What is the approximate circumference of the circle shown below?
A. 37.8 cm
14.8 cm
B. 46.5 cm
C. 23.2 cm
D. 92.9 cm
SUBMIT
Answers
The approximate circumference of the circle shown in the image is given as follows:
B. 46.5.
How to obtain the circumference of a circle?The circumference of a circle of diameter d is given by the multiplication of π and the diameter, as follows:
C = πd.
π has the numeric value of 3.14, hence the equation is approximated as follows:
C = 3.14d.
The diameter of a circle is the distance between two points on the circumference of the circle that pass through the center, hence for this problem it is given as follows:
d = 14.8 cm.
Then the circumference of the circle is of:
C = 3.14 x 14.8
C = 46.5 cm.
More can be learned about the circumference of a circle at brainly.com/question/12823137
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Answer: 46.5 cm
Just took the test and got it right!
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_____
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Help me find the radius please
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y= - 1\4x + 5 and passes through (2,-3)
QUICK
Answers
Given:
The equation of parallel line is [tex]y=-\dfrac{1}{4}x+5[/tex].
Required line passes through (2,-3).
To find:
The equation of line.
Solution:
We have,
[tex]y=-\dfrac{1}{4}x+5[/tex]
On comparing this equation with [tex]y=mx+b[/tex], where m is slope, we get
[tex]m=-\dfrac{1}{4}[/tex]
Slope of two parallel lines are always same. So, slope of required line is [tex]m=-\dfrac{1}{4}[/tex].
The required line passes through the point (2,-3) having slope [tex]m=-\dfrac{1}{4}[/tex], so the equation of line is
[tex]y-y_1=m(x-x_1)[/tex]
[tex]y-(-3)=-\dfrac{1}{4}(x-2)[/tex]
[tex]y+3=-\dfrac{1}{4}(x)-\dfrac{1}{4}(-2)[/tex]
[tex]y+3=-\dfrac{1}{4}(x)+\dfrac{1}{2}[/tex]
Subtracting 3 from both sides, we get
[tex]y=-\dfrac{1}{4}(x)+\dfrac{1}{2}-3[/tex]
[tex]y=-\dfrac{1}{4}(x)+\dfrac{1-6}{2}[/tex]
[tex]y=-\dfrac{1}{4}(x)-\dfrac{5}{2}[/tex]
Therefore, the equation of required line is [tex]y=-\dfrac{1}{4}(x)-\dfrac{5}{2}[/tex].