What effect does pollution have on condensation? A There are more particles in the air for water vapor to cluster around. B Areas with more pollution have more clouds and rain. C Pollution creates more ground level clouds. D It is harder for the sun to warm up the water vapor.

Answer:

I think its b be ause it looks like a better answer and it has some detail to it

Answer:

3

Explanation:

3 see below.

Take a much much easier problem that you might actually encounter in your life.

Suppose you have a sock drawer in your room that you haven't had the energy to put in order. Suppose you only look at that drawer when it is pitch black in the room. There are only 2 color socks in there -- red and green. How many socks to you have to pull out to assure that you have 2 of one color when you pull them out.

No cheating!

Three right. Suppose you pull out 1 green and 1 red. The next sock you pull out will have to be one of those 2 colors, right?

You could use sodium accetate a put it in water...

Answer:

Option C is true to be honest

Answer:

i put c and got it wrong its b

Explanation:

Answer:

what grade is this for and i think ik what the answer is

Explanation:

Answer:

0.024 mm

Explanation:

The quantity of charge deposited Q = It where I = current = 84.780000 mA = 0.084780000 A and t = time = 3.670000 hours = 3.670000 × 3600 s = 132120000 s.

Also Q = nF where n = number of moles of electrons silver deposited and F = Faraday's constant = 96500 C/mol

So, It = nF

n = It/F = 0.084780000 A × 132120000 s/96500 C/mol = 1120.1134 C/96500 C/mol = 0.012 mol

So, we have 0.012 mol of electrons

Our chemical equation is

Ag⁺ + e⁻ → Ag

Since 1 mol of electrons deposits 1 mol of silver atoms, then, 0.012 mol of electrons deposits 0.012 mol of silver atoms.

Since number of moles of silver atoms, n' = m/M where m = mass of silver atoms deposited and M = molar mass of silver = 107.868 g/mol

So, m = n'M

since n' = 0.012 mol,

m = 0.012 mol × 107.868 g/mol = 1.294 g

Since density of silver ρ = m/V where m = mass of silver deposited = 1.294 g and V = volume of silver deposited

V = m/ρ

Since, ρ = 10.650000 g/cm³

V = 1.294 g/10.650000 g/cm3 =

V = 0.122 cm³

Since the dimensions of the measuring rod are 13.870000 x 3.640000 x 5.980000 cm which represent its length, l, width, w and height, h respectively, the volume of silver deposited V = Ah' where A = area of the rod, lw and h' = thickness of silver deposited

So, V = Ah

V = lwh'

h' = V/lw

= 0.122 cm³/13.870000 cm x 3.640000 cm

= 0.122 cm³/50.4868 cm²

= 0.0024 cm

= 0.024 mm

Answer:

coal chemicals sun

Explanation:

Answer:

molerat

Explanation:

Answer:

3.28 mol

Explanation:

2 mol FeCl3 forms from 2mol of FeCl2

therefore 3.28 mol of FeCl3 forms from=2/2×3.28 mol=3.28 mol

Answer:

s orbital

Explanation:

The elements of Group 1 (IA) and Group 2 (IIA) have one and two electrons in their outermost shells respectively.

For the elements in group Group 1 (IA), the general outer electron configuration is ns1. This last electron is accommodated within an s orbital.

For the elements in Group 2 (IIA), the two outermost electrons are accommodated in an ns orbital, hence the answer.

Answer:

a) 226.6 grams of Cl₂

b) 19.2 grams of C

c) 303.2 grams of TiCl₄ and 70.4 grams of CO₂

Explanation:

The balanced chemical reaction is the following:

TiO₂(s) + C(s) + 2 Cl₂(g) → TiCl₄(s) + CO₂(g)

(a) What mass of Cl₂ gas is needed to react with 1.60 mol TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 2 moles of Cl₂. So, the stoichiometric ratio is 2 mol Cl₂/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of Cl₂ we need:

1.60 mol TiO₂ x 2 mol Cl₂/1 mol TiO₂ = 3.2 mol Cl₂

Now, we convert from moles to mass by using the molecular weight (MW) of Cl₂:

MW(Cl₂) = 35.4 g/mol x 2 = 70.8 g/mol

mass of Cl₂= 3.2 mol x 70.8 g/mol = 226.6 g

Therefore, 226.6 grams of Cl₂ are needed to react with 1.6 mol of TiO₂.

(b) What mass of C is needed to react with 1.60 mol of TiO₂?

From the chemical equation, 1 mol of TiO₂ reacts with 1 moles of C(s). So, the stoichiometric ratio is 1 mol C/1 mol TiO₂. We multiply this ratio by the moles of TiO₂ we have to calculate the moles of C(s) we need:

1.60 mol TiO₂ x 1 mol C(s)/1 mol TiO₂ = 1.60 mol C(s)

So, we convert the moles of C(s) to grams as follows:

MW(C) = 12 g/mol

1.60 mol x 12 g/mol = 19.2 g C(s)

Therefore, a mass of 19.2 grams of C is needed to react with 1.60 mol of TiO₂.

(c) What is the mass of all the products formed by reaction with 1.60 mol of TiO₂?

From the chemical equation, we can notice that 1 mol of TiO₂ produces 1 mol of TiCl₄ and 1 mol of CO₂. So, from 1.60 moles of TiO₂, 1 mol of each product will be produced:

1 mol TiO₂/1 mol TiCl₄ ⇒ 1.60 mol TiO₂/1.60 mol TiCl₄

1 mol TiO₂/1 mol CO₂ ⇒ 1.60 mol TiO₂/1.60 mol CO₂

Finally, we convert the moles to grams by using the molecular weight of each compound:

MW(TiCl₄) = 47.9 g/mol Ti + (35.4 g/mol x 4 Cl) = 189.5 g/mol

1.60 mol x 189.5 g/mol = 303.2 g

MW(CO₂) = 12 g/mol C + (16 g/mol x 2 O) = 44 g/mol

1.60 mol x 44 g/mol = 70.4 g

Therefore, from the reaction of 1.60 mol of TiO₂ are formed 303.2 grams of TiCl₄ and 70.4 grams of CO₂.

Answer: A river flowing at a certain speed

Explanation: as water has certain velocity and mass.

Answer:

IT IS CHLORIDE!

Explanation:

protons and neutrons.....

...

Answer:

The subatomic particles are Protons and Neutrons.

Answer: Neil Armstrong

Explanation

On July 20, 1969, Neil Armstrong became the first human to step on the moon. He and Aldrin walked around for three hours. They did experiments. They picked up bits of moon dirt and rocksExplanation:

Answer:

In 1969, Neil Armstrong was the first person to reach the moon.

Explanation:

Answer:In the given molecule the methyl group is attached at the second carbon atom of the parent chain. Therefore the name of hydrocarbon is 2-methylbutane.

Explanation:

Answer:

sulfite ion SO32

Explanation:

A molecular ion is a covalently bonded set of two or more atoms, or of a metal complex, that can be considered to behave as a single unit and that has a net charge that is not zero.

Answer:

mhm

Explanation:

Answer:

XCl₂ + 2AgNO₃ —> X(NO₃)₂ + 2AgCl

The coefficients are: 1, 2, 1, 2

Explanation:

XCl₂ + AgNO₃ —> X(NO₃)₂ + AgCl

The equation can be balance as follow:

XCl₂ + AgNO₃ —> X(NO₃)₂ + AgCl

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by writing 2 before AgCl as shown below:

XCl₂ + AgNO₃ —> X(NO₃)₂ + 2AgCl

There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balance by writing 2 before AgNO₃ as shown below:

XCl₂ + 2AgNO₃ —> X(NO₃)₂ + 2AgCl

Now, the equation is balanced.

The coefficients are: 1, 2, 1, 2

Answer: weigh is m = n × M = 2.87 mol × 58.44 g/mol

Explanation: mass = amount of substance × molar mass

M((NaCl) = 22.99 +35.45

Answer:

because it was in the mixture

Explanation:

Answer:

The other name for this isotope is a proton. This is because it contains just a  single proton.

Explanation:

H+

Protons = 1

Electrons = 1 - 1 = 0 (The + sign means it has lost a single electron)

Neutrons = 0

Answer:

1.634 molL-1

Explanation:

The mol ration between NH3 and HCl is 1 : 1

Using Ca Va / Cb Vb = Na / Nb   where a = acid and b = base

Na = 1

Nb = 1

Ca = 0.208 molL-1

Cb = ?

Va = 19.64 mL

Vb = 25.00mL

Solving for Cb

Cb = Ca Va / Vb

Cb = 0.208 * 19.64 / 25.0

Cb = 0.1634 molL-1 (Concentration of diluted ammonia solution)

Using the dilution equation;

C1V1 = C2V2

Initial Concentration, C1 = ?

Initial Volume, V1 = 25.00 mL

Final Volume, V2 =  250 mL

Final Concentration, C2 = 0.1634 molL-1

Solving for C1;

C1 = C2 * V2 / V1

C1 = 0.1634 * 250 / 25.00

C1 = 1.634 molL-1

Answer: The pH of a 0.00250 M oxycodone solution is 9.96

Explanation:

[tex]C_{18}H_{21}NO_4\rightarrow C_{18}H_{20}NO_3^++OH^-[/tex]

 cM                     0  M         0 M

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]         [tex]c\times \alpha[/tex]

So dissociation constant will be:

[tex]K_b=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Give c= 0.00250 M and [tex]pK_b[/tex] = 5.47

[tex]pK_b=-log(K_b)[/tex]

[tex]K_b=3.38\times 10^{-6}[/tex]

Putting in the values we get:

[tex]3.38\times 10^{-6}=\frac{(0.00250\times \alpha)^2}{(0.00250-0.00250\times \alpha)}[/tex]

[tex](\alpha)=0.036[/tex]

[tex][OH^-]=c\times \alpha[/tex]

[tex][OH^-]=0.00250\times 0.0369=9\times 10^{-5}[/tex]

Also [tex]pOH=-log[OH^-][/tex]

[tex]pOH=-log[9\times 10^{-5}]=4.04[/tex]

[tex]pH+pOH=14[/tex]

[tex]pH=14-404=9.96[/tex]

Thus pH of a 0.00250 M oxycodone solution is 9.96

"" ANSWER""

Protons are values ​​of atomic numbers that do NOT change, that is, they are located inside the nucleus of the atom, whereas electrons are located in the electrosphere that can gain or lose electrons, the electron has a negative charge and the Proton positive, that is, if in any atom it wins an electron the atom will be negative and if the atom loses it will be positive because we already know that the number of protons does not change. To calculate the number of neutron we have to make the number of rounded atomic mass which becomes mass less the number of protons for example oxygen gas has 8 protons which is the atomic number and has atomic mass 15,999 which rounding up to 16 to find the number of neutrals we do 16-8 = 8 so now we know that oxygen has: 8 protons, 8 electrons and 8 neutrons but the values ​​will not always be the same but the possibility of protons and neutrals having the same value is 75% by my count .

● ○ ● RULES ○ ● ○ ●

Atomic number = number of protons

Atomic mass ROUNDNESS = mass

Number of neutrons = number of protons - mass number

OBSERVATION- EXPLANATION FOR STUDENTS OF 9 YEARS BECAUSE IN THE HIGH SCHOOL UP SOME CHANGES CHANGE.

■■ GOOD STUDIES ■■

Answer:

Cows and other ruminant animals (like goats and sheep) emit methane, a potent greenhouse gas, as they digest grasses and plants. This process is called “enteric fermentation,” and it's the origin of cows' burps.

Explanation: