frisbee relies upon good sportsmanship since there are no referees and players must self-officiate the game. What is this known as?
Group of answer choices
Spirit of the Team
Spirit of the Frisbee
Spirit of Sportsmanship
Spirit of the Game
Answer:
spirit of the team / game
A car moving initially at 20 m/s accelerates up to 60 m/s during the
course of 5 seconds. The average acceleration of the car is m/s2
ASAP DUE TO DAY PLS HELP MEEEEEE
1. Kinetic energy is the energy of:
A. potential
B. objects at rest
C. objects in motion
D. accelerating objects
--------------------------------------------------------------------------------------------
a book falls off a 1-meter tall table. how long will it take for the book to hit the floor ?
Answer:
0.45 s
Explanation:
Step 1: Given and required data
Displacement of the book (s): 1 mInitial velocity of the book (u): 0 m/s (rest)Acceleration due to the gravitational force of Earth (a): 9.8 m/s²Step 2: Calculate the time that it will take for the book to hit the floor (t)
The book undergoes a Uniformly Accelerated Motion. We can calculate the time required to reach the floor using the following suvat equation.
s = u × t + 1/2 × a × t²
s = 0 m/s × t + 1/2 × a × t²
s = 1/2 × a × t²
t = √(2s/a)
t = √(2 × 1 m/9.8 m/s²)
t = 0.45 s
2/3
If the crate has a mass of 80 kg, how much would it weigh?
3. A cart (m= 10.0 kg) is currently traveling with a velocity of 3.0 m/s. The cart then gains speed,
achieving a new velocity of 7.0 m/s after 8.0 seconds. Calculate the magnitude of the net force acting
on the cart.
A 0.0 N
B. 1.25 N
C. 5.0 N
D. 80N
First we calculate the acceleration of the cart:
a = (v₂ - v₁) / (t)
a = (7 m/s - 3 m/s) / (8 s)
a = 4 m/s / 8 s
a = 0.5 m/s²
Using the Newtons Second Law:
F = m×a
F = (10 kg)(0.5 m/s²)
F = 5 N
The correct option is CAs a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.60 cm2 and the woman's mass is 54.0 kg. Express the force in N/m2 and lb/in2. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to resist such large pressures.)
Answer:
P = 3.3075 x 10⁶ N/m² = 479.71 lb/in²
Explanation:
In order to find the pressure , we first need to find the force exerted by the lady. The force must be equal to the weight of the lady:
Force = F = Weight = mg
F = mg = (54 kg)(9.8 m/s²)
F = 529.2 N
Now, we convert area to S.I unit:
Area = A = (1.6 cm²)(1 m/100 cm)²
A = 1.6 x 10⁻⁴ m²
Now, the pressure can be calculated as:
Pressure = P = F/A
P = 529.2 N/1.6 x 10⁻⁴ m²
P = 3.3075 x 10⁶ N/m²
Now, we convert this into lb/in²:
P = (3.3075 x 10⁶ N/m²)[(0.000145038 lb/in²)/(1 N/m²)
P = 479.71 lb/in²
You have to move your 100 N couch before a delivery company drops off your new one. Unfortunately your roommate is passed out on it. The coefficient of friction between the couch and floor is .43. It takes 250 N of force to get the couch moving. a) How much does your roommate weigh in Newton’s? b) After you get the couch moving it only takes 200 N to keep it moving at a constant speed, what is the coefficient of kinetic friction?
Answer:
a) Weight of Roommate = 481.4 N
b) μk = 0.34
Explanation:
a)
The force required to move the couch must be equal to the force of friction:
F = frictional force
F = μW
W = F/μ
where,
W = Total Weight of Couch and Roommate
F = Force Required start to move couch = 250 N
μ = coefficient of static friction between couch and floor = 0.43
Therefore,
[tex]W = \frac{250 N}{0.43}\\\\W = 581.4 N[/tex]
So, the total weight is given as:
W = Weight of Couch + Weight of Roommate
Weight of Roommate = W - Weight of Couch
Weight of Roommate = 581.4 N - 100 N
Weight of Roommate = 481.4 N
b)
Now, the force required to keep the couch moving can be given as equal to the kinetic friction force:
F = kinetic friction
F = μk*W
μk = F/W
where,
μk = coefficient of kinetic friction = ?
F = Force required to keep the couch moving = 200 N
Therefore,
μk = 200 N/581.4 N
μk = 0.34
Which of the following cars have the most kinetic energy
[tex]\huge\boxed{OptionA}[/tex]
_____________________________________DATA:Blue Car:mass = 4 kg
velocity = 5 m/s^2
Orange truck:Mass= 2kg
Velocity = 7m/s^2
Grey Car:mass = 6 kg
velocity = 4m/s^2
Green Car:Mass = 8 kg
Velocity = 3 m/s^2
_____________________________________SOLUTION:By the equation of kinetic energy,
K.E = [tex]\frac{1}{2} mv^2[/tex]
Where,
K.E is kinetic energy
m is mass
v is velocity
_____________________________________Kinetic energy of Blue car:
Directly substitute the variables in the equation,
K.E = [tex]\frac{1}{2}x4x5^2[/tex]
Simplify the equation,
K.E = 50 J
_____________________________________Kinetic Energy of Silver Car:
Directly substitude the variable in the equation,
K.E = [tex]\frac{1}{2}x6x4^2[/tex]
Simplify the equation,
K.E = 48J
_____________________________________Kinetic Energy of Green Car:Substitute the variables in the equation,
K.E = [tex]\frac{1}{2}x8x3^2[/tex]
Simplify the Equation,
K.E = 36J
_____________________________________Kinetic Energy of Orange Truck:Substitute the variable,
K.E = [tex]\frac{1}{2}x 2x7^2[/tex]
Simplify the equation,
K.E = 49J
_____________________________________As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.
_____________________________________Best Regards,'Borz'the maximum intensity levels of a trumpet, trombone, and a bass drum, each at a distance of 3m are 94 dB, 107dB, and 113dB respectively. What is the intensity level of the three different instruments when played simultaneously, again at 3m?
Answer:
β = 114 db
Explanation:
The intensity of sound in decibles is
β = 10 log [tex]\frac{I}{I_{o}}[/tex]
in most cases Io is the hearing threshold 1 10-12 W / cm²
let's calculate the intensity of each instrument
I / I₀ = 10 (β / 10)
I = I₀ 10 (β / 10)
trumpet
I1 = 1 10⁻¹² 10 (94/10)
I1 = 2.51 10⁻³ / cm²
Thrombus
I2 = 1 10⁻¹² 10 (107/10)
I2 = 5.01 10-2 W / cm²
low
I3 =1 1-12 (113/10) W/cm²
I3 = 1,995 10-1 W / cm²
when we place the three instruments together their sounds reinforce
I_total = I₁ + I₂ + I₃
I_ttoal = 2.51 10-3 + 5.01 10-2 + 1.995 10-1
I_total = 0.00251 + 0.0501 + 0.1995
I_total = 0.25211 W / cm²
let's bring this amount to the SI system
β = 10 log (0.25211 / 1 10⁻¹²)
β = 114 db
A solid disk rotates in the horizontal plane at an angular velocity of 0.649 rpm with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.101 kg m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.415 m from the axis. The sand in the ring has a mass of 0.499 kg. After all the sand is in place, what is the angular velocity of the disk
Answer:
The angular velocity of the disk is 0.0369 rad/sec.
Explanation:
Convert 0.649 rpm to rad/s
0.649 rpm = 0.649 * (2π/60) = 0.0679rad/sec
From the question,
Summation of final angular momentum equals summation of initial angular momentum
I*w = Io*wo
w = wo (lo/I)
But I = Isand + Io
and Isand = Msand * R²sand
Therefore, w = wo (lo/I) = wo (Io/Msand * R²sand + Io)
Where,
wo = 0.0679rad/sec
Io = 0.101 kg m2
Msand = 0.499 kg
Rsand = 0.415 m
Hence,
w = 0.0679 {0.101/(0.499*(0.415)²+0.101)}
w = 0.0679 (0.101/0.1869)
w = 0.0679*0.544 = 0.0369 rad/sec
The angular velocity of the disk is 0.0369 rad/sec.
The diagram shows an electromagnet made with copper wire, a steel nail,
and a 1.5 V battery. Which change would make this electromagnet weaker?
A. Reverse the direction of the battery
B. Rap more coils around the nail
C. Replace the steel nail with a wooden stick
D. Replace the battery with a 3V battery
Correct answer is C
If an electromagnet is made with copper wire, a steel nail, and a 1.5 V battery then replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.
What is electromagnetic force?It is a type of force that occur between electrically charged particles. The electromagnetic force is the combination of all the electrical and magnetic forces generated by any charged particle.
As given in the problem statement diagram shows an electromagnet made with copper wire, a steel nail, and a 1.5 V battery, then we have to find out which change would make this electromagnet weaker,
Hence, By replacing the steel nail with a wooden stick would make this electromagnet weaker, therefore the correct answer is option C.
To learn more about electromagnetic forces, refer to the link;
brainly.com/question/13191643
#SPJ5
What is the slope of the line that passes through the points (-8, -3)(−8,−3) and (-12, -3) ?(−12,−3)? Write your answer in the simplest form.
single black dude
Notice that both of those points are 3 units below the x-axis. So the line is horizontal ... its slope is zero.
The weight of the bricks is 5000N. Calculate the mass of the bricks.
(1 kg weighs 10N)
Answer:
500kg
Explanation:
....................
Answer:
500Kg
Explanation:
1 kg = 10N
? =5000N
5000N÷10N * 1Kg = 500Kg
Obesity and stress are confirmed risk factors for which of the following?
lost of nutrition in human
Answer:
True
Explanation:
Obesity and stress are confirmed risk factors for CHD
What is food called when it enters the pharynx?
A.Bile
B.bolus
C. Food
D. Feces
Answer:
its food this was easy
If you add a light bulb to the circuit, the filament in the bulb will resist the flow of
electrons and convert energy into____and_____
a.)light and heat
b.)electrons and neutrons
c.)energy and matter
d.)electrons and protons
Answer:
Light and heat!
Explanation:
This is correct<3
Answer:
light and heat
Explanation:
i love science
A Ferris wheel with 60 spokes has a diameter of 100 m. It makes one rotation every 60 seconds. Find the speed of the passengers when the Ferris wheel is rotating at this rate.
Answer:
The speed of the passengers is 5.24 m/s
Explanation:
Uniform Circular Motion
It occurs when an object in a circular path travels equal angles in equal times.
The angular speed can be calculated in two different ways:
[tex]\displaystyle \omega=\frac{v}{r}[/tex]
Where:
v = tangential speed
r = radius of the circle described by the rotating object
Also:
[tex]\omega=2\pi f[/tex]
Where:
f = frequency
Since the frequency is calculated when the number of revolutions n and the time t are known:
[tex]\displaystyle f=\frac{n}{t}[/tex]
The Ferris wheel has a diameter of 100 m and makes n=1 rotation in t=60 seconds, thus the frequency is:
[tex]\displaystyle f=\frac{1}{60}\ Hz[/tex]
The angular speed is:
[tex]\displaystyle \omega=2\pi \frac{1}{60} =\frac{\pi}{30} \ rad/s[/tex]
Now we calculate the tangential speed, solving this formula for v:
[tex]\displaystyle \omega=\frac{v}{r}[/tex]
[tex]v=\omega . r[/tex]
The radius is half the diameter, r=100/2=50 m:
[tex]\displaystyle v=\frac{\pi}{30} . 50[/tex]
Calculating:
v = 5.24 m/s
The speed of the passengers is 5.24 m/s
you are driving at 18m/s down Lyndale avenue. A car backs out a driveway 25 meters in front of you. You continue at that speed while your brain processes the danger which takes 0.25 seconds. You then slam on the brakes and your car has an acceleration of -5.4m/s^2. Do you stop before reaching the driveway(and hitting the car)? Show your work. This is a two-part problem with constant speed and braking.
Hello!
For this, first let's calculate time of stop:
t = (V - Vi) / a
Replacing:
t = (0 m/s - 18 m/s) / -5,4 m/s^2
Resolving:
t = -18 m/s / -5,4 m/s^2
t = 3,33 s + 0,25 s = 3,58 s
Now lets calculate distance traveled, with formula:
d = Vi*t + (a*t^2)/2
Replacing:
d = 18 m/s * 3,58 s + (-5,4 m/s^2 * (3,58 s)^2) /2
Resolving:
d = 64,44 m + (-34,604 m)
d = 29,83 m
Then, the vehicle will CRASH
An object at rest is suddenly broken apart into two fragments by an explosion. The first fragment (with mass m1) acquires twice the kinetic energy of the second one (with mass m2).
What is the ratio of their masses?
Answer:
m1 ÷ m2 = 1 ÷ 2
Explanation:
The ratio of their masses is as follows:
As it is given that the mass m1 is twice of mass m2
So the equation could be written as
[tex]\frac{1}{2} m1 v1 v1 = 2 \times \frac{1}{2} m2 v2 v2\\\\\frac{m1}{m2} = \frac{2 v2 v2}{v1 v1} ..........(1)[/tex]
Here we used the conservation of momentum
Prior to the explosion, the object is in rest so the momentum would be zero but after the explosion the total momentum would be m1v1 + m2v2, that is also zero.
So,
[tex]m1 v1 + m2 v2 = 0\\\\m1 v1 = - m2 v2\\\\\frac{m1}{m2} = \frac{- v2}{v1}[/tex]
Now squaring to the both sides
m1 m1 ÷ (m2 m2) = v2 v2 ÷ (v1 v1) ........(2 )
Solved both the equations
After solving it, the ratio is
m1 ÷ m2 = 1 ÷ 2
HELP ASAP!! i’ll mark you the brainliest!!
Answer:
yes
Explanation:
What speed should a satellite with a mass of 1500 kg at 8,500 km above the center of the earth be traveling at in order to stay in orbit (remember the mass of the earth is 5.97×10 to the 24th kg ) (in m/s , G= 6.67×10 to the -11 n (m/kg) ^2)
Answer:
6844.5 m/s.
Explanation:
To get the speed of the satellite, the centripetal force on it must be enough to change its direction. This therefore means that the centripetal force must be equal to the gravitational force.
Formula for centripetal force is;
F_c = mv²/r
Formula for gravitational force is:
F_g = GmM/r²
Thus;
mv²/r = GmM/r²
m is the mass of the satellite and M is mass of the earth.
Making v the subject, we have;
v = √(GM/r)
We are given;
G = 6.67 × 10^(-11) m/kg²
M = 5.97 × 10^(24) kg
r = 8500 km = 8500000
Thus;
v = √((6.67 × 10^(-11) × (5.97 × 10^(24)) /8500000) = 6844.5 m/s.
Answer:
6.8 × 10³ m/s
Explanation:
for those using CK12, the answer, (6.78 × 10³ m/s), rounds to 6.8 × 10³ m/s
Which of the following is true of changes in momentum?
A small force may produce a large change in momentum by acting over a short time interval.
A large force may produce a small change in momentum by acting over a short time interval.
A small force may produce a large change in momentum by acting on a very massive object.
A small force may produce a large change in momentum by acting over a short distance.
can you please explain why this is the answer as well and how you got it?
Answer: ⇒ Answer is 3
Explanation: momentum = mass × velocity"A small force may produce a large change in momentum by acting on a very massive object".
THEY HAVEN'T GIVEN US THE TIME PERIOD NOR THE DISTANCE TRAVELED. THEREFORE WE CANNOT ACTUALLY DECIDE IF THE FORCE IS KEPT FOR A LONG TIME OR SHORT TIME. ANYWAYS SINCE THE MASS IS GIVEN AS MASSIVE , THE MOMENTUM SHOULD BE DEFINITELY HIGH.
WHY I SAY OTHERS ARE WRONG:
1) For a small force to give a large change in momentum, it should act for a long time interval.
2) By applying a large force for a short time interval, the change of momentum should be large.
3) Correct answer.
4) Acting over a short distance can be the same as acting over a short period of time.Therefore the distance should be large in order for a larger momentum.
I HOPE IT HELPS!
The true statement is required.
The true statement is A large force the change in momentum may be small acting over a short time interval.
Force is given by
[tex]F=ma[/tex]
m = Mass of object
a = Acceleration = [tex]\dfrac{v-u}{t}[/tex]
t = Time
So, force is
[tex]F=m\dfrac{v-u}{t}\\\Rightarrow F=\dfrac{mv-mu}{t}\\\Rightarrow F=\dfrac{\Delta p}{t}[/tex]
[tex]\Delta p[/tex] = Change in momentum.
If the time taken is small then the force will be large.
The change in momentum can also be small.
So, for a large force the change in momentum may be small acting over a short time interval.
Learn more:
https://brainly.com/question/14559060
https://brainly.com/question/18762737
a boy pushing a 200kg object on the floor it begins from rest and reaches 20 m/s² in 10 minutes, what is it's acceleration?
Answer:
I hope the above pic helps you mate
I will always help you understanding your assingments
have a great day
#Captainpower:)
In specific heat capacity experiment, the ammeter in circuit is connected in
Answer:
In series
Explanation:
In such experiment, the ammeter is connected in series with the heater, in order to measure the circulating current.
By the way, ammeters are always connected in series in circuits to measure the running current in it.
A block with a mass of 0.30 kg is attached to a horizontal spring. The block is pulled back from its equilibrium position until the spring exerts a force of 1.2 N on the block. When the block is released, it oscillates with a frequency of 1.1 Hz.
How far was the block pulled back before being released?
Answer:
The value is [tex]x = 0.084 \ m[/tex]
Explanation:
From the question we are told that
The mass of the block is [tex]m = 0.30 \ kg[/tex]
The force exerted is [tex]F = 1.2 \ N[/tex]
The frequency is [tex]f = 1.1 \ Hz[/tex]
Generally the spring constant of the spring is mathematically represented as
[tex]k = (2 \pi f)^2 * m[/tex]
=> [tex]k = (2 * 3.142 * 1.1 )^2 * 0.30[/tex]
=> [tex]k = 14.33 \ N/m[/tex]
Generally the spring constant is also mathematically represented as
[tex]k = \frac{ F }{x }[/tex]
=> [tex]14.33 = \frac{ 1.2 }{x }[/tex]
=> [tex]x = 0.084 \ m[/tex]