Answers
Answer:
i cant explain well but the answer is letter b
x-5
Explanation:
dont report me or i will report you too
Answer:
x-5 is the answer
Explanation:
pick her as the brainliest
Related Questions
The variables for Part I of this experiment include whether or not the car hits the barrier and the distance that the washers travel. Use the drop-down menus to identify the independent and dependent variables.
The independent variable, the one that is intentionally manipulated, is
____.
The dependent variable, the one that you measure the response in, is
___.
Answers
Answer:
1. An encounter with the barrier
2. The distance traveled by the washer.
Explanation:
Answer:
Peep above me is correct
1.An encounter with the barrier
2.The distance traveled by the washer
Explanation:
got it right on edge2020 have a nice day peeps ^w^
a student determines the circumference of a golf ball. a man pulls a sledge of mass 25 kg across level ground with a horizontal force of 60 N. a constant force of friction of 20 N acts on sledge. what is the acceleration of the sledge?
Answers
Explanation:
Fnet = Ft - Ff = 60N - 20N = 40N
a = Fnet / m = 40N / 25kg = 1.6m/s².
Calculate resultant force:
R = ma
Descomposing:
F - Fr = ma
Replacing we have:
60 N - 20 N = 25 kg * a
Resolving:
40 N = 25 kg * a
40 N / 25 kg = a
1,6 m/s^2 = a
The aceleration is 1,6 meters per second squared.
How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?
Answers
Answer:
The car will travel 541.67 m
Explanation:
Constant Acceleration Motion
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
The relation between the initial and final speeds is:
[tex]v_f=v_o+a.t[/tex]
Where:
vf = Final speed
vo = Initial speed
a = Acceleration
t = Elapsed time
The acceleration can be calculated by solving for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
And the distance traveled is:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]
The car travels during t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.
Let's convert the speeds to m/s. Recall 1 Km=1000 m and 1 h= 3600 s:
vo=50 Km/h * 1000/3600 = 13.89 m/s
vf=80 Km/h * 1000/3600 = 22.22 m/s
Calculating the acceleration:
[tex]\displaystyle a=\frac{22.22-13.89}{30}[/tex]
[tex]a = 0.28\ m/s^2[/tex]
Now for the distance:
[tex]\displaystyle x=13.89*30+\frac{0.28.30^2}{2}[/tex]
[tex]x=416.67\ m+125\ m[/tex]
[tex]\boxed{x = 541.67\ m}[/tex]
The car will travel 541.67 m
According to the question,
Final speed, [tex]v_f = 80 \ km/h \ ,or \ 22.22 \ m/s[/tex]Initial speed, [tex]v_o = 50 \ km/h, or \ 13.89 \ m/s[/tex]Elapsed time, [tex]t = 30 \ s[/tex]We know the relation,
→ [tex]v_f = v_o +at[/tex]
or,
→ [tex]a = \frac{v_f-v_o}{t}[/tex]
Now,
The acceleration,
→ [tex]x = v_o.t+ \frac{a.t^2}{2}[/tex]
By substituting the values,
[tex]= \frac{22.22-12}{30}[/tex]
[tex]= 0.28 \ m/s^2[/tex]
hence,
The distance traveled be:
→ [tex]x = 13.89\times 30+\frac{0.28.30^2}{2}[/tex]
[tex]= 416.67+125[/tex]
[tex]= 541.67 \ m[/tex]
Thus the above answer is right.
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A force of 10N is making an angle of 30
with the horizontal. Its vertical component
will be;
Answers
Explanation:
The vertical component = 10sin30° = 5.0N.
We work in less time.
3.
Differentiate between:
a)
Work and energy
b)
Work and power
c) Kinetic energy
Kinetic energy and potential energy
Work from burning fuel and work from moving objects
d)
110
Answers
Answer:
1 work is scalar quantity
2 it si unit of work is joule
3The equation of caculate is work= Force× Displacement
1 power is scalar quantity
2 it si unit of power is watt
3 the equation of calculateis power= work \time
What is the velocity of a car with a momentum of 100 kg*m/s and a mass of 35kg?
Answers
Answer:
2.86 m/sExplanation:
The velocity of the car can be found by using the formula
[tex]v = \frac{p}{m} \\ [/tex]
p is the momentum
m is the mass
From the question we have
[tex]v = \frac{100}{35} = \frac{50}{7} \\ = 2.857142...[/tex]
We have the final answer as
2.86 m/sHope this helps you
does the voice from loudspeaker also get shrill when the listener reaches the sounding source?
Answers
Answer:
Yes, cause when listener is far away from music source... the listener feels it's pleasant.... but when observer approaches near loudspeaker... sound become unpleasant..........sound becomes noise when frequency crosses 85 Decibels.....so you can say that the voice from loudspeaker also get shrill when the listener reaches the surrounding source......
PLEASE ANSWER - WILL MARK BRAINLIEST - THANKS
List three scientific ideas, discoveries, concepts, or issues that interest you.
Answers
Answer:
Evolution, Big Bang Theory and Cell theory.
Explanation:
These theories interest me because they talk about life and how life started.
A car of weight 11000 N moves with constant velocity along a horizontal road.A driving force of 5000 N acts on the car what is the force opposing the motion of the car
Answers
Answer:
5000 N
Explanation:
Since F - f = ma, where F = driving force = 5000 N, f = opposing force, m = mass of car and a = acceleration of car.
Since the car is moving with constant velocity, a = 0.
So, F - f = ma
F - f = m(0)
F - f = 0
F = f.
Since F = 5000 N and F = f, f = 5000 N.
So, the opposing force is 5000 N
The opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
The opposing force can be calculated by the formula,
F - f = ma
Where,
F = driving force = 5000 N,
f = opposing force = ?
m = mass of car = 11000 N
a = acceleration of car
Since, the car is at constant velocity, a = 0.
So,
F - f = m(0)
F - f = 0
F = f.
Therefore, the opposing force car, weight 11000 N that is moving at constant velocity is 5000 N.
To know more about opposing force,
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an object on a planet has a mass of 243 Kg. what is the acceleration of the object, if the radius of the planet is 2.32 x 10^7m and the mass of the planet is 6.35 x 10^30 Kg estimate g as 6.67 x 10^-11 N (m/kg)
Answers
Answer:
7.87x10^5m/s^2
Explanation:
A stunt-rider on a motorcycle rides down a ramp and into a vertical loop-the-loop. If the diameter of the loop is 7.50 m, then the slowest speed the motorcycle can have at the top of the loop if it is to remain in contact with the loop is _________ km/h.
Answers
Answer:
v = 6.06 m/s
Explanation:
In order for the rider to pass the top of the loop without falling, his weight must be equal to the centripetal force:
[tex]Centripetal Force = Weight \\\frac{mv^2}{r} = mg\\\\\frac{v^2}{r} = g\\\\v = \sqrt{gr}[/tex]
where,
v = minimum speed of motorcycle at top of the loop = ?
g = acceleration due to gravity = 9.8 m/s²
r = radius of the loop = diameter/2 = 7.5 m/2 = 3.75 m
Therefore, using these values in equation, we get:
[tex]v = \sqrt{(9.8\ m/s^2)(3.75\ m)}[/tex]
v = 6.06 m/s
A tourist stands at the top of the Grand Canyon, holding a rock, overlooking the valley below. Find the final velocity and displacement of the rock after 4.0 seconds give the three initial conditions listed below:
a. the rock is dropped vertically from rest
b. the rock is tossed vertically upward with 8.0m/s of speed
c. The rock is tossed vertically downward with 8.0 m/s speed
Answers
Answer:
a. -39.2 m/s; -78.4 m
b. -31.2 m/s; -46.4 m
c. -47.2 m/s; -110.4 m
Explanation:
Part (a)We are given/can infer these variables:
t = 4.0 sa = -9.8 m/s² v_0 = 0 m/sWe want to find the displacement and the final velocity of the rock.
Δx = ?v = ?We can use this equation to find the final velocity:
v = v_0 + atPlug in the known variables into this equation.
v = 0 + (-9.8)(4.0) v = -9.8 * 4.0 v = -39.2 m/sThe final velocity of the rock is -39.2 m/s.
Now we can use this equation to find the displacement of the rock:
Δx = v_0 t + 1/2at²Plug in the known variables into this equation.
Δx = 0 * 4.0 + 1/2(-9.8)(4.0)² Δx = 1/2(-9.8)(4.0)² Δx = -4.9 * 16 Δx = -78.4 mThe displacement of the rock is -78.4 m.
Part (b)We are given/can infer these variables:
v_0 = 8.0 m/sa = -9.8 m/s²t = 4.0 sWe can use this equation to find the final velocity:
v = v_0 + atPlug in the known variables into this equation.
v = 8.0 + (-9.8)(4.0) v = 8.0 + -39.2 v = -31.2 m/sThe final velocity of the rock is -31.2 m/s.
We can use this equation to find the displacement:
Δx = v_0 t + 1/2at²Plug in known variables:
Δx = 8.0(4.0) + 1/2(-9.8)(4.0)² Δx = 32 - 4.9(16)Δx = -46.4 mThe displacement of the rock is -46.4 m.
Part (c)We are given/can infer these variables:
v_0 = -8.0 m/sa = -9.8 m/s²t = 4.0 sWe can use this equation to find the final velocity:
v = v_0 + atPlug in the known variables into this equation.
v = -8.0 + (-9.8)(4.0) v = -8.0 - 39.2 v = -47.2 m/sThe final velocity of the rock is -47.2 m/s.
We can use this equation to find the displacement:
Δx = v_0 t + 1/2at²Plug in known variables:
Δx = -8.0(4.0) + 1/2(-9.8)(4.0)²Δx = -32 - 4.9(16)Δx = -110.4 mThe displacement of the rock is -110.4 m.
(1) A block of wood weighs 980N on earth where acceleration due to gravity is 9.8N/Kg. The
moon has acceleration times that on earth. Determine the weight of the block of wood
on the moon.
(3 marks)
Answers
Given,
Weight of a block on the Earth = 980 N
Acceleration due to gravity on Earth = 9.8 N/kg
To find,
Weight of the block on the moon.
Solution,
The moon has acceleration (1/6) times that on earth. Let m be the mass of the block on the moon.
We know that,
W = mg
[tex]m=\dfrac{W}{g}\\\\m=\dfrac{980}{9.8}\\\\=100\ kg[/tex]
As mass of an object remains the same everywhere. Weight of the block on Moon is :
W' = mg'
As g'=(g/6)
So,
[tex]W=100\times \dfrac{g}{6}\\\\=100\times \dfrac{9.8}{6}\\\\=163.33\ N[/tex]
So, the weight of the block on the moon is 163.33 N.
An object has an acceleration of 6.0 m/s/s. If the net force acting upon this object were tripled , then its new acceleration would be _____ m/s/s.
Answers
Answer:
18m/s/s
Explanation:
6 times 3= 18
the work of warren washington would be most likely to explain which of the following phenomena
Answers
Answer:
t
Explanation:
A gradual shift of the North Magnetic Pole's position on Earth a steady rise in the planet's average temperature, a reduction in the Moon's light reflection.
What is the work of warren Washington?Dr. Washington and his team were able to recreate the impacts of physics on several components of weather, such as “how heat energy, water vapor, and chemicals travel between Earth's seas and the atmosphere,”
Through the use of climate models. 3 After that, computers projected atmospheric changes using the information from the climate models.
The 2007 Intergovernmental Panel on Climate Change (IPCC) report, which found that human behavior has a direct impact on the environment, used these models to support its findings.
As a result, Dr. Washington and his team were awarded the 2007 Nobel Peace Prize3.
Therefore, a slow change in the location of Earth’s North Magnetic Pole A gradual increase in Earth’s average temperature A decrease in the light reflection of the Moon
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n=Q/e formula of this?
Answers
Answer:
Its not just a mere formula . It tells a hell lot about charges .
q = ne . As you know , q stands for charge and e stands for charge on an electron . As for n , it represents an integer.
This whole q=ne thing represents quantisation of charge. The formula tells us that charge is quantized ( in the form of small packets)
Every body on this small earth has a charge which has to be an integral multiple of ‘e’ . So , we represent charge on a body(q) as
q=ne.
Hence the formula .
I hope you got what I want to say .
Thanks for reading .
A wagon moving down the road has 2000 kg m/s of momentum. Then a 500-kg bag of feed with no velocity is added to the wagon. What is the new momentum of the wagon with the feed bag in kg m/s?
Answers
Answer:
The new momentum of the wagon with the feed bag is (also) 2,000 kg·m/s
Explanation:
The given momentum of the wagon = 2000 kg·m/s
The mass of the added bag = 500 kg
The initial velocity of the bag of feed = 0 m/s
Therefore, by the conservation of momentum principle, we have;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = The new momentum of the wagon with the feed bag
Which gives;
The total initial momentum of the wagon and the bag of feed before the bad of feed is added to the wagon = 2,000 kg·m/s + 500 kg × 0 = 2,000 kg·m/s = The new momentum of the wagon with the feed bag
Therefore, the new momentum of the wagon with the feed bag = 2,000 kg·m/s.
Which statement illustrates how progress in engineering has affected the natural environment? (O A. Engineers continue to make design improvements to solar panels, making them ever more efficient in providing electricity. O B. The development of new solar panel technology drives the development of battery technology. O C. Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. (® D. As solar energy technology continues to improve, it is becoming a more attractive source of energy than sources that use fossil fuels.
Answers
Explanation:
sorry but Oz is the option or anything else can clarify
Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. So, option C.
What is meant by solar energy ?Solar energy is defined as the solar radiation that has the potential to ignite chemical processes, produce heat, or generate electricity.
Here,
In order to protect wildlife, and ecosystems, it is imperative that greenhouse gas emissions are reduced and climate change is mitigated. Solar energy plays a significant part in this as a renewable source of energy.
Additionally, solar energy can reduce water use in energy production and enhance air quality.
An extremely crucial factor considering the scarcity of water is that solar energy does not produce waste or contaminate water. Wind energy is essential for preserving hydrological resources because it consumes among the least amounts of water compared to fossil fuels and nuclear power facilities.
Hence,
Engineers have developed solar energy technology that reduces the need for other sources of energy that can pollute the atmosphere. So, option C.
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An object has three forces acting upon it, the first force is 58.2 N to the right and the second force is 14.0 N to the left. What is the magnitude of the third force, such that the object travels at a constant velocity? Answer in units of N and be sure to include all necessary work, as well as a free body diagram.
Help Please!
Answers
Answer:
44.2 N towards left
or
-44.2 N towards right
Explanation:
pls refer attachment for detailed solution
A graph showing the kinetic energy of a 10 kg object at different
speeds is provided:
Answers
Answer:
20 Joules
Explanation:
by seeing the Graph, we know that the graph will be curved. Then we can assume that the KE at speed 2 m/s is 20 Joules. But lets count it:
KE = ½ x m x v²
KE = ½ x 10 x 2²
KE = 5 x 4 = 20 Joules
Two equal forces act at the same time on the same motionless object, but in opposite directions. Which statement best describes the object’s resulting motion?
A. The object will accelerate.
B. The object will move at a constant speed.
C. The object will remain motionless.
D. The object will change direction.
Answers
Dawn and Timothy are sailboating in Lake Obewon. Starting from rest near the shore, they accelerate with a uniform acceleration of 0.39 m/s/s. How far are they from the shore after 18 seconds? *
Answers
Answer:
The value is [tex]s =63.18 \ m[/tex]
Explanation:
From the question we are told that
The uniform acceleration is [tex]a = 0.39 \ m/s^2[/tex]
The time considered is [tex]t = 18 \ seconds[/tex]
Generally the from kinematic equation we have that
[tex]s = ut + \frac{1}{2} at^2[/tex]
Given that the boat started from rest , the initial velocity is u = 0 m/s
So
[tex]s = 0 * 18 + \frac{1}{2} *0.39 * 18^2[/tex]
=> [tex]s =63.18 \ m[/tex]
The speed of sound is 344 m/sec when the air is 20 degrees Celsius how far is the source of the sound if it takes 8 seconds for the sound to reach you?
Answers
Answer: 2752 m
Explanation:
344*8=
Where is the epicenter of the hypothetical earthquake as shown in the illustration below?
A. Point A
B. Point B
C. Point C
D. Point D
Answers
Answer:
Point D
Explanation:
The epicenter of a hypothetical earthquake is located at the point where the earthquake begins.
(See the attached image).
Hope it helps!
The stars with medium temperatures appear ______________ in color (check all that apply.)
a. red
b. orange
c. yellow
d. blue
Answers
Which ball has larger Inertia before touching the ground when it falls freely from a
certain height (air friction is zero)
a. mass 50 kg b. mass 25 kg
c. mass 10 kg d. All of these
Answers
Answer:
[tex]Mass = 50kg[/tex]
Explanation:
Required
Which has the larger inertia
Inertia (I) is calculated as follows:
[tex]I = mr^2[/tex]
Where m represents the mass of the object and r represents the distance from the axis.
Take for instance m = 10 and r = 4
The inertia would be:
[tex]I = 10 * 4^2[/tex]
[tex]I = 160[/tex]
Assume r is constant and m is increased to 25
The inertia becomes:
[tex]I = 25 * 4^2[/tex]
[tex]I = 25 * 16[/tex]
[tex]I = 400[/tex]
Notice that there is an increment in inertia, when the mass increased.
Hence, mass of 50kg will have the larger inertia.
what is happening to energy as a substance goes from a gas state to a liquid state
Answers
Answer:
If we give it enough energy, the atom will eventually gain enough energy to vibrate out of the body. This is the next change of state. The molecules of water gain enough energy to escape from the surface of the water. This change of state from liquid to gas is called vaporization.
Explanation:
Answer:
B
Explanation:
It is decrasing
Hot air balloon ( look at pic)
Answers
Answer:
I think that the answer is convection.
Explanation:
Hope this helps.
A billiard ball bangs against a side bumper, giving the ball a speed of 5 m/s. If the
ball has a mass of 0.15 kg, what is the ball's kinetic energy in joules?
Answers
Answer:
1.875 joules
Explanation:
K.E=1/2 mv²
K.E=1/2 0.15×5²
K.E=1.875 joules
A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.
Answers
Complete Question
A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope
Answer:
The value is [tex]F = 150 \ N[/tex]
Explanation:
From the question we are told that
The mass of the man is [tex]m_m = 75 \ kg[/tex]
The mass of the woman is [tex]m_f = 100 \ kg[/tex]
The acceleration of the man is [tex]a_m = 2.0 \ m/s ^2[/tex]
Generally the force which she used to pull the rope is mathematically represented as
[tex]F = m * a[/tex]
=> [tex]F = 75 * 2[/tex]
=> [tex]F = 150 \ N[/tex]