Answer:
1/1
Step-by-step explanation:
The total cost of a sketchpad and 6 pecils is $22.53. The sketch pad costs $9.99. Each. pencil costs the same amount. How much does each pencil cost
Answer:
22.53-9.99=12.54
12.54 divided by 6 = 2.09
Each pencil costs $2.09
Step-by-step explanation:
Find the value of x need help
Answer:
x=-10
Step-by-step explanation:
since there's a given 120 degrees, and it's a isosceles triangle, we know that the line adds up to 180 (where the 120 degrees is). so 120+x=180, the interior angle measures 60 degrees. That being said, the 3 angles measure 60 degrees also. now there's a right angle mark on top, so we find the angle of the smaller triangle (near angle 2) by doing 90-60=30 degrees.
angle 2 is said to be x+160, and there's a line, which tells us that they must add to 180.. so x+160+30=180
x+190=180
x=-10.
One angle in a complementary pair of angles measures 3 times the other angle.
What is the measure, in degrees, of the
smaller angle?
Answer:
22.5 degrees
Step-by-step explanation:
Complementary angles add up to be 90 degrees. You can model the simple equation [tex]x+3x=90[/tex] where is x is the small angle and 3x is the large angle.
[tex]4x=90\\x=22.5[/tex]
the smaller angle is 22.5 degrees
The PTA was doing a fundraiser and bought 500 megaphones to sell for a pep rally. The profit, p, from the sale of megaphones can be represented by p(m) = 3.5m-875. Which inequalities represents the constraints of the range?
A. m>= - 875
B. 0<=p(m) <- 500
C. 0<=m<=500
D. p(m) >= -875
The inequality which represents the constraints of the range is D. p(m) ≥ -875
Since the PTA was doing fundraiser and bought 500 megaphones to sell for the pep rally, and the profit, p, from the sale of megaphones can be represented by p(m) = 3.5m - 875 where m = number of megaphones sold.
To find the inequalities represents the constraints of the range of p(m), we need to know the domain of m.
Since we have 500 megaphones and we can sell from 0 to 500 inclusive. So, the domain of m is 0 ≤ m ≤ 500.
To determine the range of p(m), we insert the values of m at its extreme points into p(m).
So, when m = 0
p(m) = 3.5m - 875
p(0) = 3.5(0) - 875
p(0) = 0 - 875
p(0) = -875
when m = 500
p(m) = 3.5m - 875
p(500) = 3.5(500) - 875
p(500) = 1750 - 875
p(500) = 875
Since for a profit, m ≥ 0. So, p(m) ≥ p(0) = -875
So, p(m) ≥ -875
So, the inequality which represents the constraints of the range is D. p(m) ≥ -875
Learn more about inequalities here:
https://brainly.com/question/17457213
1 A community group is painting classrooms. One 20 litre can of costs R1 699,00. It is then reduced by 6%. Determine the new cost of a 20 litre can
Please answer the question on the image.
Answer:
both isosceles???
Step-by-step explanation:
Answer:
They are similar.
Step-by-step explanation:
There might be other ways but
<X(Angle of x) is used for both triangle XAB and XYZ
And lines AB and YZ are parallel, From this we know that a line intersected by parallel lines it forms same angles for both parallel angles.
The similarity statement is: AAA Because angle(A=B , B=Z)
FREE-POINTS
Find x
x+3=5
Answer:2
Step-by-step explanation:
x+3=5
subtract 3 from both sides
x=5-3
x=2
Answer:
x= 2
Step-by-step explanation:
Ilana has 70¢ in her purse. All the coins have the same value. What could describe all the coins she has in her purse?
71 pennies
8 dimes
14 nickels
3 quarters
Answer:
14 nickels is the answer
Step-by-step explanation:
what is x- 2 1/2 = 6 3/4
Answer:
3 2/2
Step-by-step explanation:
The first three terms of a geometric sequence are as follows.
-10, -30, -90
Find the next two terms of this sequence.
Give exact values (not decimal approximations)
Answer:
-270,810
Step-by-step explanation:
c.r. r=-30/-10=3
[tex]a_{n} =a_{1}r^{n-1} \\a_{4}=-10(3)^{4-1}\\=-10(3)^3=-10 \times 27=-270\\a_{5}=-10 \times(3)^{5-1}\\=10 \times3^4\\=-810[/tex]
Algebra 2
K.14
Write a quadratic function with zeroes 2 and 8.
Answer:
[tex]x^{2}[/tex] - 10x + 16
Step-by-step explanation:
If the 0s are 2 and 8, then the factors are (x - 2) and (x - 8)
Multiply them together to get [tex]x^{2}[/tex] - 10x + 16
In 2000, there were 285 cell phone subscribers in the small town of Centerville. The number of subscribers increased by 65% per year after 2000. How many cell phone subscribers were in Centerville in 2020?
To determine the total number of cell phone subscribers that were in Centerville in 2020 is 5,928,227 people.
Given the following data:
Number of subscribers = 285Percentage increase = 65% Starting year = 2000Ending year = 2020Increment rate = 165% = 1.65
To determine the total number of cell phone subscribers that were in Centerville in 2020:
First of all, we would calculate the difference in years:
[tex]Year = 2020 - 2000[/tex]
Year = 20 years
Mathematically, the growth rate of cell phone subscribers that were in Centerville in 2020 is given by the formula:
[tex]A_n = Pr^t[/tex]
Substituting the given parameters into the formula, we have;
[tex]A_{20}=285(1.65)^{20}\\\\A_{20}=285 \times 22370.67\\\\A_{20}=5,928,227.55[/tex]
Subscribers = 5,928,227 people.
Read more: https://brainly.com/question/24731714
Please look for the question in the picture.
Answer:
two negitives equals a positive so C none of the above
Hope This Helps!!!
Answer:
A and B
Step-by-step explanation:
Wite a numerical expression for the below problems. Simplify the expressions.
Multiply six times three then divide by lwo
The quotient of twelve and two subiracled from thirty-six
Answer:
1) 9
2) 34
Step-by-step explanation:
For the first one, it would be
= (6×3)/2
= 18/2
= 9
The second one is,
= 36- (12/6)
= 36 - 2
= 34
find the equivalent fraction 2/6= __ 2/5= ___
#7) Identify all pairs of congruent angles
Answer:
A, D, G, H
Step-by-step explanation:
Look at the pink(or purple) lines. R and F both have 4 lines, so they're congruent. S and G both have 1 line, so those are congruent too.
-hope it helps
Answer:
1st option: ∠S ≅ ∠G
4th option: ∠T ≅ ∠H
7th option: ∠Q ≅ ∠E
8th option: ∠R ≅ ∠F
Step-by-step explanation:
Side lengths are unnecessary you just look at those loop things. Angles with the same number of "loops" are congruent like how ∠Q and ∠E both have 3 "loops", this means those angles are congruent.
been trying to solve this, need help
Given :-
The given triangle is isosceles triangle.Length of one side is 4 .To Find :-
The value of x in simplest radical form.Solution :-
The given triangle is a right isosceles triangle . So here we can use the Pythagoras theorem as ,
[tex]\longrightarrow[/tex] hypotenuse² = perpendicular ² + base²
[tex]\longrightarrow[/tex] x² = 4² + 4²
[tex]\longrightarrow[/tex] x² = 16 + 16
[tex]\longrightarrow[/tex] x² = 32
[tex]\longrightarrow[/tex] x = √32
[tex]\longrightarrow[/tex] x = √2⁵
[tex]\longrightarrow[/tex] x = 4 × 1.732
[tex]\longrightarrow[/tex] x = 6.928 ≈ 7
please help
step bu step
Answer:
what ang hirap nmn anong grade ka na ba
HELP ME! I WILL GIVE BRAINLIEST
Answer:
#1 matches with the pizza scenario
#2 matches with the present scenario
#3 matches with the Sarah scenario
Step-by-step explanation:
Look for keywords at the end of the questions and if they go hand and hand (such as in 7 hours / yield 20 servings) then they go together as a pair
1 42.6×37.2 =
2 99.2×48.5 =
3 246.3×9.67 =
4 68.54×24.4 =
5 123.86×31.5 =
Please i need answer
Answer:
1) 1584.72
2) 4811.2
3) 2381.721
4) 1672.376
5) 3901.59
Step-by-step explanation:
#keep learning:)A car traveling at 48 mph overtakes a cyclist who is riding at 16mph had a 3 hour head start how far from the starting point does the car overtake the cyclist?
The car overtakes the cyclist at a distance of 72 miles from the starting point.
,Speed is the ratio of distance travelled to time taken. It is given by:
Speed = distance / time
Let the car overtake the cyclist at distance d and time t.
For the car:
48 = d / t
d = 48t
For the cyclist:
16 = d / (t + 3)
d = 16t + 48
48t = 16t + 48
32t = 48
t = 1.5 hours
d = 48(1.5) = 72 miles
The car overtakes the cyclist at a distance of 72 miles from the starting point.
Find out more on speed at: https://brainly.com/question/3004254
Simplify 4 to the seventh power over 5 squared all raised to the third power . (4 points)
a
4 to the tenth power over 5 to the fifth power
b
4 to the fourth power over 5
c
4 to the twenty-first power over 5 to the sixth power
d
12 to the seventh power over 15 squared
Answer: The answer is C, 4 to the 21st over 5 to the 6th power.
20 POINTS!! PLEASE HELP DUE NOWWW!
Gia started to solve the equation 3(x − 10) − 5x = 2x − 26 below. They want to move the variables to the left side of the equation for their next step.
Fill in Line 4 and give the property.
Line 1: 3(x − 10) − 5x = 2x − 26 Original Problem
Line 2: 3x − 30 − 5x = 2x − 26 Distributive Property
Line 3: -2x − 30 = 2x − 26 Collect Like Terms
Line 4: _______________ _______________
The value of x from the given equation is -1
Given the equation expressed as:
[tex]3(x - 10) - 5x = 2x - 26[/tex]
Expand using the distributive law as shown:
3x - 3(10) - 5x = 2x - 26
3x - 30 - 5x = 2x - 26
Collect the like terms to have:
3x - 5x - 2x = -26 + 30
-2x - 2x = -26 + 30
Simplify the result by addition and subtraction:
-4x = 4
Divide both sides by -4 (Division property of equality)
-4x/-4 = 4/-4
x = -1
Hence the value of x from the given equation is -1
Learn more equations here: https://brainly.com/question/22688504
A helicopter starting on the ground is rising directly
into the air at a rate of 25 ft/sec. You are running on the
ground starting directly under the helicopter at a rate of 10
ft/sec. What is the rate at which the distance between you and the helicopter is changing when the helicopter has risen to a height of 60 ft in the air, assuming that, initially, it was 30 ft above you?
I want to understand how any why this is solved. So images/diagrams, detailed step by step breakdowns solutions are VERY much appreciated. Thanks!
Answer:
Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need, in general what you want is to move one end of the segment up, the other right, and stretch it.
That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.
For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]
The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.
The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.
Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.
Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]
Justin is making cookies, using a recipe in which the ratio
of flour to chocolate chips to sugar is 4: 2: 1 for each
batch.
a. If he is using 8 cups of flour how many cups of sugar
does he need?
b. To make 3 batches of cookies, what is the ratio of flour
to chocolate chips to sugar?
Answer:
Part A - he will need 2 cups of sugar
Part B - 12 : 6 : 3
Step-by-step explanation:
Part A :
8 divided by 4 is 2
Part B :
Multiply all the numbers by 3
Hope this helped! :)
Which expression shows how 8⋅54 can be rewritten using the distributive property?
4⋅50+4⋅4
50⋅8+50⋅4
8⋅50+8⋅4
8⋅50+8⋅54
Answer:
8 • 54=8 • 50 + 8 • 4
Option C is the right answer
Step-by-step explanation:
Answer:
C I think, sorry if I'm wrong
Determine whether or not the given value is a solution. 1. -5x + 4 = -1; x = -1 2.4x3 = -7; x = -1 3. 3y -4 = 5; y = // 4.-2y + 7 = 12; y = -1/2 5.3a-6 = 18 - a; a = -3 6. 5(2t - 1) = 2 = t; t = 2 7. ax = b = 0; x = b/a 8. ax + b = 2b; x = b/a
#1
[tex]\\ \sf\hookrightarrow -5x+4=-1[/tex]
[tex]\\ \sf\hookrightarrow -5x=-5[/tex]
[tex]\\ \sf\hookrightarrow x=1[/tex]
Incorrect
#2
[tex]\\ \sf\hookrightarrow 4x-3=-7[/tex]
[tex]\\ \sf\hookrightarrow 4x=-4[/tex]
[tex]\\ \sf\hookrightarrow x=-1[/tex]
Correct
#3
[tex]\\ \sf\hookrightarrow 3y-4=5[/tex]
[tex]\\ \sf\hookrightarrow 3y=9[/tex]
[tex]\\ \sf\hookrightarrow y=3[/tex]
Ans not given
#4
[tex]\\ \sf\hookrightarrow -2y+7=12[/tex]
[tex]\\ \sf\hookrightarrow -2y=5[/tex]
[tex]\\ \sf\hookrightarrow y=-5/2[/tex]
Incorrect
#5
[tex]\\ \sf\hookrightarrow 3a-6=18-a[/tex]
[tex]\\ \sf\hookrightarrow 4a=24[/tex]
[tex]\\ \sf\hookrightarrow a=6[/tex]
Incorrect
#6
[tex]\\ \sf\hookrightarrow 5(2t-1)=2[/tex]
[tex]\\ \sf\hookrightarrow 10t=7[/tex]
[tex]\\ \sf\hookrightarrow t=7/10[/tex]
Incorrect
#7
[tex]\\ \sf\hookrightarrow ax-b=0[/tex]
[tex]\\ \sf\hookrightarrow x=\dfrac{b}{a}[/tex]
Correct
Done
Find the exponential function f(x)=ab^x that satisfies the conditions f(0)=-4 and f(-2)=-64.
f(x)=
[tex]f(x) = ab^x~\hfill \begin{array}{llll}\textit{we know that}~f(0)=-4\begin{cases}x=0\\f(x)=-4\end{cases}\\\\-4=ab^0\implies -4=a(1)\implies -4=a\end{array}\\\\\\\stackrel{therefore}{f(x)=-4b^x}~\hfill \textit{we also know that}~f(-2)=-64\begin{cases}x=-2\\f(x)=-64\end{cases}[/tex]
[tex]-64=-4b^{-2}\implies \cfrac{-64}{-4}=b^{-2}\implies 16=b^{-2}\implies 16=\cfrac{1}{b^2} \\\\\\ b^2=\cfrac{1}{16}\implies b=\sqrt{\cfrac{1}{16}}\implies b = \cfrac{\sqrt{1}}{\sqrt{16}}\implies b = \cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill f(x)=-4\left( \frac{1}{4} \right)^x~\hfill[/tex]
QUESTION 20 PLEASE HELPPPP ASAPPPP
Answer: x=-1, y=-8
Step-by-step explanation: solve for the first variable in one of the equations then subsitutte the result into the other equation
HELP ANSWER PART A AND B
Answer:
part A: median is 12
part B: interquartile rage is 10
Step-by-step explanation:
Part A: to find your median on a box and whisker plot, you just need to look at your middle line in your box. In this case it's 12.
Part B: to find your interquartile range on a box and whisker plot, you subtract your Q1 and Q3. Your Q1 and Q3 will be the two outside lines that make up the rest of your box, in this case would be 6 and 16. To find your Q1 if you don't already have your plot set up, you separate the numbers that are given to you in half and find the median of each side. The first half will be your Q1 and the second half your Q3.