What is the area of sector ACB? Leave your answer in terms of pi.​

Answer:

65

Step-by-step explanation:

Answer:

65

Step-by-step explanation:

=23+42

=65

Answer: 250 m

Step-by-step explanation:

Given

Distance between Ursula and Velda house is 4 km or 4000 m

Ursula walks at the rate of [tex]400\ m/h\ or\ \frac{20}{3}\ m/min[/tex]

Velda walks at the rate of [tex]600\ m/h\ or\ 10\ m/min[/tex]

Time taken by them to cover 4000 m is

[tex]\Rightarrow \dfrac{4000}{400+600}=4\ h\ or\ 240\ min[/tex]

Distance covered by them 15 min before they meet

Ursula [tex]=\frac{20}{3}\times 225=1500\ m[/tex]

Velda [tex]=10\times 225=2250\ m[/tex]

The total length covered by them is [tex]=1500+2250=3750\ m[/tex]

They are [tex]4000-3750=250\ m[/tex] apart before they meet

Answer:

x = 5

Step-by-step explanation:

Jeez this diagram is horribly drawn.

16/32 = 26/(32 + 4x)

16(32 + 4x) = 32(26)

32 + 4x = 2(26)

4x = 20

x = 5

Wow, my incorrect answer happened to also be the actual right one, wooh!

Answer:

She will hire EZ Excavation.

Step-by-step explanation:

For a company EZ Excavation,

Per cubic yards cost of the dirt = [tex]\frac{\text{Total cost}}{\text{Volume of the dirt}}[/tex]

                                                   = [tex]\frac{196}{8}[/tex]

                                                   = $24.5

Total cost of 40 cubic yards of the dirt = 40 × 24.5

                                                                   = $980

For second company Happy Hauling service,

Per cubic yard cost of the dirt = [tex]\frac{25}{1}[/tex]

                                                  = $25

Cost of 40 cubic yards of the dirt = 40 × 25

                                                       = $1000

Budget of the contractor = $1000

Cost of dirt offered by EZ Excavation is in her budget and she is saving $20.

Therefore, she will hire EZ Excavation.

Answer:

Step-by-step explanation:

Answer: D. 42 meters

Step-by-step explanation:

In calculating the distance between the seagull and the fish, you need to add their distances from sea level as this shows their distance from the sea and then from each other:

Seagull is 11 meters above the water

Fish is 31 meters below the water

Total difference

= Fish + Seagull

= 31 + 11

= 42 meters

Answer:

[tex]A=600\: u^{2}[/tex]

The correct answer is letter c.

Step-by-step explanation:

The area equation of a triangle is given by:

[tex]A=\frac{bh}{2}[/tex]  (1)

Where:

b is the base

h is the height

Let's find first the angle MJK (α), using the tangent definition.

[tex]tan(\alpha)=\frac{24}{32}[/tex]

[tex]\alpha=tan^{-1}(\frac{24}{32})[/tex]

[tex]\alpha=36.9^{\circ}[/tex]

Now, if α = 37° then β (angle JLK) must be:

[tex]37^{\circ} + \beta + 90^{\circ}=180^{\circ}[/tex]

[tex]\beta=53^{\circ}[/tex]

Now, we can find the distance ML using again the tangent definition:

[tex]tan(\beta)=\frac{24}{ML}[/tex]

[tex]ML=\frac{24}{tan(53)}[/tex]

[tex]ML=18[/tex]

The base of the triangle LKJ will be:

[tex]b=32+ML=32+18=50[/tex]

Therefore, using equation (1) the area of △LKJ will be:

[tex]A=\frac{50*24}{2}[/tex]

[tex]A=600\: u^{2}[/tex]

The correct answer is c.

I hope it helps you!

Answer:

it aint they are both the same

Step-by-step explanation:

Let the shared amount be 2x and 3x Then

2x + 3x = £ 250

5x = £ 250

x =£250/ 5

x = £ 50

Now

2x = 2 *£ 50 = £ 100

3x = 3 * £50 = £150

Hope it will help :)❤

Answer:

Jaylin spent $119.49

Step-by-step explanation:

Answer:119.49 US$

Step-by-step explanation:

its really just adding i did 49 plus 69 and added the 99 cents and got that

Answer:

36 yards of fabric

Step-by-step explanation:

Set up the proportion

quilts/yards = quilts/yards

Let x = no. of yards to make 12 quilts

x/12 = 21/7 = 3

x = 12(3) = 36 yards of fabric

Answer:

45

Step-by-step explanation:

There are 45 total marbles. The probability of drawing a yellow marble on the first draw is 3/4. Given replacement, the probability on the second draw is the same as on the first draw, so the probability of black marble on the second draw is 6/14. The probability of drawing first a yellow marble then a black marble is 3/14 * 6/14 = 18/196.

Answer:

1. The square root of 100

2.c=27.11

d=13.96

e=12.6

Step by step explanation:

1. 2×50=100 the geometric mean is the square root of 100

2. The diagram is made up of three right angled triangles the big outer one and two triangles inside the big one thus we can use the pythagorean theorem to come up with expressions which will help us in solving the unknown parts as below.

c²=30²-d²

c²=e²+24²

d²=e²+6²

both the following add up to c² meaning they are equal:

c²=30²-d²

c²=e²+24²

thus

30²-d²=e²+24²

I want to remain with d² only thus;

30²-24²-e²=d²

900-576=324 (squareroot of 324=18) so

d²=18²-e² and d²=e²+6²

both the above add up to d² meaning they are equal thus;

18²-e²=e²+6²

18²-6²=e²+e²

324-36=2e²

318=2e²

159=e²

e=12.61

Thus d²=e²+6²

d²=12.61²+6²

d²=159+36

d²=195

d=13.96

c²=e²+24²

c²=12.61²+24²

c²=159+576

c²=735

c=27.11

I hope this helps

Answer:

[tex]x = 9[/tex]

Step-by-step explanation:

Assume EFGH and JKLM are rectangles

JKLM appears to be the smaller of both.

So:

[tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

Where n is the scale of dilation

The area of EFGH is:

[tex]Area = EF * GH[/tex] ----- (1)

Substitute [tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

[tex]Area = n*JK * n*LM[/tex]

[tex]Area = n^2*JK * LM[/tex]

So, we have:

[tex]Area = EF * GH[/tex] and [tex]Area = n^2*JK * LM[/tex]

[tex]EF * GH = 2x + 9[/tex] --- Given

[tex]JK * LM = 2x - 6[/tex] --- Given

So:

[tex]Area = EF * GH[/tex] and [tex]Area = n^2*JK * LM[/tex]

[tex]Area = 2x + 9[/tex] and [tex]Area = n^2 * (2x - 6)[/tex]

Equate bot areas

[tex]2x + 9 = n^2*(2x - 6)[/tex]

Make n^2 the subject

[tex]n^2 = \frac{2x + 9}{2x - 6}[/tex]

The perimeter (P) of EFGH is:

[tex]P = 2*(EF + GH)[/tex] ----- (1)

Substitute [tex]EF = n * JK[/tex] and [tex]GH = n * LM[/tex]

[tex]P = 2*(n*JK + n*LM)[/tex]

[tex]P = 2n*(JK + LM)[/tex]

So, we have:

[tex]P = 2*(EF + GH)[/tex] and [tex]P = 2n*(JK + LM)[/tex]

[tex]2*(EF + GH) = x + 3[/tex] --- Given

[tex]2*(JK + LM) = x - 1[/tex] --- Given

So:

[tex]P = 2*(EF + GH)[/tex] and [tex]P = 2n*(JK + LM)[/tex]

[tex]P =x + 3[/tex] and [tex]P = n *(x - 1)[/tex]

Equate bot perimeters

[tex]x + 3 = n(x - 1)[/tex]

Make n the subject

[tex]n =\frac{x + 3}{x - 1}[/tex]

Square both sides

[tex]n^2 =\frac{(x + 3)^2}{(x - 1)^2}[/tex]

Recall that: [tex]n^2 = \frac{2x + 9}{2x - 6}[/tex]

So, we have:

[tex]\frac{(x + 3)^2}{(x - 1)^2} = \frac{2x + 9}{2x - 6}[/tex]

Evaluate all squares

[tex]\frac{x^2 + 6x +9}{x^2 - 2x + 1} = \frac{2x + 9}{2x - 6}[/tex]

Cross multiply

[tex](x^2 + 6x +9)(2x - 6) = (x^2 - 2x + 1)(2x + 9)[/tex]

Open brackets

[tex]2x^3 +12x^2 + 18x - 6x^2 -36x -54 = 2x^3 - 4x^2 + 2x + 9x^2 - 18x +9[/tex]

Subtract 2x^3 from both sides

[tex]12x^2 + 18x - 6x^2 -36x -54 = - 4x^2 + 2x + 9x^2 - 18x +9[/tex]

Collect like terms

[tex]12x^2 - 6x^2 + 18x -36x -54 = - 4x^2 + 9x^2+ 2x - 18x +9[/tex]

[tex]6x^2 - 18x -54 = 5x^2- 16x +9[/tex]

Collect like terms

[tex]6x^2 -5x^2 - 18x +16x -54 -9= 0[/tex]

[tex]x^2 -2x -63= 0[/tex]

Expand

[tex]x^2 +7x - 9x - 63 = 0[/tex]

Factorize

[tex]x(x +7) - 9(x + 7) = 0[/tex]

[tex](x -9) (x + 7) = 0[/tex]

[tex]x = 9\ or\ -7[/tex]

x can not be negative.

So: [tex]x = 9[/tex]

Answer:

circumference = pi (3.14 or 22/7, whatever your teacher wants or whatever the problem asks) x the diameter

Step-by-step explanation:

Answer:

To calculate the circumference of a circle, multiply the diameter of the circle with π (pi). The circumference can also be calculated by multiplying 2×radius with pi (π=3.14).

Step-by-step explanation:

I hope the images help!!

answer:

true

false

true

good luck :)

hopefully, this helps

have a great day !!

**please let me know if this was wrong**

Answer: True.

If two parallel lines are cut by a transversal, then the alternate interior angles formed are congruent . When two lines are cut by a transversal, the pairs of angles on either side of the transversal and outside the two lines are called the alternate exterior angles .

Answer:

She isn't correct because after you find the common denominator, the numerator needs to be changed as well, so when she multiplied the denominator of 2/3 by 4 to get 12, she also had to multiply the 2 by 4, to get 8/12, and then subtracted, because otherwise, the new fraction isn't equivalent to the original fraction.

The triangle VXW should look like that in the attachment.

sine of W = opposite side/hypotenuse

=> sine of W = 77/85

Other formulae:

Just multiply all them together for volume, 468 ft ^3

Answer:

4 feet and 3 inches

Step-by-step explanation:

The measure of ladder in feet is 4.15.

Given that, a ladder is 51 inches tall.

Metric Conversion refers to the conversion of the given units to desired units for any quantity to be measured.

We know that, 1 feet = 12 inches

So, in inches = 51/12

= 4.25 feet

Therefore, the measure of ladder in feet is 4.15.

To learn more about the metric conversion visit:

brainly.com/question/21244256.

#SPJ6

Answer:

10/10

Step-by-step explanation:

Ez..........................................................

It is true that if data set A has a larger standard deviation than data set B, data set A is more spread out than data set B.

The standard deviation is a measure of spread.

And the more the standard deviation, the more the spread

This means that if the dataset A has a larger standard deviation than the dataset B, then the dataset A is more spread out than B

Hence, the given statement is true

Read more about standard deviation at:

https://brainly.com/question/15858152

#SPJ1

Answer:

180 seconds

Step-by-step explanation:

Just mulitply 60 by 3 to get 180 seconds in 3 minutes.

Answer:

180 seconds

Step-by-step explanation:

Answer:

[tex]\angle b + \angle c + \angle e = 120^\circ[/tex]

Step-by-step explanation:

Given

[tex]\angle d = 150[/tex]

See attachment for illustration

Required

Find [tex]\angle b + \angle c + \angle e =[/tex]

The sum [tex]of\ angles\ at[/tex] a point is [tex]360^\circ[/tex]

So:

[tex]\angle a + \angle b + \angle c + \angle d + \angle e = 360^\circ[/tex]

Angle a is at right angled.

So:

[tex]90 + \angle b + \angle c + 150 + \angle e = 360^\circ[/tex]

Collect like terms

[tex]\angle b + \angle c + \angle e = 360^\circ -150^\circ - 90^\circ[/tex]

[tex]\angle b + \angle c + \angle e = 120^\circ[/tex]