Answer:
a 5 kilogram mass, at a height of 3 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.
Explanation:
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]
Learn more about average speed: https://brainly.com/question/24884027
Answer:
6.983 km/hr
Explanation:
The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr
Mejor yo por favor
What is the momentum of a 5 kg object that has a velocity of 1. 2 m/s? 3. 8 kg • m/s 4. 2 kg • m/s 6. 0 kg • m/s 6. 2 kg • m/s.
Answer:
6 kg.m/s
Explanation:
Momentum is the product of mass and velocity. So,
p = mvHere,
p denotes momentum [?]m denotes mass [5kg]v denotes velocity [1.2 m/s]→ p = 5 kg × 1.2 m/s
→ p = (5 × 1.2) kg.m/s
→ p = (5 × 12/10) kg.m/s
→ p = 12/2 kg.m/s
→ p = 6 kg.m/s
Therefore, momentum of the object is 6 kg.m/s.
The momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
MOMENTUM:Momentum of a substance is the product of its mass and velocity. That is;
Momentum (p) = mass (m) × velocity (v)
According to this question, an object has a mass of 5kg and velocity of 1.2m/s. The momentum is calculated thus:
Momentum = 5kg × 1.2m/s
Momentum = 6kgm/s.
Therefore, the momentum of a 5kg object that has a velocity of 1.2m/s is 6.0kgm/s.
Learn more about momentum at: https://brainly.com/question/250648?referrer=searchResults
Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.
Answer:
Sound waves bend around the corners of various obstacles.
Explanation:
I took the test
A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function of its horizontal position x.
Part A
Find the net work done on the box as it moves from x = 0 m to x = 8.0 m. .
Part B
Apply concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m. Assume the box started from rest.
From the graph, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
From the question, these are the given parameters;
Mass M = 5.5 KgPosition X = 0 to X = 8mPart A
The net work done will be the area under the graph.
From position X = 2m to X = 8m gives us the shape of a trapezium.
A = 1/2( a + b )h
A = 1/2( 2 + 6 ) x 8
A = 8 x 4
A = 32 Nm
From X = 0 to X = 2 gives us the shape of a triangle.
A = 1/2bh
A = 1/2 x 2 x (-4)
A = -4 x 1
A = -4 Nm
Net Work done = 32 - 4
Net work done = 28 Nm
Part B
Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m
Net Work done = 1/2m[tex]V^{2}[/tex]
Substitute all the necessary parameters
28 = 1/2 x 5.5 x [tex]V^{2}[/tex]
5.5[tex]V^{2}[/tex] = 56
[tex]V^{2}[/tex] = 56/5.5
[tex]V^{2}[/tex] = 10.18
V = [tex]\sqrt{10.1818}[/tex]
V = 3.19 m/s
Therefore, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
Learn more about work done here: https://brainly.com/question/8119756
a 280 nm thin film with index of refraction 1.6 floats on waterwhat is the largest wavelength of reflected light for which constructive interference occur? answer in units of m.
Answer:
Inside the film the wavelength will be λ/n
For constructive interference to occur the film must be λf/4 thick where λf is the wavelength of the light in the film - there will be a 180 degree phase shift at the water/film interface since the index of refraction of the film is greater than that of water - and the light has to travel λ/2 inside the film for constructive interference to occur
280 nm / 1.6 * 4 = 700 nm is the greatest wavelength allowed
Note that 700 nm is also the upper wavelength of the visible spectrum
when did humans learn that the earth is not the center of the universe?
Answer:
When did humans learn that the Earth is not the center of the universe?
Answer
1
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4 Answers
Asked in 3 Spaces


Science - Next Generation
Alexander Somm
, Consultant, Investor Relations at Novelpharm AG (2015-present)
Answered Oct 16
What, it isn’t?!
Sorry, I had to.
As far as I have read and understood, the Sumerians and later the Babylonians both had astronomical calendars that already differentiated planets and stars. Earth was not the center to them, the Sun likely was. That was around 2,200 - 1,600 BC.
After that, Greek philosopher Aristarchus of Samos (310 - 230 BC) was the first (recorded) to have believed the solar system was organized around the Sun, rather than the Earth. His heliocentric model was unpopular during Aristarchus’ lifetime, although it would inspire astronomers centuries later, such as Copernicus and Galileo.
Now, there are numerous archeological findings (cave paintings) and studies, that all suggest an understanding of complex astronomy in prehistoric times dating back as far as 40,000 years. This also explains how early, prehistoric migrants may have navigated the seas.
Explanation:
hope it helps
have a good day
What is Newton's 1st Law?
Forces come in pairs that are equal in size and opposite in direction.
F=ma
An object in motion will stay in motion at the same speed and in the same direction (ie with constant velocity) unless a force makes it change.
Answer:
An object in motion will stay in motion at the same speed and in the same direction (ie with constant velocity) unless a force makes it change.
Explanation:
compared to spiral galaxies, elliptical galaxies are:
flat disk like shape
________________
o0o0o0o0o0o0o0o0
Explain Body Mechanics.
PLUS BRAINLY! and 50 Points
Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.
Explanation:
which research model refers to the study of an individual group or community over a predetermined period
Developing Psychological Theories: Mastery Test
-
Hope this helps :)
-
How does NaOH form a basic solution when it dissolves in water
When NaOH is added to water, it separates into Na+ and OH-. The hydroxyls make it more basic.
What is basic solution?A basic solution is an aqueous solution containing more OH⁻ ions than H⁺ ions.
When NaOH as a solute is mixed into the solvent like water, it separates NaOH into Na+ and OH-. The sodium ions Na⁺ have little effect on the solution, but the hydroxyls OH⁻ ions makes the solution more basic.
Thus, NaOH form a basic solution by the presence of OH⁻ ions into it.
Learn more about basic solution.
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how to find change in kinetic energy wfrom joules
Answer:
What do you mean? Can you please explain yourself better?
In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s
Answer: 0.22
Explanation: Subtract 0.01kg from 0.23kg
What are the three different social perspectives on sport
Answer:
functionalist theory,feminist theory. discipline of sociology
Block 1, of mass m1
m
1
= 0.500 kg
k
g
, is connected over an ideal (massless and frictionless) pulley to block 2, of mass m2
m
2
, as shown. For an angle of θ
θ
= 30.0 ∘
∘
and a coefficient of kinetic friction between block 2 and the plane of μ
μ
= 0.400, an acceleration of magnitude a
a
= 0.450 m/s2
m
/
s
2
is observed for block 2.
Find the mass of block 2, m2
m
2
.
Answer:
M2=0.52kg
Explanation:
thats rightt
An instrument made of brass is an example of which of these?
solid–liquid solution
solid solution
liquid–liquid solution
gas–liquid solution
Answer:
a solid made of liquid solution
Explanation:
a trumpet for example has intrcuite valves , the only way to do this is by creating a liquid form of the metal to be able to create the solid formed instrument.
Answer:
a solid made of liquid solution
Explanation:
domne
which planet should punch travel to if his goal is to weigh in at 118 lb? refer to the table of planetary masses and radii given to determine your answer.
The planet that Punch should travel to in order to weigh 118 lb is Pentune.
The given parameters:Weight of Punch on Earth = 236 lbDesired weight = 118 lbThe mass of Punch will be constant in every planet;
[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]
The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;
[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]
where;
M is the mass of Earth = 5.972 x 10²⁴ kgR is the Radius of Earth = 6,371 kmFor Planet Tehar;
[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]
For planet Loput:
[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]
For planet Cremury:
[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]
For Planet Suven:
[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]
For Planet Pentune;
[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]
For Planet Rams;
[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]
The weight Punch on Each Planet at a constant mass is calculated as follows;
[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]
Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.
The complete question is below:
Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.
Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).
In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.
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PLEASE HELP-I LITERALLY NEED THIS RIGHT NOW!!! I'LL GIVE BRAINLIEST AND 5 STARS!!!!!!!!!!!!!!!!
why has the number of islands in hawaii increased over the last 100 million years
Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.
Answer:
Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.
A 78 N block is supported by a spring whose constant is 12 N/m. Calculate the elongation of the spring under this load.
a. 6.5 m
b. 1.5 m
c. 8.2 m
d. 7.2 m
Answer:
a 6.5 m
Explanation:
[tex]f = kx = > x = \frac{f}{k} = \frac{78}{12} = 6.5 m[/tex]
15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.
This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:
[tex]\rho =\frac{m}{V}[/tex]
In such a way, we can proceed as follows:
15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:
[tex]V=2cm*6cm*7cm=84 cm^3[/tex]
And the density turns out to be:
[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]
16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:
[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]
17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:
[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]
Which can be converted to kg/mL as follows:
[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]
18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:
[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]
19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.
Learn more:
(Density) https://brainly.com/question/952755Look at the diagram of two trains. Calculate the relative speed.
Answer:speed difference
Explanation:
Can someone please help me with number 10
Answer:
A
Explanation:
increase
Answer:
B???
Explanation:
The rate of it going up is lower than L
It might be D too.
HELP!!!!
Which statement describes earthquakes?
They release energy.
They are caused by reduced stress in rocks.
They begin at the epicenter.
They result from movement on Earth’s surface.
Answer:
A
Explanation:
earthquakes release energy
Answer:
i think it begins at the epicenter
Explanation:
i can remember
pls give brainleist
The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
We are given –
Mass of earth,m = 5.98×10²⁴ kgMass of sun, M= 1.99×10³⁰ kgDistance between Earth andSun, r= 1.5×10¹¹ m
G = 6.67×10⁻¹¹ Nm²/kg²We are asked to find the gravitational attraction between the sun and the earth.
By Universal Law of Gravitation, we know that –[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]
Substituting values, we get –
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]
Henceforth ,gravitational attraction between the sun and the earth. is 3.53×10²²N .______________________________________________
Can someone please give me the (Answers) to this? ... please ...
Answer:
Jake’s horse will only need to exert enough force to make the carriage accelerate. Even though the carriage will pull on the horse as well, that force is not enough to make the horse accelerate in the direction of the carriage because it is only strong enough to make the carriage accelerate, not the horse.
Explanation:
Additional info: the horse has more mass than the carriage does so it would require a stronger force to make the horse accelerate.
Answer: Jake’s horse will only need to exert enough force to make the carriage accelerate .Since the horse has a greater mass than the carriage, it requires a stronger force to make the horse accelerate.
Explanation: Sorry it took so long lol
What happens to a liquid in a U-tube manometer when placed in a vacuum
Answer:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid, as indicated by h, exactly balances the pressure.
Answer:
Here
Explanation:
With a greater pressure applied to the left side of a U-tube manometer, the liquid lowers in the left leg and rises in the right leg. The liquid moves until the unit weight of the liquid
Resultant of two froce 3N nad 4N acting ar apoit is 5N show that the two froce are 2 perpendicular to each other
[tex]\qquad[/tex] ☀️We are asked to prove that two forces are perpendicular to each other.
Formula to calculate magnitude of resultant 'R' of two forces 'A' and 'B' when they are at an angle 'p' to each other.
[tex]\qquad[/tex][tex]\purple{ \longrightarrow \bf R^2= A^2 + B^2 + 2 AB cos p} [/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 5^2= 3^2 + 4^2+ 2 \times 3\times 4\times cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 = 9 + 16 + 24 cos p [/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 = 25 + 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 25 - 25 = 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf 0 = 24 cos p[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf cos p = 0[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf cos p = cos 90°[/tex]
[tex]\qquad[/tex][tex]\purple{ \longrightarrow \sf p = 90°}[/tex]
Hence, Proved that –
Forces A = 3N and B = 4N are Perpendicular to each other.[tex]\qquad[/tex]_________________________
A rock is lying on a rock ledge that is 3 m high. The rock as 120 J of potential energy. What is the mass of the rock?
Have a great day!
[tex]\\ \sf\Rrightarrow PE=mgh[/tex]
[tex]\\ \sf\Rrightarrow m(10)(3)=120[/tex]
[tex]\\ \sf\Rrightarrow 30m=120[/tex]
[tex]\\ \sf\Rrightarrow m=4kg[/tex]
Mass=4kgThe momentum of a system is conserved:
I. when no net external force act on the system
II. when no internal forces act on the system
III. always
Answer:
I. when no net external force act on the system
Explanation:
Suppose you are exerting an external force F on an object, it's velocity keeps increasing. Which means its momentum = velocity * mass is also increasing. In this case the initial momentum of that object is not preserved (but increased).
Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation: