What happens to the function f(x)=(x−1)2+1 when it becomes f′(x)=(13x−1)2+1?
It is compressed toward the y-axis.
It is stretched away from the x-axis.
It is compressed toward the x-axis.
It is stretched away from the y-axis.

Answers

Answer 1
I think the answer is the last one
Answer 2

     Option (2). function f will be stretched away from the x-axis to form the image function f'.

Rule for the transformation of a function:  For a function is given by,

          f(x) = a(x - h)² + k

          If a > 1, graph of the function will be stretched vertically (towards  

          y-axis or away from the x-axis).

          If 0 < a < 1, graph of the function will be compressed vertically

          (towards x-axis or away from the y-axis)

Function given in the question,

f(x) = (x - 1)² + 1

Transformed function → f'(x) = (13x - 1)² + 1

                                        [tex]f'(x)=13(x-\frac{1}{13})^2+1[/tex]

By applying rule of the transformation,

a = 13 and 13 > 1

Therefore, function will be stretched vertically away from the x-axis.

      Hence, Option (2) will be the answer.

Learn more about the transformations here,

https://brainly.com/question/19279703


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Answer:

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Step-by-step explanation:

I've gone ahead and labeled some points.

There is a formula that says PA*PB = PC*PD, this is what you use.  If you would like me to show why this works I would be happy to.

So what we have is PA = 6, PB = 9+6 = 15, PC = 5 PD = 5+x so let;s writ ethe formula with these values

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EDIT: Here is the explanation for the formula

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This also means if you divide one side by its similar side you get the scale value, so this means if you do it to two different sets of similar sides you get the same number

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Answers

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