What is a property of the Noble Gases? *
A. They are not reactive because their outer valence electron shell is full.
B They are very reactive
C. They can be found in the atmosphere
D. They react readily with oxygen in the atmosphere

Answer:

I think the answer is false

Answer:

-189.55°C

Explanation:

Given data:

Initial volume of gas = 3.6 L

Final volume of gas = 15.5 L

Initial temperature = ?

Final temperature = 87°C (87+273 = 360 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₁  = V₁T₂  /V₂

T₁   = 3.6 L × 360 K / 15.5 L

T₁   = 1296 L.K / 15.5 L

T₁  = 83.6 K

Kelvin to °C:

83.6 K - 273.15 = -189.55°C

Answer:

x = w/v

General Formulas and Concepts:

Pre-Algebra

Explanation:

Step 1: Define

v = w/x

Step 2: Solve for x

Answer:

wsp

Explanation:

Answer: the pressure releases gas. The two most abundant gases are sulfur dioxide and carbon dioxide, and if levels of these gases increase,

Explanation:

Answer:

Due to "Common ion effect".

Explanation:

Lead chloride and Silver chloride have an ion in common which is Cl-, when these two solutions are dissolved, more chloride reacts with lead which shifts equilibrium position to the right hence precipitating out.

Answer:

True

Explanation:

When a force acts on an object, the object may change shape by bending, stretching or compressing - or a combination of all three shape changes.

Answer: I think it is D

Explanation:

Answer:

I think that the answers A, not 100% sure tho

Explanation:

Because the problem says "highly radioactive" chemicals and gamma rays are highly radioactive chemicals, and gamma rays are very penetrating to the human body

Answer:

P₂ =  3.19 atm

Explanation:

Given data:

Initial volume = 700 mL

Initial pressure = 1 atm

Initial temperature = 273K

Final temperature =100°C (100+273= 373 K)

Final volume = 300 mL

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1 atm × 700 mL × 373K / 273 K ×300 mL  

P₂ = 261100 atm .mL. K   /81900 K .mL

P₂ =  3.19 atm

Answer:

They run out of fuel

Some heat radiates out

High pressure gases move the piston

Answer:

Coefficients represents no of moles while subscripts represent no of atoms.

Answer:

Coefficients came before formula . Example = 4CO means there are 4 molecules of carbonmonooxide.

Subscripts came after and below the formula . Example = Oxygen gas in which 2 is a subscript which means there are 2 atoms of Oxygen in 1 molecule of Oxygen i.e. oxygen gas

Answer:D

Explanation:

Your skin makes vitamin D

Your skin prevents dehydration

And your skin maintains body temperature. So you are left with D

Answer:

The correct option is D.

works with bones to help you move

Explanation:

Skin is the outer layer of the body and it is the body's largest organ.

It protect the body from heat and other harmful substances.

It is comprises of three layers;

The Epidermis which is the outer layer.

The dermis which is a fibrous later that protect the Epidermis.

The subcutis is the subcutaneous layer that is beneath the dermis.

Function of the skin.

1. It's regulate body temperature

2. It's protect the body from heat and pathogenic entry.

3. It produces vitamin D

4. The skin allow sensations or feelings of touch, heat, and cold.

Therefore;

works with bones to help you move is wrong because it is the muscle that work with the bone.

1. A radical is a reactive intermediate with a single ____________ electron, formed by ____________ of a covalent bond.

1. A: Unpaired, and homolysis

2. Allylic radicals are stabilized by ____________ , making them ____________ stable than tertiary radicals.

2. A: Resonance, and more

3. A compound that contains an especially weak bond that serves as a source of radicals is called a radical ____________ .

3. A: Initiator

4. Treatment of cyclohexene with N-bromosuccinimide in the presence of light leads to ____________ by ____________ intermediates.

4. A: Allylic substitution by radical

Answer:

The Sun's gravitational pull keeps our planet orbiting the Sun. The motion of the Moon is affected by the gravity of the Sun AND the Earth. The Moon's gravity pulls on the Earth and makes the tides rise and fall every day. As the Moon passes over the ocean, there is a swell in the sea level.

Explanation:

The statement of factor that keeps Earth in orbit around the Sun is "the gravitational pull of the Sun."

The Sun is the primary star of our Solar System. The Earth revolves around our Sun, which really is a star. At a distance of around 93 million miles from the Sun, Earth is the third planet.

The fundamental force that governs the planets' orbits around the sun is gravity. While each planet does have its own gravity, which is determined by its size and speed of movement, orbit is determined by the gravity of the sun.

Our planet orbits the Sun due to it's gravitational pull. The Sun, as well as all of the planets and moons, are gravitationally bound together and circle all around solar system's centre of gravity.

The Sun's gravity is around 27.9 times that of Earth's, and it helps to govern the tides on Earth in a modest degree.

Hence the correct answer is the gravitational pull of the Sun.

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#SPJ2

Answer:

oxidize

Explanation:

Answer:

Mole, also spelled mol, in chemistry, a standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other

Answer:

Mole, also spelled mol, in chemistry, a standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.

Explanation:

Answer:

D

Explanation:

4 bars

Answer:

pH = 4.164

Explanation:

The first process is to find the initial moles for the base (B) & the acid (HA)

i.e.

[tex]= \dfrac{27 mL \times 0.0758 \ moles \ \ of \ B}{1000 \ mL}[/tex]

[tex]=0.0020466[/tex]

[tex]\simeq 2.047\times 10^{-3} \ moles \ of \ B[/tex]

[tex]= \dfrac{27 mL \times 0.0553 \ moles \ \ of \ HA}{1000 \ mL}[/tex]

[tex]=0.0014931[/tex]

[tex]\simeq 1.493\times 10^{-3} \ moles \ of \ HA[/tex]

The acid with base reaction is expressed as;

          HA              +      B         →             A⁻            +         HB⁺

to    1.493 × 10⁻³       2.047 × 10⁻³             -                         -

    -  1.493 × 10⁻³       1.493 × 10⁻³         1.493 × 10⁻³         1.493 × 10⁻³

            0                    5.54 × 10⁻⁴         1.493 × 10⁻³         1.493 × 10⁻³

From observation; both the acid & base weak

Given that:

The pKa for base = 4.594

The pKa for acid = 3.235

Recall that;

pKa = -log Ka

So; Ka = [tex]\mathbf{10^{-Ka}}[/tex]

By applying this:

For Base; Ka = [tex]10^{-4.594}[/tex] = 2.5468 × 10⁻⁵

For Acid:  Ka = [tex]10^{ -3.235}[/tex] = 5.821 × 10⁻⁴

After the reaction; we have the base with its conjugate acid & conjugate base of acid; Thus, since the conjugate acid of the base possesses a higher value of K, it is likely it would be the one to define the pH of the solution.

By analyzing the system, we have:

              HB⁺         + H₂O           ↔           B          +            H₃O⁺

     [tex]\dfrac{1.493\times 10^{-3}}{0.1 \ L}[/tex]                                 [tex]\dfrac{5.54\times 10^{-4}}{0.1 \ L}[/tex]

to   0.01493 M                                 0.00554   M

  -      x                                                   x                                x

    0.01493 - x                                 0.00554 - x                     x

Thus;

[tex]2.5468 \times 10^{-5} = \dfrac{(0.00554 -x)\times x}{(0.01493-x)}[/tex]

Using the common ion effect;

0.00554 - x   [tex]\simeq[/tex]  0.00554   &

0.01493 -  x   [tex]\simeq[/tex]   0.01493

∴

[tex]x = \dfrac{2.5468 \times 10^{-5} \times 0.01493}{0.00554}[/tex]

x =  [H₃O⁺] = 6.8635  × 10⁻⁵

∴

pH = -log(6.8635  × 10⁻⁵)

pH = 4.164

Answer:

Nobelium or Beryllium

Answer:pull

Explanation:

it is push i think to move the car

Answer:

Either A. Push or B.Pull because the truck is either pushing or pulling the car to move it. So it depends on if it's pushing or pulling the car.

Explanation:

The reason why chemists synthesize polymers in the lab is;

because of the need to perform and observe the results of a variety of synthesized polymer reactions and to predict when a reaction will happen.

      Polymers are simply defined as a substance or material made up of long repeating chemical chains of molecules.

     Now, polymer synthesis is simply called polymerization and it is the process by which smaller molecules called monomers undergo covalent bonding to form a longer polymer chain.

      Now, from the definition above, the reason why chemists synthesize polymers in the lab is because of the need to perform and observe the results of a variety of synthesized polymer reactions and to predict when a reaction will happen.

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Answer:

The chemical equation for step 1 is 2 NO2(g) → NO(g) + NO3(g), and the rate law is rate = k[NO2]^2

Explanation:

We know that the rate determining step is the slowest step in a sequence of non elementary reactions.

As we can see, the first reaction is slow so it is the rate determining step. From here we obtain the rate equation.

Also, the specie NO3 is absent in the overall reaction equation indicating that it is merely an intermediate produced in step 1 and used up in step 2.

The chemical equation for step 1 is [tex]2 NO_2(g) \rightarrow NO(g) + NO_3(g)[/tex], and the rate law is [tex]rate = k[NO_2]^{2}[/tex].

The rate -determining step is the slowest step in a sequence of non -elementary reactions.  The first reaction is slow so it is the rate determining step. From here we obtain the rate law.

Also, the specie [tex]NO_3[/tex]  is absent in the overall reaction equation indicating that it is merely an intermediate produced in step 1 and used up in step 2.

So, the chemical equation for step 1 is [tex]2 NO_2(g) \rightarrow NO(g) + NO_3(g)[/tex], and the rate law is [tex]rate = k[NO_2]^{2}[/tex].

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