Answer:
E. x² + (y - 3)² = 16
Step-by-step explanation:
The equation of a circle in the standard (x, y) coordinate plane with center (h, k) and radius r is given by:
[tex]\boxed{(x - h)^2 + (y - k)^2 = r^2}[/tex]
To find the equation of the circle with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0, we need to first write the equation of the second circle in the standard form.
We can complete the square for y to rewrite this equation in standard form. To do this move the constant to the right side of the equation:
[tex]\implies x^2 + y^2 - 6y + 4 = 0[/tex]
[tex]\implies x^2 + y^2 - 6y = -4[/tex]
Add the square of half the coefficient of the term in y to both sides of the equation:
[tex]\implies x^2 + y^2 - 6y +\left(\dfrac{-6}{2}\right)^2= -4+\left(\dfrac{-6}{2}\right)^2[/tex]
[tex]\implies x^2 + y^2 - 6y +9= -4+9[/tex]
[tex]\implies x^2 + y^2 - 6y +9=5[/tex]
Factor the perfect square trinomial in y:
[tex]\implies x^2+(y-3)^2=5[/tex]
[tex]\implies (x-0)^2 + (y-3)^2=5[/tex]
So the center of this circle is (0, 3) and its radius is √5 units.
Since the new circle has the same center, its center is also (0, 3).
We know its radius is 4 units, so we can write the equation of the new circle as:
[tex]\implies (x - 0)^2 + (y - 3)^2 = 4^2[/tex]
[tex]\implies x^2 + (y - 3)^2 = 16[/tex]
Therefore, the equation of the circle in the standard (x, y) coordinate plane with a radius of 4 units and the same center as the circle determined by x² + y² - 6y + 4 = 0 is x² + (y - 3)² = 16.
To find:-
The equation of circle which has a radius of 4units and same centre as determined by x² + y² - 6y + 4 = 0.Answer:-
The given equation of the circle is ,
[tex]\implies x^2+y^2-6y + 4 = 0 \\[/tex]
Firstly complete the square for y in LHS of the equation as ,
[tex]\implies x^2 + y^2 -2(3)y + 4 = 0 \\[/tex]
Add and subtract 3² ,
[tex]\implies x^2 +\{ y^2 - 2(3)(y) + 3^2 \} -3^2 + 4 = 0 \\[/tex]
The term inside the curly brackets is in the form of a²-2ab+b² , which is the whole square of "a-b" . So we may rewrite it as ,
[tex]\implies x^2 + (y-3)^2 -9 + 4 = 0 \\[/tex]
[tex]\implies x^2 + (y-3)^2 - 5 = 0 \\[/tex]
[tex]\implies x^2 + (y-3)^2 = 5\\[/tex]
can be further rewritten as,
[tex]\implies (x-0)^2 + (y-3)^2 = \sqrt5^2\\[/tex]
now recall the standard equation of circle which is ,
[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]
where,
(h,k) is the centre.r is the radius.So on comparing to the standard form, we have;
[tex]\implies \rm{Centre} = (0,3)\\[/tex]
Now we are given that the radius of second circle is 4units . On substituting the respective values, again in the standard equation of circle, we get;
[tex]\implies (x-h)^2 + (y-k)^2 = r^2 \\[/tex]
[tex]\implies (x-0)^2 + (y-3)^2 = 4^2 \\[/tex]
[tex]\implies \underline{\underline{\red{ x^2 + (y-3)^2 = 16}}}\\[/tex]
and we are done!
Which of the following is a true statement?The area under the standard normal curve between 0 and 2 is twice the area between 0 and 1.The area under the standard normal curve between 0 and 2 is half the area between -2 and 2.For the standard normal curve, the IQR is approximately 3.For the standard normal curve, the area to the left of 0.1 is the same as the area to the right of 0.9.
For the standard normal curve, the area to the left of 0.1 is the same as the area to the right of 0.9 is true . So, the correct answer is D.
The standard normal curve is a normal distribution with a mean of 0 and a standard deviation of 1. This curve is often used in statistics to model natural phenomena, and it has many important properties.
Option A is incorrect because the area under the standard normal curve between 0 and 2 is not twice the area between 0 and 1. The area under the curve increases as we move away from the mean, so the area between 0 and 2 will be greater than the area between 0 and 1.
Option B is also incorrect because the area under the standard normal curve between 0 and 2 is not half the area between -2 and 2. The area between -2 and 2 covers more of the curve than the area between 0 and 2, so the area between 0 and 2 will be smaller than half the area between -2 and 2.
Option C is incorrect because the standard normal curve does not have a fixed IQR (interquartile range). The IQR depends on the quartiles of the distribution, which can vary depending on the sample size and the distribution's shape.
Option D is the correct answer because the standard normal curve is symmetric around the mean of 0. This means that the area to the left of any point on the curve is the same as the area to the right of its negative counterpart. Therefore, the area to the left of 0.1 is equal to the area to the right of 0.9.
Therefore, Correct option is D.
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ellas normal rate of pay is $10.40 an hour.
How much is she paid for working 5 hours overtime one Saturday at time-and-a-half?
Answer:
52
Step-by-step explanation:
10.40 TIMES 3
alexia lunch at a restaurant costs $34.00, without tax. She leaves the waiter a tip of 12% of the cost of the lunch, without tax. What is the total cost of the lunch, including the tip?
Answer:
$38.08
Step-by-step explanation:
12% of 34.00 as an equation would be [tex]34*0.12[/tex], [tex]34*0.12=4.08[/tex] so we add 4.08 to the total of the lunch already. [tex]34.00+4.08=38.08[/tex]. So the answer is $38.08. Hope this helps :)
An organization wishing to attract more people decides to base its
membership fees on the age of the member. Also, wanting members to
attend more activities, it gives a reduction on the membership fee for each
activity attended in the previous year.
The following table depicts the corresponding fee and reductions. The
minimum membership fee is $1, even if the member attended a lot of
activities.
Age
6 years or less
7-12 years
13-18 years
Over 18 years
Membership
Fee Reduction per Activity
$0.75
$1.25
$2
$5
$10
$15
$25
$2
Write a program that asks the user to input their age and the number of
activities attended and then displays the corresponding membership fee.
Input Validation: Do not accept a negative value for either the age or the
number of activities
C++
1. Begin the program by including the header file <iostream> which includes basic input/output library functions as well as the <vector> library which is needed for this program.
2. Declare a vector of integer type named 'ageGroups' which will store the age groups and the corresponding membership fee and reductions.
3. Create a void function named 'calculateFee()' which will take a parameters age and activities attended.
4. In the calculateFee() function, use the switch statement for the age group and store the corresponding membership fee and reduction value in variables.
5. Use an if statement to check that the number of activities attended is non-negative.
6. Calculate the membership fee using the variables and store it in a variable named 'fee'.
7. Use an if statement to check if the fee is less than 1 and if yes, assign the fee to 1.
8. Print the fee to the user.
9. End the program.
Use the shell method to set up and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the y-axis.
Answer:
[tex]\dfrac{4096\pi}{5}\approx 2573.593\; \sf (3\;d.p.)[/tex]
Step-by-step explanation:
The shell method is a calculus technique used to find the volume of a solid revolution by decomposing the solid into cylindrical shells. The volume of each cylindrical shell is the product of the surface area of the cylinder and the thickness of the cylindrical wall. The total volume of the solid is found by integrating the volumes of all the shells over a certain interval.
The volume of the solid formed by revolving a region, R, around a vertical axis, bounded by x = a and x = b, is given by:
[tex]\displaystyle 2\pi \int^b_ar(x)h(x)\;\text{d}x[/tex]
where:
r(x) is the distance from the axis of rotation to x.h(x) is the height of the solid at x (the height of the shell).[tex]\hrulefill[/tex]
We want to find the volume of the solid formed by rotating the region bounded by y = 0, y = √x, x = 0 and x = 16 about the y-axis.
As the axis of rotation is the y-axis, r(x) = x.
Therefore, in this case:
[tex]r(x)=x[/tex]
[tex]h(x)=\sqrt{x}[/tex]
[tex]a=0[/tex]
[tex]b=16[/tex]
Set up the integral:
[tex]\displaystyle 2\pi \int^{16}_0x\sqrt{x}\;\text{d}x[/tex]
Rewrite the square root of x as x to the power of 1/2:
[tex]\displaystyle 2\pi \int^{16}_0x \cdot x^{\frac{1}{2}}\;\text{d}x[/tex]
[tex]\textsf{Apply the exponent rule:} \quad a^b \cdot a^c=a^{b+c}[/tex]
[tex]\displaystyle 2\pi \int^{16}_0x^{\frac{3}{2}}\;\text{d}x[/tex]
Integrate using the power rule (increase the power by 1, then divide by the new power):
[tex]\begin{aligned}\displaystyle 2\pi \int^{16}_0x^{\frac{3}{2}}\;\text{d}x&=2\pi \left[\dfrac{2}{5}x^{\frac{5}{2}}\right]^{16}_0\\\\&=2\pi \left[\dfrac{2}{5}(16)^{\frac{5}{2}}-\dfrac{2}{5}(0)^{\frac{5}{2}}\right]\\\\&=2 \pi \cdot \dfrac{2}{5}(16)^{\frac{5}{2}}\\\\&=\dfrac{4\pi}{5}\cdot 1024\\\\&=\dfrac{4096\pi}{5}\\\\&\approx 2573.593\; \sf (3\;d.p.)\end{aligned}[/tex]
Therefore, the volume of the solid is exactly 4096π/5 or approximately 2573.593 (3 d.p.).
[tex]\hrulefill[/tex]
[tex]\boxed{\begin{minipage}{4 cm}\underline{Power Rule of Integration}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}(+\;\text{C})$\\\end{minipage}}[/tex]
Andy has 4 red cards, 3 blue cards, and 2 green cards. He chooses a card and replaces it before choosing a card again. How many possible outcomes are in the sample space of Andy's experiment?
A) 18
B) 9
C)81
D)3
Answer: C) 81
Step-by-step explanation:
Since Andy chooses a card and replaces it before choosing another card, each choice is independent and the total number of possible outcomes is the product of the number of choices for each card.
There are 4 red cards, 3 blue cards, and 2 green cards, so there are a total of 4+3+2=9 cards to choose from.
For each choice, Andy has 9 options. Since he does this twice, the total number of possible outcomes is:
9 x 9 = 81
Therefore, the answer is C) 81.
For ever 100 clovers that Lucy picked 22 of them had four leaves while the others only had three leave in total Lucy picked 1,000 clovers if her pattern continued, how many three - leaf and four leaf would Lucy have how many of each clover would she have if she picked 2,000 clovers
Answer:
a)220 4 leaf clovers, 780 3 leaf clovers b)440 four leaf clovers, 1560 3 leaf clovers
Step-by-step explanation:
100:1000=1:10 22:x=1:10 x=220
220x2=440
1000-220=780
780x2=1560
Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y=mx+b (3.5). x + 2y = 5 The equation of the line is ____(Type an equation Type your answer in slope intercept form. Use integers or fractions for any numbers in the equation. Simplify your answer
The equation of the line is y = -1/2 + 13/2.
The point is (3, 5).
An equation of line is x + 2y = 5.
To determine the slope intercept form of the equation using the point and line we first determine the slope of the equation from the given line.
Convert the equation of line in slope intercept form.
x + 2y = 5
Subtract x on both side, we get
2y = -x + 5
Divide by 2 on both side, we get
y = -1/2 x + 5
On comparing with y = mx + c, where m is slope, we get
m = -1/2
Now the equation of the line is;
y - y₁ = m(x - x₁)
y - 5 = -1/2(x - 3)
Simplify the bracket
y - 5 = -1/2x + 3/2
Add 5 on both side, we get
y = -1/2x + 3/2 + 5
y = -1/2 + 13/2
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The complete question is:
Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y = mx + b.
(3, 5); x + 2y = 5
The equation of the line is ____ . (Type an equation Type your answer in slope intercept form. Use integers or fractions for any numbers in the equation. Simplify your answer)
Question 20 (2 points)
Suppose a survey was given to students at WCC and it asked them if they voted for
the Democrat or Republican in the last election. Results of the survey are shown
below:
Democrat Republican
Male. 50. 75
Female. 125. 50
If a student from the survey is selected at random, what is the probability they voted
for the republican?
75/50
50/75
75/300
125/300
Answer:
The table given provides the number of male and female students who voted for each party, but it does not give the total number of students in the survey. To find the probability of selecting a student who voted for the Republican party, we need to know the total number of students who participated in the survey.
The total number of students in the survey is:
50 + 75 + 125 + 50 = 300
The number of students who voted for the Republican party is:
75 + 50 = 125
Therefore, the probability of selecting a student who voted for the Republican party is:
125/300 = 0.4167 (rounded to four decimal places)
So, the answer is option D: 125/300
(please mark my answer as brainliest)
The following cross-tabulation of frequencies for Income Levels (A, B, and C) and Education Levels (E, F, and
G
) has been obtained for a sample of 122 persons: Download Excel Table Here 1) For a randomly selected observation from the above data, determine the probability
P(B∪E)
. Round your answer to four decimal places (include zero if necessary). 2) For a randomly selected observation from the above data, determine the probability
P(G c
)
. Round your answer to four decimal places (include zero if necessary). 3) For a randomly selected observation from the above data, determine the probability
P(C∣F)
. Round your answer to four decimal places (include zero if necessary).
The probability of P(B U E) is 0.5984, the probability of the complement of G (i.e. Gᶜ) is 0.6818, and the probability of C given F is 0.4706
To find the probability P(B U E), we need to add the frequencies in column B and row E, but since the cell where they intersect has already been counted in both, we need to subtract it once. Therefore:
P(B U E) = (6+13+17) + (15+20+10+45) - 43 = 73
Then we divide by the total number of observations:
P(B U E) = 73/122 = 0.5984 (rounded to four decimal places)
To find the probability of the complement of G (i.e. Gᶜ), we need to subtract the frequency in the cell where G and Total intersect from the total number of observations:
P(Gᶜ) = 1 - 39/122 = 0.6818 (rounded to four decimal places)
To find the probability of C given F, we need to divide the frequency in the cell where C and F intersect by the total frequency in the row where F is located:
P(C|F) = 24/51 = 0.4706 (rounded to four decimal places)
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Complete question is attached below
Two trains A and B left the same station at the same time. The speed of
train A is 105 kmph, while train B's is 87 kmph. If they travel in the same
direction, how far apart will they be in three hours?
Answer:
Step-by-step explanation:
Since they are traveling in the same direction, the distance between them increases at a rate of the difference of their speeds.
The relative speed of train A with respect to train B is:
105 kmph - 87 kmph = 18 kmph
In three hours, the distance between them will be:
Distance = Speed x Time
Distance = 18 kmph x 3 hours
Distance = 54 km
Therefore, the two trains will be 54 kilometers apart after three hours.
Could you please solve this one.
The proof that the lines CD and XY are parallel is shown below in paragraghs
How to prove the lines CD and XY are parallelGiven that
∠CAY ≅ ∠XBD
This means that the angles CAY and XBD are congruent angles
The above means that
The angles ∠AYX & ∠ACD correspond to the angle ∠CAYThe angle ∠BXY & ∠BDC corresponds to the angle ∠XBDBy the corresponding angles, we have
∠BXY = ∠AYX
∠ACD = ∠BDC
By the congruent angles above, the following lines are parallel
Line AC and BX
Line AY and BD
Line CD and XY
Hence, the lines CD and XY are parallel
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I need help with this question.
you need to match it to the percentage of the fraction for example 1/2 is 50 percentage and than you do 1/4 is 25 percent.
A pond in the shape of a right-angled triangle is shown below. Calculate the perimeter of the pond. Give your answer in metres to 1 d.p. 1.46 m 100 73°
The perimeter of the pond is 2.92 meters.
What s a right-angle triangle:
A right-angled triangle is a triangle in which one of the angles measures exactly 90 degrees, also known as a right angle.
The side opposite the right angle is called the hypotenuse, and the other two sides are called the legs.
The perimeter of a right-angled triangle is the sum of the lengths of its three sides.
Here we have
The Hypotenuse of the triangle is 1.46 m
The angle between hypotenuse and perpendicular height = 73°
From triagonometric ratios,
=> cos A = Perpendicular height/ Hypotenuse.
=> cos (73) = Perpendicular height/1.46
=> Perpendicular height = 1.46 × 0.29 = 0.42 m
As we know from Pythagoras' theorem,
Hypotenuse² = side² + side²
Side = √Hypotenuse² - side²
= √[(1.46)²- (0.42)²] = 1.04
Therefore, the sides of the pond are 1.46 m, 0.42 m, and 1.04
Hence, perimeter of the pond = 1.46 + 0.42 + 1.04 = 2.92 meters
Therefore,
The perimeter of the pond is 2.92 meters.
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The complete Question is given below
a fire truck is parked 25 feet away from a high rise. the ladder on the truck reaches 100 feet. how high up the high rise can the ladder reach?
Answer:
If the fire truck is parked 25 feet away from the high rise and the ladder on the truck reaches 100 feet, we can use the Pythagorean theorem to find out how high up the high rise the ladder can reach.
Let's assume that the height the ladder can reach is "x". Then, we can set up the following equation:
25^2 + x^2 = 100^2
Simplifying this equation, we get:
625 + x^2 = 10000
Subtracting 625 from both sides, we get:
x^2 = 9375
Taking the square root of both sides, we get:
x = sqrt(9375)
x ≈ 96.81
Therefore, the ladder on the fire truck can reach a height of approximately 96.81 feet up the high rise
pls helppppppp explain !!!
Answer:
x²
Step-by-step explanation:
[tex]{ \tt{ \frac{ {x}^{ - 3} . {x}^{2} }{ {x}^{ - 3} } }} \\ \\ \dashrightarrow{ \tt{x {}^{( - 3 + 2 - ( - 3))} }} \\ \dashrightarrow{ \tt{ {x}^{( - 3 + 2 + 3)} }} \: \: \: \: \\ \dashrightarrow{ \boxed{ \tt{ \: \: \: \: {x}^{2} \: \: \: \: \: \: }}} \: \: \: \: [/tex]
FILL IN THE BLANK. In the context of data-flow diagrams (DFDs), a(n) _____ shows either the source or destination of the data.
a. data-flow line
b. entity symbol
c. process symbol d. data store symbol
In the context of data-flow diagrams (DFDs), a(n) option a. data-flow line shows either the source or destination of the data.
In data-flow diagrams (DFDs), an entity symbol represents an external agent or entity that interacts with the system being modeled. It could be a person, organization, or system that sends or receives data from the system being modeled. An entity symbol is represented as a rectangle with its name written inside it. It shows either the source or destination of the data in the DFD. An example of an entity symbol in a DFD could be a customer who provides orders to a company, or a supplier who delivers goods to a company. The entity symbol helps to illustrate the flow of data between external entities and the system being modeled.
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what is the second derivative of x^n when n= greater than or equal to 2
Answer:
The second derivative of x^n when n is greater than or equal to 2 is n(n-1)x^(n-2).CDs are on sale for $5 each. Jennifer has $45 and wants to buy as many as she can. How many CDs can Jennifer buy?
Answer:
9 CDs
Step-by-step explanation:
r u d0mb? 45 divided by 5 = 5 10 15 20 25 30 35 40 45
count the numbers
BOOM ANSWER
NEXT TIME PAY ATTENTION IN 2ND GRADE10 points!!! ASAP PLEASE HELP FIND THE AREA AND THE PERIMETER!!
Answer:
Area = 559.17 square feet
Perimeter = 94.26 ft
Step-by-step explanation:
Make sure all the units are the same and consistent.
r = radius of semi-circle
= [tex]\frac{Diameter}{2}[/tex]
= [tex]\frac{18}{2}[/tex] ft
= 9 ft
Area of composite figure = Area of rectangle + Area of semi-circle:
= [Length × Breadth] + [[tex]\frac{1}{2}[/tex] × (Area of circle)]
= [24 ft × 18 ft] + [[tex]\frac{1}{2}[/tex] × ([tex]\pi r^{2}[/tex])]
= 432 [tex]ft^{2}[/tex] + [[tex]\frac{1}{2}[/tex] × ([tex]\pi 9^{2}[/tex])] [tex]ft^{2}[/tex]
= 432 + [[tex]\frac{1}{2}[/tex] × (3.14) ×(81)]
= 559.17[tex]ft^{2}[/tex]
Perimeter of composite figure =
Circumference of semi-circle + 3 outer sides of rectangle:
= [[tex]\frac{1}{2}[/tex] × [tex]2\pi r[/tex]] + [24 + 18 + 24]
= ( [tex]\pi r[/tex] + 66) ft
= [(3.14)(9) + 66] ft
= 94.26 ft
What is the missing value in the equation shown below?
4/10+ ?/100= 7/10
A 1
B 3
C 10
D 30
Answer: D 30
Step-by-step explanation:
4/10 + 30/100
2/5 + 3/10
7/10
NB: LEFT-HAND SIDE IS EQUAL TO THE RIGHT-HAND SIDE
Please help me with number 9 and 10!??? Thank you for help anyone who help me ((:!!!
Answer:
9. $18
10. 68
Step-by-step explanation:
$8 + $2 + $3 + $5= $18
104 - 36= 68
which of the following equations represent the profit-maximizing combination of resources for a firm?
The profit-maximizing combination of resources for a firm is MRPl / Pl = MRPc / Pc = 10/2 = 5/1 . The correct option is D).
The profit-maximizing combination of resources for a firm is determined by the equality of the marginal revenue product (MRP) per unit of input (labor, L, or capital, C) to the price per unit of input.
Therefore, the equation that represents the profit-maximizing combination of resources for a firm is:
MRPl / Pl = MRPc / Pc
where MRPl is the marginal revenue product of labor, Pl is the price of labor, MRPc is the marginal revenue product of capital, and Pc is the price of capital.
Among the given options, only option D satisfies the above equation. Therefore, option D represents the profit-maximizing combination of resources for a firm.
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_____The given question is incomplete, the complete question is given below:
Which of the following equations represent the profit-maximising combination of resources for a firm?
A. MRPl / Pl = MRPc / Pc = 1
B. MRPl / Pl = MRPc / Pc = 5
C. MRPl / Pl = MRPc / Pc = 10/10 = 5/5
D. MRPl / Pl = MRPc / Pc = 10/2 = 5/1
what is the half life of a substance that decays at a rate of 2.5% p.a?
Answer:
The half-life of a substance is the amount of time it takes for half of the initial amount of the substance to decay.
We can use the following formula to calculate the half-life (t1/2) of a substance with a decay rate of r:
t1/2 = (ln 2) / r
where ln 2 is the natural logarithm of 2 (approximately 0.693).
In this case, the decay rate is 2.5% per year, or 0.025 per year. Plugging this into the formula, we get:
t1/2 = (ln 2) / 0.025
t1/2 = 27.73 years (rounded to two decimal places)
Therefore, the half-life of the substance is approximately 27.73 years.
HELP ME ASAP ITS DUE TODAY!!!!!! I'LL GIVE YOU ONE HUNDRED POINTS AND BE MARKED BRAINLIEST IF YOU HELP ME!!!
Suppose parametric equations for the line segment between (8,-2) and (9,-2) have the form:
{x(t)=a+bt
{y(t)=c+dt
If the parametric curve starts at (8,-2) when t=0 and ends at (9,-2) at t=1, then find a,b,c, and d. a= b=
c=
d=
A parametric equation is one where the x and y coordinates of the curve are both written as functions of another variable called a parameter; this is usually given the letter t or θ . And the value of a= 8, b= 1, c= -2 and d= 0.
Equation of this form is known as a parametric equation; it uses an independent variable known as a parameter (often represented by t) and dependent variables that are defined as continuous functions of the parameter and independent of other variables.
You require 4 independent solutions because there are 4 unknowns. You can put two equations at each end point if you know t at each end point. (one for the x value and one for the y value).
At (8,-2), time is equal to zero as follows: 8 = a + bt = a + b(0) a = 8 -2 = c + dt = c + d(0) c = -2
At (9,-2), t = 1 because 9 = a + bt = 8 + b(1) b = 1 and -2 = c + dt = -2 + d(1) d = 0.
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here's a graph that represents f (x) = 5. 4321*2^x .
the coordinate of a are ( 1,c) and the coordinates of b are ( 4,d) what is the value of d/c ? explain your reasoning
The value of d/c = 8, when the given graph represents the equation f(x) = 5.4321*(2)ˣ, and A (1, c), and B (4, d) pass through the graph.
What does the graph of an equation show?The graph of an equation passes through all the points that satisfy the given equation. The graph shows a curve joining all those points.
How do we solve the given question?In the question, we are given a graph and its equation f(x) = 5.4321*(2)ˣ.
We are given the coordinates of two points on graphs A: (1, c) and B: (4, d).
We know that any point of the form (x, y) which passes through the graph of the equation, satisfies the equation.
∴ A (1, c) and B (4, d) satisfies the equation f(x) = 5.4321*(2)ˣ.
∴ c = 5.4321*(2)¹ = 5.4321 * 2
d = 5.4321*(2)⁴ = 5.4321 * 16
∴ d/c = (5.4321*16)/(5.4321*2) = 16/2 = 8.
∴ The value of d/c = 8, when the given graph represents the equation f(x) = 5.4321*(2)ˣ, and A (1, c), and B (4, d) pass through the graph.
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In each case either show that the statement is true, or give an example showing it is false. a. If a linear system has n variables and m equations, then the augmented matrix has n rows.
The given statements are true or false are shown below, about linear system has n variables and m equations, then the augmented matrix has n rows.
First, let's write how A and C look like.
A = [C|b], where b is the constant matrix.
(a) False.
Example
[tex]\left[\begin{array}{ccc}1&0&2\\0&1&3\\\end{array}\right][/tex]
We can see that z = t and so we have infinitely many solutions but there's no row of zeros.
(b) False.
Example
[tex]\left[\begin{array}{cc}1&0&0\1&1&0&0\\\end{array}\right][/tex]
Here; x1 = 1 and x2 = 1 is a unique solution and we have a row of zeros.
(c) True.
In the row-echelon form, the last row is either a row of zeros or a row that contains a leading 1. If the row has a leading 1, then there is a solution. Since we assume there is no solution, then the row must be a row of zeros.
(d) False.
Example
[tex]\left[\begin{array}{cc}1&3\\0&0\end{array}\right][/tex]
Here; x₁ = 1 − 3t and x2 = t. Thus, the system is consistent.
(e) True.
Suppose we have a typical equation in a system
а1x1 + A2X2 + ··· + anxn = b
Now, if b≠0 and x1 = x2 = ··· = x₂ = 0, then the system is Xn inconsistent. But, if b = 0, then we have a solution.
(f) False.
Example
[tex]\left[\begin{array}{cc}1&2&0&0\end{array}\right][/tex]
If a = 0, then it's consistent(infinitely many solutions) but if a 0, then it's inconsistent.
(g) Ture.
Since the rank would be at most 3 and this will lead to a free variable (4 columns in C and the rank is 3, so there is at leat 1 free variable). Thus, the system has more thatn one solution.
(h) True.
Because the rank is the number of leading 1's lying in different rows and A has 3 rows. Thus, the rank ≤ 3.
(i) False.
Because we could have a row of zeros in C and a leading 1 in A. In other words, a31 = a32 = A33 = A34 = 0 and c3 1. This makes the system inconsistent.
(j) True.
If the rank of C = 3, then there will be a free variable and this means the system is consistent.
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Complete question:
In each case either show that the statement is true, or give an example showing it is false. (a) If a linear system has n variables and m equations, then the augmented matrix has n rows. quations • ( *b) A consistent linear system must have infinitely many solutions. . (c) If a row operation is done to a consistent linear system, the resulting system must be consistent. (d) If a series of row operations on a linear system results in an inconsistent system, the original system is inconsistent.
Find area of a circle whose diameter 21cm
The area of the circle is approximately 346.36 square centimeters.
What is area?Area is a mathematical concept that refers to the amount of space that is inside a two-dimensional shape or surface. It is typically measured in square units, such as square meters (m² or square centimeters (cm²).
What is a diameter?The diameter of a circle is the distance across the circle passing through its center. It is twice the length of the circle's radius.If you know the diameter of a circle, you can calculate its radius by dividing the diameter by 2: radius = diameter/2
In the given question,
The diameter (d) of a circle is the distance across the circle passing through the center.
If the diameter of the circle is 21 cm, then the radius (r) of the circle (which is half of the diameter) is:
r = d/2 = 21/2 = 10.5 cm
The formula for the area (A) of a circle is:
A = πr²
where π (pi) is a mathematical constant that represents the ratio of the circumference of a circle to its diameter, approximately equal to 3.14159.
Substituting the value of r into the formula, we get:
A = π(10.5)² A = 346.36 cm² (rounded to two decimal places)
Therefore, the area of the circle is approximately 346.36 square centimeters.
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The figure to the right shows the results of a survey in which 1007 adults from Country A, 1005 adults from
Country B, 1016 adults from Country C, 1016 adults from Country D, and 1000 adults from Country E were
asked whether national identity is strongly tied to birthplace.
National Identity and Birthplace
People from different countries who believe national
identity is strongly tied to birthplace
Country A
Country B
Country C
Country D
Country E
34%
22%
29%
50%
14%
Construct a 99% confidence interval for the population proportion of adults who say national identity is strongly tied to birthplace for each country listed.
99% confidence interval is that the true population proportion of adults who say national identity is strongly tied to birthplace in Country A is between 30.7% and 37.3%.
What is confidence interval?The confidence interval is a set of values that, with a given level of certainty, contains the real population parameter. The likelihood that the genuine population parameter falls inside the interval is represented by the degree of confidence. In this instance, we created 99% confidence intervals for the percentage of individuals in each demographic who claim that national identity is highly correlated with birthplace. This indicates that 99% of the intervals we build would include the genuine population percentage if the survey were to be repeated numerous times.
The confidence interval is given using the formula:
CI = p ± z*(√((p*(1-p))/n))
Using the given values for different intervals the 99% for different countries are:
For Country A we have:
p = 0.34
n = 1007
z = 2.58 (based on a 99% confidence level)
CI = 0.34 ± 2.58*(√((0.34*(1-0.34))/1007)) = 0.307 to 0.373
For Country B we have:
p = 0.22
n = 1005
z = 2.58
CI = 0.22 ± 2.58*(√((0.22*(1-0.22))/1005)) = 0.187 to 0.253
For Country C we have:
p = 0.29
n = 1016
z = 2.58
CI = 0.29 ± 2.58*(√((0.29*(1-0.29))/1016)) = 0.259 to 0.321
For Country D we have:
p = 0.5
n = 1016
z = 2.58
CI = 0.5 ± 2.58*(√((0.5*(1-0.5))/1016)) = 0.469 to 0.531
For Country E we have:
p = 0.14
n = 1000
z = 2.58
CI = 0.14 ± 2.58*(√((0.14*(1-0.14))/1000)) = 0.108 to 0.172.
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